A stunt pilot in an air show performs a loop-the-loop in a vertical circle of radius 3.80 103 m. During this performance the pilot whose weight is 623 N, maintains a constant speed of 2.10 102 m/s. (a) When the pilot is at the highest point of the loop determine his apparent weight in N. N (b) At what speed, in m/s, will the pilot experience weightlessness

Answer:

The speed of the wave will decrease (due to a shorter wavelength after passing from air to a more dense medium)

The power generated or output power of the turbine is determined as 42.96 W.

The power generated or output power of the turbine is calculated as follows;

eff = 0utput power/1nput power x 100%

13 = 0utput power/(0.62 x 533)

0.13 = 0utput power/330.46

0utput power = 0.13 x 330.46

0utput power = 42.96 W

Thus, the power generated or output power of the turbine is determined as 42.96 W.

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Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters

Explanation:

As the moon phase approaches full we say the Moon has now completed one half of the lunar month.

This is defined as the time it takes the Moon to pass through all of the phases.

When the moon approaches full then itn has completed one half of the lunar month which is the time taken to form a new moon.

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[tex]\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}[/tex]

[tex] \sf \red{what \: is \: potential \: energy}[/tex]

[tex]\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}[/tex]

Potential energy: A type of energy which is possessed by an object due its position.

Example: A raised weight or when we raise any weight is a potential energy.

[tex]\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}[/tex]

[tex] \sf \red{on \: which \: factor \: potential \: energy \: depends}[/tex]

[tex]\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}[/tex]

Potential energy depends upon three factors. They are:

[tex] \boxed{ \huge \frak \red{brainlysamurai}}[/tex]

The distance, van travels while coming to rest after brake applied is 6.4m

It states that the Work done in moving a body is equal to the change in kinetic energy of the body

Given is a delivery van  whose kinetic energy K.E = 80000J and the force applied to brake F = 12500 N.

The brakes are applied to stop the van, so, final velocity is zero. Then, change in kinetic energy will be

According to work energy theorem, work done is

W = ΔK.E = K.Ef - K.Ei

W = -  80000J

Work done is also defined as the product of force applied and the distance it travelled.

W = Fs

80000 = 12500 x s

s = 6.4 m

Thus, the distance, van travels while coming to rest after brake applied is 6.4m

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Answer:

The angle of the Sun's rays:

At about June 21 the sun is directly overhead at about 23 deg north of the equator

On about Dec 21 the sun is directly overhead at about 23 deg south of the equator

It is this tilt 23 deg to the ecliptic (path of earth about sun) that causes the major temperature changes on earth

The miracle year for Albert Einstein  was the year 1905 within which he published so many renowned papers.

The miracle year for Albert Einstein  was the year 1905 within which he published so many renowned papers in a short time and became very popular.

His mindset in that year was one that challenged the orthodox explanations and sought to think outside the box.

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The error percentage in measuring the volume of the cylindrical box is 6.3 x 10⁻³ %

The total error percentage in measuring the volume of the cylinder is calculated as follows;

Volume of cylinder = πr²h

Volume of cylinder = π(0.03r)²(0.07h)

Volume of cylinder = (6.3 x 10⁻⁵)πr²h

Error in measuring the volume = 6.3 x 10⁻⁵ x 100% = 6.3 x 10⁻³ %

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Answer:

Valence electrons

Explanation:

I don't exactly understand the question. However, I do know that the main commonality between elements of the same group (column) is their valence electrons. Valence electrons are very important when it comes to bonding, ionization, etc.

Answer:

  toward the center of the circular curve

Explanation:

An object will follow a circular path at constant speed if and only if its net acceleration is constant and directed toward the center of the curved path.

__

The result force is directed toward the center of the circle.

_____

Additional comment

If any part of the result force is in the direction of motion, the speed will not be constant. If the center-directed force is not constant, the path will not be circular.

Explanation:

[tex]a = \frac{v - v _{i} }{t} [/tex]

Her intial velocity is 10

Her final velocity is 2

Time is 10 seconds.

[tex]a = \frac{2 - 10}{10} [/tex]

[tex]a = - \frac{4}{5} [/tex]

If potential energy is conserved or remain the same, the ball will bounce 3 m high.

The principle of conservation of energy states energy can neither be created nor destroyed  but can be converted from one form to another.

If we apply the principle of conservation of energy, the total potential energy will remain the same.

