Abbey and Mia are in the basement playing pool. On Abbey's recent shot, the cue ball was moving east at 91 cm/s when it struck the slower 8-ball moving in the same direction at 18 cm/s. The 8-ball immediately speeds up to 62 cm/s. Determine the post-collision velocity of the cue ball. (Assume all balls have the same mass.)

Answers

Answer 1

Answer:

[tex]47\; {\rm cm\cdot s^{-1}}[/tex] to the east.

Explanation:

When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object will be [tex]p = m\, v[/tex].

Let [tex]m[/tex] denote the mass of one ball.

Before the collision:

Momentum of the cue ball: [tex]p(\text{cue, before}) = m\, v(\text{cue, before})[/tex].Momentum of the numbered ball: [tex]p(\text{number, before}) = m\, v(\text{number, before})[/tex].

Hence, the total momentum before the collision was:

[tex]\begin{aligned} & p(\text{cue, before}) + p(\text{number, before}) \\ &= m\, v(\text{cue, before}) + m\, v(\text{number, before})\end{aligned}[/tex].

Likewise, the total momentum right after the collision would be:

[tex]\begin{aligned} & p(\text{cue, after}) + p(\text{number, after}) \\ &= m\, v(\text{cue,after}) + m\, v(\text{number, after})\end{aligned}[/tex].

Momentum is supposed to be conserved during the collision. In other words, total momentum should be the same immediately before and after the collision. Hence:

[tex]\begin{aligned} & p(\text{cue, before}) + p(\text{number, before}) \\ &= p(\text{cue, after}) + p(\text{number, after})\end{aligned}[/tex].

[tex]\begin{aligned} & m\, v(\text{cue, before}) + m\, v(\text{number, before}) \\ &= m\, v(\text{cue, after}) + m\, v(\text{number, after})\end{aligned}[/tex].

Assume that positive velocities denote motion to the east.

In this question, [tex]v(\text{cue, before})[/tex], [tex]v(\text{number, before})[/tex], and [tex]v(\text{number, after})[/tex] are all given. Rearrange this equation to find [tex]v(\text{cue, after})[/tex]:

[tex]\begin{aligned}& m \, v(\text{cue, after}) \\ &= m\, v(\text{cue, before}) \\ &\quad\quad + m\, v(\text{number, before}) \\ &\quad\quad - m\, v(\text{number, after}) \end{aligned}[/tex].

[tex]\begin{aligned}& v(\text{cue, after}) \\ &= v(\text{cue, before}) \\ &\quad\quad + v(\text{number, before}) \\ &\quad\quad - v(\text{number, after}) \\ &= 91\; {\rm cm \cdot s^{-1}} + 18\; {\rm cm\cdot s^{-1}} - 62\; {\rm cm\cdot s^{-1}} \\ &= 47\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Since the result is greater than zero, the direction of motion of the cue ball after the collision will also be to the east.


Related Questions

a young girl from the kayan people wears a neck ring made of brass. it looks as if there are 21 individual rings but the ring is actually one continuous length of brass fashioned (bent) into a coil. the height of the brass coil is 12 cm and its average circumferences is 40 cm. neck rings are usually only removed to be replaced with a bigger one as the girls grows. however, we can estimate the mass of this neck ring without removing it.

b. the coil has a height of 12 cm and the coil has 21 turns. calculate the radius of the brass in cm.

Answers

The radius of the brass is determined as 0.091 cm.

What is the radius of the brass?

The radius of the brass is calculated by applying the equation for the circumference of a circle.

Mathematically, the equation for the circumference of a circle is given as;

C = 2πr

where;

r is the radius of the circleC is the circumference of the circle

For the given number of turns of the coil and the height of the coil, the radius of the brass is calculated as follows;

( 2πr ) N = h

where;

N is the number of turns of the brass coil = 21 turnsh is the height of the brass coil, = 12 cm

( 2πr ) N = h

( 2πr ) ( 21 ) = 12

42πr = 12

r = 12 / 42π

r = 0.091 cm

Thus, the radius of the brass is a function of height of the brass and the number of turns of the brass.

