a van of mass 2000 kg is travelling at 10 m/s calculate its kinetic energy. If its speed increases to 20m/s by how much does its kinetic energy increases

With the use of echo formula, the length of the barn is 24.75 m

An echo is a sound heard after the reflection of sound waves from a plane surface. It is simply the reflection of sound waves.

Suppose you hear an echo 0.15 seconds after banging.

Then,

V = 2L/T

330 = 2L/0.15

2L = 330 × 0.15

2L = 49.5

L = 49.5/2

L = 24.75 m

Therefore, the barn is 24.75 m long.

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The coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

The amount of volume that a substance expands by per unit of its original volume for each degree that its temperature rises is known as the coefficient of volume expansion.

As we know, The coefficient of volume expansion of the liquid

= change in volume/(original volume × temperature difference)

= (V₂ - V₁)/[V₁ × (T₂ - T₁)]

Change in volume = (V₂ - V₁)

Here, V₂ ( final volume) = 1.31 L

V₁  (initial volume)= 1.55 L

T₂ (final temperature) = 14.7 degrees

T₁ (initial temperature) = 96 degrees

The coefficient of volume expansion of the liquid

= (1.31 - 1.55) / [1.5 × (14.7- 96)]

= 1.97 × 10⁻³ /⁰C

Thus, the coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

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Value of M (mass of other block) in the mention pulley system is 3.68 kg.

Tension is the contact force transmitted when the force on both ends pulls on a rope, cord, wire, etc.

For example, a tire swing hanging from a tree creates tension in the rope that holds the swing to the branch. Pulling at the bottom of the rope is due to gravity, while pulling up is due to the branches resisting rope pull. The pulling force acts along the length of the rope and acts evenly on the objects (tires and branches) at both ends. At the hoop, the pull is upward (because the tension in the rope holds the hoop up), but at the branch the pull is downward (a taut rope pulls the branch down).

Let's calculate acceleration:

S = ut + ¹/₂ at²

Where, s = 50 cm or 0.5 m

u = 0 m/s

t = 1.0 second

Now, substitute the values:

0.5 = 0 × 1 + ¹/₂ a × 1²

0.5 = ¹/₂ a

a = 1 m/s²

Now for tension force following are the equations:

T = ma + mg

T = Mg - Ma

ma + mg = Mg - Ma

Where, T = Tension force

m = 3 kg

a = 1 m/s²

g = 9.8 m/s²

M = To be calculated

a = (Mg - mg)/(M + m)

1 = (M × 9.8 - 3 × 9.8)/(M + 3)

1(M + 3) = 9.8 M - 29.4

M + 3 = 9.8 M - 29.4

29.4 + 3 = 9.8 M - M

32.4 = 8.8 M

M = 32.4/8.8

M = 3.68 kg

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The complete question is as follows:

The system shown below is released from rest and moves 50 cm in 1.0 second. What is the value of M? All surfaces are frictionless.

The graph shows that there was more variation in 2010.

A graph can be described as a pictorial representation or a diagram that represents data or values in an organized manner. The points on the graph often represent the relationship between two or more things.

A graph is a common data structure that consists of a finite set of nodes (or vertices) and a set of edges connecting them.

From the graph show, scientists measured the beak length of a population of birds in a lake in 1960. they measured the beak length of the bird population again in 2010. The graph shows that there was more variation in 2010.

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The pressure in the upper portion of the pipe is calculated by applying Bernoulli's equation,

P₁ + ¹/₂ρv₁² + ρgh₁ = P₂ + ¹/₂ρv₂² + ρgh₂

given is

p1 =247kPa

v1=2.09 m/s

h1= 0

v2 =3.41 m/s

h2 = 10.68 m

p=817 [tex]m^{3[/tex]

p2 = ?

Solving for this we can get the required value.

Bernoulli's equation formula shows the relation between pressure, kinetic energy, and gravitational potential energy of a fluid in a container. We have the formula for Bernoulli's principle as follows: p + 1 2 ρ v 2 + ρ g h = A constant.

Bernoulli's principle is based on the principle of conservation of energy. According to it, "in a steady flow, the sum of all forms of energy in a fluid is the same at all points that are free of viscous forces". This required the sum of kinetic energy, potential energy and internal energy to be constant.

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TLC is a frequently used technique in organic chemistry labs because it can provide immediate and important information about the purity of a sample and whether or not a reaction is taking place. Using low polarity solvents, a TLC plate can be finished in less than five minutes.

