A soccer player practices kicking the ball into the goal from halfway down the soccer field, which is 45 meters away. The time it takes for the ball to get to the goal from the time it is kicked is 3 seconds. The player wants to know the velocity of the ball.
Is there enough information to calculate this?
Yes, displacement is 45 meters, elapsed time is three seconds, and the direction is toward the goal. Velocity is 135 m/s toward the goal.
No, only speed can be calculated from the distance of 45 meters and the time of 3 seconds.
Yes, displacement is 45 meters, time is three seconds, and the direction is toward the goal. Velocity is 15 m/s towards the goal.
Answers
Answer:
Yes, displacement is 45 meters, time is three seconds, and the direction is toward the goal. Velocity is 15 m/s towards the goal.
Explanation:
Hope this helped!
Related Questions
Stoichiometric coefficients indicate the ratio between ________of given substances in a chemical reaction
a) moles
b) molecules
c) molar masses
d) masses
both a) and b)
any of the a), b), c) and d)
both a) and c)
only b)
only a)
Answers
Answer:
b
Explanation:
How many seconds are in 100 years(factor label conversion)
Answers
Answer:
0.0166
Explanation:
This conversion of 100 seconds to minutes has been calculated by multiplying 100 seconds by 0.0166 and the result is 1.6666 minutes.
I hope this helps,
even a little bit
The phase of the moon you see depends on
Answers
Answer:
The phases of the Moon depend on the moon's position compared to the Earth and the Sun. Remember that the moon revolves around the Earth. As the moon goes around the Earth, half of the moon is always illuminated by the Sun.
is pasta and water magnetism, state of matter, or solubility?
please helpp!!
Answers
Answer:
solubility
Explanation:
A tank contains 7.0 moles of a mixture of nitrogen gas and oxygen gas. The total
pressure exerted by the gas mixture is 530 kPa. The partial pressure exerted by the
oxygen is 140 kPa. How many moles of NITROGEN gas are present in the tank?
Answers
Answer:
5.2 mol
Explanation:
Step 1: Given data
Total number of moles (n): 7.0 molTotal pressure (P): 530 kPaPartial pressure of oxygen (pO₂): 140 kPaStep 2: Calculate the mole fraction of oxygen
We will use the following expression.
pO₂ = P × X(O₂)
X(O₂) = pO₂ / P
X(O₂) = 140 kPa / 530 kPa
X(O₂) = 0.264
Step 3: Calculate the moles of oxygen
We will use the definition of mole fraction of oxygen.
X(O₂) = n(O₂) / n
n(O₂) = X(O₂) × n
n(O₂) = 0.264 × 7.0 mol
n(O₂) = 1.8 mol
Step 4: Calculate the moles of nitrogen
The total number of moles is equal to the sum of moles of the individual gases.
n(O₂) + n(N₂) = n
n(N₂) = n - n(O₂)
n(N₂) = 7.0 mol - 1.8 mol
n(N₂) = 5.2 mol
The volume of a gas with an initial pressure of 380 mmHg increases from 5.0 L to 8.0 L. What is the final pressure of the gas, in atm, assuming no change in moles or temperature?
a. 238 atm
b. 2.4 atm
c. 0.31 atm
d. 0.80 atm
e. 8.0 atm
Answers
I hope this helped out! Have a nice day :)
What is the answer? Please
Answers
Which periodic group has the smallest atomic radius ?
-alkali metals
- halogens
- Nobel gases
- transition metals
Answers
The Nobel gases, Group 8 elements have the smallest atomic radIi in the periodic table.
Atomic radius decreases as you move across a period. This is because Within a period, a new electron is being added to the same shell , and at the same time a new proton is added , This causes an attraction and causes the electron to pull nearer to the nucleus causing the radius to shrink and reduce in size.
In decreasing order of atomic radius, we have alkali metals>halogens> transition metal > Nobel gases
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What’s the order can someone help?
Answers
(That’s from lowest to highest don’t get confused) :)
A student has a balloon with a volume of 2.5 liters that contains 4.0 moles of air. The ballon has a small leak, allowing one mole to escape, leaving just 3.0 moles of air inside the balloon. What is the balloon's new volume after the air has escaped?
Answers
Answer:
1.9 L
Explanation:
Step 1: Given data
Initial number of moles of air (n₁): 4.0 molInitial volume of the balloon (V₁): 2.5 LFinal number of moles of air (n₂): 3.0 molFinal volume of the balloon (V₂): ?Step 2: Calculate the final volume of the balloon
According to Avogadro's law, the volume of an ideal gas is directly proportional to the number of moles. We can calculate the final volume of the balloon using the following expression.
