Answer:
28.8g
Explanation:
I think your chemical equation should be:
2KClO3 → 2KCl +3O2
Number of moles of KClO3
[tex] = \frac{mass}{molar \: mass} [/tex]
[tex] = \frac{69}{39 + 35.5 + 3(16)} [/tex]
[tex] = 0.6mol[/tex]
From the equation,
2 mol of KClO3 : 3 mol of 02
So...
0.6 mol of KClO3 : 0.9 mol of O2
Number of moles of O2= 0.9mol
So the mass of O2 formed = number of moles× molar mass
= 0.9 × 2(16)
= 28.8g
If 69 gram of KClO₃ decomposes then 27.036 grams of oxygen will form.
What is Stoichiometry ?Stoichiometry helps us use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given balanced equation is
2KClO₃ → 2KCl + 3O₂
According to Stoichiometry, x gram of oxygen will form
= [tex]69\ \text{g of}\ KClO_{3} \times \frac{1\ \text{mol}\ KClO_{3}}{122.55\ g\ KClO_{3}} \times \frac{3\ \text{mol}\ O_2}{2\ \text{mol}\ KClO_{3}} \times \frac{32\ g\ O_2}{1\ \text{mol}\ O_2}[/tex]
= 27.036 grams of Oxygen
Thus from the above conclusion we can say that If 69 gram of KClO₃ decomposes then 27.036 grams of oxygen will form.
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How many moles of O2 are needed to react
with 24 moles of C2H6?
2C2H6 + 702 — 4CO2 + 6H20
Explanation:
Mole ratio of Ethane to Oxygen = 2 : 7
Moles of O2 needed = 24 moles * (7/2) = 84 moles.
Moles are the ratio of the mass and the molar mass of the substance. 84 moles of oxygen are needed to react with Ethane.
What are moles?Moles are the unit of the measurement of small entities like molecules, atoms, or particles.
The reaction is shown as:
[tex]\rm 2C_{2}H_{6} +7O_{2} \rightarrow 4CO_{2} + 6H_{2}O[/tex]
From the reaction, it can be said that the mole ratio of ethane [tex](\rm C_{2}H_{6})[/tex] and oxygen [tex](\rm O_{2})[/tex] is 2:7.
Then moles of oxygen will be,
[tex]24 \times \dfrac{7}{2} = 84[/tex]
Therefore, 84 moles of oxygen are needed to react with 24 moles of ethane.
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A saturated hydrocarbon having molecular formula CnH2n+2 diffuses through a porous membrane twice as fast as sulphur dioxide. Calculate the volume occupied by the hydrocarbon at27°C and 2atm ?
Help me fast !
Answer:
12.3 L
Explanation:
Now we have that the rate of diffusion of the saturated hydrocarbon is R1
Rate of diffusion of sulphur dioxide is R2
Molar mass of hydrocarbon is M1
Molar mass of sulphur dioxide is 64 gmol-1
From Graham's law;
R1/R2 = √64/M1
2/1 =√64/M1
(2/1)^2 = (√64/M1)^2
4/1 = 64/M1
4M1 =64
M1 = 16
To obtain the number of moles of the gas;
(n*12) + (2n + 2) 1 = 16
12n + 2n + 2 = 16
14n + 2 = 16
14n = 16 - 2
n = 14/14
n = 1
Hence the hydrocarbon is CH4
Volume occupied by CH4 at STP = 22.4 L
Hence;
P1 = 1 atm
T1 = 273 K
V1 = 22.4 L
T2 = 300 K
P2 = 2 atm
V2 = ?
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = P1V1T2/P2T1
V2 = 1 * 22.4 * 300/2 * 273
V2 = 12.3 L
The volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L
Let the hydrocarbon be initially at standard temperature and pressure (STP)
Thus, we can obtain the new volume of the hydrocarbon by using the combined gas equation as illustrated below:
Initial volume (V₁) = STP = 22.4 L Initial pressure (P₁) = STP = 1 atmInitial temperature (T₁) = STP = 273 KFinal temperature (T₂) = 27 °C = 27 + 273 = 300 KFinal pressure (P₂) = 2 atmFinal volume (V₂) =?P₁V₁ / T₁ = P₂V₂ / T₂
(1 × 22.4) / 273 = (2 × V₂) / 300
22.4 / 273 = (2 × V₂) / 300
Cross multiply
273 × 2 × V₂ = 22.4 × 300
546 × V₂ = 6720
Divide both side by 546
V₂ = 6720 / 546
V₂ = 12.31 L
Thus, the volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L
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What type of reaction occurs between an element and a compound?