Problems with the separation can result from a location that is overly large or dense. 6. If you are using multiple samples on the same plate, be sure their spots do not overlap. In order to avoid colliding during the separation, adjacent dots must be spaced by at least 0.5 cm.

Since the ratio between the distances stays constant, the Rf value won't change if the solvent is only permitted to move halfway up the plate. After marking the front line of the solvent on the TLC plate and removing it from the developing chamber, let the plate air dry. When a substance is placed to a TLC plate in excess, the dot may streak over the plate or touch nearby samples that are being evaluated.

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Lateral rotation is an anatomical term of motion used to describe rotation along the long axis of a joint. In lateral rotation, this movement is away from the midline of the body and occurs in the transverse plane.

On the other hand, medial rotation is a rotational movement towards the midline. It is sometimes referred to as internal rotation.

According to this question, twisting one's lower limb at the hip while standing, so that the toes point off to the side is an example of lateral rotation while doing the above but in such a way that it points towards the other foot is an example of medial rotation.

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(a). The chair's dynamic friction factor with the floor is = 0.602.

(b). The chair's as well as the floor's kinetic friction factor is = 0.475.

The metre per second (m/s) is the accepted unit of velocity magnitude (also known as speed).

a)Let's practice using Newton's second law. In the reference system, the x axis is perpendicular to the axis and parallel to the floor.

Y Axis

        N-W = 0

        N = W

X axis

         F-fr = ma

The formula for the friction force is

  fr = μN

The acceleration is zero where the movement starts.

Let's replace

F = μ (mg) = 0

F = μ mg

μ = F / mg

μ = 160/30 9.81

μ = 0.602

b) The formula is the same in this instance, but the friction is kinetic.

    μ = F2 / mg

    μ = 125/30 9.81

    μ = 0.475

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By the time Ernie gets to Burt, the log has drifted 0.29 metres away from the coast.

Centre of mass definition ?

The location where the centre of the distribution of mass in space is located is the centre of mass for a given item or system of objects. For bodies to continue to be at rest, the centre of mass must equal zero.

It may be expressed as,

∑miΔxi=0

m=mass

x=distance

The 3.2m-long log weighs 290kg and is 3.2m long. Ernie weighs 32 kg, whereas Burt weighs 33 kg.

Ernie accepts Burt's offer of a cookie and moves to his side of the log to take it.

By the time Ernie gets to Burt, the log should have travelled x metres. Consequently, using the formula above,

33(x)+290(x)+32(x-32)=0

x=0.29m

As a result, the log has travelled 0.29 metres by the time Ernie gets to Burt.

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Passing a current through a wire create a magnet because the electrons create a magnetic field.

Is it possible for a wire's current to generate a magnetic field?

Flemming's Right Hand Rule states that while a current flows, it generates a magnetic field all around it. The magnetic field produced by the wire's electric current will repel both poles of the magnet by bending away from the wire since it is changing directions around the wire. Magnetic fields are produced when moving electric charges (electrons in a circuit) move, and vice versa (electricity).

A wire heats up when a current flows through it because some of the electrical energy is transformed into heat energy due to resistance the wire encounters. This is referred to as the electric current's heating impact.

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Answer:

potential

Explanation:

Answer:

Gravitational potential energy

Explanation:

GPE = MGH

M - MASS

G - GRAVITATIONAL

H - HEIGHT

The pressure difference in the 6 cm supply line is 2.31 * 10⁴Pa, and the rate at which water exits the valve is 2.65 m/s.

The ability of an object to move quickly or slowly is a very fundamental idea in motion. Distance is exactly proportional to velocity if time is constant, hence speed is merely distance divided by time. You will be asked to perform calculations for one of three supplied variables in incidents affecting speed, distance, and time.

The primary pipe's R1 radius is 3.0 cm.

The faucet's radius is R2 = 1.0 cm.

The faucet's height is h = 2.0 cm.

