A table of values shown below represents a linear function which of these points could also be an ordered pair in the table and why?

The first step that we must take before attempting to solve the problem is to understand what the problem is asking us to do and what is given to us to help accomplish that goal.  Although it does not explicitly state that we must solve for t, this is usually what the problem statement would be asking if we just receive and expression like this.  What is given to us to accomplish that goal is the expression [tex]4.9t+0.3=5.6t+0.72[/tex].

Now that we have completed that step, we can move onto the next part which is actually solving the problem.  The next step that we should take when solving for the unknown, in this case t, is to subtract 4.9t from both sides.

Subtract 4.9t from both sides

Now that we got all of the t's to one side, let us isolate t completely and the next step that we should take is to subtract 0.72 from both sides.

Subtract 0.72 from both sides

The final step that we need to take to isolate t would be to divide both sides by 0.7 which would remove the coefficient from the unknown variable t and divide 0.7 from -0.42

Divide both sides by 0.7

Therefore, after fully narrowing down the solution we were able to determine that the solution of the unknown variable or t is equal to -0.6

The value of x in the given right triangle is approximately 7.14

Hypotenuse² = opposite² + adjacent ²

10² = x² + 7²

100 = x² + 49

100 - 49 = x²

51 = x²

x = √51

x = 7.14142842854284

Approximately,

x = 7.14

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Answer:

[tex]\huge\bold\color{pink}{- Magdonal -}[/tex]

magpakailanman

[tex]\pink{\rule{1pt}{999999pt}}[/tex]

We need to explain the steps to use coordinates in calculating the perimeter and area of the polygon.

We need to explain the procedure when working with diagonal sides and irregular shapes on the coordinate plane.

The location of a point in the XY-plane is determined by coordinates. The vertex, which is the point where two lines of a shape meet to form a corner, is a unique place. We can determine the perimeter and area of a figure after we have the coordinates for all of its vertices.

Steps to calculate the perimeter and area of a polygon:

Step 1: Plot the given points on the graph.

Step 2: Connect the points and identify the figure.

Step 3: Determine lengths by counting the grid lines.

Step 4: Use a formula to calculate the perimeter and area if one exists.

Step 5: If there are no formulas for a figure, the perimeter can be calculated by summing the lengths of the sides. We might estimate the area without an area formula by counting the number of small squares enclosed.

Note: If you are using diagonal to calculate the area, then use the distance formula to calculate the length of the diagonal.

We need to explain how the distance formula and slope formula

are used to classify various quadrilaterals and triangles.

Distance formula: [tex]\sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2} }[/tex]

Now, we use slope to find the angles i.e. If:

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Answer:

Formulate

Based on the given conditions, formulate:

[tex] \sqrt{3 {9}^{2} } - 3 {3}^{2} [/tex]

Evaluate

Evaluate the equation/expression:

20.78461

SO THE ANSWER IS 20.78461

Answer:

20.78 feet

Step-by-step explanation:

[tex]39^{2} =h^{2} +33^{2} \\1521= h^{2} +1089\\h^{2}= 1521-1089\\h^{2} =432h= 20.78[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's find the value of given expression for x = 5 ~

[tex]\qquad \sf  \dashrightarrow \:3(3x + 5)[/tex]

[tex]\qquad \sf  \dashrightarrow \:9x + 15[/tex]

now, plug in the value of x as 5

[tex]\qquad \sf  \dashrightarrow \:9(5) + 15[/tex]

[tex]\qquad \sf  \dashrightarrow \:45 + 15[/tex]

[tex]\qquad \sf  \dashrightarrow \:60[/tex]

so, the equivalent value is 60

The conclusion that can be drawn from this graph on the long-run frequency of 100 rolls is The long-run frequency of rolling a 3 appears to be about 0.17.

At the 0.17 probability, the proportion of 3s calculated levels off from around the 40th roll to the 100th roll.

This means that the long-run frequency of rolling a 3 is around 0.17 because this was the probability seen for most of the rolls over time.

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Quadratic equations are equation that has degree of 3. The value of x from the quadratic equation is 3

Quadratic equations are equation that has degree of 3. Given the following equation;

5x²-11x = 1

Equate to zero

5x²-11x - 1 = 0

Find the solution using quadratic solution

[tex]x=\frac{11\pm\sqrt{121-4(5)(-1)}}{2(5)}\\x=\frac{11\pm\sqrt{141} }{10} \\x=\frac{11\pm11.87 }{10} \\x=\frac{22.87}{18}\\ x\approx 3[/tex]

Hence the value of x from the quadratic equation is 3

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The linear function that has a graph perpendicular to y = 2x – 4 is given by:

D. 2x + 4y = 1

A linear function is modeled by:

y = mx + b

In which:

If two lines are perpendicular, the multiplication of their slopes is of -1. The line y = 2x + 4 as a slope of 2, hence the slope of the perpendicular line will be given by m as such:

[tex]2m = -1[/tex]

[tex]m = -\frac{1}{2} = -0.5[/tex]

Hence option D is correct, as:

2x + 4y = 1

4y = -2x + 1

y = -0.5x + 0.25

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Answer:

45

Step-by-step explanation:

median is the middle number after arranging a set of numbers in ascending or descending order.

let's arrange the set of numbers above in ascending order

10, 10, 20, 30, 30, 40 50, 60, 70, 80, 90, 110

since there are 12 digits in total, count out five digits starting from extreme left and also count out five digits starting from extreme right.

the two numbers left in the middle are 40 and 50.

median 40+50/2 = 90/2= 45

We know that the equation of the line is in the form [tex]y=-\frac{2}{3}x+b[/tex]. To find b, we can use the fact that (6,-5) lies on the line, meaning that both sides of the equation are equal when x=6 and y=-5.