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A light ray strikes the surface of crown glass (n = 1.520), at a 25° angle with respect to the normal from air(n = 1.000293), and leaves the glass, returning to the air. Determine the angle at which the light refracts when it leaves the glass.

Answers

16.14° is the angle of refraction of the light when it leaves the glass.

What is angle of refraction?

Snell's law states that the angle of refraction, θr, is proportional to the angle of incidence, θi and the ratio of the refractive indices of the two media that comprise the interface. The angle θr=θi and no refraction occur when the mediums have equal refractive indices.

Given that,

The glass has an index of refraction (n₁) = 1.52

Air has an index of refraction (n₂) = 1.000293.

According to Snell's law:

n₂/n₁ = sin θ₁ / sin θ₂

or, 1.000293 / 1.52 = sin θ₁ / sin (25°)

or, 0.6581 = sin θ₁ / 0.42262

or, 0.2781 = sin θ₁

or, θ₁ = sin⁻¹ (0.2781)

or, θ₁ = 16.15°

So, 16.15° is the angle of refraction of the light when it leaves the glass.

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A large truck is ahead of you and is turning right onto a street with two lanes in each direction. The truck:
A. May complete its turn in either of the two lanes.
B. May have to swing wide to complete the right turn.
C. Must stay in the right lane at all times while turning.

Answers

We can see a big truck turning right in front of you onto a roadway with two lanes going in either direction. When turning, the truck must always stay in the right lane.

What's mean by direction?

Direction is characterized as the course that anything follows, the route that must be taken to reach a particular location, the direction in which something is beginning to take shape, or the direction you are facing. When you make a turn instead of left, that is an illustration of direction.

What is compass direction?

Despite taking into account compass error, the direction as shown by the instrument. The true direction referred to an Earthly meridian may vary markedly from the direction represented by a magnetic compass.

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An Atwood’s machine is set up by suspending two blocks connected by a string of negligible mass over a pulley, as shown above. The blocks are initially held at rest and then released. The acceleration of mass M1 is 4.9 m/s2 downward and M1 = 6 kg. Find the mass of M2.

Answers

The mass of M₂ = 12kg.

What is acceleration of mass?

Newton's second law of motion states that an object's acceleration is equal to its mass divided by the net force acting on it, or a = F m. When an object's mass and the net force acting on it are known, this equation for acceleration can be used to determine the object's acceleration.

The formal formulation of Newton's second law is as follows: The acceleration of an object caused by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

F = ma

F = 6×4.9

F = 29.4N.

F = (M₂ - M₁)a

29.4 = (M₂- 6) 4.9

29.4/ 4.9 = M₂- 6

M₂ = 6+6

M₂ = 12kg.

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Peter and Nancy leave their office in Sacramento at the same time. Peter drives north on I-5 at a speed of 72 miles per hour. Nancy drives south on I-5 at a speed of 76 miles per hour. How long will it take them to be 330 miles apart?

Answers

2.2 hours long will it take them to be 330 miles apart.

They are separating at (72+76) = 148 miles per hour relative to each other, so they will take (330miles/148miles per hour)

[tex]330/148=2.2[/tex]

What are the distance problems?

Distance problems are word problems that involve the distance an object will travel at a certain average rate for a given period of time. Things to watch out for: Make sure that you change the units when necessary.

How do you solve distance-time problems?

To work out speed, divide the distance of the journey by the time it took to travel, so speed = distance divided by time. To calculate time, divide the distance by speed. To get the distance, multiply the speed by time. You may see these equations simplified as s=d/t, where s is speed, d is distance, and t is time.

Thus, it takes 2.2 hours for them to be 330 miles apart.

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Figure shows an electric dipole. What are the (a) magnitude-axis) direction (relative to
the positive direction of the x axis) of the dipole’s electric field at point P, located at
distance r >> d?

