Answer:
Explanation:
as the mass cannot change, the volume per unit time is also constant so the area of the stream times the velocity is constant
If the diameter is 1 where velocity is 1.31 m/s
area is proportional to the square of the diameter A = (π/4)d²
1²(1.31) = 0.805²(v)
v = 1.31/0.805² = 2.02 m/s
v² = u² + 2as
2.02² = 1.31² + 2(9.81)h
h = 0.120819... m
h = 12.0 cm
What do these weapon stats mean?
Idle sway control is measured in Fc???
Flinch resistance is measured in N.
Answer:
its sort of like how Pounds are measured in lbs
Explanation:
Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.
A change in momentum is also called:
a. Impact
b. Imput
c. Impulse
d. Impole
Answer:
c. Impulse
Explanation:
A rock sinks straight down the surface of a pond, starting from rest and accelerating at an average rate of 2m/s^2 for the first 3 seconds of its motion. At the 3-second mark, the rock reaches its terminal speed and continues at that speed for the remaining 30 meters of motion. What is the total time it takes for the rock to sink from the surface to the bottom of the lake?
Answer:
Explanation:
Terminal speed is
2 m/s²(3 s) = 6 m/s
30 m / 6 m/s = 5 s
total sink time is
3 + 5 = 8 s
The total time taken by the rock to sink would be 8 seconds
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
The acceleration of the rock for the first three seconds = 2 meters/second²
The time taken to reach the terminal velocity = 3 seconds
terminal velocity = 2 ×3
= 6 meters/second²
The time for which the rock sink at terminal velocity = 30 /6
= 5 seconds
total time is taken by the rock to sink = 3 + 5
=8 seconds
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Which ball moved at the same speed as Ball 3?
Answer:
you forgot to attach the image
A 1500 kg car has the same momentum as a 2500 kg truck moving at 25 m/s. How fast is the car moving in m/s
Answer:
41.6m/s
Explanation:
P=mv
2500kg × 25m/s = 62500kgm/s
62500kgm/s ÷ 1500 kg = 41.6m/s
The amplitude of a lightly damped oscillator decreases by 4.2% during each cycle. What percentage of the mechanical energy of the oscillator is lost in each cycle?
Answer:
V= A ω maximum KE of object in SHM
V2 / V1 = .958 ratio of amplitudes since ω is constant
KE2 / KE1 = 1/2 m V2^2 / (1/2 m V1^2) = (V2 / V1)^2
KE2 / KE1 = .958^2 = .918
So KE2 = .918 KE1 and .082 = 8.2% of the energy is lost in one cycle
The intensity of a sound wave increases as the wave spreads out from the source of the sound. True or false
Answer:False
Explanation:
the intensity of the sound wave decreases with increasing distance from the source.
The work done by an electric force in moving a charge from point A to point B is 2.70 × 10‒3 J. The electric potential difference between the two points is VA ‒ VB = 50.0 V. What is the charge?
The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].
Given the following data:
Work done = [tex]2.70 \times 10^{-3}\;Joules[/tex]Potential difference = 50.0 VoltsTo determine the charge:
Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:
[tex]W = PQ[/tex]
Where:
W is the work done.P is the electric potential difference.Q is the charge.Making Q the subject of formula, we have:
[tex]Q =\frac{W}{P}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]
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The fundamental of a closed organ pipe is 259.6 Hz. The second harmonic of an open organ pipe has the same frequency. What is the length of the closed pipe
Answer:
A closed organ pipe is λ/4 (node-antinode) long.
λ = speed / frequency = 331.5 / 259.6 = 1.28 m
λ/4 = .319 m length of closed pipe
An open pipe has a fundamental wavelength of A-N-A or λ/2
The second harmonic would be A-N-A-N-A or λ = 1.28 m for the second harmonic 331.5 / 259.6 = 1.28 (the fundamental would be 331.5 / .628
Need quite a bit of help
When the cart was at Table
Normal reaction (N)=mgNow acceleration due to gravity acting on the gravity.
When the air comes out of straw it tries to take the cart upwards.But the force is equal to that of acceleration due to gravity but in opposite direction.Hence.
[tex]\\ \sf\Rrightarrow F_{net}=0N[/tex]
So the cart doesn't moveplease help me !!
Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on collisions?
A. The change in momentum needed to stop the gymnast is increased.
B. The change in momentum needed to stop the gymnast is decreased.
C. The force exerted by the floor on the gymnast decreases.
D. The force exerted by the floor on the gymnast increases.
URGENTLY NEED HELP
This is a 2 part question
42) You pull downward with a force of 28 N on a rope that passes over a disk-shaped pulley of mass 1.2 kg and radius 0.075 m. The other end of the rope is attached to a 0.67-kg mass. (a) Is the tension in the rope the same on both sides of the pulley? If not, which side has the greater tension? (b) Find the tension in the rope on both sides of the pulley.
