a tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. The whole arrangement is in the Earth's atmosphere. The density of mercury is 1.36*10^4, more details provided in the images.

A Tube Of Constant Circular Cross-section, Sealed At On End, Contains An Ideal Gas Trapped By A Cylinder
A Tube Of Constant Circular Cross-section, Sealed At On End, Contains An Ideal Gas Trapped By A Cylinder

Answers

Answer 1

Answer:

P V = N R T      ideal gas equation

V = .19 * A      volume of enclosed gas

.19 P = N R T / A      using volume of enclosed gas

P = Po + Phg       pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury

.19 (Po + Phg) = N R T / A which is what was asked

Note Phg = density of Hg * height of Hg * acceleration due to gravity

Answer 2

A tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. There will atmospheric pressure and pressure due to mercury column on trapped gas column  having length 0.19m which is given by,

(p₀+pm)×0.190 = nRT÷A.

What is Pressure?

Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area.  its SI unit is Pascal (Pa) which is equal to N/m².  is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].

Looking at the figure from top to bottom, we can see the top end of the tube is opened. There is 0.035m of mercury column below which we have a air 0.190m of gas column.

We can feel the physics behind this figure what is happening here, top of the tube is open so there is atmospheric pressure acting on the mercury column and mercury column is above the gas column, it means that both atmospheric pressure and mercury pressure will act on gas column.

i.e.  (p₀+pm) = pressure on the air column

this (p₀+pm) is downward pressures, hence gas inside the tube gets compressed due to this pressure because bottom end is closed. it means that back pressure will be created inside the gas in upward direction and both pressures becomes equal at equilibrium.

i.e. (p₀+pm) = back pressure inside the gas column......1)

according to ideal gas equation, PV=nRT

pressure inside the air column is P = nRT÷V

where V is volume of gas that is A×0.190.

P = nRT÷(A×0.190).....( back pressure inside the gas column).

equation 1 becomes

(p₀+pm) = nRT÷(A×0.190).

Hence we get

(p₀+pm) ×0.190= nRT÷(A).

Hence proved.

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Related Questions

A 68 g plastic ball is moving to the left at 17 m/s . How much work must be done on the ball to cause it to move to the right at 17 m/s ?

Answers

Answer:

KE = 19.652 J to the right

Explanation:

KE = J or N*m

KE = (1/2)m*v²

KE = kinetic energy

m = mass(kg)

v = velocity (m/s)

KE = .5*0.068kg*(17m/s)²

KE = 9.826 J to the left

So double it to the right to get 17m/s.

KE = 19.652 J to the right

J = Joules or can be expressed as N*m which is Newton-meters.

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Answers

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Answer:

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Answers

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The greenhouse effect is a phenomenon in which heat from a planet's host star passes through its atmosphere and warms the surface of the planet, but greenhouse gases in the atmosphere prevent part of the heat from going directly to space, making the world warmer.

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Chlorofluorocarbons​ is eliminated, would completely prevent the greenhouse effect from occurring on earth.

To learn more about greenhouse effect refer to the link:

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Answers

Answer:

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Explanation:

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Theta = 26.93°

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R = 0.38m

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Answers

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Answers

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Answers

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Answers

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ASAP
A train is travelling at 100 m/s when it receives an alert: “Brake! 600 meters ahead, the rails are broken”. The highest acceleration that the train can produce is 10 m/s^2. If the train slows down with a constant acceleration of 10 m/s^2
How long will it take for the train to stop?
How many meters will it travel before it stops?
Botcookiemaster please don't use a file just give me the answer

Answers

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Let's consider the given terms ~

Initial velocity (u) = 100 m/s

Acceleration (a) = - 10 m/s²

(Acceleration is negative bbecause train slows down)

Final velocity (v) = 0 m/s

(final velocity is 0, because train stops)

Now, let's find the time taken (t) by using the first equation of motion ~

[tex]v = u + at[/tex]

[tex]0 = 100 + ( - 10 \times t)[/tex]

[tex]0 = 100 - 10t[/tex]

[tex]10t = 100[/tex]

[tex]t = 100 \div 10[/tex]

[tex]t = 10[/tex]

The train will take 10 secs to stop,

Now, let's find how much distance (s) it will cover before it stops using second equation of motion ~

[tex]s = ut + \dfrac{1}{2} at {}^{2} [/tex]

[tex]s = (100 \times 10) + ( \dfrac{1}{ 2} \times - 10 \times 10 \times 10)[/tex]

[tex]s = 1000 + ( - 500)[/tex]

[tex]s = 1000 - 500[/tex]

[tex]500 \: \: m[/tex]

It will cover 500 meters before coming to rest ~

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Answers

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Answers

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*Round your answer to the nearest whole number.

Answers

Answer:

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Explanation:

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