[tex]-5=-\frac{2}{3}(6)+b\\-5=-4+b\\b=-1[/tex]

Hence, the equation of the line is [tex]y=-\frac{2}{3}x-1[/tex], and its graph looks something like follows.

Step by Step Explanation:

The distance between rhea and her friend's house could be 8 km and The distance of the library from the rocks house could be 15 km.

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

rhea got a new e-scooter. She wanted to show it to her friend on the way to the library.

Her friend Ronan's house is due north of her house.

After showing him the new scooter she went to the library which is due west from rocks house.

while returning back she drove 17km diagonally to her house.

By Pythagoras' theorem

|AC|^2 = |AB|^2 + |BC|^2    

Here we can assume that

AB = The distance between rhea and her friend's house.

BC = The distance of the library from rocks house.

The triplet of the 17 would be (8, 15, 17)

So, we can say that the AB could be 8 km and BC could be 15 km or vice versa.

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Step-by-step explanation:

open ur compass more than half of the line and draw arc from both end. connect the line from 2 point of from the two arc

Answer:

59.1 feet

Step-by-step explanation:

The formula for the circumference of a circle in C=2πr. Since the radius of the circle is given, all you have to do is plug it into the equation.

C=2πr

C=2π(9.4)

C=18.8π feet  <-- this is the exact answer

C=59.1 feet

Answer:

12

Step-by-step explanation:

3/(22 + 3) voted for athelete

multiply everything by 4 to get fraction over 100

12/(88 + 12) voted for athelete

that means 12 percent voted for athelete

Step-by-step explanation:

1) x+6 =4

x. =4-6

x. =-2

2) x-(-4) =-6

x+ 4. =-6

x. =-6-4

x. =-10

3)2(x-1)=-200

2x-2 =-200

2x. = -200+2

2x. = -198

x. = -198/2

x. = -99

4)2x+(-3) =-23

2x-3. =-23

2x. =-23+3

2x. =-20

x. =-20/2

x. = -10

Answers:

x > 9

Graph has open circle

Arrow points to the right

======================================

Reason:

Add 7 to both sides to go from the original inequality to 9 < x, which is the same as x > 9

The graph will involve an open circle at 9. We don't include this endpoint because there isn't "or equal to" in the inequality sign.

We shade to the right due to the "greater than"

This visually shows all values larger than 9.

Answer:

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Answer:

119.1

Step-by-step explanation:

Pt+1=1.06x100

P3=106^3x100

=119.1016

Answer:

2x < 600

Step-by-step explanation:

Step-by-step explanation:

mark me brainlist please!!

the answer is A

The standard deviation of the sample mean differences is 4.854

The table of values is given as:

Sample      Standard deviation

Red box     3.868

Blue box   2.933

The standard deviation of the sample mean differences is calculated using:

[tex]\sigma = \sqrt{\sigma_1^2 + \sigma_2^2}[/tex]

This gives

[tex]\sigma = \sqrt{3.868^2 + 2.933^2}[/tex]

Evaluate the expression

[tex]\sigma = 4.854[/tex]

Also, the table of value do not give any information regarding the sample size.

This means that the sample size of the session regarding the number of people would purchase the red box and the blue box are unknown

Hence, the standard deviation of the sample mean differences is 4.854

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Check the picture below.

The distance covered by the motorcycle is 31.4 km and displacement will be equal to 0.

Distance and Displacement both are the measure of the movement of an Object from one point to another.

Distance is a scalar quantity while Displacement is a vector quantity , and so it depends upon direction.

Distance travelled will always be positive but Displacement can be positive , negative and zero.

A motorcycle rides from point P to Q to R to S and finally to P in a circular path as shown in the below figure

The missing figure is attached with the answer.

(a) The distance covered by the motorcycle is

2πr = 2 * 3.14 * 5 = 31.4 km

(b) The displacement will be equal to 0 as the starting and the ending point is same.

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Answer:

I believe the answer is: [tex]3B_i[/tex]. (Your equation should look something like this: [tex]\sum _{i=3}^5\:B_{\left(i\right)}[/tex] )

Step-by-step explanation:

[tex]1. \sum _{i=3}^5=\sum _{i=1}^5-\sum _{i=1}[/tex]

2.[tex]=\sum _{i=1}^5B_{\left(i\right)}-\sum _{i=1}^2B_{\left(i\right)}[/tex]

3.=[tex]=\sum _{i=1}^5B_{\left(i\right)}= 5B_{\left(i\right)[/tex]

4.[tex]\sum _{i=1}^2B_{\left(i\right)}= 2B_{\left(i\right)[/tex]

5.[tex]5B_{\left(i\right)}-2B_{\left(i\right)}[/tex]

6.[tex]5B_{\left(i\right)}-2B_{\left(i\right)}=3B_{\left(i\right)}[/tex]

7. The answer should be: [tex]3B_{\left(i\right)}[/tex]

Hope this helps...

Answer:

I think it's the one in the middle

Step-by-step explanation: