A stone of mass m = 1.05 kg is released from a height of h = 2.1 m into a pool of water. At a time of t = 1.83 s after hitting the surface of the water, the stone's velocity has decreased by 50%.
What is the magnitude of the average force the stone experiences, in newtons, during the time t?

Answers

Answer 1

Answer:

Explanation:

ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted

½mv² = mgh

v = √(2gh)

v = √(2(9.81)2.1) = 6.4188... m/s

after impact, an impulse will result in a change of momentum.

There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.

FΔt = mΔv

(F - mg)Δt = m(vf - vi)

(F - mg) = m(vf - vi)/Δt

F = m(vf - vi)/Δt + mg

F = m((vf - vi)/Δt + g)

F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)

F = 12.14198...

F = 12.1 N

Answer 2

The magnitude of the average force the stone experiences, will be 12.1 N.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem is;

m is the stone mass = 1.05 kg

The height is h, = 2.1 m i

The time is, t = 1.83 s

Velocity decreased by 50%.

From the law of conservation of energy the kinetic energy is equal to the potential energy;

[tex]\rm \frac{1}{2} mv^2 = mgh \\\\ v = \sqrt{2gh}\\\\ v = \sqrt{2 \times 9.81 \times 2.1 } \\\\ v= 64188 \ m/sec.[/tex]

From Newton's second law of motion, the impulsive force is equal to the change in momentum;

[tex]\rm F \triangle T = m \traingle v \\\\ (F - mg) = \frac{v_f-v_i}{\triangle t } \\\\ F = \frac{v_f-v_i}{\triangle t } + mg \\\\ F =m\frac{v_f-v_i}{\triangle t + g} \\\\ F= 12.14 98 \\\\ F=12.1 N[/tex]

Hence the magnitude of the average force the stone experiences, will be 12.1 N.

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Related Questions

Wtz the answer to this question? I need to get it right

Answers

Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?


A 25.0kg boy is sliding on a frictionless frozen lake at 5.00m/s to the north when he is struck by a 1.00kg
snowball moving at 15.0m/s from the west. If the snowball sticks to him, how fast, and in what direction,
does the boy move after the collision?

Answers

The final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

The given parameters;

Mass of the boy, m₁ = 25 kgSpeed of the boy, u₁ = 5 m/sMass of the snowball, m₂ = 1.0 kgSpeed of the snow ball, u₂ = 15 m/s

The initial momentum of the boy is calculated as follows;

[tex]P_y = m_1 u_1\\\\P_y = 25 \times 5\\\\P_y = 125 \ kgm/s \ \ north[/tex]

The initial momentum of the snowball is calculated as follows;

[tex]P_x = m_2 u_2\\\\P_x = 1 \times 15 \ \\\\P_x = 15 \ kgm/s \ \ west[/tex]

The resultant momentum of the boy and the snowball after collision is calculate as follows;

[tex]P_f = \sqrt{P_y^2 + P_x^2} \\\\P_f = \sqrt{125^2 + 15^2} \\\\P_f = 125 .9 \ kgm/s[/tex]

The final velocity of the system boy-snowball system is calculated as;

[tex]v_f(m_1 + m_2)= P_f\\\\v_f = \frac{P_f}{m_1 + m_2} \\\\v_f = \frac{125.9}{25 + 1} \\\\v_f = 4.84 \ m/s[/tex]

The direction of the boy after the collision is calculated as follows;

[tex]\theta = tan^{-1}(\frac{v_y}{v_x} )\\\\\theta = tan^{-1} (\frac{5}{15} )\\\\\theta = 18.4 \ ^0[/tex]

Thus, the final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

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Define faith in your own words.

Answers

Answer:

Faith, to me is almost like hope but for faith you need to believe. Some people associate the word faith with religion. But that's not it. Faith is really just a stronger term than believing someone. Like you can believe in someone but not have faith in that same person. You can have faith in someone but to do that you have to believe and trust them.

Explanation:

Zoe is setting up a track for a toy car. The track has a ramp that is 32° above horizontal. If Zoe wants the car to travel as a projectile for 1.0 seconds, how fast does the toy car need to be moving as it leaves the ramp?
4.9 m/s
1.0 m/s
9.2 m/s
7.4 m/s m

Answers

Answer:

Explanation:

Not enough information.

IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.

THEN

The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was

v = gt

vy₀ = 9.8(0.5)

vy₀ = 4.9 m/s

vsinθ = vy₀

v = vy₀/sinθ

v = 4.9/sin32

v = 9.2466...

v = 9.2 m/s

) Water flows through the system shown below. Estimate the volumetric flow rate if friction
losses are negligible.

Answers

The volumetric flow rate if friction is negligible = 0.00197 m³/sec

Given data :

P₁ = 7 atm  =  709.275 kPa

P₂ = 1.5 atm = 151.988 kPa

d₁  = 0.74 cm = 0.0074 m

d₂ = 1.20 cm  = 0.0120 m

h = 82 m

density of water ( p ) = 1000 kJ/m³

Estimate the volumetric flow rate

given that friction losses are negligible

V₁² - V₂² = [tex]\frac{2(P_{2} - P_{1}) }{p} + 2g(h )[/tex]

             = 2( 151.988 - 709.275 )  + 2 * 9.81 * 82

             = 2 ( - 557.287 ) + 1608.84

             = - 1114.574 + 1608.84  =  494.266

V₁² - V₂² =  494.266 ----- ( 1 )

Also given that:

volumetric flow rate ( Q ) = A₁V₁ = A₂V₂

                                          = π / 4 ( 0.0074 )² * V₁   =   π / 4 ( 0.0120 )² * V₂

                                          = 0.000043 V₁ = 0.000113 V₂

∴ V₁ = 2.63 V₂

Back to equation ( 1 )

( 2.63 v₂ )² - V₂² = 494.266

V₂² = ( 494.266 ) / 1.63

∴ V₂ = √303.23 = 17.41  m/sec

Therefore the volumetric flow rate ( Q )

Q = A₂V₂

   =  π / 4  * ( 0.0120 )² * 17.41

   = 0.00197 m³/sec

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Hey guys can you help me with this problem it's giving me a headache. "If 2500 kg roller coaster car begins its descent from 500m above above the first hill. What is its kinetic energy at the bottom of the hill."

Answers

The kinetic energy of the roller coaster at the bottom of the hill is 12250000 J

To answer this question, we must understand that the energy of a system is always conserved as explained by the law of conservation of energy.

The kinetic energy of the roller coaster will be equivalent to the potential energy of the roller coaster.

The kinetic energy of the roller coaster can be obtained as follow:

Mass (m) = 2500 KgHeight (h) = 500 mAcceleration due to gravity (g) = 9.8 m/s²Kinetic energy (KE) =?

Kinetic energy = Potential energy

KE = mgh

KE = 2500 × 9.8 × 500

KE = 12250000 J

Therefore, the kinetic energy of the roller coaster is 12250000 J

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According to Hebrews 11, what did Abraham believe God would do if Isaac was slain as a sacrifice?

Answers

Answer:

That he would be happy,for he had ordered him to be sacrificed

2. Define Lightning conductor. How does it work?

Answers

In Building, there are a host of protective devices that are installed to protect lives and properties, one of them is the Lightning Conductor that  a metal rod mounted on a structure and intended to protect the structure from a lightning strike. It works on the principle of induction

Principle of Operation of Lightning Conductor

The lightning conductor works on the principle of induction:

When a charged cloud passes by the building hosting the Lightning conductor, it gets a charge opposite to that of the cloud through the process of induction. They are Typically made from copper material.

Most Lightening conductors are made from copper materials.

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Please answer the question in the picture

Answers

To me I would most think the answer is A.
PLEASE GIVE BRAINLIEST!!!


The potential at point P is the work required to bring a one-coulomb test charge from far
away to the point P?

True or false ?

Answers

true so true Its so true

Use words in the box to complete the diagram, and the definitions below it. Some words will be used
more than once and some words may not be used at all
Hertz
period
metros
dip
seconds
peak
wavelength trough
crest
frequency
amplitudo
oscillation equilibrium line
- the top of a wave
the bottom of a wave
the level if the wave flattened out
a repeated action back and forth or up and down
the number of waves that pass every second (measured in
the time it takes for one complete wave to pass (measured in

Answers

Answer:

There ya go

Explanation:

The correct words to fill the given blanks would be as follows:

- Peak

- Trough

- Equilibrium Line

- Oscillation

- Frequency, Hertz

- Period, seconds

The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave. The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.Oscillation is defined as the process in which an object moves in the "back and forth motion."Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.Amplitude is the breadth or magnitude of the waves.

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7. Cellular respiration that uses oxygen is called ​

Answers

Answer:

Cellular respiration that uses oxygen is called ​Cellular respiration

Explanation:

Without oxygen, it's call fermentation.

Select the correct answer.
What is the force that can cause two pieces of iron to attract each other?
A.
gravitational force
B.
magnetic force
C.
elastic force
D.
electrostatic force

Answers

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

ur mom walked into a store and got milk

Answers

Answer:

is there any questions

Answer:

What is your question???

Explanation:

An object falls through the air, gaining speed as it falls. A student claims th
new energy, and so it breaks the law of conservation of energy. Which stat
why the student is incorrect? (1 point)
Energy can be created without breaking the law of conservation
Energy is converted from other forms, not created.
O Equal and opposite amounts of other energy are also created.
O Speed is not related to energy in any way.

Answers

Answer:

Energy is converted from other forms, not created

Explanation:

The ball has a decrease in potential energy which allows the kinetic energy, and therefore speed, to  increase

an electron moves in a circular path in a region os space filled with a uniform magnetic field B= 0.4 T. to double the radius of the electron’s path, the magnitude of the magnetic field must become:

a. 0.8 T
b. 0.2 T
c. 0.1 T
d. 0.3 T
e. zero

Answers

Answer:

[tex]0.2\; {\rm T}[/tex], assuming that the speed of the electron stays the same.

Explanation:

Let [tex]v[/tex] denote the speed of this electron. Let [tex]q[/tex] denote the electric charge on this electron. Let [tex]m[/tex] denote the mass of this electron.

Since the path of this electron is a circle (not a helix,) this path would be in a plane normal to the magnetic field.

Let [tex]B[/tex] denote the strength of this magnetic field. The size of the magnetic force on this electron would be:

[tex]F = q\, v\, B[/tex].

Assuming that there is no other force on this electron. The net force on this electron would be [tex]F = q\, v\, B[/tex]. By Newton's Second Law of motion, the acceleration of this electron would be:

[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{q\, v\, B}{m}\end{aligned}[/tex].

On the other hand, since this electron is in a circular motion with a constant speed:

[tex]\begin{aligned} a = \frac{v^{2}}{r} \end{aligned}[/tex].

Combine the two equations to obtain a relationship between [tex]r[/tex] (radius of the path of the electron) and [tex]B[/tex] (strength of the magnetic field:)

[tex]\begin{aligned}\frac{q\, v\, B}{m} = \frac{v^{2}}{r}\end{aligned}[/tex].

Simplify to obtain:

[tex]\begin{aligned}r &= \frac{m\, v^{2}}{q\, v\, B} \\ &= \frac{m\, v}{q\, B} \\ &= \left(\frac{m\, v}{q}\right)\, \frac{1}{B}\end{aligned}[/tex].

In other words, if the speed [tex]v[/tex] of this electron stays the same, the radius [tex]r[/tex] of the path of this electron would be inversely proportional to the strength [tex]B[/tex] of the magnetic field. Doubling the radius of this path would require halving the strength of the magnetic field (to [tex]0.2\; {\rm T}[/tex].)

A train travels at 40m/s. Calculate the time it takes to travel:
A) 30,000 m
B) 50 km

Answers

Answer:

a is 750 second

b is 2 hour

The time it takes for the train to travel 30,000m and 50,000m is 750seconds and 1250 seconds, respectively.

What is speed?

The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.

[tex]\rm{Speed = \dfrac{Distance}{Time}[/tex]

A train travels at 40m/s. Now, the time it takes to travel the given distance is,

A.) 30,000m

Speed = Distance / Time

Time = Distance / Speed

Time = 30,000m / 40m/s

Time = 750 seconds

B.) 50 km

1 km = 1000m

50 km = 50 × 1000m = 50,000 m

Speed = Distance / Time

Time = Distance / Speed

Time = 50,000m / 40m/s

Time = 1250 seconds

Hence, the time it takes for the train to travel 30,000m and 50,000m is 750seconds and 1250 seconds, respectively.

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How long does it take the second hand of a clock to move through 3.57 rad?
Answer in units of s.

Answers

Answer:

Its angular velocity is  

π

30

radians per second (about 0.105 radians/s.

Explanation:

Explanation:

Think of it like this:

There are  

2

π

radians in one complete rotation, and that takes the second hand 60 seconds to complete.

So, the rate of rotation (the angular velocity) is

2

π

/60 = pi/30 radians per second# which is about 0.105 radians per second.

To solve the problem we will first calculate the time taken by the second arm to travel 1 rad.

Time taken by the second arm to travel 1 rad

We know that the arm of the second travels 2π radians in 60 seconds. therefore, the time is taken to travel 1 rad by the second arm,

[tex]1\rm\ rad = \dfrac{60}{2\pi}[/tex]

Time taken by the second arm to travel 3.57 rad

Time taken by the second arm to travel 3.57 rad

[tex]=3.57\times \dfrac{60}{2\pi}\\\\= 34.09\rm\ sec[/tex]

Hence, the time taken by the second arm to travel 3.57 rad is 34.09 sec.

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If a wave is traveling at a constant speed, and the frequency decreases, what would happen to the wavelength?

A. It would increase.

B. It would decrease.

C. It would remain constant.

D. It would drop to zero.

Answers

It would decrease because the frequency is decreasing

what are the applications of triangle law of forces​

Answers

Answer:

The triangle law of forces can also be stated as. if a body is in equilibrium under the action of three forces acting at a point, then the three forces can be completely represented by the three sides of a triangle taken in order. A body might be subjected to further than one force at a similar time.