Answer:
The net force on the hanging mass is thus
2 T Mg 18 6.6 N 11.4 N
, enough to accelerate it upward at
17 m/s2
. The angular acceleration of the pulley is thus
2 2
Explanation:
The tension in the rope on both sides of the pulley 20.21N.
To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:
(a) Is the tension in the rope the same on both sides of the pulley?
No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.
(b) Find the tension in the rope on both sides of the pulley:
Calculate the gravitational force on each mass:
Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).
Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.
Calculate the net force on the pulley:
Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.
Apply Newton's second law to the pulley:
For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.
Use the relationship between linear acceleration and angular acceleration:
α = a / r.
Equate the torque due to the tension to the moment of inertia times the angular acceleration:
τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.
Substitute the expression for α and solve for the net tension:
Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).
Now, substitute the expression for a from step 3 and solve for the net tension:
Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).
Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:
Tnet = (1/2 * Fnet).
Now, you can find the tensions on each side of the pulley:
Tleft = Tnet + Fhanging
Tright = Tnet - Fpulle
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13. In which of the following climates does chemical weathering generally occur most
rapidly?
A. Canda
B. Greenland
C. Brazil
D. Algeria
How should an artistic statement be written?
ОА.
from your own perspective
OB.
in a non-factual, persuasive manner
O C.
as a lengthy and overly extensive essay
OD. by the artist alone with no outside critique
An artistic statement should be written from your own perspective.
What is an artistic statement ?An artist's statement, also known as an artist statement, is a written summary of their creative output. The brief essay serves as an explanation of and a defense of their own work for the spectator. As a result, it is didactic, descriptive, or reflective in nature and seeks to inform, connect with an artistic environment, and reveal the inspiration behind the work.
The writing created by the artist aims to contextualize, justify, extend, and/or explain their body of work. It situates—or tries to situate—the piece in relation to art history, art theory, the contemporary art scene, and the times. The statement also demonstrates that the artist is aware of their aims, their practice, its place within the parameters of art, and the debate that surrounds it.
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Look at the circuit given below. It consists of a cell, a bulb with two terminals X, Y and wires. P, Q, R and S are positions marked. What is the direction of the flow of current? a) PQXYRS b) SRYXQP c) SPQXYR d) PSRYXQ
The conventions for the current allow to find the result for which is the direction of the current the is circuit is:
It leaves the positive pole, goes to the blue cable, to the light bulb, from there to the red cable and reaches the negative pole.
Current is the movement of electrons in a circuit per unit time.
In an electrical circuit the electrons that have a negative charge leave the negative electrode towards the positive electrode, by convention the current goes in the opposite direction from the positive electrode towards the negative electrode.
When analyzing the given circuit, the current leaves the positive pole at the top of the battery and moves through the blue wire, reaches the light bulb and moves the red wire and reaches the negative pole of the battery.
In conclusion using the conventions for the current we can find the result for which is the direction of the current the is circuit is:
It leaves the positive pole, goes to the blue cable, to the light bulb, from there to the red cable and reaches the negative pole.
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a car moves at a speed of 30m/s to the west of 3hr, what is its displacement of the car in km?
Answer:
Explanation:
30 m/s • 3 hr •3600 s/hr / 1000 m/km = 324 km west
Identify the types of motion a) The movement of a snail on the ground b) The strings of the guitar c) The whirling of stone tied with a thread
Answer:
1. friction, gravity,
Explanation:
Please help me! Some people have proposed a new way to build houses in areas that are likely to experience tsunamis. In this design, a house wouldn’t have solid walls on all four sides. Instead, some of the wall areas would be replaced by substances that water can travel through quickly, as shown in the diagram. How would this design help a house survive a tsunami? What drawbacks might there be to this design?
Answer:
I think some drawbacks are that since there are no solid walls meaning it is weak and if murphy's law is in place, the water will destroy the substance. Tsunami waves also happen very quickly so even if the water can travel thru the substance quickly, it probably won't be quick enough. This design could help if the wave is smaller because less destruction would occur.
Explanation:
yeah
Two 5 kg potted cacti, one in a black pot and one in a blue pot, slide down a sagging shelf in the same direction with
the same speed.
Which two equations correctly model the momentum of the two-cactus system?
Answer:
Answers A and D are the correct solution.
Explanation:
Both pots have the same mass and the same velocity vector.
the only difference between A and D is the selection of the reference frame positive direction.
The equation (A) and equation (D) correctly model the momentum of the two-cactus system.
What is momentum?The product of a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.
According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.
Given that: mass of each cactus: m = 5 kg.
And they slide down a sagging shelf in the same direction with the same speed.
