A surveyor whose eye level is 5 feet above the ground determines the angle of elevation to the top of an office building to be 41.7°. If the surveyor is standing 40 feet from the base of the building, what is the height of the building to the nearest foot?
A.) 32ft.
B)50 ft
C)36ft
D.)41ft​

Answers

Answer 1

The height of the building when the surveyor is standing that far is D.)41ft​

How to find the height of the building ?

The tangent function would be best to use to find the height because we would be able to use the adjacent and and opposite.

Assuming that 5 feet is the height and the angle of elevation is 41. 7 degrees, and the distance of 40 feet, we have :

tan ( A ) = (h - x) / D

tan ( 41. 7° ) = ( h - 5 ) / 40

h - 5 = 40 x tan ( 41. 7 ° )

h - 5 = 40 x 0.8895

h = 35.58 + 5

= 40.58

= 41 feet

The height of the building is 41 feet.

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Related Questions

As seen in the diagram below, Dalvin is building a walkway with a width of x x feet to go around a swimming pool that measures 7 feet by 9 feet. If the total area of the pool and the walkway will be 143 square feet, how wide should the walkway be?

Answers

Answer: 2

Step-by-step explanation:

(7+2x)(9+2x)= 143 (area= length x width)

63+14x+18x+4x^2=143

4x^2+32x−80=0

x^2+8x−20=0

(x−2)(x+10)=0

x = 2 or -10

Since the length of the walkway can't be negative, the answer is 2.

A quality control technician at a candle factory tested the eight 16-ounce candles, each 3 inches in diameter. These candles came from the same production run. The table shows the decrease in weight of each candle after burning for 3 hours. Candle makers believe that the rate at which the candles burn is constant.



Write an equation that can be used to model the weight,
of such a candle as a function of
, the number of hours burning. Then, explain how the equation can be used to predict the weight of a candle that has burned for 5 hours.

Enter your equation and your explanation in the box provided.

Answers

Answer:

According to the model. the weight of the candle after S hours of burning would be about 15.05 ounces

Step-by-step explanation:

If the burn rate is believed to be constant, determine the average burn rate for the eight candles as the ratio of weight loss per hour.

ounces lost over three hours

0.5+0.6+0.5÷0.7÷0.7÷0.5÷0.5÷0.6

8

* 0.575

0.575

ounces lost per hour on average

= 0.19

For 0 hours, the weight of each candle is 16 ounces. Therefore, w 16 - 0.19h.

This model can be used to predict the weight of the candle when h, the number of hours of burning, is 5.

W * 16 - 0.19(5)

W = 16 - 0.95

W = 15.05

According to the model. the weight of the candle after S hours of burning would be about 15.05 ounces.

What is the perimeter of the parallelogram?
units

Answers

Answer:

Step-by-step explanation:

Now, find the solution to the system of equations

Answers

The solution of equation is (2, 3).

We have,

x= 3y -7.........(1)

y= x + 1.........(2)

Solving equation (1) and (2) we get

y = 3y - 7 + 1

y - 3y = -7 + 1

-2y = -6

y = -6/(-2)

y = 3

and, x = 3(3) - 7

x = 9 - 7

x = 2

Thus, the solution of equation is (2, 3).

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In the diagram shown, ABC is equilateral. AD is an altitude.


10). ABD = _____.

11). ADB = _____.

12). BAD = _____.

13). CAD = _____.


Suppose AB = 6. Find:


14). BD

15). AD

16). Area of ABC

Answers

All the correct values are,

⇒ ∠ABD = 60°

⇒ ∠ADB = 90°

⇒ ∠BAD = 30°

⇒ ∠CAD = 30°

⇒ BD = 3

⇒ AD = √27

⇒ The value of area of triangle ABC is, 3√27

Given that;

In the diagram shown, ABC is equilateral. AD is an altitude.

Hence, We get;

All the angles of a equilateral triangle are,

⇒ 60°

Thus, We get;

⇒ ∠ABD = 60°

Since, AD is an altitude.

⇒ ∠ADB = 90°

And,

⇒ ∠BAD = 60 / 2 = 30°

⇒ ∠CAD = 60/2 = 30°

By Pythagoras theorem;

AB² = AD² + BD²

6² = AD² + 3²

36 = AD² + 9

AD² = 27

AD = √27

Thus, The value of area of triangle ABC is,

⇒ 1/2 × AD × BC

⇒ 1/2 × √27 × 6

⇒ 3√27

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View photo below. This is timed.