P.E(initial) = P.E(final)

Thus, If potential energy is conserved or remain the same, the ball will bounce 3 m high.

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Answer:

you will use the OTDR tool ti will very much so help

Explanation:

The amount of nutrients added to the tree subsystem in one year after leaf fall is 36 kg of nutrients.

Plants nutrients are the mineral elements required by plants for their growth and development.

Plant nutrients are mostly obtained from the soil as well as from the atmosphere.

Based on the data provided, each tree will absorb 23 - 21 Kg nutrients = 2 kg of nutrients

18 trees will absorb 18 × 2 = 36 Kg of nutrients.

Therefore, the amount of nutrients added to the tree subsystem in one year after leaf fall is 36 kg of nutrients.

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If the experiment had been repeated with frequencies 10 times lower than those in table 5.2, then Vc will increase 10 times to the values given in the table.

It is the number of oscillations per second of the sinusoidal wave.

Vc is the voltage across the capacitor and Xc is the capacitive reactance.

Xc = - 1/2πfC

where f is the frequency and C is the capacitance of the capacitor.

If the frequency is lowered, the potential difference will increase because frequency is inversely proportional to the voltage.

Thus, Vc will increase by lowering the frequency by 10 times.

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A Personality test is said to be reliable because (A). a reliable test will give consistent results over time.

Personality test can be defined as a test that can be used to verify or ascertain an individuals personality.

Personality test is a test that is carried out by different organizations to help to help them know the individuals in that organization and to help others know how to relate and work with them.

In conclusion, A Personality test is said to be reliable because a reliable test will give consistent results over time.

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Answer:

a.

Explanation:

Answer:

Explanation:

If generator really means alternator as used in cars, the following can be said:

The rotor is fed with a variable voltage ranging from 0 volt to 12 volts. The 2 brushes (fixed, not rotating, like the stator) make contact with two rings that are rotating with the rotor. The rotor acts like a fixed magnet, but the magnetic field strength is constantly updated to provide a constant output voltage, even if the load current change or the motor speed change.

The stator is basically 3 coils and 6 diodes that convert the 3 phases of AC output to an almost ripple-free DC.

Note that as more energy is extracted from the alternator (for example, adding 10 amps by turning on the headlights) the shaft resists more rotation. This can be easily tested by holding an alternator in your hand, and trying to rotate the shaft by hand with no load (rotate easily, keep rotating for a few seconds), then short-circuiting the output (much harder to rotate, stop rotating immediately). The quest for magical perpetual energy where a motor is powered by an alternator is a child's dream.

Answer:

ioinl

Explanation:

Answer:

c. a and c

Explanation:

ammeters are connected in series to measure charge/current

The kinetic energy in the first case is 4 times more than the second case.

Hence, option D)It is 4 times greater is the correct answer.

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given that;

For the first case, kinetic energy of the car will be;

K = (1/2)mv²

K = (1/2) × m × (16m/s)²

K = (1/2) × m × 256m²/s²

K = mass × 128m²/s²

For the second case, kinetic energy of the car will be;

K = (1/2)mv²

K = (1/2) × m × (8m/s)²

K = (1/2) × m × 64m²/s²

K = mass × 32m²/s²

Comparing the kinetic energy of the car with the same mass but different velocity, we can see that the kinetic energy in the first case is 4 times more than the second case.

Hence, option D)It is 4 times greater is the correct answer.

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Answer:

Wasted energy is energy that is not usefully transferred or transformed. Energy cannot be made or destroyed. Energy is transformed into a different form that can be used. When energy is transformed or transferred only part of it can be usefully transformed or transferred.

By Newton's second and third laws, we have the following net forces at

[tex]\sum F_x = -T_1 \cos(60^\circ) + T_2 \cos(60^\circ) = 0[/tex]

[tex]\sum F_y = T_1 \sin(60^\circ) + T_2 \sin(60^\circ) - 600 \,\mathrm N = 0[/tex]

Together, these equations tell us [tex]\boxed{T_1=T_2\approx 346 \,\mathrm N}[/tex].