Explanation:

Hope it's help

what is the speed of a boy moving around a circular park of radius 6m if he goes around the park in 20s

Answers

Answer:

1.884 meters per second

Explanation:

s = d/t

d = C = 2πr = 2π(6) = 37.68 m

t = 20 s

s = (37.68 m)/(20 s)

s = 1.884 m/s

The speed of the boy is 1.88 m/s while he is moving around a circular park of radius 6m and taking time 20 seconds.

What is speed?

Speed can be defined as a measurement of how quickly the distance an object traveled changes with time. Speed is a scalar quantity as it has magnitude but no direction as a unit of measurement.

An object that moves quickly and with high speed, traveling a lot of ground in a lesser time.

Given, the radius of the circular park, r = 6m,

The time taken to cover one round of the park, t = 20 s

The total distance traveled by the boy is equal to the circumference of the circular park, so

Circumference of park, C = d = 2πr = 2× 3.14 × 6 =37.68 m

The speed of the boy, S = d/t

S = 37.68 /20

S = 1.88 m/s

Therefore, the speed of the boy is equal to 1.88 m/s.

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What net force acting on a 6 kg car produces an acceleration of 6 m/s2?

Answers

Explanation:

Mass (m) = 6 kgAcceleration (a) = 6 m/s²Force (F) = ?

We know that,

• F = ma

→ F = (6 × 6) N

F = 36 N

Therefore, the net force is 36N.

1. A 1.30 kg ball strikes a wall with a velocity of -10.5 m/s. The ball bounces off with a velocity of 6.50 m/s. If the ball is in contact with the wall for 0.0210 seconds, what is the force exerted
on the ball by the wall?
O 1050 N
22.1 N
0 402 N
0 651 N
CAN SOMEONE PLS PLS ACTUALLY HELP ME

Answers

Let F be the magnitude of the force. The impulse of this force while the ball is in contact with the wall is

Ft = F (0.0210 s)

and this impulse is equal to the change in the ball's momentum,

m ∆v = (1.30 kg) (6.50 m/s - (-10.5 m/s)) = (1.30 kg) (17.0 m/s)

Solve for F :

F (0.0210 s) = (1.30 kg) (17.0 m/s)

F = (1.30 kg) (17.0 m/s) / (0.0210 s)

F ≈ 1050 N

Do you think the rider in the above figure is really in danger? What If people below were removed?

Answers

The rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium.

A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.

For a system subject to two opposite forces, the following exists;

If the upward force and the downward forces are equal, the system will remain in equilibrium positionIf the upward or downward force is greater than the other, the system will move in the direction of the greater force.

Thus, we can conclude that the rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.

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What can happen when untreated sewage water contaminates water?

Answers

Answer:

Health Effects

Life-threatening human pathogens carried by sewage include cholera, typhoid and dysentery. Other diseases resulting from sewage contamination of water include schistosomiasis, hepatitis A, intestinal nematode infections, and numerous others.

Explanation:

BRAINLIEST PLEASE • •

︴︴

____

Physical Science A 2021-2022
Why does increasing the number of trials increase confidence in the results of the experiment?

Answers

Answer:

Increasing the number of trials reduces the impact of any one imprecise measurement. … To increase the number of attempts, you can find an average result for the experiment, as well as find and discrepancies as human error if you perform an experiment several times.

Explanation:

hope it helps :)

Answer:

It is because the increase in the number of trials reduces the impact of any one imprecise measurement. Using an average value for data points provides a better representation of the true value.

What is an element?
1. A substance made of more than one type of atom.
2. A substance that is made of water.
3. A substance that is made of no atoms.
4. A substance made of only one type of atom.

Answers

Answer:

Hey Friend...

Explanation:

This is ur answer.....

4. A substance made of only one type of atom.

Hope it helps!

Brainliest pls!

Follow me! :)

Answer:

4

Explanation:

element is a substance that cannot be broken down into any other substance which means every element is made up of its own type of atom

a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v​

Answers

Here

Acceleration and initial velocities are constant.

According to first equation of kinematics.

[tex]\\ \sf\longmapsto v=u+at[/tex]

[tex]\\ \sf\longmapsto v=0+at[/tex]

[tex]\\ \sf\longmapsto v=at[/tex]

[tex]\\ \sf\longmapsto v\propto t[/tex]

Time was t at velocity vTime will be 4t at velocity 4v

A moving car initially has kinetic energy K. The car then moves in the opposite direction with four times its initial speed. What is the kinetic energy now

Answers

If initial speed was v, Kinetic energy was K = 1/2mv^2

When speed will be 4v, KE will be:

= 1/2 m (4v)^2

=1/2m 16 v^2

=16K

Now kinetic energy will become 16 times of initial Kinetic Energy

How far has a 15 kg object moved, when a force of 22 N is applied for 5 seconds if it started at 3 m/s?

Answers

First start by finding the acceleration experienced by the force. Then use the acceleration and a suvat equation to solve for distance.
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