Answers

At point P, which is situated at a distance of r >> d, the electric field of the dipole has a magnitude-axis direction that is 1 / 4 x qd/r³ in relation to the positive direction of the x axis.

What is electric field?

The physical field that surrounds electrically charged particles and has the power to either attract or repel other charged particles in the vicinity is known as an electric field. Arrows pointing toward or away from charges can be used to depict the vector quantity known as an electric field.

| E net | = 2 E sinθ = 2[1 / 4λεο x q / (d/2)² + 1³] d/2 / √(d/2)² + r ²

            = [1 / 4λεο x qd / [(d/2)² + r²] ³/²

For r >> d [(d/2)² + r²] ³/² ≅ r

So the expression will be reduced to

| E net | = 1 / 4λεο x qd / r³

Thus, at point P, which is situated at a distance of r >> d, the electric field of the dipole has a magnitude-axis direction that is 1 / 4 x qd/r³ in relation to the positive direction of the x axis.

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short-wave (visible and ultraviolet) radiation that reflects off the earth's surface is absorbed by the lower atmosphere and heats it up, a process otherwise known as the greenhouse effect.

Answers

The statement "short-wave (visible and ultraviolet) radiation that reflects off the Earth's surface is absorbed by the lower atmosphere and heats it up, a process otherwise known as the greenhouse effect" is true.

How does the greenhouse effect work?

Solаr energy аbsorbed аt Eаrth’s surfаce is rаdiаted bаck into the аtmosphere аs heаt. Аs the heаt mаkes its wаy through the аtmosphere аnd bаck out to spаce, greenhouse gаses аbsorb much of it. Greenhouse gаses аre more complex thаn other gаs molecules in the аtmosphere, with а structure thаt cаn аbsorb heаt. They rаdiаte the heаt bаck to the Eаrth's surfаce, to аnother greenhouse gаs molecule, or out to spаce.

Eаrth is constаntly bombаrded with enormous аmounts of rаdiаtion, primаrily from the sun. This solаr rаdiаtion strikes the Eаrth's аtmosphere in the form of visible light, plus ultrаviolet (UV), infrаred (IR) аnd other types of rаdiаtion thаt аre invisible to the humаn eye. UV rаdiаtion hаs а shorter wаvelength аnd а higher energy level thаn visible light, while IR rаdiаtion hаs а longer wаvelength аnd а weаker energy level.

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Read the definitions then match it with the correct force.
This image is an example of Newton's ___Law of Motion.

Answers

Here in this scenario, this image is an example of Newton's first Law of Motion.

What is newton's law of motion?

The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following is a paraphrasing of these laws:

Unless a force acts upon a body, it remains at rest or in continual straight-line motion.When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.When two bodies exert force on one another, the direction and amount of the force are opposed.

Isaac Newton first identified the three laws of motion in his 1687 book Philosophies Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).

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A proton (charge 1.602 * 10-19) moves a distance of d
= 0.59 m from point A to point B in a straight line inside a linear accelerator. The electric field of the accelerator is uniform and has a magnitude of 15 MN/C.

What is the electric force on the proton?
F=


What is the work done on the proton?
W=


What is the potential difference between the points A and B?

Vab=

Answers

A proton (charge 1.602 * 10-19) moves a distance of d= 0.59 m from point A to point B in a straight line inside a linear accelerator. The electric field of the accelerator is uniform and has a magnitude of 15 MN/C.

i.) The expression for the force on proton is,

F=qE

(1.6⋅10−19 )(1.5⋅10 7)

=2.4⋅10 −12 N

Thus, the force on the proton is 2.4⋅10 −12 N.

ii) The expression for the work done by the field is,

W=qEd

(1.6⋅10 −19)(1.5⋅10 7 )(0.5)

=1.2⋅10 −12J

iii) The expression for the potential difference is,

U=Ed

=(1.5⋅10 7) (0.5)

=0.75⋅10 7 V

Electric potential of a system of point charges?