[tex]\sum F_x = T_3 \cos(20^\circ) - T_2 \cos(60^\circ) - T_5 = 0[/tex]

[tex]\sum F_y = T_3 \sin(20^\circ) - T_2 \sin(60^\circ) = 0[/tex]

[tex]\sum F_x = -T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5 = 0[/tex]

[tex]\sum F_y = T_4 \cos(20^\circ) - T_1 \sin(60^\circ) = 0[/tex]

Combining the horizontal force equations for points B and C and using the fact that [tex]T_1=T_2[/tex] gives

[tex](T_3 \cos(20^\circ) - T_2 \cos(60^\circ) - T_5) + (-T_4  \cos(20^\circ) + T_1 \cos(60^\circ) + T_5) = 0 + 0[/tex]

[tex]\implies (T_3 - T_4) \cos(20^\circ) = 0 \implies T_3=T_4[/tex]

Then combining the vertical force equations for B and C, we find

[tex](T_3 \sin(20^\circ) - T_2 \sin(60^\circ)) + (T_4 \sin(20^\circ) - T_1 \sin(60^\circ)) = 0 + 0[/tex]

[tex]\implies 2 T_3 \sin(20^\circ) - 2 T_1 \sin(60^\circ) \implies T_3 = \dfrac{\sin(60^\circ)}{\sin(20^\circ)} T_1[/tex]

so that [tex]\boxed{T_3 = T_4 \approx 877 \,\mathrm N}[/tex]

Lastly solve for [tex]T_5[/tex] using either horizontal force equation for B or C.

[tex]-T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5 = 0[/tex]

[tex]\implies T_5 = \left(\dfrac{\sin(60^\circ)}{\sin(20^\circ)} - \cos(60^\circ)\right) T_1 \implies \boxed{T_5 \approx 651\,\mathrm N}[/tex]

Answer:

Currently 1,915

Explanation:

I don't know if this is still exactly accurate to date, but when I answered this question, an astronomer had been tracking that many constallations

Answer:

2.84 seconds

Explanation:

t = ?

distance = 125

Velocity origianal = 60 m/hr = 88 ft/s

     AVERAGE velocity = 88/2 = 44 ft/s

44 t = 125

t = 125/44 = 2.84 s

Answer:

V = λ f    (wavelength * frequency)

λ  = V / f = 343 m/s / 262 / s = 1.3 m

4.  The answer is that you will see the same sights as when you are resting.  That is because you and mirror are in rest one relative another.  If your relative speed is 0, it doesn't matter how quickly you both travel in relation to other objects.

5. The relativistic effects will not alter if the speed of light is reduced to 50m/s. According to the principle of constancy (2nd postulate), the upper limit of speed is 50m/s, which will be impossible for material objects to achieve because as the speed of light decreases, the sizes of humans and all other materials decrease as well, decreasing our relativistic velocity and thus making c=50m/s unattainable for material objects, and thus the relativistic effects will remain unchanged. A pedestrian must use caution when crossing the roadway. Let's assume you see a car arriving at 60 kilometers per hour, or 16.666 meters per second, from a distance of 100 meters. It'll take 6 seconds to arrive, giving you plenty of time to cross the street. Because the light reflected from the car to your eyes left the car two seconds ago, the car will reach at your location in four seconds and hit you (if the car is travelling in the lane on the far side of the road). It looks to you that approaching automobiles traveling at the legal limit are traveling at a speed of 100 / 4 = 25 m/s, which is 50% faster than the genuine speed of 16.666 m/s. When considering whether or not it is safe to cross the road, one would quickly become accustomed to this.

6.

The car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.

The average velocity of the car is calculated as follows;

x(t) = a + bt + ct2

v = dx/dt

v(t) = b + 2ct

v(0) = -10.1 m/s + 2(1.1)(0) = -10.1 m/s

v(10) = -10.1 + 2(1.1)(10) = 11.9 m/s

V = ¹/₂[v(0) + v(10)]

V = ¹/₂ (-10.1  + 11.9 )

V = 0.9 m/s

Thus, the car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.

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The maximum speed the car can move without skidding is determined as 28 m/s.

The maximum speed of the car moving in a circular path is provided by static frictional force.

Fs = μFₙ = mv²/r

μFₙ = mv²/r

mv² = μFₙr

v² = μFₙr/m

[tex]v_{max} = \sqrt{\frac{\mu_s F_n r}{m} } \\\\v_{max} = \sqrt{\frac{\mu_s (mg) r}{m} } \\\\v_{max} = \sqrt{\mu_sgr} \\\\v_{max} = \sqrt{(0.8)(9.8)(100)}\\\\v_{max} = 28 \ m/s[/tex]

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