V₁ / n₁ = V₂ / n₂
V₂ = V₁ × n₂ / n₁
V₂ = 2.5 L × 3.0 mol / 4.0 mol
V₂ = 1.9 L
Calculate the number of S atoms in 0.670 mole of S.
Answers
Answer:
4.03 × 10²³ atomsExplanation:
The number of S atoms can be found by using the formula
N = n × Lwhere n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.67 × 6.02 × 10²³
We have the final answer as
4.03 × 10²³ atomsHope this helps you
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 725 mL of a solution that has a concentration of Na ions of 1.30 M
Answers
Answer:
51.53 grams .
Explanation:
Na₃PO₄ ⇄ 3Na⁺¹ + PO₄⁻³ .
1 mole 3 mole
725 mL of 1.3 M Na⁺ ions
= .725 x 1.3 moles of Na⁺ ions
= .9425 moles
3 mole of Na⁺ is formed by 1 mole of Na₃PO₄
.9425 mole of Na⁺ is formed by .9425/3 mole of Na₃PO₄
Na₃PO₄ needed = .9425/3 moles = .3142 moles
Molecular weight of Na₃PO₄ = 164
grams of Na₃PO₄ needed = .3142 x 164 = 51.53 grams .
Where do karst regions occur?
Answers
Answer:
Image result for Where do karst regions occur?
Karsts are found in widely scattered sections of the world, including the Causses of France; the Kwangsi area of China; the Yucatán Peninsula; and the Middle West, Kentucky, and Florida in the United States.
Explanation:
Answer:
Middle West Kentucky.
Explanation:
Karst are found in widely scatter sections of the world.
Draw the product or products that are obtained from the reaction of HCl with 1-butene and with 2-butene. Show the relative stereochemistry if the product has two or more stereocenters.
Answers
Delete me please!!!!!!
A 2kg metal cylinder is supplied with 1600J of energy to heat it from 5*C to 13*C. What is the SHC of the metal?
Answers
Answer:
100Jkg/°C
Explanation:
Given parameters:
Mass of metal = 2kg
Amount of heat energy = 1600J
Initial temperature = 5°C
Final temperature = 13°C
Unknown:
Specific heat capacity of the metal = ?
Solution:
Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.
H = m x C x (T₂ - T₁ )
H is the amount of heat
m is the mass
C is the unknown specific heat capacity
T is the temperature
Insert the parameters and solve;
1600 = 2 x C x (13 - 5)
1600 = 16C
C = 100Jkg/°C
How do her cells use these molecules to release energy for her body to run?
Answers
Her cells use oxygen, in the oxidation of sugar(glucose) to provide energy in the body's admissible form (i.e ATP).
Her cells, like that of every animal depend on the oxidation of sugars particularly glucose by Oxygen, O2 to provide energy in a process termed Cellular respiration.
The process of cellular respiration in her cell occurs in the mitochondria although the first part of cellular respiration occurs in the cytoplasm.
Essentially, the process of cellular respiration is made of 3 metabolic pathways as follows;
GlycolysisKreb's cycleThe Electron Transport ChainUltimately, the admissible form of energy, the Adenosine Tri Phosphate-ATP is the end result of this glucose metabolism.
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Calculate how many grams of sodium hypochlorite can be theoretically formed when 1.23 mol of sodium hydroxide is combined with 1.36 mol of chlorine.
Answers
Answer:
45.78 g NaClO
Explanation:
The reaction that takes place is:
2NaOH + Cl₂ → NaCl + NaClO + H₂OIn order to react completely, 1.36 moles of chlorine would require (2*1.36) 2.72 moles of NaOH. There are more moles than that, so NaOH is the limiting reactant.
We calculate the moles of NaClO formed, from the limiting reactant:
1.23 mol NaOH * [tex]\frac{1molNaClO}{2molNaOH}[/tex] = 0.615 mol NaClOFinally we convert NaClO moles to grams, using its molecular weight:
0.615 mol NaClO * 74.44 g/mol = 45.78 g NaClOBalance the following equation.
C3H8(g) + O2(g) → CO2(g) + H2O(l)
Answers
Explanation:
C3H8+5O2----->3CO2+4H2O
Answer:
C3H8+5O2----->3CO2+4H2O
Explanation:
You have two pure substance that you cannot identify. Each sample is solid at room temperature. Describe at least five steps in the appropriate sequence that you would take to be able to identify the substance.