Answers

Answer: ∠EFB, ∠DFE, and ∠CFB

Step-by-step explanation:

Starting Angle: ∠CFD

Since its in an X formation: ∠EFB, ∠DFE, and ∠CFB would all work.

URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS

Answers

Answer:

Step-by-step explanation:

1 -E (102/234) *100 =43.6%

2- F

3-C

4-A

Find the weighted mean. Round your answer to the nearest tenth.

Answers

The weighted mean of the deliveries each week can be found to be 5. 38 .

How to find the weighted mean ?

The weighted mean is a type of mean that takes into account, the weight of the various items in question.

First, find the total frequency :

= 1 + 5 + 4 + 3

= 13

The weighted mean would then be:

= ∑ ( weight of delivery x number of deliveries )

= ( 1 / 13 x 2 ) + ( 5 / 13 x 4 ) + ( 4 / 13 x 6 ) + ( 3 / 13 x 8 )

= 0. 15  + 1. 54 + 1. 84 + 1. 85

= 5. 38

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18.
Simplify.
y²-6y +11
y-2
Oy-1
Oy³-8y² +23y - 22
none of the answer choices
Oy²-5y +9
O-y²-2y + 10

Answers

Answer:

the answer is none of the answer choices

Answer:

the answer is none of the answer choices

EASY POINTS!

A machine in a factory makes 2 1/4 pounds of nails in 1 1/2 hours. At this rate, in pounds per hour, does the machine make nails? Show your work!

A. 2/3
B. 3/4
C. 1 1/2
D. 3 3/4

Answers

To find the rate at which the machine makes nails in pounds per hour, we need to divide the amount of nails by the time taken to make them.

The machine makes 2 1/4 pounds of nails in 1 1/2 hours.

To convert 2 1/4 to an improper fraction, we multiply the whole number (2) by the denominator (4) and add the numerator (1), then write the result over the denominator:

2 1/4 = (2 x 4 + 1)/4 = 9/4

To convert 1 1/2 to an improper fraction, we multiply the whole number (1) by the denominator (2) and add the numerator (1), then write the result over the denominator:

1 1/2 = (1 x 2 + 1)/2 = 3/2

Now we can divide the amount of nails by the time:

(9/4) ÷ (3/2) = (9/4) x (2/3) = 18/12 = 3/2

Therefore, the machine makes nails at a rate of 3/2 pounds per hour. The correct answer is C.


tructor
Watch the video and then answer the problem given below.
Click here to watch the video.
The circle graph represents a sample of 600 people who were asked which one automobile accessory they would most
prefer to have on a family trip. How many people indicated Bluetooth capability?
people
CEFF
Automobile Accessories for a Family Road Trip
Bluetooth capability 29%
Other 21%
Clear all
Roof rack 8%
Extra cup holders 15%
DVD player 27%
Check answer

Answers

Based on the above, about  174 people out of the sample of 600 people indicated Bluetooth capability.

What is the graph  about?

To know the number of individuals who shown Bluetooth capability, we have to to begin with calculate the division of individuals who chose this choice from the circle chart.

Note that:

People who Bluetooth capability =29%

Number of people = Percentage × Total sample size

= 0.29 × 600

= 174

So,  174 individuals shows that the Bluetooth capability is their favored option for the family trip.

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SAT/ACT An arc has a central angle of
radians and a length of 6. What is the
circumference of the circle?
A 12T
B 15T
30T
D 36л

Answers

Answer: D 36л

Step-by-step explanation:

s = θr

where r is the radius of the circle.  given that the arc length is 6, and the central angle is π/3 radians r:

6 = (π/3)r

r = 6/(π/3) = 18/π

the circumference of the circle is given by:

C = 2πr

Substituting r = 18/π, we get:C = 2π(18/π) = 36

I’m unsure where to plot the five points and shade in

Answers

The image is attached of the graph of the inequality y < 4x - 5.

What is the inequality equation?

An inequality equation is a mathematical statement that compares two expressions using an inequality symbol such as < (less than), > (greater than), ≤ (less than or equal to), or ≥ (greater than or equal to).

