A student receives a gift card and decides to purchase medium coffees on it at the same coffee shop daily until her
funds are depleted. After purchasing two coffees, her balance is $23.28 (2, 23.28). After buying five coffees, her
balance is $13.20 (5. 13.20). How many total coffees can she buy on the gift card? What was the original balance on
the gift card? Use the graph and table below to help construct a linear function representing this scenario. Type your
solutions in the text box.

Answer:

780

Step-by-step explanation:

17 is the divisor, while 2635 is the dividend. So that,

[tex]\frac{2635}{17}[/tex] = 155

The quotient = 155 = 1 hundreds, 5 tens and 5 units

Also,

2635 - 1700 = 935

Hence, let the unknown value be represented by x. Then;

935 - x

The answer of the subtraction should be equal to the quotient of the division.

935 - x = 155

935 - 155 = x

780 = x

Therefore the unknown value represented by a box is 780.

Answer:

780

Step-by-step explanation:

Answer:

900 miles it will fly in 9 hours

Step-by-step explanation:

the rate of the speed of the jet is 100 miles per hour because if the jet traveled 500 miles in 5 hours that means it's been flying at 100 miles per hour.

Answer:

your new should be c $20

The final cost is $30.

Option C is the correct  answer.

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

The original price of the coat = $50

Discount = 40%

Now,

The final cost.

= (100 - 40)% of 50

= 60% x 50

= 60/100 x 50

= $30

Thus,

The final cost is $30.

Learn more about percentages here:

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Answer: Line L : Y=4

Line P : X=-4

Line M : Y= -2x+4

Line N : Y= 1x-1

Step-by-step explanation:

Answer:

3.55 miles

Step-by-step explanation:

You add the mileage of the two trails which is 1.75+1.8=3.55 miles

Answer:

Suppose 123 people voted for Danny. If 55 of the votes were from girls, what would be the ratio of votes from girls to votes from boys? If 55 were girls then there were 123-55 = 68 boys. Thus the ratio would be 55 girls to 68 boys, or 55/68.

Answer:

60

Step-by-step explanation:

Answer:

I'm gonna say b

Step-by-step explanation:

b should be the answer

Answer:

f•g(x) = f(x)•g(x)

f•g(x) = (2x-1) (x²-2x+1)

= 2x³-4x²+2x-x²+2x-1

= 2x³-5x²+4x-1

Answer:

Number of books sold = 14.75*x

Step-by-step explanation:

Answer: The 1/10, 0.22, then 1/4.

Second Picture: 9.8, Pie^2, then 99

Answer:

The 1/10, 0.22, then 1/4.

Second Picture: 9.8, Pie^2, then 99

Answer: The answer is 11/12 problems

Step-by-step explanation:

You add 2/12 + 9/12 which gives you a result of 11/12

Answer:

= -1/14

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

    = ( -3 - -4)/( -6 -8)

   = ( -3+4)/( -6-8)

   1/-14

= -1/14

Step-by-step explanation:

LHS = (tan β + Sec β)(1 - sin β)

= ((sin β / cos β) + (1/cos β))(1-sin β)

= ((1+ sin β)*(1- sin β))/cos β

= (1 - sin^2 β) / cos β

= cos^2 β / cos β

= cos β

= RHS

Hence proved

Answer:

No value

Step-by-step explanation:

Y has zero solutions

Answer:

The probability that any given family who is selected has two or more children at home is 85%.

Step-by-step explanation:

The information provided is as follows:

Number of Children        Probability

             1                            0.15

             2                            0.65

          > 3                            0.20

Compute the probability that any given family who is selected has two or more children at home as follows:

P (At least 2 Children) = P (2 children) + P (More than 3 children)

                                   = 0.65 + 0.20

                                   = 0.85

Thus, the probability that any given family who is selected has two or more children at home is 85%.

Answer:

- Integers, b ≠ 0 and d ≠ 0.

- r - s = (ad - bc)/bd.

- products and differences of integers are integers.

-  zero product property

- quotient.

Step-by-step explanation:

Rational numbers are integers that can take the form of numerator divided by a denominator, that is to say in the form of 'a/b;. So, we are given from the question or problem to prove and fill in the gap the correct information or data:

For the first part of the question:

The missing data in the gap = Integers; b ≠ 0 and d ≠ 0. That is to say the denominators can not be zero or say that the denominators are non zero. This is one of the properties or let us say one of the ways of identifying a Rational number.

For the second part:

The missing data in the gap = a/b - c/d =  (ad - bc)/bd. This is the representation in  a simplified form.

For the third part:

The missing data or information = products and differences of integers are integers.

For the fourth part:

The missing data or information: zero product property, that is to say the product of the numerators is not equal to zero, or it is non zero.

For the fifth part:

The missing data or information: quotient.  r - s is a quotient of two integers.

Answer: 27.688

Step-by-step explanation:

The critical chi-square value [tex]\chi^2_{(df,\alpha)}[/tex] depends on significance level ([tex]\alpha[/tex])  and degrees of freedom (df) .

Given significance level: ([tex]\alpha[/tex]) = 1% = 0.01

Degrees of freedom (df)= 13

From the chi-square table, the critical chi-square value for df = 13 and [tex]\alpha =0.01[/tex]

is [tex]\chi^2_{(df,\alpha)}=27.688[/tex]

Hence, the  required critical value = 27.688

Answer:

balance $4

Step-by-step explanation:

12 - 8 = 4

Answer:

$4

Step-by-step explanation:

$ = 12 - 8

12 - 8 = $4

Answer:

i didn't understand in third line mate

Answer:

The answer is "[tex]\bold{\frac{1024}{3}}[/tex]".

Step-by-step explanation:

[tex]= \int\limits^{4}_{-4} \int\limits^{4}_{0} \int\limits^{16}_{x^2} dy\ dx \ dz \\\\= 2 \int\limits^{4}_{0} \int\limits^{4}_{0} \int\limits^{16}_{x^2} dy\ dx \ dz \\\\ = 2 \int\limits^{4}_{0} \int\limits^{4}_{0} (16-x^2) dx \ dz \\\\= 2 \int\limits^{4}_{0} \int\limits^{4}_{0} 16x -\frac{x^3}{3} dx \ dz \\\\= 2 (16x -\frac{x^3}{3})^4_{0} \ dz \\\\= 2 (4) (16x -\frac{64}{3}) \\\\=8(\frac{2}{3} \times 64) \\\\=(\frac{16\times 64}{3} ) \\\\= \frac{1024}{3}[/tex]

The volume of the given solid is [tex]\frac{1024}{3}[/tex] cubic units.

In this question we must use the triple integral formula in rectangular coordinates to determine the volume of the solid ([tex]V[/tex]):

[tex]V = \iiint dy\,dx\,dz[/tex] (1)

The solid is constrained by the following intervals:

[tex]y \in [x^{2}, 16][/tex], [tex]x \in [-4, 4][/tex], [tex]z\in [0, 4][/tex]

Then, the triple integral is now described:

[tex]V = \int\limits_{0}^{4}\int\limits_{-4}^{4}\int\limits_{x^{2}}^{16} dy\,dx\,dz[/tex]

Now we proceed to integrate thrice to obtain the volume:

[tex]V = \int \limits_{0}^{4}\int \limits_{-4}^{4} (16-x^{2})\,dx\,dz[/tex]

[tex]V = \int\limits_{0}^{4} \left(16\cdot x - \frac{x^{3}}{3}\right)\left|\limits_{-4}^{4} dz[/tex]

[tex]V = \frac{256}{3} \int\limits_{0}^{4} dz = \frac{1024}{3}[/tex]

The volume of the given solid is [tex]\frac{1024}{3}[/tex] cubic units.

