A solenoid has 18 turns per centimeter of its length. the solenoid is twisted into a circle so that it becomes shaped like a toroid, the magnetic field at the center of each turn of the toroid is mathematically given as
B=3.39292007×10^−5 T
What is the magnetic field at the center of each turn of the toroid?Generally, the equation for magnetic field is mathematically given as
B=\mu_0 * n *I
Where
n=18
n=1800turns/m
Therefore
B=4*\pi*10^{-7}*1800*15*10^{-3}
B=3.39292007×10^−5T
In conclusion, the magnetic field at the center of each turn of the toroid is
B=3.39292007×10^−5T
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the unit of energy is a derived unit give reasons.
Answer:
ioinl
Explanation:
A delivery van has 80000j of kinetic energy. if the brakes can supply a force of 12,500n to bring the van to stop, how far will the van travel while coming to rest after the brakes are applied?
The distance, van travels while coming to rest after brake applied is 6.4m
What is Work energy theorem?It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Given is a delivery van whose kinetic energy K.E = 80000J and the force applied to brake F = 12500 N.
The brakes are applied to stop the van, so, final velocity is zero. Then, change in kinetic energy will be
According to work energy theorem, work done is
W = ΔK.E = K.Ef - K.Ei
W = - 80000J
Work done is also defined as the product of force applied and the distance it travelled.
W = Fs
80000 = 12500 x s
s = 6.4 m
Thus, the distance, van travels while coming to rest after brake applied is 6.4m
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Where do nebulae come from, in the opinion of science?
*
1 point
It was made from a giant rabbit's skin.
It formed from the same cloud of dust that our entire galaxy is made from
It formed from hydrogen, the first element created in the universe.
It formed debris that was left over after a nova or supernova
Answer:
It formed from the same cloud of dust that our entire galaxy is made from
How does the kinetic energy from the forward motion of a car traveling at 16 m/s
compare with the kinetic energy of the same car traveling at 8 m/s?
(A) It is 2 times greater.
(C) It is 8 times greater.
(B) It is 4 times greater.
(D)
It is 16 times greater.
The kinetic energy in the first case is 4 times more than the second case.
Hence, option D)It is 4 times greater is the correct answer.
What is Kinetic Energy?Kinetic energy is simply a form of energy a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Given that;
For the first case, velocity v = 16m/sFor the second case, velocity = 8m/sLet the mass of the car be mFor the first case, kinetic energy of the car will be;
K = (1/2)mv²
K = (1/2) × m × (16m/s)²
K = (1/2) × m × 256m²/s²
K = mass × 128m²/s²
For the second case, kinetic energy of the car will be;
K = (1/2)mv²
K = (1/2) × m × (8m/s)²
K = (1/2) × m × 64m²/s²
K = mass × 32m²/s²
Comparing the kinetic energy of the car with the same mass but different velocity, we can see that the kinetic energy in the first case is 4 times more than the second case.
Hence, option D)It is 4 times greater is the correct answer.
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How many starlink satellites are in orbit right now.
Answer:
Currently 1,915
Explanation:
I don't know if this is still exactly accurate to date, but when I answered this question, an astronomer had been tracking that many constallations
Which is one factor that contributes to the formation of polar, temperate, and tropical zones?
the angle of the Sun’s rays
the direction of seasonal winds
the presence of prevailing winds
the movement of wind near a mountain
help im timed
Answer:
The angle of the Sun's rays:
At about June 21 the sun is directly overhead at about 23 deg north of the equator
On about Dec 21 the sun is directly overhead at about 23 deg south of the equator
It is this tilt 23 deg to the ecliptic (path of earth about sun) that causes the major temperature changes on earth
A bus starts from rest.if the acceleration is 2m/s square, find
i.the distance travelled
ii.the velocity after 2 seconds.
Answer:
The velocity after 2 seconds can be found through:
V = u +a*t
Where V is final velocity, u is initial velocity, a is acceleration and t is time.
V = 0 + 2* 2= 4 meters/second
The distance (s) can be found through:
V^2= u^2 +2*a* s
Where V is final velocity, u is initial velocity, a is acceleration.