To graph the inequality y < 4x - 5 using the slope-intercept form, follow these steps:

Rewrite the inequality in slope-intercept form, y = mx + b, where m is the slope of the line and b is the y-intercept.

y = 4x - 5

Plot the y-intercept on the y-axis.

The y-intercept is -5, so plot the point (0, -5).

Use the slope to find a second point on the line.

The slope is 4, so start at the y-intercept and move up 4 units and to the right 1 unit to find the point (1, -1).

Draw a dashed line through the two points.

Since the inequality is y < 4x - 5, use a dashed line to indicate that the line itself is not part of the solution.

Shade the region that satisfies the inequality.

To do this, pick a test point that is not on the line and plug its coordinates into the inequality. If the inequality is true for that point, shade the region that contains the test point. If the inequality is false for that point, shade the region that does not contain the test point.

Let's use the test point (0, 0). Plug its coordinates into the inequality to get:

0 < 4(0) - 5

This simplifies to 5 < 0, which is false. Therefore, we need to shade the region that does not contain the test point.

Since the inequality is y < 4x - 5, we need to shade the region below the dashed line.

Label the shaded region with the inequality symbol.

The inequality is y < 4x - 5, so label the shaded region below the dashed line with the symbol "<".

hence, The image is attached of the graph of the inequality y < 4x - 5.

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Triangle D has been dilated to create triangle D′. Use the image to answer the question.

image of a triangle labeled D with side lengths of 3.8, 4.8, 4.2 and a second triangle labeled D prime with side lengths of x, 2.4, 2.1

Determine the scale factor used.

one half
2
one fourth
3

Answers

Answer:

To determine the scale factor used, we need to find the ratio of corresponding side lengths in both triangles.

Let's compare the length of the first side in both triangles:

x/3.8 = 2/4.8

Cross-multiplying, we get:

4.8x = 7.6

Dividing both sides by 4.8, we get:

x = 1.58

Now, let's compare the length of the second side in both triangles:

2.4/4.2 = 0.57

Finally, let's compare the length of the third side in both triangles:

2.1/4.8 = 0.44

Since the scale factor is the same for all corresponding side lengths, we can take the average of the ratios:

(scale factor) = (1.58/3.8 + 0.57 + 0.44)/3

(scale factor) = 1.01

Therefore, the scale factor used is approximately 1.

The scale factor used to dilate triangle D to triangle D' is 1/2.

To see this, notice that the side lengths of triangle D' are half the length of the corresponding sides in triangle D. For example, the length of the shortest side in triangle D is 3.8, while the length of the shortest side in triangle D' is x. Since the length of the shortest side in triangle D' is half the length of the shortest side in triangle D, the scale factor is 1/2.

Which number line shows the solution set for |h-3| ≤5?​

Answers

Answer:

Second number line

Step-by-step explanation:

(h-3)^2 <= 25

h^2 - 6h + 9 <= 25

h^2 - 6h - 16 <= 0

(h-8)(h+2) <=0

Using the graph of (x-8)(x+2),

-2 <= h <= 8

Hence, the answer is the second one (as it has shaded circles)

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Calculating Loan Payments You want to buy a new sports coupe for $69,300, and the finance office at the dealership has quoted you a loan with an APR of 5.6 percent for 48 months to buy the car. What will your monthly payments be? What is the effective annual rate on this loan?

Input area:


Amount borrowed $69,300
APR 5.6%
# of years 4
# of times compounded per year 12


(Output area) Complete the following analysis. Do not hard code values in your calculations. All answers should be positive.

Loan Payment __________
Effective Intrest Rate ____________

Answers

The monthly payments will thus be $1,612.81.

The annual effective rate on this loan is 5.78%.

What is the loan payment formulae?

We can use the following loan payment formula to determine the loan payment:

Loan Payment  = [tex]\\\frac{p * \frac{r}{n} }{1 - (1 + \frac{r}{n} )^{-n *t} }[/tex]

where P = borrowed amount = $69,300

r = yearly interest rate (decimal) = 0.056

n = number of times compounded per year = 12

t = number of years = 4

When we plug in the values, we get:

Loan Payment = [69300 x (0.056/12)] / [1 - (1 + 0.056/12)^(-12*4)]

= $1,612.81 (to the nearest cent)

The monthly payments will thus be $1,612.81.