A point charge's electric potential is V=kQ/r. Electric field is a vector while electric potential is a scalar.

What is the electric potential at a point distance?

Electric potential at point P, located at a distance of r=R2 from the center, where R is the radius of an evenly charged shell with a density of surface charges.

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Box A of mass m sits on the floor of an elevator with box B of mass 2 m on top of it, as shown the figure above. The elevator is moving upward and slowing down. F_A is the magnitude of the force exerted on box A by box B, F_B is the magnitude of the force exerted on box B by box A, and F_g is the magnitude of the gravitational force exerted on box {B}. Which of the following ranks the forces in order of increasing magnitude?

Answers

Box A of mass m sits on the floor of an elevator with box B of mass 2 m on top of it, in this case option b) would be correct in order of increasing magnitude.

What is magnitude?

Magnitude is a term used in physics to describe an object's maximal size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have just magnitude by definition. Those quantities with both magnitude and direction are considered vector quantities.

There are different ways in which magnitude can be used. Some of them are:

Magnitude of earthquakeMagnitude of charge on an electronMagnitude of forceMagnitude of displacementMagnitude of gravitational force

An earthquake's size is measured in terms of its length, breadth, and width. It is calculated based on the earthquake's actual size. A single magnitude is thought to exist for an earthquake. Due to variables including the type of surface material and distance from the epicentre, the magnitude of the shaking brought on by the earthquake varies depending on where it occurs.

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Given that : A = 4i+6j+12k and B = 3i+12j-7k.
(a) find the magnitude of A and B
(b) find magnitude of A-B
(c) find the sum of A and B
(d)Find the magnitude of A+B

Answers

(a) The magnitude of A is 14  and magnitude of B is 14.2.

(b) The magnitude of A - B is 19.95.

(c) The sum of A and B is 7i + 18j + 5k

(d) The magnitude of A + B is 19.95.

What is the magnitude of A and B?

The magnitude of A and B is calculated as follows;

| A | = √ ( 4² + 6² + 12² )

| A | = 14

| B | = √ ( 3² + 12² + 7² )

| B | = 14.2

The magnitude of A - B is calculated as follows;

A - B = ( 4i + 6j + 12k ) - (3i + 12j - 7k)

A - B = ( i  - 6j + 19 k )

|A-B| = √ (1² + 6² + 19²) = 19.95

The sum of A and B is calculated as follows;

A + B = ( 4i + 6j + 12k ) + (3i + 12j - 7k)

A + B = ( 7i  18j + 5k )

The magnitude of A + B is calculated as follows;

|A+B| = √ (7² + 18² + 5²) = 19.95

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Figure shows an electric dipole. What are the (a) magnitude-axis) direction (relative to
the positive direction of the x axis) of the dipole’s electric field at point P, located at
distance r >> d?

Answers

The magnitude-axis direction relative to the positive direction of the x axis of the dipole’s electric field at point P, located at distance r >> d is 1 / 4λεο x qd/r³.

What is electric field?

Electric field is defined as the physical field that surrounds electrically charged particles and acts as an attractor or repellent on all other charged particles in the field. A vector quantity called an electric field can be represented by arrows pointing in the direction of or away from charges.

| E net | = 2 E sinθ = 2[1 / 4λεο x q / (d/2)² + 1³] d/2 / √(d/2)² + r ²

            = [1 / 4λεο x qd / [(d/2)² + r²] ³/²

For r >> d [(d/2)² + r²] ³/² ≅ r

So the expression will be

| E net | = 1 / 4λεο x qd / r³

Thus, the magnitude-axis direction relative to the positive direction of the x axis of the dipole’s electric field at point P, located at distance r >> d is 1 / 4λεο x qd/r³.

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A cart at the end of a spring undergoes simple harmonic motion of amplitude A = 10 cm and frequency 5.0 Hz. Assume that the cart is at x=−A when t=0.
a) Determine the period of vibration.
b) Write an expression for the cart's position as a function of time.
c) Determine the position of the cart at 0.050 s .
d) Determine the position of the cart at 0.100 s .