4^2= 0^2 + 2 *2*s
16= 0 + 4s
s= 4 meters
Distance (s) can also be found through:
s= ut + 1/2 at^2
s= 0+ 1/2 *2*2^2= 1 *2*2
s= 4 meters
Explanation:
Question 1 of 10
What is the wavelength of a wave with a frequency of 262 Hz and a speed of
343 m/s?
O A. 1.3 m
OB. 89,866 m
O C. 1.11 x 10-5 m
O D. 0.76 m
SUBMIT
Answer:
V = λ f (wavelength * frequency)
λ = V / f = 343 m/s / 262 / s = 1.3 m
If the net force acting on a moving object CAUSES NO CHANGE IN ITS VELOCITY, what happens to the object's momentum?
A. It decreases.
B. It remains equal to the force.
C. It increases.
D. It stays the same.
If the net force acting on a moving object causes no change in its velocity, the object's momentum will stay the same.
What is momentum?Momentum of a body in motion refers to the tendency of a body to maintain its inertial motion.
The momentum is the product of its mass and velocity.
This suggests that if the net force acting on a moving object causes no change in its velocity, the momentum of the object will remain the same.
Therefore, if the net force acting on a moving object causes no change in its velocity, the object's momentum will stay the same.
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A uniform cylindrical rod is 0.63m long and it has cross sectional area of 0.1m. calculate the depth of immersion
The depth of immersion of the uniform cylindrical rod is 0.63m.
What is Depth of immersion?This is defined as the distance in which a body reaches when it is submerged.
Depth of immersion = Volume/Cross-sectional area
Volume = Cross-sectional area × length
= 0.1m² × 0.63m = 0.063m³
Depth of immersion = 0.063m³ / 0.1m²
= 0.63m
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During the time interval from 0.0 to 10.0 s, the position vector of a car on a road is given by x(t) = a + bt + ct2, with a = 17.2 m, b = -10.1 m/s, and c = 1.10 m/s2. What is the car’s velocity as a function of time? What is the car’s average velocity during this interval?
im stuck with this :(
The car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.
Average velocity of the carThe average velocity of the car is calculated as follows;
x(t) = a + bt + ct2
v = dx/dt
v(t) = b + 2ct
v(0) = -10.1 m/s + 2(1.1)(0) = -10.1 m/s
v(10) = -10.1 + 2(1.1)(10) = 11.9 m/s
Average velocityV = ¹/₂[v(0) + v(10)]
V = ¹/₂ (-10.1 + 11.9 )
V = 0.9 m/s
Thus, the car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.
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What happens to the light in a
concave lens?
a. the light diverges when it passes
through the lens.
b. the light diverges before it enters the
lens.
c. the light converges when it enters the
lens.
Answer:
a. the light diverges when it passes through the lens.
Explanation:
All the light rays after passing through the concave lens diverge and when produced backwards appear to meet at a point on the principal axis of the lens. This point is known as principal focus of a concave lens.
mention part of generetor and write the uses of each part
Answer:
Explanation:
If generator really means alternator as used in cars, the following can be said:
The rotor is fed with a variable voltage ranging from 0 volt to 12 volts. The 2 brushes (fixed, not rotating, like the stator) make contact with two rings that are rotating with the rotor. The rotor acts like a fixed magnet, but the magnetic field strength is constantly updated to provide a constant output voltage, even if the load current change or the motor speed change.
The stator is basically 3 coils and 6 diodes that convert the 3 phases of AC output to an almost ripple-free DC.
Note that as more energy is extracted from the alternator (for example, adding 10 amps by turning on the headlights) the shaft resists more rotation. This can be easily tested by holding an alternator in your hand, and trying to rotate the shaft by hand with no load (rotate easily, keep rotating for a few seconds), then short-circuiting the output (much harder to rotate, stop rotating immediately). The quest for magical perpetual energy where a motor is powered by an alternator is a child's dream.
to complete the statement.
Atoms of elements in the same group have the same number of
chemical properties.
This is why they have similar chemical properties.
Answer:
Valence electrons
Explanation:
I don't exactly understand the question. However, I do know that the main commonality between elements of the same group (column) is their valence electrons. Valence electrons are very important when it comes to bonding, ionization, etc.
which wave carries the least energy?