We can use the following calculation to obtain the effective annual rate:

Annual Effective Rate =[tex](1 + r/n)^{n-1}[/tex]

When we plug in the values, we get:

Annual Effective Rate =[tex](1 + 0.056/12)^{12 - 1}[/tex]= 0.0578 or 5.78%

As a result, the annual effective rate on this loan is 5.78%.

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how do I do 75% of 200

Answers

You can use the part=percent(whole) method, which would produce X=75%(200), which is X=0.75(200), which is 150. 75% is 0.75 because 75% is really 75/100, which is 0.75. You can also use the proportion method, which is (percent)/100=(part)/whole. This would be 75/100=X/200. When cross multiplying and solving for X, you would once again get 150.

Answer:

150

Step-by-step explanation:

divide the percentage by 100 to make it decimal form,
75/100= .75

The multiple .75 by the total amount to find the 75%,

200 x .75 = 150

Which means 75% of 200 is 150

The graph of f(x) and table for g(x)= f(kx) are given.- WORTH 40 BRAINLY POINTS PLEASE ANSWER FAST


The graph shows an upward opening parabola labeled f of x that passes through a point negative 2 comma 8, a point negative 1 comma 2, a vertex 0 comma 0, a point 1 comma 2, and a point 2 comma 8.


x g(x)
−6 8
−3 2
0 0
3 2
6 8

What is the value of k?
k = 3
k is equal to one third
k = 6
k is equal to negative one sixth

Answers

The value of k include the following: B. k is equal to one third.

What is the vertex form of a quadratic equation?

In Mathematics, the vertex form of a quadratic function can be modeled by this formula:

y = a(x - h)² + k

Where:

h and k represents the vertex of the graph.a represents the leading coefficient.

Based on the information provided about the quadratic function f(x), we can logically deduce that its vertex is at (0, 0);

f(x) = a(x - h)² + k

2 = a(1 - 0)² + 0

2 = a

f(x) = 2(x - 0)² + 0

f(x) = 2x²

For the quadratic function g(x), we have;

g(x) = f(kx)

g(x) = 2(kx)²

g(x) = 2k²x²

By using the point (3, 2) from the table, we have:

2 = 2k²3²

1 = k²9

k² = 1/9

k = √(1/9)

k = 1/3 i.e one third.

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This shows a number line. Which point is located at 90 ?

Answers

Answer:

incomplete question bru

x^2+7x-9 + 2x-1 what is the polynomial and degree

Answers

Answer:

The given expression is a polynomial:

f(x) = x^2 + 7x - 9 + 2x - 1

Combining like terms, we get:

f(x) = x^2 + 9x - 10

The degree of the polynomial is 2, since the highest power of x is 2.

4. Mackenzie's dog can jump 2 1/2 feet off the ground. Jordyn's dog can
jump 1/2 foot off the ground. What is the difference in inches between
2how high Mackenzie's dog can jump and how high Jordyn's dog can
jump? Circle what to do to solve this problem.

Answers

The difference in the length of dogs jump is 24 inches.

Given that, Mackenzie's dog can jump [tex]2\frac{1}{2}[/tex] =5/2 feet off the ground. Jordyn's dog can jump 1/2 foot off the ground.

We know that, 1 feet = 12 inches

Here, 5/2 feet = 5/2 ×12

= 30 inches

1/2 foot = 1/2 ×12

= 6 inches

Now, difference = 30-6 = 24 inches

Therefore, the difference in the length of dogs jump is 24 inches.

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Use the graph below to answer the question.
Money Spent on Food
dinner
42%
lunch
30%
snacks
10%
breakfast
18%
A shopper spent $100 at the store. How many dollars did the shopper spend on snacks?
A. $10
B. $18
C. $30
D. $42

Answers

A

if the shopper spent $10 on snacks and 10% of 100 is 10 then the answer is A

A sample of n = 64 scores has a mean of M = 68. Assuming that the population mean is μ = 60, find the z-score for this sample:
If it was obtained from a population with σ = 16
z =
If it was obtained from a population with σ = 32
z =
If it was obtained from a population with σ = 48
z =

Answers

c) Population [tex]\sigma = 48[/tex]

Z = [tex]\frac{68-60 }{\frac{48 }{\sqrt{64}}}[/tex]

