A skateboard chsnges velocity from 15 meters per second to 5 meters per second, over the course of 5 seconds. What is the skateboards acceleration?
A. -2 m/s^2
B. +2 m/s^2
C. +0.5 m/s^2
D. -0.5 m/s^2​

Answers

Answer 1

Option A) is correct.

We are given –

Initial velocity of skateboard is, u= 15m/sFinal velocity of skateboard is,v = 5 m/s Time taken, t = 5 secAcceleration, a =?

Formula To be used:-

[tex]\qquad[/tex] [tex]\star\: \: \pink{\boxed{\frak{ a = \dfrac{(v-u)}{t}}}}[/tex]

Where–

A = Acceleration v = Final velocity u = Initial velocity t = time

[tex]\qquad\qquad\quad\underline{\sf{Substituting \ Values \ :}}[/tex]

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━

[tex]\qquad[/tex][tex] \bf \longrightarrow a = \dfrac{v-u}{t}[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow a = \dfrac{5-15}{t}[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow a = \dfrac{-10}{5}[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow a = \cancel{\dfrac{-10}{5}}[/tex]

[tex]\qquad[/tex][tex]\pink{ \bf \longrightarrow a = -2 \:m/s^2}[/tex]

Henceforth, acceleration is -2 m/s².
Answer 2

Answer:

-2 m/s²

Explanation:

Here it's given that a skateboard changes its velocity from 15m/s to 5m/s in an interval of 5s . We are interested in finding out the acceleration of the skateboard. Firstly we know that,

The rate of change of velocity is called acceleration. Mathematically,

[tex]\qquad\rm\twoheadrightarrow accl^n =\dfrac{v - u }{t} [/tex]

Here ,

initial velocity = 15m/s final velocity = 5m/stime = 5s

On substituting the respective values, we have;

[tex]\qquad\rm\twoheadrightarrow accl^n =\dfrac{5m/s-15m/s}{5s}[/tex]

Simplify numerator,

[tex]\qquad\rm\twoheadrightarrow accl^n =\dfrac{-10m/s}{5s}[/tex]

Divide,

[tex]\qquad\rm\twoheadrightarrow \underline{\boxed{\blue{\rm acceleration= -2\ m/s^2}}} [/tex]

Therefore, Option A is correct choice.


Related Questions

What is Socio historical context​

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Answer:

It is the combination of social and historical factors.

A charge is divided q1 and (q-q1)what will be the ratio of q/q1 so that force between the two parts placed at a given distance is maximum?

Answers

Answer:

[tex]q / q_{1} = 2[/tex], assuming that [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] are point charges.

Explanation:

Let [tex]k[/tex] denote the coulomb constant. Let [tex]r[/tex] denote the distance between the two point charges. In this question, neither [tex]k[/tex] and [tex]r[/tex] depend on the value of [tex]q_{1}[/tex].

By Coulomb's Law, the magnitude of electrostatic force between [tex]q_{1}[/tex] and [tex](q - q_{1})[/tex] would be:

[tex]\begin{aligned}F &= \frac{k\, q_{1}\, (q - q_{1})}{r^{2}} \\ &= \frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\end{aligned}[/tex].

Find the first and second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex]. (Note that [tex]0 < q_{1} < q[/tex].)

First derivative:

[tex]\begin{aligned}\frac{d}{d q_{1}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q\, q_{1} - {q_{1}}^{2})\right] \\ &= \frac{k}{r^{2}}\, \left[\frac{d}{d q_{1}} [q\, q_{1}] - \frac{d}{d q_{1}}[{q_{1}}^{2}]\right]\\ &= \frac{k}{r^{2}}\, (q - 2\, q_{1})\end{aligned}[/tex].

Second derivative:

[tex]\begin{aligned}\frac{d^{2}}{{d q_{1}}^{2}}[F] &= \frac{d}{d q_{1}} \left[\frac{k}{r^{2}}\, (q - 2\, q_{1})\right] \\ &= \frac{(-2)\, k}{r^{2}}\end{aligned}[/tex].

The value of the coulomb constant [tex]k[/tex] is greater than [tex]0[/tex]. Thus, the value of the second derivative of [tex]F[/tex] with respect to [tex]q_{1}[/tex] would be negative for all real [tex]r[/tex]. [tex]F\![/tex] would be convex over all [tex]q_{1}[/tex].