In equation (A), both velocities of two cacti are in positive direction whereas, in equation (B), both velocities of two cacti is in negative direction. Hence, equation (A) and equation (D) correctly model the momentum of the two-cactus system.
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Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!
using dimensional analysis find the relation between the velocities of transverse waves produced from the vibration of thin homogeneous string and between the tension in the string and mass per unit length of it.
Answer:
[tex]v^2=\frac{T}{M}[/tex]
where v = transverse wave velocity, T = tension in the string, M = mass per unit length.
Explanation:
Dimensional analysis is where you just look at the units and see how they fit within each other.
In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.
For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.
If you play around a little with the powers, you can find a relationship:
[tex]v^2=\frac{T}{M}[/tex]
since:
[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²
Two positive charges of 1 mC and 10 mC are separated by a distance of 10 m. Find the
direction and the magnitude of electrostatic force between the charges. |Describe the
direction in terms of the charges attract each other," or "the charges repel each other."
mili C=1043 C
Answer:
900N, charges repel
Explanation:
F = KQq/d²
K = 9 × 10^9Nm²/C²
Q= 10mC = 10 × 10^-3C
q = 1mc = 1 × 10^-3C
d = 10m
F = ?
Force = (9 × 10^9 × 10 × 10^-3 × 1 × 10^-3)/10²
= 9 × 10²
= 900N
It will be an electrostatic force of repulsion since like charges(two positive charges) repel
The magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.
What is Coulomb's law of forces?Coulomb's law states that whenever the two charged particles are separated by a particular distance then there will be a force of attraction or repulsion acts between the charge.
The formula of coulomb's force will be given by
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
[tex]K=9\times 10^9\ \frac{Nm^2}{C^2}[/tex]
[tex]q_1= 10\times 10^{-3}\ C[/tex]
[tex]q_2=1\times 10^{-3}\ C[/tex]
[tex]\rm Distance \ d=10 \ m[/tex]
Now the force will be calculated as
[tex]F=(9\times 10^9)\dfrac{(10\times 10^{-3})\times (1\times 10^{-3})}{10}[/tex]
[tex]F= 900\ N[/tex]
The charges are positive in nature so they will repel each other
Hence the magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.
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Một chất điểm khối lượng m=200g chuyển
động chậm dần với vận tốc biến đổi theo qui luật
v=30 – 0,4t2 (SI). Lực hãm tác dụng vào chất điểm
lúc t = 5 giây là
A. 8 N B. 0,8 N C. 4 N D. 0,4 N
A sailcraft is stalled on a windless day. A fan is attached to the craft and blows air into the sail which bounces backward upon impact. The boat can what?
Answer:
Impulse = change in momentum w bounce
There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.
4. Protons and neutrons are held together to form this _________
Answer:
strong nuclear force.
Explanation:
hope this helps you!!
Which one is it??? The question and the choice are in the photo.
The answer is:
That they are switched on
Define the following units used for measuring distances in space.
a. Arcsecond
b. Astronomical unit
c. Parsec
d. Light year
Answer:
The astronomical unit is used primarily for measuring distances within the Solar System or around other stars.
How large is the acceleration of a 25 kg mass with a net force of 75 N applied horizontally to it?
Answer:
Explanation:
F = ma
a = F/m
a = 75/25
a = 3 m/s²
explain how wind erosion changes land forms
Answer:
the wind carries abrasive materials
Explanation:
such as sand and salt over time theses small particles slowly strip way at the land form sculpting it by eroding the softer layers first
a
A soccer player kicks a ball horizontally and it travels 150 m. The ball was kicked off of a cliff that was 75 m
high. What speed was the ball kicked at?
The ball was kicked with a speed of 38.4 m/s.
Using s = ut + 1/2gt², we find the time it takes the ball to reach the ground. Where
s = height of cliff = 75 mu = initial vertical velocity of ball = 0 m/s(since it is kicked horizontally)g = acceleration due to gravity = 9.8 m/s²t = time taken for ball to reach the ground.Substituting the values of the variables into the equation, we have
s = ut + 1/2gt²
75 m = (0 m/s)t + 1/2 × 9.8 m/s² × t²
75 m = 0 m + (4.9 m/s²) t²
75 m = (4.9 m/s²)t²
Dividing both sides by 4.9, we have
t² = 75 m/4.9 m/s²
t² = 15.306 s²
Taking square-root of both sides, we have
t = √15.306 s²
t = 3.91 s
The horizontal distance covered by the ball d = vt where
v = horizontal speed of ball and, t = time taken for the ball to reach the ground.Since we require v, we make it subject of the formula.
So, v = d/t
Given that d = 150 m and t = 3.91 s, substituting these into v, we have
v = d/t
v = 150 m/3.91 s
v = 38.4 m/s
So, the ball was kicked with a speed of 38.4 m/s.
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