Answers

A cart at the end of a spring undergoes simple harmonic motion of amplitude A = 10 cm and frequency 5.0 Hz. Assume that the cart is at x = −A when t = 0.

(a) T = 0.2 sec

(b) x(t) = − (10 cm)cos(10π) s⁻¹ t

(c) x(0.050) = 0

(d) x(0.100) = 10 cm

What is Simple harmonic motion?

Simple harmonic motion is described as the periodic movement of a point down a straight line with an acceleration that is always toward a fixed point on that line and is proportional to that point's distance from the moving point.

Given that,

frequency (f) = 5.0 Hz

Amplitude (A) = 10 cm

(a) As we know,

T = 1/f

or, T = 1/5 Hz

or, T = 0.2 sec

(b) Because the expression for the cart position is at  x= −A when t=0 , this means that the function which describes the position of the cart is a cosine function because, cos(0)=1.

Notice that the form of the equation that describes the position of a vibrating object is as follows :

x(t) = A cos (2Π/T) × t

Substitute for the values of T=0.2s ; A=10 cm and because x = −A when t = 0,then the function will have a negative sign

x(t) = −(10 cm)cos(10π) s⁻¹ t

(c) the position of the cart at 0.050 s:

x(0.050) = −(10 cm)cos(10π) s⁻¹ × (0.050)

x(0.050) = −(10 cm) (cos π/2)

x(0.050) = 0

(d) the position of the cart at 0.100 s:

x(0.100) = −(10 cm)cos(10π) s⁻¹ × (0.100)

x(0.100) = −(10 cm) (cos π)

x(0.100) = 10 cm

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Two boxes with different masses slide down a ramp from the same initial height. Assuming friction is 0, which statement correctly describes the energy of the boxes when they are halfway down the ramp?




Each box has one-half the kinetic energy it had at the top of the ramp.

Both boxes have the same amount of kinetic energy as each other.

Each box has one-half the potential energy it had at the top of the ramp.

Both boxes have the same amount of potential energy as each other.

Answers

Both boxes have the same amount of kinetic energy as each other (option- b) is correct.

How does the mechanical energy in the system change as a result of friction?

If no energy is lost through friction, the system's mechanical energy stays constant. When the speed picks up, the energy would change into kinetic energy. Providing there is no energy loss from friction, the system's mechanical energy increases.

The potential energy of an object falls while its kinetic energy rises. The increase in kinetic energy exactly offsets the decrease in potential energy. The idea of work is another crucial one.

Some kinetic energy is converted into heat energy when friction occurs between two surfaces that are moving over one another.

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A 4.5-kg, three legged stool supports a 65-kg person. If each leg of the stool has a cross-sectional diameter of 2.6 cm and the weight of the person is evenly distributed, determine the pressure exerted on the floor by each leg.

Answers

The pressure exerted on the floor by each leg is 427832.0079 Pa.

F = mg

F = (4.5 + 65) × 9.8

F= 681.1 N

This force is evenly distributed on the three leg

radius, r = d/2

= 2.6 / 2

= 1.3 cm = 0.013 m

Total cross sectional area of the three legs, A = 3×π×[tex]r^{2}[/tex]

A = 3 × 3.14 × [tex]0.013^{2}[/tex]

A = 0.00159 [tex]m^{2}[/tex]

Pressure due to weight,

P = Weight/A

P = 681.1/ 0.00159

P = 427832.0079 Pa

Hence, the pressure exerted on the floor by each leg is 427832.0079 Pa.

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Wax is a nonpolar substance. In which type of substance is it the most soluble?

Answers

Answer: C. A hot non-polar substance

Explanation: I am guessing you have options for this, because I've already had this question at school. So C.

Can you summarize what it takes to make an object change direction ill report if you steal my point and put the wrong answer

Answers

Answer: The only way for the object to change its motion is if an external unbalanced force acts on it.