Answer:
B
Explanation:
The answer is B, because the waves are farther apart then the others. And it also looks like radio waves, which carries the least energy.
Answer: The third one
Explanation: there isnt many waves in that one les waves = less energy and i took the quiz/test.
After travelling 4.0 km, the train reaches its maximum speed. it continues at this constant speed on the next section of the track where the track follows a curve which is part of a circle.
state the direction of the resultant force on the train as it follows the curved path.
Answer:
toward the center of the circular curve
Explanation:
An object will follow a circular path at constant speed if and only if its net acceleration is constant and directed toward the center of the curved path.
__
The result force is directed toward the center of the circle.
_____
Additional comment
If any part of the result force is in the direction of motion, the speed will not be constant. If the center-directed force is not constant, the path will not be circular.
sandra is riding a bice at 10.0 meters/second. she slows down to 2.0 meters/second in 10 seconds. her acceleration is blank meters/seconds^2
Explanation:
[tex]a = \frac{v - v _{i} }{t} [/tex]
Her intial velocity is 10
Her final velocity is 2
Time is 10 seconds.
[tex]a = \frac{2 - 10}{10} [/tex]
[tex]a = - \frac{4}{5} [/tex]
Which describes an image that a concave mirror can make?
The image is always virtual.
The image can be either virtual or real.
The image is never upside down.
The image can only be the same size as the object.
Answer:
B. The image can either be virtual or real.
Explanation:
Concave mirrors can either produce real or virtual images. The image is upright given that it is virtual or real given that it is in front of the mirror. The images produced by the concave mirrors can also be reduced (in height), enlarged (in terms of size) or having same size as that of the object.
I hope this helps you understand about the images formed by concave mirrors.
Have a nice studies.
17. what does it mean if a personality
test is reliable?
a. a reliable test will give consistent
results over time.
b. a reliable test reveals forgotten
experiences.
c. a reliable test has strong personal
bias.
d. a reliable test accurately predicts?
your actions.
A Personality test is said to be reliable because (A). a reliable test will give consistent results over time.
Meaning of Personality testPersonality test can be defined as a test that can be used to verify or ascertain an individuals personality.
Personality test is a test that is carried out by different organizations to help to help them know the individuals in that organization and to help others know how to relate and work with them.
In conclusion, A Personality test is said to be reliable because a reliable test will give consistent results over time.
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Answer:
a.
Explanation:
Would young rocks be found near a volcano?
Answer:
maybe
Explanation:
young rocks may be found near volcanoes
Find the tension in the ropes shown in the figure if the supported object weighs 600N.
By Newton's second and third laws, we have the following net forces at
point A:[tex]\sum F_x = -T_1 \cos(60^\circ) + T_2 \cos(60^\circ) = 0[/tex]
[tex]\sum F_y = T_1 \sin(60^\circ) + T_2 \sin(60^\circ) - 600 \,\mathrm N = 0[/tex]
Together, these equations tell us [tex]\boxed{T_1=T_2\approx 346 \,\mathrm N}[/tex].
point B:[tex]\sum F_x = T_3 \cos(20^\circ) - T_2 \cos(60^\circ) - T_5 = 0[/tex]
[tex]\sum F_y = T_3 \sin(20^\circ) - T_2 \sin(60^\circ) = 0[/tex]
point C:[tex]\sum F_x = -T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5 = 0[/tex]
[tex]\sum F_y = T_4 \cos(20^\circ) - T_1 \sin(60^\circ) = 0[/tex]
Combining the horizontal force equations for points B and C and using the fact that [tex]T_1=T_2[/tex] gives
[tex](T_3 \cos(20^\circ) - T_2 \cos(60^\circ) - T_5) + (-T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5) = 0 + 0[/tex]
[tex]\implies (T_3 - T_4) \cos(20^\circ) = 0 \implies T_3=T_4[/tex]
Then combining the vertical force equations for B and C, we find
[tex](T_3 \sin(20^\circ) - T_2 \sin(60^\circ)) + (T_4 \sin(20^\circ) - T_1 \sin(60^\circ)) = 0 + 0[/tex]
[tex]\implies 2 T_3 \sin(20^\circ) - 2 T_1 \sin(60^\circ) \implies T_3 = \dfrac{\sin(60^\circ)}{\sin(20^\circ)} T_1[/tex]
so that [tex]\boxed{T_3 = T_4 \approx 877 \,\mathrm N}[/tex]
Lastly solve for [tex]T_5[/tex] using either horizontal force equation for B or C.
[tex]-T_4 \cos(20^\circ) + T_1 \cos(60^\circ) + T_5 = 0[/tex]
[tex]\implies T_5 = \left(\dfrac{\sin(60^\circ)}{\sin(20^\circ)} - \cos(60^\circ)\right) T_1 \implies \boxed{T_5 \approx 651\,\mathrm N}[/tex]
Is the universe endless?
The universe may indeed have an end one day according but it is yet to be shown in science.
Is the universe endless?While there is certainly no way a person will live long enough to know if the universe will end or not, nevertheless certain scientific calculations are helpful.
From astronomical calculations, the universe is anticipated to have existed for about 13.8 million years. Thus, the universe may indeed have an end one day according but it is yet to be shown in science.
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A 0.3Kg mass of liquid is heated from 20°C to 53°C. The specific heat capacity of the
liquid is 22001/Kg C. How much energy is transferred to the liquid?
The total energy is transferred to the liquid is = 217809.9 J
Given:-It is given in the question that—
weight of the liquid= 0.3kg
specific heat capacity=22001/kg C
temperature changes between 20°C to 53°C
Solution:-we can easily solve this problem by using the formula of the calorimetry principle.
The formula is —
Q= m×s×t [Q=total energy is transferred, m= mass of the substance, s= specific heat, t= final temperature - initial temperature]
by putting the value on what is given in this question —
Q= 0.3×22001×(53-20)
= 217809.9 J
So energy transferred to the liquid is=217809.9 J
A car with a mass of 1000 kg is moving on an un-banked ramp with a radius of 100 m. what is the maximum speed the car can move without skidding if the coefficients of static and kinetic friction are 0.80 and 0.60 respectively
The maximum speed the car can move without skidding is determined as 28 m/s.
Maximum speed of the car
The maximum speed of the car moving in a circular path is provided by static frictional force.
Fs = μFₙ = mv²/r
μFₙ = mv²/r
mv² = μFₙr
v² = μFₙr/m
[tex]v_{max} = \sqrt{\frac{\mu_s F_n r}{m} } \\\\v_{max} = \sqrt{\frac{\mu_s (mg) r}{m} } \\\\v_{max} = \sqrt{\mu_sgr} \\\\v_{max} = \sqrt{(0.8)(9.8)(100)}\\\\v_{max} = 28 \ m/s[/tex]
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Which two options would INCREASE the electric force between two charged particles?
A. Increase the distance between the particles. B. Decrease the charge of one of the particles. C. Decrease the charge of both particles
D. Decrease the distance between the particles
E. Increase the charge of one of the particles.
The electric force between two charged particles can be increased by decreasing the distance between the two particles.
How to increase electric force between two charged particles.The technique of decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. while
increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.
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Type the correct answer in the box.use numerals instead of words. if necessary, use / for the fraction bar. δabc is a right triangle in which ∠b is a right angle, ab = 1, ac = 2, and bc = . cos c × sin a =
From the diagram The value of cos C × sin A = [tex]\frac{3}{4}[/tex]
Determine the numerical value of cos C × sin AFirst step : determine the values of cos C and sin A
cos C = adjacent / hypotenuse
= a / b
= [tex]\sqrt{3} / 2[/tex]
= √3/2
sin A = sin 60⁰
= √3/2
Therefore the numerical value of cos C * sin A = [tex]\frac{3}{4}[/tex]
In conclusion From the diagram The value of cos C × sin A = [tex]\frac{3}{4}[/tex]
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Calculate the total distance travelled by the motorcyclist over 0-60
a student investigates the efficiency of a scale model of an electricity generating wind turbine using the equipment in figure 1.
the student changed the number of sales on the turbine and measures the power output from the turbine's generator. the air blower is supplied with 533w and has efficiency of 0.62.
when using two sails, the efficiency of turbine was 13%. calculate the power generated.
