A spherical glass ornament is 6 cm in diameter. If an object is placed 10.5 cm away from the ornament, where will its image form? What is the magnification?

Answers

Answer 1

The magnification is mathematically given as

M= 0.125

Lens magnification

Question Parameters:

A spherical glass ornament is 6 cm in diameter.

If an object is placed 10.5 cm away from the ornament, where will its image form

Generally, the mirror equation for ornament  is mathematically given as\

1/q = 2 / r - 1/p

Therefore

1/q = 2 / (-3 cm) - 1/(10.5 cm)

q = -1.31 cm

Therefore, the magnification

M = -q/p

M= -(-1.31 m)/ (10.5 cm)

M= 0.125

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Related Questions

A car that weighs 40,000 N is driving down a hill at a constant velocity. If the car’s momentum is 80,000 kg∙m/s, how fast is the car moving?

Answers

The velocity of the car is equal to 20 m/s.

Given the following data:

Weight of car = 40,000 Newton.Car’s momentum = 80,000 kg∙m/s.

Scientific data:

Acceleration due to gravity = 10 [tex]m/s^2[/tex].

To determine the velocity of the car:

How to determine the car's velocity.

First of all, we would calculate the mass of the car by using this formula:

[tex]Weight = mg\\\\40000=m \times 10\\\\m=\frac{40000}{10}[/tex]

Mass, m = 4,000 kg.

For the velocity:

Mathematically, momentum is giving by this formula;

[tex]Momentum = mass \times velocity[/tex]

Making velocity the subject of formula, we have:

[tex]Velocity = \frac{Momentum}{Mass}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Velocity = \frac{80000}{4000}[/tex]

Velocity = 20 m/s.

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If thermal energy is added to a liquid, what is the most likely thing that will happen to the substance?

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Explanation:

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Answers

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Explanation:

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Answer:

Explanation:

Solution,

Distance(d)=60m

Time(t)=5sec

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Which wire has the most total charge carriers flowing past a point in the wire during the specified time interval

Answers

The wire 2 has the most charge flowing in it at the given time interval.

Charge flowing in each wire

The total charge flowing in each wire is calculated using the following equation;

Q = It

where;

I is the currentt is the time of current flow

Charge in wire 1

The charge flowing in wire 1 is calculated as follows;

Q = 1 x 60 = 60 C

Charge in wire 2

The charge flowing in wire 2 is calculated as follows;

Q = 2 x 45 = 90 C

Charge in wire 3

The charge flowing in wire 3 is calculated as follows;

Q = 3 x 10 = 30 C

Thus, the wire 2 has the most charge flowing in it at the given time interval.

The complete question is below

The current across three identical current carrying wires is measured during a certain time interval. The reading is reported in the table

        Current (A)        Time Interval (S)

Wire 1          1                  60

Wire 2         2                 45

Wire 3         3                  10

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Explanation:

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Answer:

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[tex]kai6417[/tex]

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Answers

Answer:

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Answers

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Answers

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