Explanation:

Newton's First Law of Motion (aka Law of Inertia) states:

An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

Velocity is a VECTOR, so it has both magnitude (size) and direction.  The magnitude of the velocity of an object in motion (its speed) can stay the same, but if it changes direction, its velocity has changed.  The only way for the object to change its direction of motion is if an external unbalanced force acts on it.

relationship between the amplitude, velocity, acceleration and kinetic energy for the simple harmonic oscillator)

Answers

Because the mass is moving at a constant speed, its kinetic energy equals equal to zero. square of a amplitude and therefore is equal to the block's energy.

What is a acceleration explain?

Acceleration is the rate at which an moving object's speed and direction change over time. Travel on a circle increases irrespective of whether the speed stays the same since its orientation is always changing.

What are the 3 types of acceleration?

The three main types of accelerated motions are regular acceleration, non-uniform acceleration, or average acceleration. The motion in which an item moves inside a straight line while increasing in velocity at regular intervals is referred to as uniform acceleration.

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You measure the mass of your rubber band airplane and find that it is 15 grams (0.015 kg). You also measure the acceleration of the airplane with a motion detector and find that the airplane initially accelerates upward at a rate of 2 m/s 2. Calculate the net force on the airplane and the upward force from the lift.

Answers

F=ma

Mass= 0.015 kg
Acceleration= 2 m/s^2

So force is equal to 0.015 * 2 = 0.03 N.

For many years Colonel John P. Stapp, USAF, held the world's land speed record. On March 19.1954, he rode a rocket-propelled sled that moved down a track at a speed of 632 mi/h . He and the sled were safely brought to rest in 1.40 s (Fig. P2.31). Determine (a) the negative acceleration he experienced and (b) the distance he traveled during this negative acceleration.

Answers

The negative acceleration and distance is 451.42m/s² and 175.55m.

When an object experiences negative acceleration, its velocity changes in a negative direction, which can indicate that it is moving either slower or faster.

As a vector quantity that denotes both magnitude and direction, the term "acceleration" is used in physics to describe a change in an object's velocity.

Positive velocity, which is also a vector, makes something move more slowly than something experiencing negative acceleration. An object that has both negative acceleration and velocity, however, is actually moving faster.

a]. Negative Acceleration = dv/dt

 a=632/1.40=451.42m/s²

b]. distance= speed x time

d=632x 5/18=175.55m

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A cube with edge length L = 0.29 m and density ρc = 0.89×103 kg/m3 floats in equilibrium in a liquid of density ρl = 1.5×103 kg/m3, with the top of the cube a distance d above the liquid’s surface
A; Write an expression to find d using the image

Answers

It is given that,

Cube Length (L) = 0.29m

Density of Cube (Pc) = 0.89 *103 Kg/m3

Density of Liquid (P1) = 1.5 *103 Kg/m3

Distance (d) =?

We know that,

d = {(P1 - Pc)/P1}*L

d = {(1.5*103–0.89*103)/1.5*103}* 0.29

d = {(1.5 – 0.89)/1.5} * 0.29

d = 0.118m

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The expression to find distance using the given quantities is:

d = ( ρl - ρc ) L / ρl  

How to apply this expression to find distance?

In this question, it is given that a cube with length L= 0.29 meter and the density of cube ρc = 0.89×103 kg/m3 and it floats in equilibrium in liquid of density  ρl = 1.5×103 kg/m3 with the top of the cube a distance d above the liquid surface. So here is the liquid, and the cube will float on the liquid at a distance d. Thus, the expression in terms of the given quantities to find distance d can be written as-

d = ( ρl - ρc ) L/ρl  

We are given that,

Density of cube, ρc = 0.89×103 kg/[tex]m^{3}[/tex]

Density of liquid, ρl = 1.5×103 kg/[tex]m^{3}[/tex]

Edge length of cube, L = 0.29 m

So, on substituting the given values in above expression, we get:

d = [(1.5×103 – 0.89×103) / 1.5×103] × 0.29

d = [(1.5 – 0.89) / 1.5] × 0.29

d = 0.118 m

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a 300 g mass hangs vertically from a spring. a spring elongation of 11 cm is recorded. calculate the spring constant k in newtons per meter (n/m). (make sure to use the right si units for the mass and elongation)

Answers

The spring constant (K) is 2.67n/m when 300 g mass hangs vertically from a spring.