Z-score= 1.3333

How to solve

According to the question , sample size n=64 , mean M = 68 , population mean [tex]\mu= 60[/tex]

Z = [tex]\frac{M-\mu }{\frac{\sigma }{\sqrt{n}}}[/tex]

where M = Sample Mean

[tex]\mu[/tex] = Population Mean

[tex]\sigma[/tex] = Population Standard Deviation

n = Sample Size

a) Population [tex]\sigma[/tex] = 16

Z = [tex]\frac{68-60 }{\frac{16 }{\sqrt{64}}}[/tex]

Z-score = 4

b) Population [tex]\sigma[/tex] = 32

Z = [tex]\frac{68-60 }{\frac{32 }{\sqrt{64}}}[/tex]

Z-score = 2

c) Population [tex]\sigma[/tex]= 48

Z = [tex]\frac{68-60 }{\frac{48 }{\sqrt{64}}}[/tex]

Z-score= 1.3333

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Find the sum of 10x² + 7x + 6 and 6x + 5.
Answer:
Submit Answer
M
DELL

Answers

10x² + 13x + 11 is the sum of linear equation .

What is a linear equation in mathematics?

The algebraic equation y=mx+b is known as a linear equation. All of its terms are constant, first-order linear ones. where m denotes the slope and b the y-intercept.

                             The aforementioned is occasionally referred to as a "linear equation in two variables" where y and x are variables. One or more variables may be present in a linear equation. The term "bivariate linear equation" refers to a linear equation with two variables.

two equations are  10x² + 7x + 6 and 6x + 5.

now add both equations

= (10x² + 7x + 6 )+ (6x + 5)

=  10x² + 7x + 6 + 6x + 5

= 10x² + 13x + 11

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What is the area of this figure?
20 mi
3 mi
11 mi
7 mi
3 mi
4 mi
3 mil
Write your answer using decimals, if necessary.
square miles
3 mi

Answers

The area of the figure composed of two rectangles is 99 mi²

How to solve an equation?

An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.

The area of a figure is the amount of space it occupies in its two dimensional state.

For the first rectangle:

Area = 11 mile * 5 mile = 55 mi²

For the second rectangle:

Area = 11 mile * 4 mile = 44 mi²

The area of figure = 55 mi² + 44 mi² = 99 mi²

The area of the figure is 99 mi²

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9. data was collected on houses currently for sale. based on a cubic modeling equation, which prediction about this data is the most reliable? a.
a $70k house would have 1,354 square ft
b. a $70k house would have about 1,460 square ft
c. a $400k house would have 492 square ft
d. a $400k house would have 4,328 square ft

10. suppose a scatterplot is created from the points in the following table. when x=7, what is the second coordinate in a scatterplot of the linearized data? round the answer to the tenth place.
a. 0.8
b. 2.1
c. 54.3
d. 112.8

11. the equation that best models the linearized data for a particular data set is log y= 0.75821x+0.03442. find the approximate value x=4. round your answer to the nearest whole number.
a. 3
b. 25
c. 1,168
d. 62,034

Answers

question 9.

Based on a cubic modeling equation, the  prediction about this data that is  most reliable is a $70k house would have 1,354 square ft.

Option A is correct.

Question 10.

The second coordinate in a scatterplot of the linearized data and  rounding the answer to the tenth place is 0.8

Option A is correct.

Question 11.

The approximate value when x=4 and rounding the answer to the nearest whole number is 1,168

Option C is correct.

How do we calculate?

The equation is given as

Log y= 0.75821x+0.03442

We substitute x = 4 into the given equation and solve for y:

log y = 0.75821(4) + 0.03442

log y = 3.07286 + 0.03442

log y = 3.10728

We take the antilogarithm of both sides,

y = 10^(3.10728)

y = 1,168.66

Rounding off, the closest answer is option  (c) 1,168.

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4. Find the product

()

Answers

Answer: n^6-25

Step-by-step explanation:

Use the distributive property to obtain: n^6-5n^3+5n^3-25

Simplify: n^6-25

Answer: n^6-25

The product of the given expression [tex](n^{3} + 5) (n^{3} - 5)[/tex] will be the second option  [tex]n^{6} - 25[/tex].

This is a simple math problem that can be solved using algebraic identities. Algebraic identities are mathematical formulas that hold true regardless of the value assigned to each of the variables. They can be used to resolve equations and simplify expressions.