(a) The flow rate

[tex]$$\mathrm{R}=\mathrm{Av}=\frac{25 \mathrm{~L}}{30}=0.833 \mathrm{~L} / \mathrm{s}=833 \mathrm{~cm}^3 / \mathrm{s}$$[/tex]

The area of faucet [tex]$\mathrm{A}_2=\pi r_2{ }^2$[/tex]

[tex]$$=\pi(1 \mathrm{~cm})^2=\pi \mathrm{cm}^2$$[/tex]

then the speed

[tex]$$\begin{aligned}\mathrm{v}=\frac{\mathrm{R}}{\mathrm{A}} & =\frac{833 \mathrm{~cm}^2 / \mathrm{s}}{\pi \mathrm{cm}^2}=265 \mathrm{~cm} / \mathrm{s} \\& =2.65 \mathrm{~m} / \mathrm{s}\end{aligned}$$[/tex]

b) from continuity equation

[tex]$$\begin{aligned}A_1 v_1 & =A_2 v_2 \\\text { then } \mathrm{v}_1=\frac{A_2 v_2}{A_1} & =\frac{(\pi)}{\pi(3 \mathrm{~cm})^2}(265) \\& =0.295 \mathrm{~m} / \mathrm{s}\end{aligned}$$[/tex]

From Bernoulli's theorem

[tex]$$\begin{aligned}\mathrm{P}_1 & +\frac{1}{2} \rho v_1^2+\rho g y_1=\mathrm{P}_2+\frac{1}{2} \rho v_2^2+\rho g y_2 \\P_1-P_2 & =\frac{1}{2} \rho\left(v_2^2-v_1^2\right)+\rho g\left(y_2-y_1\right) \\& =\frac{1}{2}\left(10^3\right)\left[(2.65)^2-(0.295)^2\right]+\left(10^3\right)(9.8)(2) \\& =2.31 \times 10^4 \mathrm{~Pa}\end{aligned}$$[/tex]

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The mechanical energy of the swing is the sum of the potential energy and the kinetic energy which is equal to 225 Joules.

Mechanical energy is the energy which is present either in an object which is in motion or the energy which is stored in objects by their position. Mechanical energy is the main driver of renewable energy. Many different forms of renewable energy rely directly on the mechanical energy to adequately produce enough amount of power or convert energy.

The mechanical energy of the object is the sum total of individual energies which are present in the object. The mechanical energy of an object can be represented as:

M.E. = P.E. + K.E.

M.E. = Mechanical energy,

P.E. = Potential energy,

K.E. = Kinetic energy

Therefore, the mechanical energy of the swing will be:

M.E. = 150J + 75J

M.E. = 225 Joules

Therefore, the mechanical energy of the swing is equal to 225 Joules.

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One of the things that are NOT a typical consequence that is associated with open pit mines is the release of high concentrations of ozone into the local environment, causing long-term respiratory harm to individuals and the environment.

The open-pit mine is a surface mining technique used to extract rocks or minerals from the earth using an open-air pit. This technique is used when ore or rock deposits are found near the surface, which makes digging a tunnel unnecessary.

The main consequence of open-pit mine that concerns most people is that it generates a large amount of dust that contains heavy metals to the environment, as well as creating deposits of toxic waste ponds. Ozone is not considered a heavy metal.

Attached below is an image of the Sunrise Dam Gold Mine open pit mine in Australia.

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True , The magnetizing inductance and this inductance are parallel. Each coil in a transformer has the same voltages each turn.

Power transformers, distribution transformers, and isolation transformers, in that order. We have Twin Winding Generators and Autotransformers based on windings. We include Core Type Transformers, Shell Type Transformers, and Berry Type Transformers based on core designs.

Electric circuits employ transformers to modify the voltage of the electricity flowing through the circuit. In AC circuits, it is utilized to step up or step down the voltage (thus, "stepping up" or "stepping down").

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Answer:

[tex]47\; {\rm cm\cdot s^{-1}}[/tex] to the east.

Explanation:

When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object will be [tex]p = m\, v[/tex].

Let [tex]m[/tex] denote the mass of one ball.

Before the collision:

Hence, the total momentum before the collision was:

[tex]\begin{aligned} & p(\text{cue, before}) + p(\text{number, before}) \\ &= m\, v(\text{cue, before}) + m\, v(\text{number, before})\end{aligned}[/tex].

Likewise, the total momentum right after the collision would be:

[tex]\begin{aligned} & p(\text{cue, after}) + p(\text{number, after}) \\ &= m\, v(\text{cue,after}) + m\, v(\text{number, after})\end{aligned}[/tex].

Momentum is supposed to be conserved during the collision. In other words, total momentum should be the same immediately before and after the collision. Hence:

[tex]\begin{aligned} & p(\text{cue, before}) + p(\text{number, before}) \\ &= p(\text{cue, after}) + p(\text{number, after})\end{aligned}[/tex].

[tex]\begin{aligned} & m\, v(\text{cue, before}) + m\, v(\text{number, before}) \\ &= m\, v(\text{cue, after}) + m\, v(\text{number, after})\end{aligned}[/tex].