Answers
Answer:
pue like ad
Explanation:
For the two pure substance that you cannot identified , The steps taken in the right sequence are:
When two pure substance are places before you. you have to visually anaylse the sample, note the various colors that they have. It can tell you if it's an anions or cations.You can use reactants to precipitate the cations of the sample you have We then add a reactant to the sample and you did not see any precipitate, it corresponds to any of the elements or compound. If you do not see a precipitate, you can add other reactant.You then observe the color of this precipitate. example if the color changes to green, it will tell you that the substance is Ni(OH)₂ etc. One can also find out through the melting and boiling point of the two substances.Pure substance are regarded as substance that does not have impurities. one common way of finding out the purity of a substance is by its melting and boiling point determination.
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The atomic of nitrogen is 7. The number of electrons a neutral atom has is_, and its atomic mass is approximately_amu.
Answers
Electrons - 7
Atomic mass - 14
For future reference, you can find the number of Electrons by subtracting the number of protons (7) from the element's mass number (14
We know, Atomic Number = Number of Electrons (In a neutral atom).
& Atomic mass = Number of protons + Number of Neutrons
The atomic number of nitrogen is 7. The number of electrons a neutral nitrogen atom has is "Seven (7)", and its atomic mass is approximately "Fourteen(14)" amu
Hope this helps!
why is there not a corresponding drop in ionization energies between Bi and Po in the sixth period as N and O?
and why is there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B?
Answers
Answer:
See explanation
Explanation:
According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be anomalous......It has been claimed that spin– orbit coupling by the Russell–Saunders scheme would lower the ground state of Bi+ ..."
However, the involvement of d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.
The same argument could be extended to explain the reason why there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.
why does 3-methylcyclohexene elute before
1-methylcyclohexene in gas chromatography?
Answers
Answer: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%. This is because 1-methylcyclohexene is the major product with the more stable carbocation intermediate and 3-methylcyclohexene is the minor product with the less stable carbocation intermediate.
Explanation: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%
What might happen if you mixed a strong acid with an equally strong base? Question 2 options:
A.You'd wind up with a pH-neutral salt and water.
B.You would see an explosive chemical reaction.
C.The base would destroy the acid.
D.The acid would destroy the base.
Answers
Answer:
b
Explanation:
Can you answer these two questions right please and thank you
Answers
Answer:
B. LZAQD
A. Younger than A but older than Q
Explanation:
To solve this problem, we simply apply the stratigraphic laws which are the law of superposition and principle of cross cutting.
According to the law of superposition, in an undeformed sequence of strata, the oldest layer is always at the bottom and the youngest on top. In this case, we have a little disturbance but it did not affect much of the original bedding. So, the rock ages from L to Z to A to Q and D. L is the oldest and D is the youngest.According to the principle of cross-cutting "features that cuts through a rock are younger than the layers they cut through". In this problem, the fault cuts through layers LZ and A which suggests that these layers are older than the faulting event. Layer Q is unaffected by the faulting so, the fault is older than the layer.
A music performance takes place in an enclosed arena. A person sitting a distance of 20.0 m from the speaker experiences a sound intensity of 0.32 W/m2. What is the power of the speaker? (Assume that the area over which the speaker transmits sound is given by A = 4πd2, where d is the distance from the speaker.)
A.
100 W
B.
550 W
C.
1,200 W
D.
1,600 W
Answers
A reaction vessel is charged with 0.50 atm of A and 0.030 atm of B. Once the reaction reaches equilibrium, what is the equilibrium partial pressure of B? Kp for this reaction is 67.2A (g) ⇌ 2 B (g)
Answers
Answer:
1.000 atm
Explanation:
Step 1: Write the reversible reaction
A(g) ⇌ 2 B(g)
Step 2: Calculate the reaction quotient
Q = [B]²/[A]
Q = 0.030²/0.50
Q = 0.0018
since Q < Kp, the reaction will proceed to the right
Step 3: Make an ICE chart
A(g) ⇌ 2 B(g)
I 0.50 0.030
C -x +2x
E 0.50-x 0.030+2x
Step 4: Find the value of "x"
We will use the definition of the pressure equilibrium constant.
Kp = 67.2 = [B]²/[A] = (0.030+2x)²/0.50-x
33.6 - 67.2x = 0.0009 + 0.12x + 4x²
4x² + 67.32x -33.5991 = 0
We solve this quadratic equation and we get x=0.485112 and x=−17.3151 (neglected).