In the above question, we have used the following identity:

[tex](a^{2} - b^{2} ) = (a + b) (a - b)[/tex]

In the given question, a = [tex]n^{3}[/tex] and b = 5

So putting values in the identity, we get

[tex][(n^{3})^{2} - 5^{2}] = (n^{3} + 5) (n^{3} - 5)[/tex]

On solving the left side of the equation, we get

[tex]n^{6} - 25[/tex] which is our answer to the given question.

Note: [tex](n^3)^2 = n^6[/tex] because the powers get multiplied.

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2x + y = 7
x + y = 1

Answers

Answer:  x = 6 and y = -5.

Step-by-step explanation: Multiply the second equation by -2 to eliminate the y term:

-2(x + y) = -2(1) -> -2x - 2y = -2

Add the resulting equation to the first equation to eliminate the y term:

2x + y = 7

-2x - 2y = -2

0x - y = 5

Solve for y:

-y = 5

y = -5

Substitute y = -5 into either of the original equations and solve for x:

x + y = 1

x + (-5) = 1

x = 6

Therefore, the solution to the system of equations is x = 6 and y = -5.

A bacteria culture initially contains 2500 bacteria and doubles every half hour.

Find the size of the baterial population after 20 minutes.


Find the size of the baterial population after 4 hours.

Answers

Answer:

After half hour=30 min you have 2×2500=5000 bacteria so you can use this into your equation to write:

and:

Apply the natural logarithm ln to both sides and get:

so  in units of

so your equation is now:

1] it t= 50 min substituting you get:

bacteria

2] if t= 8 h = 480 min you get:

bacteria

Step-by-step explanation:

A genetic experiment with peas resulted in one sample of offspring that consisted of 427 green peas and 154 yelow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25%, of the offspring peas would be yellow? a. Construct a 90% confidence interval. Express the percentages in decimal form. ​

Answers

a. To construct a 90% confidence interval, we can use the following formula:

CI = p ± z*sqrt((p*(1-p))/n)

where:
p = proportion of yellow peas = 154/(427+154) = 0.265
z = z-score for a 90% confidence level = 1.645 (from a standard normal distribution table)
n = sample size = 427+154 = 581

Substituting the values, we get:

CI = 0.265 ± 1.645*sqrt((0.265*(1-0.265))/581)
CI = 0.265 ± 0.042
CI = (0.223, 0.307)

Therefore, we can say with 90% confidence that the true proportion of yellow peas in the population lies between 0.223 and 0.307.