Assume that positive velocities denote motion to the east.

In this question, [tex]v(\text{cue, before})[/tex], [tex]v(\text{number, before})[/tex], and [tex]v(\text{number, after})[/tex] are all given. Rearrange this equation to find [tex]v(\text{cue, after})[/tex]:

[tex]\begin{aligned}& m \, v(\text{cue, after}) \\ &= m\, v(\text{cue, before}) \\ &\quad\quad + m\, v(\text{number, before}) \\ &\quad\quad - m\, v(\text{number, after}) \end{aligned}[/tex].

[tex]\begin{aligned}& v(\text{cue, after}) \\ &= v(\text{cue, before}) \\ &\quad\quad + v(\text{number, before}) \\ &\quad\quad - v(\text{number, after}) \\ &= 91\; {\rm cm \cdot s^{-1}} + 18\; {\rm cm\cdot s^{-1}} - 62\; {\rm cm\cdot s^{-1}} \\ &= 47\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Since the result is greater than zero, the direction of motion of the cue ball after the collision will also be to the east.

Answer:

24km/h

Explanation:

V = D/T

   = 60/2.5

   = 24

The current, i, in the circuit by using ohm's law (generalized for alternating currents), v is  [tex]\begin{aligned}& I= \\& \quad 0.4000+0.8000 i\end{aligned}[/tex]

What is circuit?

An electronic circuit is composed of individual electronic components, such as resistors, transistors, capacitors, inductors and diodes, connected by conductive wires or traces through which electric current can flow.

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Answer: 60 joules

Explanation:

The amount of work done in pulling back the string of a bow

= FORCE * DISPLACEMENT

W = 100 * 0.60 = 60 J

The change in kinetic energy is the net work done.

Therefore,  

W = k1 - k2 = k1  

This implies that the work done is equal to the kinetic energy.

Because Newton as Pressure = Thrust/Area, the answer will be 7.5.

The rotating equivalent of Newton's first law is this. When each child's weight exerts an equal amount of torque about the pivot in opposing directions, two kids can balance on a seesaw (clockwise and counter clockwise).

The idea of the seesaw You are probably aware that any two people, regardless of their weights, can balance each other while seated on opposite sides of a seesaw. All that is required is for each individual to contribute an equal moment, which is determined by multiplying the person's weight by the distance from the fulcrum.

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The rotational kinetic energy (in J) of Jupiter in its orbit around the Sun is 1.613 × 10³⁵ J

Rotational kinetic energy is kinetic energy due to rotation about an axis.

The rotational kinetic energy is given by K = 1/2Iω² where

So, We have that the rotational kinetic energy of Jupiter is

K = 1/2Iω²

K = 1/2(MR²)(2π/T)²

K = 1/2(MR²)(4π²/T²)

K = 2π²MR²/T²

Substituting the values of the variables into the equation, we have that

K = 2π²MR²/T²

K = 2π² × 1.898 × 10²⁷ kg × (7.78 × 10¹¹ m)²/(3.74976 × 10⁸ s)²

K = 2π² × 1.898 × 10²⁷ kg × 60.5284 × 10²² m²/14.0607 × 10¹⁶ s²

K = 2π² × 114.8829 × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²

K = 229.7658π² × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²

K = 16.3410π² × 10³³ kgm²/s²

K = 161.2791 × 10³³ kgm²/s²

K = 1.612791 × 10³⁵ kgm²/s²

K ≅ 1.613 × 10³⁵ J

So, the  rotational kinetic energy is 1.613 × 10³⁵ J

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Having said that,

Gravitational Constant: g=GMR2

G=6.621011Nm2kg2 R=Radius Earth's M stands for Earth's mass.

The spacecraft is currently far away. R′=2R

As a result, g will be as follows: g′=GMR′2 R′=2R g′=GM4R2 g′=g4 g′=9.84 g′=2.45ms2

At any point on its surface, a non-rotating perfect sphere with equal mass density or one whose density varies exclusively with distance from the centre (spherical symmetry) will produce a constant gravitational field. The Earth is an oblate spheroid because it rotates and is not spherically symmetric; rather, it is slightly flatter towards the poles and bulges at the Equator. As a result, the magnitude of gravity varies slightly throughout the surface.

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If you wanted to see stars hidden behind a molecular cloud, you would probably look at light with an infrared wavelength.

The duration, which will also apply to troughs, seems to be the distance between the two wave crests. The unit of frequency by cycles per second (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz).

