A speed skater just finished a race. After she crossed the finish line, she coasted to a complete stop. If her initial speed was 13.0 m/s and her acceleration was -2.9 m/s2, how long did it take her to stop?

Answers

Answer 1

Answer:

5seconds

Explanation:

because she was going through the same time


Related Questions

3) A square coil of sides 0.40 m carries a current of 3.0 A in a uniform magnetic field of 5.0 mT. the plane of the coil is parallel to the magnetic field as shown in figure below.

a) Calculate the force on each side of the coil.
b) What is the resultant effect of the force on the coil?
c) What happen to the coil?

Answers

It’s B I took the assignment and passed

Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
meters/second?

Answers

To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.

Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: [tex]\frac{∆v}{t}[/tex]

If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 [tex]\frac{feet}{second}[/tex] then sped up to 5 [tex]\frac{feet}{second}[/tex], then the change in my speed would be 2 [tex]\frac{feet}{second}[/tex], because I started walking 2 [tex]\frac{feet}{second}[/tex] faster!

Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 [tex]\frac{meters}{second}[/tex] to 16 [tex]\frac{meters}{second}[/tex]  in 4 seconds. What would the acceleration be? Let's set up an equation:

a = [tex]\frac{∆v}{t}[/tex]

a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.

Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 [tex]\frac{meters}{second}[/tex] by 4 [tex]\frac{meters}{second}[/tex]. That makes sense, right? Back to the equation.

a = [tex]\frac{∆v}{t}[/tex]
a = [tex]\frac{16-4}{4}[/tex]

(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)

a = [tex]\frac{12}{4}[/tex]

a = 3 ([tex]\frac{meters}{second^{2}}[/tex])

We have our answer! The car's acceleration is 3 meters per second^{2}.

(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit [tex]\frac{\frac{meters}{second}}{second}[/tex], which can be simplified down to [tex]\frac{meters}{second^{2} }[/tex])

Let me know if you need clarification on anything I explained here!
- breezyツ

A 200g ball is accelerated from 5m/s to 25m/s in 0.3sec. What force was applied?​

Answers

Answer:

30N

Explanation:

30N of force was applied

quizlet

Two dwarf galaxies revolve in circles around a normal large galaxy. Dwarf Galaxy A is 70,000 light years away from the large galaxy, and Dwarf Galaxy B is 500,000 ly away from the large galaxy. Which of the two galaxies, A or B, takes the longest time to orbit the large galaxy and what law tell us so

Answers

Answer:

B

Explanation:

From Kepler's Third Law, T^2 is proportional to r^3.

Now r of B is larger than r of A,

so T of B is larger than T of A.

Then B takes the longest time.

Dwarf Galaxy B takes the longest time to orbit the large galaxy. This can be explained using Kepler's Third Law of Planetary Motion, also known as the Law of Periods.

Kepler's Third Law states that the square of the orbital period (T) of a celestial body is directly proportional to the cube of the semi-major axis (a) of its elliptical orbit. Mathematically, it can be expressed as:

[tex]\[ T^2 \propto a^3 \][/tex]

Where:

T is the orbital period (time taken for one complete orbit), and

a is the semi-major axis of the elliptical orbit.

In the case of dwarf galaxies A and B revolving around the large galaxy, we can use the distances from the large galaxy to each of the dwarf galaxies as the semi-major axes (a) of their orbits.

Let's compare the values of [tex]\( a^3 \)[/tex] for the two dwarf galaxies:

For Dwarf Galaxy A:

[tex]\( a_{\text{A}} = 70,000 \)[/tex] light years

For Dwarf Galaxy B:

[tex]\( a_{\text{B}} = 500,000 \)[/tex] light years

Now, let's calculate [tex]\( a^3 \)[/tex] for each galaxy:

For Dwarf Galaxy A:

[tex]\( a_{\text{A}}^3 = (70,000)^3 = 343,000,000,000 \)[/tex] cubic light years

For Dwarf Galaxy B:

[tex]\( a_{\text{B}}^3 = (500,000)^3 = 125,000,000,000,000,000 \)[/tex] cubic light years

Since [tex]\( a_{\text{B}}^3 \)[/tex] is significantly larger than [tex]\( a_{\text{A}}^3 \)[/tex], it means that Dwarf Galaxy B has a larger a value and therefore a longer orbital period according to Kepler's Third Law. In other words, Dwarf Galaxy B takes the longest time to orbit the large galaxy.

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Peak expiratory flow readings are Higher in the morning; lower in the evening Lower when patients are well; higher when patient's airway is constricted Lower in the morning; higher in the evening Higher when patients are well; lower when patient's airway is constricted

Answers

Peak expiratory flow readings are higher when patients are well, but lower when a  patient's airway is constricted.

What is the peak expiratory flow?

This term is used in medicine to refer to the maximum rate of a person's exhalation or to how fast and how long can they exhale.

This rate is measured by using the peak expiratory flow test that requires you to deeply inhale and then exhale as fast as hard as possible.

What does the peak expiratory flow indicate?

This rate is closely related to the amount of air flowing out of the lungs. This implies the peak expiratory flow is lower if there is a disease such as asthma that can constrict the airways.