b. The expected proportion of yellow peas is 0.25. Since the confidence interval does not contain 0.25, the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow.
Other Questions
A convenient method to implement friendly code uses bit-specific addressing. Using this, individual pins of a port can be accessed independently.This feature is available on the Texas Instruments TM4C line of microcontrollers. This bit-specific addressing works on the parallel port data registers.Given the base address for Port A is 0x4000.4000, the bit-specific address of all pins in Port A are shown below.#define PA7 (*((volatile unsigned long *)0x40004200))#define PA6 (*((volatile unsigned long *)0x40004100))#define PA5 (*((volatile unsigned long *)0x40004080))#define PA4 (*((volatile unsigned long *)0x40004040))#define PA3 (*((volatile unsigned long *)0x40004020))#define PA2 (*((volatile unsigned long *)0x40004010))#define PA1 (*((volatile unsigned long *)0x40004008))#define PA0 (*((volatile unsigned long *)0x40004004))Use this PA71 you defined in the previous question, to make both bits 7 and 1 of Port A high. Chris is covering a window with a decorative adhesive film to filter light. The film cost $2.35 per square root. How much will the film cost? A tabular presentation that shows the outcome for each decision alternative under the various states of nature is called: A) a payback period matrix. B) a payoff table. C) a decision tree. D) a decision matrix. a 100 g ball rolls off a table and hits 2.0 m from the base of the table. a 200 g ball rolls off the same table with the same speed. it lands at distance Please implement the following procedure in MIPS 32:############################################################# # Given an integer, convert it into a string## Pre: $a0 contains the integer that will be converted# Post: $v0 contains the address of the newly-created string#############################################################PROC_CONVERT_INT_TO_STRING:# add your solution here# loop div by 10, get remainder# EX: 42 / 10 -> rem = 2# 4 / 10 -> rem = 4# result: 24, reverse string for 42...# returnjr $raI'm given some helper procedures to help implement the above:############################################################# # This procedure will determine the number of digits in the# provided integer input via iterative division by 10.## Pre: $a0 contains the integer to evaluate# Post: $v0 contains the number of digits in that integer#############################################################PROC_FIND_NUM_DIGITS:# prologue# function bodyli $t0, 10 # load a 10 into $t0 for the divisionli $t5, 0 # $t5 will hold the counter for number of digitsmove $t6, $a0 # $t6 will hold the result of the iterative divisionNUM_DIGITS_LOOP:divu $t6, $t0 # divide the number by 10addi $t5, $t5, 1mflo $t6 # move quotient back into $t6beq $t6, $zero, FOUND_NUM_DIGITS # if the quotient was 0, $t5 stores the number of digitsj NUM_DIGITS_LOOPFOUND_NUM_DIGITS:move $v0, $t5 # copy the number of digits $t5 into $v0 to return# epilogue# return jr $ra ############################################################# # This procedure will reverse the characters in a string in-# place when given the addresses of the first and last# characters in the string.## Pre: $a0 contains the address of the first character# $a1 contains the address of the last character# Post: $a0 contains the first character of the reversed# string#############################################################PROC_REVERSE_STRING:# prologue# function body move $t0, $a0 # move the pointer to the first char into $t0move $t2, $a1 # move the pointer to the last char into $t2# Loop until the pointers cross LOOP_REVERSE: lb $t9, 0($t2) # backing up the $t2 position char into $t9lb $t8, 0($t0) # load the $t0 position char into $t8sb $t8, 0($t2) # write the begin char into $t2 positionsb $t9, 0($t0) # write the end char into $t0 position# increment and decrement the pointersaddi $t0, $t0, 1subi $t2, $t2, 1ble $t2, $t0, END_OF_REVERSE_LOOPj LOOP_REVERSEEND_OF_REVERSE_LOOP:# epilogue# return jr $ra A rare form of malignant tumor occurs in 11 children in a million, so its probability is 0.000011. Four cases of thistumor occurred in a certain town, which had 17,199 children.a. Assuming that this tumor occurs as usual, find the mean number of cases in groups of17,199 children.b. Using the unrounded mean from part (a), find the probability that the number of tumor cases in a group of17.199 children is 0 or 1.c. What is the probability of more than one case?d. Does the cluster of four cases appear to be attributable to random chance? Why or why not? you discover that the plate you selected had only been inoculated with 0.1mL of the dilution instead of 1mL. Using the count data and observational data you acquired re-calculate the number of CFUs in the origional sample. an object of mass 9.00 kg attached to an ideal massless spring is pulled with a steady horizontal force across a frictionless level surface. if the spring constant is 95.0 n/m and the spring is stretched by 22.0 cm , what is the magnitude of the acceleration of the object? A direct access hash table has items 51, 53, 54, and 56. The table must have a minimum of a.4b.5 c.56 d.57 Find the tangential and normal components of the acceleration vector. r(t) = ti + t^2 j + 3tK a_T = a_N = Question 1-5Every year from June to November Florida is at risk for tropical storms and hurricanes. Which step should individuals take to be prepared for these storms?A) During the storm move to an exterior area.B) Check emergency equipment during the storm.C) Stock up on food items that are reliant on refrigeration.D) Before hurricane season determine safe evacuation route. All business decisions involve aspects of risk and return. Rank order the following investment activities from 1 through 4, where "1" is most risky and "4" is least risky. a. U.S. government Treasury Bond b. Stock of a highly successful company Medium-risk corporate bond d. High-risk corporate bond C. parole rapporte cest quoi help please I need someone to tutor me with this lol which type of associations is an unobserved variable that correlates with both the exposure and outcome variable? Find the Laplace transform of a +bt+c for some constants a, b, and c Exercise 6.1.7: Find the Laplace transform of A cos(t+Bsin(t Answer the following questions. If an electron and a hydrogen ion are removed from a structure during a chemical reaction, the structure is said to have been: A tugboat pulls a ship with a constant net horizontal force of 7.5x10^3 N. How much work is done on the ship if it moves 5km? what are three music features of the music piece "the Moldau 1874"?