What is Spring?

A spring is a material that may be bent by an external force before resuming its original shape.

What is the Spring constant?

Now, the force required for every unit of spring extension is known as the "Spring constant." Knowing the spring constant makes it simple to calculate the amount of force needed to bend the spring.

Hooke's law states that F = -KX.

Calculations:

Given,

Mass = 300g = 0.3kg

Spring elongation = x = 11cm = 1.1m

Spring constant = k =?

Kx= mg

K = mg/x

K = (0.3 * 9.81) / 1.1m

K = 2.67n/m.

Hence, the spring constant (K) is 2.67n/m when 300 g mass hangs vertically from a spring.

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There are three general types of spectra: continuous, emission, and absorption. Each is characterized by a different distribution of the wavelengths (i.e., colors) of radiation. Sort the images of the three types of spectra into the appropriate bins.
Each type of spectrum is unique in the way the wavelengths (colors) of light are distributed. The continuous spectrum shows a continuum of all the colors, whereas the emission spectra show only specific lines of emitted color. The absorption spectra show only small black ranges where specific colors have been absorbed away.

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There are three general types of spectra: continuous, emission, and absorption. The image drag are:

Continuous

Image 1 (full spectrum)

Emission

Image  2 (mostly dark)

Image 5 (mostly dark)

Absorption

Image 3 (full with lines)

Image 4 (full with lines)

What is the spectrum above about?

The distribution of light's wavelengths (or colors) differs for each type of spectrum. While the emission spectra only display individual lines of emitted color, the continuous spectrum displays a continuum of all hues. Only tiny black ranges where particular colors have been taken away are seen in the absorption spectrum.

From the image attached:

A hot, high-density light source generates a continuous spectrum.A hot, low-density light source generates an emission spectrum.A hot, high-density light source passing through a cold, low-density medium results in an absorption spectrum.

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Physics question, vectors

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The typical canoeist can paddle at about 2.6 knots, or 3 mph (ca. 5 km/h), when paddling without stopping and in calm, quiet water. Obviously, the length of time depends on the weather, the person's health, and the speed of the canoe.

What speed of canoe with respect to water and shore?

The typical canoeist can paddle at about 2.6 knots, or 3 mph (ca. 5 km/h), when paddling without stopping and in calm, quiet water. Obviously, the length of time depends on the weather, the person's health, and the speed of the canoe.

Therefore, When the medium is deepest, water waves propagate more quickly. Water waves will therefore slow down as they go from deep to shallow water.

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A disk between vertebrae in the spine is subjected to a shearing force of 530 N. Find its shear deformation in meters, taking it to have the shear modulus of 1 109 N/m2. The disk is equivalent to a solid cylinder 0.700 cm high and 3.80 cm in diameter.

Answers

The disk is equivalent to a solid cylinder 0.700 cm high and 3.80 cm in diameter. The shear deformation is .∆x=3.34×10⁻⁶ m.

What is deformation?

Deformation refers to the change in size or shape of and object whereas displacements are the absolute change in to the  position of a point on the  the object. Deflections is the relative changes in external displacements in an object.

The shear deformation is .

Given that,

Shearing force F = 600 nm

Shear modulus S=1×10⁹ n/m²

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

S=Flo/A ∆x

∆x=Flo/(rd²/4)S

∆x=4Flo/(rd²/)S

Put the value into the formula

∆x=4×600×0.700×10²/3.14×1×10⁹×(4.00×10²)

∆x=3.34×10⁻⁶ m

Hence, The shear deformation is .∆x=3.34×10⁻⁶m

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Two springs are attached side by side to a box of mass that is resting on a frictionless horizontal surface as shown in the figure. The springs have force constants of 1 and 2. Determine an expression that describes the period of the motion of the box attached to this combination of springs. Assume that the box does not rotate, so the amount of stretch or compression for each spring is the same.