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Answer:

No, your classmate is not correct because the line isn't a line segment but a line and a line is never ending so their isn't a middle and their can't be those angles.

Answer:

Since they are vertical angles (or angles opposite each other), you set them equal to each other.

5x + 4 = 74

5x = 70

x = 15

Answer:

640 & 400

Step-by-step explanation:

Cost of books: x and 1040-x

x sold at a loss of 15%= .85 x

1040 - x sold at a profit of 36% = (1040 - x) *1.36

x*.85= (1040-x)*1.36

0.85x+1.36x= 1040*1.36

2.21x= 1414.4

x= 1414.4/ 2.21

x= Rs. 640

Rs. 1040 - 640 = 400

Answer:

The probability is   [tex]P(X  >300 ) = 0.97219 [/tex]

Step-by-step explanation:

From the question we are told that

 The capacity of  an Airliner  is  k =  300 passengers

 The sample size n =  320 passengers

  The probability the a randomly selected passenger shows up on to the airport

    [tex]p = 0.96[/tex]

Generally the mean is mathematically represented as

    [tex]\mu  =  n*  p[/tex]

  => [tex]\mu  =  320 *  0.96[/tex]

    => [tex]\mu  = 307.2[/tex]

Generally the standard deviation is  

    [tex]\sigma =  \sqrt{n *  p *  (1 -p ) }[/tex]

=>  [tex]\sigma =  \sqrt{320  *  0.96 *  (1 -0.96 ) }[/tex]

=> [tex]\sigma =3.50 [/tex]

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

  [tex]P(X  > k ) =  P( \frac{ X -\mu }{\sigma }  >  \frac{k - \mu}{\sigma } )[/tex]

Here [tex]\frac{ X -\mu }{\sigma }  =Z (The \ standardized \  value \  of  \ X )[/tex]

=>[tex]P(X  >300 ) =  P(Z >  \frac{300 - 307.2}{3.50} )[/tex]

Now applying  continuity correction we have

    [tex]P(X  >300 ) =  P(Z >  \frac{[300+0.5] - 307.2}{3.50} )[/tex]    

=>    [tex]P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )[/tex]

=>    [tex]P(X  >300 ) =  P(Z >  -1.914 )[/tex]

From the z-table  

    [tex]P(Z >  -1.914 ) =  0.97219[/tex]

So

    [tex]P(X  >300 ) = 0.97219 [/tex]

Answer: Suppose that [tex]S_{n}[/tex],  [tex]K_{n}[/tex] and [tex]A_{n}[/tex] are all sequences, also suppose that  [tex]A_{n}[/tex] ⊂ [tex]K_{n}[/tex] ⊂ [tex]S_{n}[/tex]  ∀ [tex]n[/tex] ∈ [tex]Z^{+}[/tex]. This implies that [tex]A_{n}[/tex] ⊂ [tex]S_{n}[/tex] as required. 

Step-by-step explanation:

If you suppose that [tex]S_{n}[/tex],  [tex]K_{n}[/tex] and [tex]A_{n}[/tex]  are all representing three sequences respectively, and you also suppose that  [tex]A_{n}[/tex] is a subset (in other words subsequence) of [tex]K_{n}[/tex] and [tex]K_{n}[/tex]  is a subset (in other words subsequence) of [tex]S_{n}[/tex], where n takes its values from the set of positive integers. We can safely say that [tex]A_{n}[/tex] is a subsequence of [tex]S_{n}[/tex] and this can demosnstrated mathematically as follows:

Suppose that [tex]S_{n}[/tex],  [tex]K_{n}[/tex] and [tex]A_{n}[/tex] are all sequences, also suppose that  [tex]A_{n}[/tex] ⊂ [tex]K_{n}[/tex] ⊂ [tex]S_{n}[/tex]  ∀ [tex]n[/tex] ∈ [tex]Z^{+}[/tex]. This implies that [tex]A_{n}[/tex] ⊂ [tex]S_{n}[/tex] as required.