Step 5: Find the partial pressure of B at equilibrium
pB = 0.030+2x = 0.030+2(0.485112) = 1.000 atm
The equilibrium partial pressure of B would be:
[tex]1.000 atm[/tex]
Reversible Reaction
Given that,
Reaction
[tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex]
Charge on the reaction vessel [tex]= 0.50 atm[/tex] of A
[tex]0.030 atm[/tex] of B
To find,
Reaction quotient first
[tex]= B^2/A\\= (0.030)^2/0.50\\= 0.0018[/tex]
This shows that the reaction quotient is greater than Kp.
Through the reaction [tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex], ICE can be drawn
I [tex]0.50[/tex] [tex]0.030[/tex]
C [tex]-x[/tex] [tex]+2x[/tex]
E [tex]0.50-x[/tex] [tex]0.030+2x[/tex]
Now,
We will determine the value of [tex]x[/tex],
Kp [tex]= 67.2[/tex]
[tex]= [B]^2/[A][/tex]
[tex]= (0.030+2x)^2/0.50-x[/tex]
⇒ [tex]33.6 - 67.2x[/tex] [tex]= 0.0009 + 0.12x + 4x^2[/tex]
⇒ [tex]4x^2 + 67.32x -33.5991 = 0[/tex]
∵ [tex]x = -17.3151[/tex]
Therefore, Equilibrium Partial Pressure
[tex]= 0.030+2x[/tex]
[tex]= 0.030+2(0.485112)[/tex]
= [tex]1.000[/tex] atm
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what is aluminum’s nuclear charge?
Answers
Answer:All six of the ions contain 10 electrons in the 1s, 2s, and 2p orbitals, but the nuclear charge varies from +7 (N) to +13 (Al)
Explanation:
hope this helped if it did may i have brainliest
In the metallurgic industry one of the processes to get pure iron takes tree steps.
a) CaCO3→CaO + CO2
b) CO2 + C → CO
c) Fe2O3 + CO → Fe + CO2
Calculate the kilograms of iron that would be produced from 1340 g of calcium carbonate.
Answers
Mass of Iron produced : 1.5 kg
Further explanationReaction
a) CaCO3→CaO + CO2
b) CO2 + C → 2CO
c) Fe2O3 + 3CO → 2Fe + 3CO2
From the reaction above : 1 mol CaCO₃ = 2 mol Fe
mol CaCO₃ :
1340 : 100 g/mol = 13.4
mol Fe :
2 x 13.4 = 26.8
mass Fe :
26.8 x 56 g/mol=1500.8 g⇒1.5 kg
Suppose the current flowing from a battery is used to electroplate an object with silver. Calculate the mass of silver that would be deposited by a battery that delivers 1.65 A·hr of charge.
Answers
Answer:
m = 0.00659 kg = 6.59 g
Explanation:
From Faraday's Law of Electrolysis, we know that:
m = ZQ
where,
m = mass of silver deposited = ?
Q = charge supplied = (1.65 A-hr)(3600 s/1 hr) = 5940 C
Z = electrochemical equivalent of silver = 1.18 x 10⁻⁶ kg/C
Therefore,
m = (1.11 x 10⁻⁶ kg/C)(5940 C)
m = 0.00659 kg = 6.59 g
The mass of silver that would be deposited by a battery is 6.65 grams
The precipitation of Ag requires the removal of one electron. The reduction process for silver electrode at the cathode is as follows:
[tex]\mathbf{Ag^+ + e^- \to Ag(s)}[/tex]
The current flowing in the battery = 1.65 A = 1.65 C/sThe time at which the current is flowing = 1 hr = 3600sec∴
The charge Q = Current (I) × time (t)Charge Q = 1.65 C/s × 3600 sCharge (Q) = 5940 CIn one mole of an electron, the charge carried = 96500 C
Recall that:
The atomic mass of silver (Ag) = 108 g
∴
The mass of silver that would be deposited in a 5940 C can be computed as:
[tex]\mathbf{=5940\ C \times \dfrac{108 \ g }{96500 \ C}}[/tex]
= 6.65 grams
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At what power of ten are we able to view the entire Earth in space?
Answers
Answer:
If I remember correctly it should be 10^7 meters.
Explanation:
The power of ten are we able to view the entire Earth in space is 10^8. This is further explained below.
What power of ten are we able to view the entire Earth in space?Generally, A telescope is simply defined as a device that magnifies views of faraway things
In conclusion, The power of the telescope will be at 10^8.
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