Answer:
exothermic reaction
Explanation:
because it occurs in the presence of heat
True or False: Most metals are found to occur naturally in their uncombined states.
Answer:
I think it's true. But I'm not sure
Answer:
True
Explanation:
Will give brainliest
Which is one advantage of using a reflecting telescope instead of a refracting telescope?
Reflecting telescopes are less expensive.
Reflecting telescopes produce clearer images.
Reflecting telescopes require only concave lenses.
Reflecting telescopes usually take up less space.
Answer:
Reflecting telescopes take up less space, is the suitable answer.
Answer:
B, or 2: Reflecting telescopes produce clearer images.
Explanation:
Took the test
Which type of energy is the tree changing the light energy into?
Answer: Chemical energy
Explanation: In this case plants convert light energy (1) into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy.
Answer:
chemical energy
In this case plants convert light energy into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy.
Explanation:
Complete the statement of equality.
Answer:
This is not a viable question.
Explanation:
Which force keeps the planets from floating off into space?
Earth’s gravity
the Sun’s gravity
the moon’s gravity
Milky Way’s gravity
Answer:
Suns gravity
Explanation:
Answer: 2021
B
The Sun's gravity
Explanation: Just took the big test
A radical is a reactive intermediate with a single ____________ electron, formed by ____________ of a covalent bond. Allylic radicals are stabilized by ____________ , making them ____________ stable than tertiary radicals. A compound that contains an especially weak bond that serves as a source of radicals is called a radical ____________ . Treatment of cyclohexene with N-bromosuccinimide in the presence of light leads to ____________ by ____________ intermediates.
1. A radical is a reactive intermediate with a single ____________ electron, formed by ____________ of a covalent bond.
1. A: Unpaired, and homolysis
2. Allylic radicals are stabilized by ____________ , making them ____________ stable than tertiary radicals.
2. A: Resonance, and more
3. A compound that contains an especially weak bond that serves as a source of radicals is called a radical ____________ .
3. A: Initiator
4. Treatment of cyclohexene with N-bromosuccinimide in the presence of light leads to ____________ by ____________ intermediates.
4. A: Allylic substitution by radical
28. After 3 substances are mixed, an odor emits
a. chemical change
b. physical change
c. thermal energy is used
a do
Answer:
a. chemical change
Explanation:
A chemical change can cause an odor, however a physical change cannot, and the use of thermal energy will only make an object colder, not give it an odor.
Which of the physical processes below result in the formation of metamorphic rocks
i dont see any processes below
Answer:
Heat and pressure
Explanation:
got it on study island
What is the molar mass of sodium bicarbonate, NaHCO3.
Answer:
84.01 g/mol
Explanation:
Look at your periodic table for the atomic mass for Na, H, and C, and O
Na = 22.99
H = 1.01
C = 12.01
O = 16.00
They are three oxygen atoms. So 16(3) = 48
Now do basic math.
22.99 + 1.01 + 12.01 + 16.00(3) = 84.01 g/mol.
Literally found this in a YouTuube video lol. Hope it helped doe!
The molar mass of sodium bicarbonate (NaHCO₃) is approximately 84.01 grams per mole (g/mol).
To calculate the molar mass of sodium bicarbonate (NaHCO₃), you need to sum the atomic masses of all the atoms in the chemical formula.
The atomic masses:
Sodium (Na) = 22.99 g/mol
Hydrogen (H) = 1.01 g/mol
Carbon (C) = 12.01 g/mol
Oxygen (O) = 16.00 g/mol
Now, let's calculate the molar mass of NaHCO₃:
Molar mass of NaHCO₃ = (1 * Na) + (1 * H) + (1 * C) + (3 * O)
Molar mass of NaHCO₃ = (1 * 22.99 g/mol) + (1 * 1.01 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol)
Molar mass of NaHCO₃ = 22.99 g/mol + 1.01 g/mol + 12.01 g/mol + 48.00 g/mol
Molar mass of NaHCO₃ = 84.01 g/mol
Therefore, the molar mass of sodium bicarbonate (NaHCO₃) is approximately 84.01 grams per mole (g/mol).