Answers

Answer: 4+5z (x) + 9

Explanation:

So I got this by... I don't really know, but this might be the right answer..

In what direction and at what point does the buoyant force on a body due to liquid act?

Answers

At the center of buoyancy, the buoyant force operates in an upward, vertical direction.

What kind of force is buoyant, for instance?

Here are a few real-world instances of the buoyant force. Iceberg drifting on the sea, a boat traveling down a river An individual wearing a life jacket floating in the water, a ship sailing the seas, a helium balloon soaring into the sky, etc. The density has a direct relationship with the buoyant force.

What generates the force of buoyancy?

The fluid's pressure on the object is what creates the buoyant force. The net upward force results from the fact that the pressure on the bottom of an item is always greater than the force on the top since pressure rises as depth increases. Whether an object sinks or floats, the buoyant force always exists.

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Eli wanders around the park. First he walks north 4 meters to the swings. Then he walks south
2.5 meters to the bench to take a break. If he spends 600 seconds doing these things...
What is the distance traveled?

Answers

Answer: total distance traveled = 6.5 m

Explanation:

Important to note the difference between displacement and distance.  Distance is the total length of the path taken:  4 + 2.5 = 6.5 m

Displacement is the distance from the point of origin to the ending point:

4 - 2.5 = 1.5 m

The question asked for the DISTANCE, so the answer is 6.5 m

The road runner was being chased and outsmart the coyote. He ran past the road runner an fell straight down off a cliff. He fell with the same acceleration as gravity (9.8). Calculate his displacement if he fell for 4 seconds

Answers

The displacement of the runner after four seconds is 78.4 m.

What is the displacement after 4 seconds?

We know that in this case, we are dealing with a case of an object that has a motion under gravity. We are told that the road runner an fell straight down off a cliff. The fact that we have been told that the runner just fell down the cliff means that the initial velocity of the runner would have to be taken in this context as zero since the runner was dropped from a height as shown.

Acceleration of the runner (g) = 9.8 m/s^2

Initial velocity of the runner (u) = 0 m/s

Time take (t) = 4 seconds

We then have;

h = ut + 1/2gt^2

If we then know that the initial velocity of the person is zero, then we have;

h = 1/2gt^2

h = 0.5 * 9.8 * (4)^2

h = 78.4 m

The height is 78.4 m.

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The position , in meters, of an object moving along the -axis is given as a function of time , in seconds, as ()=0.09814−0.1953+0.8552+3.15−7.49 Find the object's acceleration at time =3.41 s.

Answers

With the knowledge of differential calculus, the magnitude of the object's acceleration is 11.4 m/s²

What is Position ?

Position is any point of coordinate in space or any region in which an object can be located.

Given that the position , in meters, of an object moving along the x-axis is given as a function of time t, in seconds, as

x(t) = 0.09814[tex]t^{4}[/tex] − 0.1953t³ + 0.8552t² + 3.15t − 7.49

The object's acceleration at time =3.41 s can be found with the knowledge of differential calculus.

The derivative of position = velocity

The derivative of velocity = acceleration

That is,

If x(t) = 0.09814[tex]t^{4}[/tex] − 0.1953t³ + 0.8552t² + 3.15t − 7.49

dx/dt = 0.39256t³ - 0.5859t² + 1.7104t + 3.15 = v

dv/dt = 1.17768t² - 1.1718t + 1.7104

when time t = 3.41 s

Substitute for t

dv/dt = a = 1.17768(3.41)² - 1.1718(3.41) + 1.7104

a = 13.69 - 4.00 + 1.7104

a = 11.4 m/s²

Therefore, the object's acceleration at time = 3.41 s, is 11.4 m/s² approximately.

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