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i’m kinda stuck right now…

Answers

This is easy
Number 2 is 20 N to the right
Number 3 is 30 N up
Both are unbalanced

If you increase your speed from 10 mph to 30 mph, how much will your stopping distance increase?

Answers

When you double the speed of your car, your braking distance quadruples. every time you double your speed, you multiply your braking distance by four.

The stopping distance of a vehicle is the sum of breaking distance and thinking distance. The stopping distance of a vehicle when we increase the velocity from 10mph to 30 mph, increases from30 feet to 90 feet.

What is stopping distance?

Stopping distance is the distance covered by a vehicle when we stops. Distance is the product of time and velocity. As the velocity increases then, the time taken to cover the distance will be lower.

Stopping distance mathematically is the sum of breaking distance and thinking distance .Thinking distance is simply the speed and it is in fact means how long it takes on average to think for a break.

Breaking distance is means how long the driver takes to break or stop in actual. In general, the breaking distance is speed multiplied by 2.

Thus, for 10 mph, the thinking distance is 10 feet and breaking distance is 10 × 2 = 20 feet and therefore, the stopping distance is 10 + 20 =30 feet.

Similarly for 30 mph, breaking distance is 60 feet and thinking distance is 30 feet thus, having 60 + 30 = 90 feet of stopping distance.

Therefore, when the speed increased from 10 mph to 30 mph, stopping distance increases from 30 feet to 90 feet.

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pysics question can anyone answer me this question ​

Answers

Answer:

Im pretty sure they're equal, i could be wrong though. Hope i helped have an amazing day :D

Explanation:

Answer:

B: equal

Explanation:

What is the acceleration of the object?

Answers

30 because v1 - v2 is 30 v1 is 40 v2 is 10

the nuclues of an atom contains which subatomic particles

Answers

Protons and neutrons. Explanation:
Protons are massive, positively charged
nuclear particles.

Why do charged particles interact with each other?(1 point)

because they are small
because they are small

because they are in the same molecule
because they are in the same molecule

because of their electric and magnetic fields
because of their electric and magnetic fields

because they have opposite charges

Answers

Answer:

because they have opposite charges

Explanation:

If you're talking about magnetism and electricity, the laws are that like charges attact and and unlike charges repel.

Charged particles interact with each other because they have opposite charges.

How charged particles interact with each other?

When charged particles are close to each other, their electric fields interact. So particles with opposite charges attract each other whereas particles with similar charges repel each other.

So we can conclude that Charged particles interact with each other because they have opposite charges.

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3. A wooden block is at rest on a wooden inclined
plane. As the angle the plane makes with the
horizontal is increased, the magnitude of the
force of static friction between the block and
the plane
(1) decreases
(2) increases
(3) remains the same

Answers

As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

Static frictional force

Since the static frictional force between the block and the plane is given by F = μN where

μ = coefficient of static friction and N = normal force on plane = component of weight of block perpendicular to the plane = Wcosθ where W = weight of block and θ = angle of inclined plane

Now, F = μN

F = μWcosθ

Since μ and W are constant, we see that

F ∝ cosθ and cosθ ∝ θ

So, F ∝ θ

Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.

So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases

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The period of a .75 m pendulum is _s

Answers

Hi there!

We can use the following equation for the period of a pendulum:

[tex]\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}[/tex]

T = Period (s)
L = length of simple pendulum (.75 m)

g = acceleration due to gravity (9.8 m/s²)

Plug in the values:

[tex]T = 2\pi \sqrt{\frac{.75}{9.8}} = \boxed{1.738 s}[/tex]

What is the speed of the plane wave defined by sin(ωt−kx) with ω=3376.7 Thz and k=11.79μm−1?

Answers

The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s

Speed of a wave

the speed of the plane wave defined by sin(ωt−kx) is v = ω/k where

ω = angular frequency of wave and k = wave number of wave

Now ω = 3376.7 Thz = 3376.7 × 10¹² Hz and k = 11.79μm⁻¹ = 11.79 × 10⁶ m⁻¹

So, substituting the values of the variables into v, we have

v = ω/k

v = 3376.7 × 10¹² Hz/11.79 × 10⁶ m⁻¹

v = 286.4 × 10⁶ m/s

v = 2.864 × 10⁸ m/s

The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s

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If each pull-up requires 300 J and Ben does a pull-up in 2 seconds, what is his power? 150 watts 300 watts 600 watts 750 watts

Answers

Answer:

150 watts

Explanation:

300/2 = 150 watts

Answer:

150 watts

Explanation:

The explanation is in the picture

PLEASE MARK BRAINLIEST

compare your previous result to the present hrf result are there any changes if yes explain your answer​

Answers

Answer:

I don't know what are you saying but I don't have any results

Explanation:

[tex]kai6417[/tex]

How much work is done on a small car if 4250 N force is exerted to move it 83.5 m to the side of the road?

Answers

Answer:

354875 J

Explanation:

The equation for Work is:

[tex]Work=Force*Distance[/tex]

We can plug in the given values into the equation:

[tex]Work=4250N*83.5m=354875J[/tex]

A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.

d. At what angle do the cars move after the collision? (2 points)

Answers

Given :-

A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.