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What element needs just a single extra electron to have the same electron configuration as helium?
Answer:
Hydrogen
Explanation:
Helium has an atomic number Z = 2, that is, it has 2 protons. Since it is electrically neutral it also has 2 electrons. Thus, the electron configuration of helium is 1s².
Hydrogen has an atomic number Z = 1, that is, it has 1 proton. Since it is electrically neutral it also has 1 electron. Thus, the electron configuration of hydrogen is 1s¹.
If hydrogen gains a single extra electron to form H¹⁻, it acquires the same electron configuration than helium.
the formula of calcium oxide is CaO. What is the formula of the ionic compound containing calium abd sulfate ions
Answer:
[tex]CaS[/tex]
Explanation:
Hello!
In this case, since calcium's oxidation state when forming ionic bonds is +2 and sulfur's oxidation state when bonding those bonds is -2, for the required formula we write:
[tex]Ca^{2+}S^{2-}[/tex]
Now, since they have the same charge number, we infer the ionic compound formed when they bond is calcium sulfide:
[tex]CaS[/tex]
Best regards!
A precipitate of lead chloride is formed when silver chloride is dissolved in a saturated solution of lead chloride due to g
Answer:
Due to "Common ion effect".
Explanation:
Lead chloride and Silver chloride have an ion in common which is Cl-, when these two solutions are dissolved, more chloride reacts with lead which shifts equilibrium position to the right hence precipitating out.
you weigh out 43.9 g of potassium (K). How many moles of potassium did you weigh? How many atoms?
Answer:
1.12 moles of potassium
6.76x10²³ atoms of potassium
Explanation:
In order to convert g of potassium to moles, we need to use its molar mass (which we can find via the periodic table):
Molar Mass of K = 39.09 g/mol43.9 g K ÷ 39.09 g/mol = 1.12 mol KThen, to convert moles into atoms, we use Avogadro's number (6.023x10²³ atoms per mole):
1.12 mol K * 6.023x10²³[tex]\frac{atoms}{mol}[/tex] = 6.76x10²³ K atoms. Bob plants some seeds in a small cup. He puts the cup in the light and waters the soil every day. After 4 days, the seedlings emerge from the soil. What can Bob conclude?
answers in the picture I HAVE TO TURN IN THIS AT 10:30 PLEASE HELP ME OUT
The seedlings exerted an upward pushing force on the soil explains why the
seeds emerged from the soil.
Bob watered the soil in which the seed absorbs the water through the coat ,
the seed coat and embryo begins to enlarge and emerge from the soil.
The hydrated enzymes become active thereby increasing metabolic
activities and energy production which is needed for the growth of the plant.
The energy helps the seed exert an upward force on the soil.
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HELP 20 POINTS
What is the frequency of an Electromagnetic wave has with wavelength 2.94 x 10^-8 cm?
What's the enthalpy of neutralization and explain briefly how it relates to esterification
Answer:
The enthalpy of neutralization and its relation to esterification is explained below in details.
Explanation:
The conventional enthalpy variation of neutralization is the enthalpy exchange when extracts of an acid and an alkali respond together under conventional circumstances to generate 1 mole of water. Remark that the enthalpy change of neutralization is always estimated per mole of water produced.
Help me as soon as possible I’m gonna dieeee
A certain reaction requires 0.250 moles of Na2SO4. How
much sodium sulfate should the chemist weigh out to perform
the reaction?
The chemist weigh out 35.51 g Na2SO4
Further explanationGiven
0.250 moles of Na2SO4
Required
weight of Na2SO4
Solution
A mole is a number of particles(atoms, molecules, ions) in a substance
This refers to the atomic total of the 12 gr C-12 which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles
Moles of a substance can also be determined from its molecular weight
[tex]\tt mol=\dfrac{mass}{MW}[/tex]
For 0.250 moles of Na2SO4, mass =
[tex]\tt mass=mol\times MW\\\\mass=0.25\times 142,04 g/mol\\\\mass=35.51~g[/tex]
PLEASE HELP WILL GIVE BRAINLIEST
Answer:
Coefficients represents no of moles while subscripts represent no of atoms.