The connection between wavelength and frequency is inversely proportional. The wavelength of a wave with highest frequency is the shortest. Double the wavelength corresponds to twice the frequency. The wavelengths ratio is therefore the inverse of an applied frequency.

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The complete question is-

If you wanted to observe stars behind a molecular cloud, in what wavelength of light would you most likely observe?

A. visible

B. gamma-ray

C. X-ray

D. infrared

E. ultraviolet

Natural gas, hydrogen, electricity, hybrid vehicles, biofuels, five major alternative energy sources in transportation. Producing energy from fossil fuels no releases of greenhouse gases, lowering forms of pollution.

The relative ease with which petroleum-derived fuels may be stored and utilized in internal-combustion engines accounts for their supremacy. However, they need a more intricate storage system than other fossil fuels, such as natural gas, gas, and methanol, which can also be utilized as transportation fuels.

Use your personal automobiles sparingly. When possible, strive to use public transportation. Reduce the car's additional BOOT weight. Unnecessary objects like a flat tire and unwanted luggage—especially hefty ones—in the car might lower its mileage.

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Answer:he would most likely hit an element with which of the following characteristics: W) a naturally radioactive element X) a solid at room temperature Y) a gas at room temperature Z) a liquid at room temperature ANSWER: X) A SOLID AT ROOM TEMPERATURE

Explanation:

The center of gravity (CG) location is the average location of all the weight of an object.

The center of gravity is the balance point of an object, also expressed as the point where all the mass appears to be located.

The Center of gravity can be defined as the weighted average of all point masses in an object, which satisfies the following:

CG = sum(mi * r i)/sum(mi)

Where r i is the position of each point mass.

mi is the mass of each point mass.

The center of gravity location has several unique properties:

A different concept is used where high accuracy is required. The object is placed on top of a table that is pivoted about a defined axis. The moment due to the center of gravity offset of the object from the center axis is measured using a force transducer.

The location of the center of gravity is derived from the moment measurement by applying the following formula:

M = W x d

Where M is the moment applied.

W is the weight of the object.

d is the distance from the pivot point to the center of gravity of the object

Below is a list of examples with typical accuracy requirements:

Human: 2 inches (5 cm)

Golf ball: 0.05 inch (1.25 mm)

Rocket: 0.01 inch (0.25 mm)

Spacecraft: 0.04 inch (1 mm)

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In physics, the centre of gravity is a hypothetical location within a solid where, for the sake of convenience in some computations, the body's whole weight may be assumed to be concentrated.

The idea might be helpful when planning static structures (like buildings and bridges) or when forecasting how a moving body will behave when subjected to gravity.

The geometric centre of a body may also be where the body's centre of gravity is located, especially in symmetrically structured objects made of homogeneous material.

However, it is likely that the centre of gravity of an asymmetrical item made of various materials with different masses will be situated some distance from the object's geometric centre.

In certain circumstances, such as hollow bodies or things with irregular shapes, the centre of gravity (or centre of mass) may exist in space at a location independent of the physical substance.

Hence, the centre of gravity is a theoretical point within a solid where, for the simplicity of some calculations, the entire weight of the body may be believed to be concentrated.

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Electronic transitions that end up in the state with quantum number n = 2 are what the Balmer series for the hydrogen atom refers to. The longest wavelength is 656.3x10-9 m, and the energy is  3.03X10^33J

Given quantum number (n) = 2

This will be transition 3-2 photon energy (E)= hc/λ since we must take into account the photon with the longest wavelength that completes the electron transition in the state with the quantum number n=2

photon energy (E)= hc/λ

(a) Then the energy (El) of longest wavelength= 6.63×10 −34 x 3x10^8/656.3x10-9

E = 3.03x10^33J = 1.89eV

(b) We know that 1/λl = R(1/n1^2 - 1/n2^2) where R =  Rydberg constant

1/λl = 1.097×107m−1× (1/2^2 - 1/3^2)= 656.3x10-9m

(c) From given diagram we say thee shortest transition is from level 6 to level 2

n1 = 2 and n2 = 6

Its photon energy (Es) =  6.63×10 −34 x 3x10^8/411x10-9 = 3.023eV

(d) Wavelength of shortest transition series 1/λ = 1.097×107x(1/2^2 -1/6^2) =  411nm

(e)Shortest wavelength is emitted in Balmer series if the transition of electron takes place from n2​=∞ to n1​=2.

Shortest wavelength in Balmer series 1/λ = R(1/2^2 -1/∞)=364.6nm

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