The power generated or output power of the turbine is determined as 42.96 W.
Power generated
The power generated or output power of the turbine is calculated as follows;
eff = 0utput power/1nput power x 100%
13 = 0utput power/(0.62 x 533)
0.13 = 0utput power/330.46
0utput power = 0.13 x 330.46
0utput power = 42.96 W
Thus, the power generated or output power of the turbine is determined as 42.96 W.
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75m X A car moves with a uniform velocity 21 ms-1 from position P and a truck moves from rest with uniform acceleration 2 ms-2 from position Q in the same time in the same direction.
i) Determine the distance travelled in 20 seconds.
ii) How many times the private car will meet? Analyze mathematically.
Velocity after 20s for both
Car=21m/sTruck=2(20)=40m/s.Distance traveled for car
20(21)=420mDistance traveled by truck=
s=ut+1/2at²s=1/2(2)(20)²s=400m#b
Distance from Q
for car
420-75=345mFor truck
400mThe truck will meet the car after 75/21≈4s
Then for 6s the car keeps meeting because after 7 s Truck will archive 22m/s velocity
Total meet ups=6+1=7timesA boat crossing a 153.0 m wide river is directed so that it will cross the river as quickly as possible. The boat has a speed of 5.10 m/s in still water and the river flows uniformly at 3.70 m/s. Calculate the total distance the boat will travel to reach the opposite shore.
We have the relation
[tex]\vec v_{B \mid E} = \vec v_{B \mid R} + \vec v_{R \mid E}[/tex]
where [tex]v_{A \mid B}[/tex] denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.
We're given speeds
[tex]v_{B \mid R} = 5.10 \dfrac{\rm m}{\rm s}[/tex]
[tex]v_{R \mid E} = 3.70 \dfrac{\rm m}{\rm s}[/tex]
Let's assume the river flows South-to-North, so that
[tex]\vec v_{R \mid E} = v_{R \mid E} \, \vec\jmath[/tex]
and let [tex]-90^\circ < \theta < 90^\circ[/tex] be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that
[tex]\vec v_{B \mid R} = v_{B \mid R} \left(\cos(\theta) \,\vec\imath + \sin(\theta) \, \vec\jmath\right)[/tex]
Then the velocity of the boat relative to the Earth is
[tex]\vec v_{B\mid E} = v_{B \mid R} \cos(\theta) \, \vec\imath + \left(v_{B \mid R} \sin(\theta) + v_{R \mid E}\right) \,\vec\jmath[/tex]
The crossing is 153.0 m wide, so that for some time [tex]t[/tex] we have
[tex]153.0\,\mathrm m = v_{B\mid R} \cos(\theta) t \implies t = \dfrac{153.0\,\rm m}{\left(5.10\frac{\rm m}{\rm s}\right) \cos(\theta)} = 30.0 \sec(\theta) \, \mathrm s[/tex]
which is minimized when [tex]\theta=0^\circ[/tex] so the crossing takes the minimum 30.0 s when the boat is pointing due East.
It follows that
[tex]\vec v_{B \mid E} = v_{B \mid R} \,\vec\imath + \vec v_{R \mid E} \,\vec\jmath \\\\ \implies v_{B \mid E} = \sqrt{\left(5.10\dfrac{\rm m}{\rm s}\right)^2 + \left(3.70\dfrac{\rm m}{\rm s}\right)^2} \approx 6.30 \dfrac{\rm m}{\rm s}[/tex]
The boat's position [tex]\vec x[/tex] at time [tex]t[/tex] is
[tex]\vec x = \vec v_{B\mid E} t[/tex]
so that after 30.0 s, the boat's final position on the other side of the river is
[tex]\vec x(30.0\,\mathrm s) = (153\,\mathrm m) \,\vec\imath + (111\,\mathrm m)\,\vec\jmath[/tex]
and the boat would have traveled a total distance of
[tex]\|\vec x(30.0\,\mathrm s)\| = \sqrt{(153\,\mathrm m)^2 + (111\,\mathrm m)^2} \approx \boxed{189\,\mathrm m}[/tex]