By the convexity of [tex]\! F[/tex] with respect to [tex]\! q_{1} \![/tex], there would be a unique [tex]q_{1}[/tex] that globally maximizes [tex]F[/tex]. The first derivative of [tex]F\![/tex] with respect to [tex]q_{1}\![/tex] should be [tex]0[/tex] for that particular [tex]\! q_{1}[/tex]. In other words:

[tex]\displaystyle \frac{k}{r^{2}}\, (q - 2\, q_{1}) = 0[/tex].

[tex]2\, q_{1} = q[/tex].

[tex]q_{1} = q / 2[/tex].

In other words, the force between the two point charges would be maximized when the charge is evenly split:

[tex]\begin{aligned} \frac{q}{q_{1}} &= \frac{q}{q / 2} = 2\end{aligned}[/tex].

A rod 7.0 m long is pivoted at a point 2.0 m from the left end. A downward force of 50 N acts at the left end, and a downward force of 200 N acts at the right end. At what distance to the right of the pivot can a third force of 300 N acting upward be placed to produce rotational equilibrium?

Answers

If the rod is in rotational equilibrium, then the net torques acting on it is zero:

∑ τ = 0

Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:

• at the left end,

τ = + (50 N) (2.0 m) = 100 N•m

• at the right end,

τ = - (200 N) (5.0 m) = - 1000 N•m

• at a point a distance d to the right of the pivot point,

τ = + (300 N) d

Then

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⇒   (300 N) d = 1100 N•m

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Consider a gas at STP in a container of 22. 4 L. What is the approximate value of n according to the ideal gas law? 0. 5 1 2008. 31 224.

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STP is defined as the standard temperature and pressure. These are some standard values given in 1982. the approximate value of n according to the ideal gas law will be 0.986.

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T is the temperature =273.15 K at STP

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Hence the approximate value of n according to the ideal gas law will be 0.986.

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Answer:

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i do not know can i get brainliest im broke

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A person invests money, or ___, in a business.

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Explanation:

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You look at a rope coiled on a beach and are able to perceive it as a single strand because of the law of.

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You are able to perceive it as a single strand because of the principle of : Good continuation

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Principle of Good continuation states that objects with very smooth edges are easily seen as been continuous ( i.e as a single strand ) rather than objects or materials with rough edges.

The rope coiled on a beach has very smooth edges therefore can be seen as a continuous strand and this is possible due to the principle of good continuation.

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Answers

Answer:

Net force required to accelerate the car is 6000 N

Explanation:

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This is based on Newton's Second Law of Motion which states that the force acting on an object is its mass times the acceleration of the object.

Here, mass = 3000 kg and acceleration = 2 m/s²

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False

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False because light can’t escape from a black hole because it’s a black hole DUH

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Answers

Answer:

c.15

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Answer:

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Answers

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Answers

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Answer:

Explanation:

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A laser printer is a common form of computer printer that uses quasi photocopier technology.  A color laser printer is up to ten times more costly than a monochrome laser printer.

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Answer:

A 100 kg person who lives on the third floor

Explanation:

its ^ the answer above

Answer:
100kg person who lived on the third floor
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Answers

Answer:

tips to get you started

Make a menu. ...

Plan your meals around foods that are on sale. ...

Plan at least one meatless meal a week. ...

Check your pantry, refrigerator and freezer. ...

Enjoy grains more often. ...

Avoid recipes that need a special ingredient. ...

Look for seasonal recipes. ...

Plan to use leftovers.

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sana po makatulong

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price ceiling
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Equilibrium is the answer

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Answers

Answer:

local group

Explanation:

Earth is in the second largest galaxy of the Local Group - a galaxy called the Milky Way. The Milky Way is a large spiral galaxy. Earth is located in one of the spiral arms of the Milky Way (called the Orion Arm) which lies about two-thirds of the way out from the center of the Galaxy.

Please mark as Brain list.

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Earth is occupying the second largest place in galaxy of the Local Group. Earth is one of the spiral arms of the Milky Way.

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Answers

Answer:

You need to look up the figure for the energy released in the formation of one He atom, and then multiply that by the number of He atoms formed each second, and the result will be the total energy release that you seek.

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PLEASE I NEED HELPPPPPP 20 POINTSSSS

Answers

Answer:

d

Explanation:

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