Answer:
Coefficients came before formula . Example = 4CO means there are 4 molecules of carbonmonooxide.
Subscripts came after and below the formula . Example = Oxygen gas in which 2 is a subscript which means there are 2 atoms of Oxygen in 1 molecule of Oxygen i.e. oxygen gas
The pressure of a sample of argon gas was increased from 3.89 atm to 8.73 atm at constant temperature. If the final volume of the argon sample was 18.4 L, what was the initial volume of the argon sample? Assume ideal behavior.
Answer:
41.29 LExplanation:
The initial volume can be found by using the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
Since we are finding the initial volume
[tex]V_1 = \frac{P_2V_2}{P_1} \\[/tex]
From the question we have
[tex]V_1 = \frac{8.73 \times 18.4}{3.89} = \frac{160.632}{3.89} \\ = 41.293573...[/tex]
We have the final answer as
41.29 LHope this helps you
g In this equation stands for the Rydberg energy, and stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with to an orbital with . Round your answer to significant digits.
The complete question is attached to this answer
Answer:
2.75 * 10^-5 m
Explanation:
The energy of the absorbed photon = ΔE
ΔE = - Ry (1/n^2 final - 1/n^2initial)
Given that Ry = 2.18 *10^-18 J
nfinal = 9
ninitial =8
ΔE = - 2.18 *10^-18 (1/9^2- 1/8^2)
ΔE = - 2.18 *10^-18 (0.0123 - 0.0156)
ΔE = 7.194 * 10^-21 J
But
ΔE =hc/λ
h = 6.6 *10^-34Js
c= 3 * 10^8 ms-1
λ= the unknown
λ= hc/ΔE
λ= 6.6 *10^-34 * 3 * 10^8/ 7.194 * 10^-21
λ= 2.75 * 10^-5 m
What statement is not true about the field of science
Answer:
where are the statements?
Explanation:
Based on the principle of complementary colors, which colors or wavelengths of light would you expect to be most strongly absorbed by Cu2 ions?
Answer:
Red and Orange
Explanation:
Complementary colors are those colours located across from each other on a color wheel. If we look at the colour wheel attached to this answer, we will see various complementary colours shown.
A good look at the attached colour wheel reveals that blue Cu2+ ions absorbs light around the red and orange portions of the visible spectrum.
0.450 moles of oxygen gas is subjected to a pressure of 3.00 atm and 75 oC.
What is it's volume (in Liters)?
Use this formula PV=nRT
Rearrange formula , question want V ,so
V=nRT/P
given
P= 3.00 atm
n=0.450 moles
R is ideal gas constant = 0.08206 L atm mol-¹K-¹
T in Kelvin so , (75 + 273)= 348 Kelvin (K)
Then insert all this information given with that rearranged formula V=nRT/P
so, V= (0.45)(0.08206)(348) / 3.00 = 4.284 LHow many grams are in 2.3 x 1024 formula units of KNO3?
390 g KNO₃
General Formulas and Concepts:ChemistryAtomic Structure
Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.MathPre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right Explanation:Step 1: Define
2.3 × 10²⁴ formula units KNO₃
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of K - 39.10 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g.mol
Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol
Step 3: Convert
[tex]2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )[/tex] = 386.172 g KNO₃
Step 4: Check
We are given 2 sig figs. Follow sig fig rules and round.
386.172 g KNO₃ ≈ 390 g KNO₃
If a system's internal energy increases by 250 kJ after the addition of375 kJ of energy as heat, what was the value ofthe work in the process?
(A) -625 kJ
(B) -125 kJ
(C) 125 kJ
(D) 625 kJ
Answer:
(B) -125 kJ
Explanation:
Going by the First Law of Thermodynamics it states that"
"A system can do work and increase it's internal energy provided we supply heat."
ΔU= q+w-----------1
where U= the internal heat
q= the quantity of heat added or removed from the system
w= the work done
Given
ΔU= 250kJ
q= 375kJ
from equation 1 make w subject of the formula we have
w= ΔU-q
w= 250-350
w= -125kJ