A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 100 m long and 60 m wide.
Find the area of the training field. Use the value 3.14 for , and do not round your answer. Be sure to include the correct unit in your answer.
Answers
Step-by-step explanation:
given,
length = 100 m
breadth = 60 m
we know,
area = l × b
now,
100 × 60 = 6000 m
therefore, area of rectangular field is 6,000 m.
and for both the semicircle if we add both the semicircle we will get a complete circle.
as the width of the rectangle is the diameter of circle so the radius of the circle is 60/2 = 30m
we know,
Area = πr²
now,
→ 3.14 × 30²
→ 3.14 × 900
→ 2826 m
so,
area of rectangle + area of circle = area of the training field.
→ 6000 + 2826 = 8826.
therefore, area of training field is 8,826 m.
hope this answer helps you dear...take care and may u have a great day ahead!
Answer:
8826 m²
Step-by-step explanation:
The field is composed of a rectangle and a circle .( the 2 semicircles form a complete circle when placed together )
area = area of rectangle + area of circle
= lb + πr² ( r = 60 ÷ 2 = 30 )
= (100 × 60) + (3.14 × 30²)
= 6000 + (3.14 × 900)
= 6000 + 2826
= 8826 m²
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