To Find :-

At what angle do the cars move after the collision?

Solution :-

Here it's given that a car of mass 1000kg moving with velocity of 25m/s North . Another car of mass 1200kg is moving with velocity 30m/s East.

So that ,

[tex]v_{1}= 25m/s \ E= 25 \hat{i} m/s [/tex]

And ,

[tex]v_{2}= 30m/s \ N = 30 \hat{j} m/s [/tex]

See attachment .

From Triangle law of vector addition , the resultant of both vectors will be given by third side of the triangle taken in opposite direction.

So , if the resultant velocity makes an angle [tex]\theta[/tex] . Then ,

[tex] tan\theta = \dfrac{v_2}{v_1} [/tex]

Substituting the respective values,

[tex]tan\theta =\dfrac{30m/s}{25m/s} [/tex]

Simplify ,

[tex]tan\theta =\dfrac{6}{5}[/tex]

Take arctan both sides ,

[tex]\theta = tan^{-1}\bigg(\dfrac{6}{5}\bigg)[/tex]

Hence the cars move at an angle of tan-¹(6/5) NE after the collision .

Alkali Metals • Most ___________________ metals

Answers

Answer: They’re the most reactive metals

Explanation: They have larger ionic radii and low ionization energies

What is the difference between molecules and
compounds?

Answers

Answer:

All compounds can be classified as molecules, but not all molecules can be called compounds. Molecules are formed by two or more atoms that are bonded by chemical bonding's. Compounds are constructed by two or more elements where the elements are mixed in fixed ratios.

Answer:

Molecules are formed by two or more atoms that are bonded by chemical bondings.
Compounds are constructed by two or more elements where the elements are mixed in fixed ratios

*All compounds can be classified as molecules, but not all molecules can be called compounds.

Explanation:

 pls brainliest if you don't mind

anyway i hope this helped have an awesome day bye byee

according to Newton's second law of motion. what is force product​

Answers

Newton's second law equates the net force on an object to the rate of change of its momentum, the latter being the product of the mass of a body and its velocity.

Hope this helps :)

Answer:

Force can be defined as the product of mass and acceleration.

Explanation:

~Cornasha_Weeb

Which statement describes the density of the inner planets?

All the inner planets are dense.
The inner planets are less dense than the outer planets.
Earth is dense, while the other inner planets are not.
Mercury and Venus are dense, while Earth and Mars are no

Answers

Answer:

The inner planets are less dense than the outer planets

Please brainliest my answer iam begging you for god sake

Answer:

The inner planets are less dense than the outer planets .

Explanation:

Please Mark Me As a brainliest


Really need help! ;(
Could you please explain it? :)
GIVING 10 POINTS

Answers

Answer:b

Explanation: If you look at the line on the graph, you can see that it is going downward, meaning it has a negative slope, and choice b is the only one that has a negative slope

The answer is y=-x

Explanation:
In the formula y=mx+b, m stands for the slope while b stands for the y-intercept.

The slope, in this case, is negative one. You can see this by finding two points on the line and using the slope formula

y(2)-y(1)
————
x(2)-x(1)

As for the y-intercept. That is just the point at which the line crosses the y-axis. In this case, the line intercepts at y=0. So, you do not need to put anything in for ‘b’

So, when m=-1 and b=0, your equation is y=-x

The net force on an object is

Answers

Answer:

Net Force. when all combinations of force acting on an object. Force. A push or pull

So it's the third answer

( the combination of all forces acting on it )

A football is kicked at ground level with a speed of 18.0 m/s at an angle of 31.0 to the horizontal. How much longer does it hit the ground?

Answers

The football hit the ground 2.11 seconds later.

Hope this helps

what is the relationship between distance, average speed and time​

Answers

Answer:

average speed= total distance/total time

Explanation:

Related to the distance traveled by the object which means, it is only represented by the magnitude and direction of travel is not important. so average speed= total distance/total time

Can you please help me with this one

Answers

oh ok where is it bring it

3. An airplane travels at a speed of 600 km/h. How much time will it take to fly a distance of 3180 km to California

Answers

Answer:

5.3 hours

Explanation:

(3180 km) / (600 km/h) = 5.3 hours

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by
−0.50t, in m/s2 for t in seconds. It stops at t =
A. 64 s
B. 32 s
C. 16 s
D. 8.0s
E. 4.0s​

Answers

A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.

What is velocity?

The change of displacement with respect to time is defined as the velocity.  velocity is a vector quantity.

Given data;

t = 0 ,u=16 m/s

acceleration = −0.50t m/s²

v=0,t=?

The acceleration is found as;

[tex]\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt[/tex]

Intregating both sides we get;

[tex]\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec[/tex]

Hence, the car stops at t=8sec. Option D is correct.

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If a green ball is rolled from an initial position of 2m and travels to a final
position of 10m - what distance does it travel? (just type the number, no
need for units).

Answers

Answer:

10m-2m = 8m

8

Hope this helps!

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