Answer:
[tex]1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
[tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
[tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
Explanation:
[tex]p_0[/tex] = Hole concentration = [tex]2\times 10^{16}\ \text{cm}^{-3}[/tex]
[tex]n_i[/tex] = Intrinsic concentration = [tex]10^{10}\ \text{cm}^{-3}[/tex]
[tex]\tau_{n0}[/tex] = Minority carrier life time = [tex]3\times 10^{-6}\ \text{s}[/tex]
[tex]\delta n[/tex] = Excess concentration of electrons = [tex]10^{13}\ \text{cm}^{-3}[/tex]
Majority carrier electron concentration is given by
[tex]n_0=\dfrac{n_i^2}{p_0}\\\Rightarrow n_0=\dfrac{(10^{10})^2}{2\times 10^{16}}\\\Rightarrow n_0=5000\ \text{cm}^{-3}[/tex]
Recombination rate is given by
[tex]R_{n0}=\dfrac{n_0}{\tau_{n0}}\\\Rightarrow R_{n0}=\dfrac{5000}{3\times 10^{-6}}\\\Rightarrow R_{n0}=1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
The recombination rate is [tex]1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
Recombination rate is given by
[tex]R_n=\dfrac{\delta_n}{\tau_{n0}}\\\Rightarrow R_n=\dfrac{10^{13}}{3\times 10^{-7}}\\\Rightarrow R_n=3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
The recombination rate is [tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
Change in the recombination rate is
[tex]\Delta R_n=3.33\times 10^{19}-1.67\times 10^{9}\\\Rightarrow \Delta R_n=3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
The change in the recombination rate is [tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]
Calculate the cost per cubic yard to place concrete using each of the alternatives described. The work in both cases consists of placing 140 cubic yards of concrete in footings.
a. Using a crane and bucket at a price of $225 per hour, including an operator, with a crew consisting of 6 laborers, a cement finisher, and a foreman. The concrete will be placed in 7 hours using this setup, and transportation of the crane costs $390.
b. Using a concrete pump at a price of $295 per hour, including an operator and a crew consisting of 5 laborers, a cement finisher, and a foreman. With this setup, concrete is placed in 6 hours and transportation of the pump costs $290.
Answer:
Cost per cubic yard to place concrete using each of the following alternatives:
Alternative a = $14.04
Alternative b = $14.71
Explanation:
a) Data and Calculations:
Work of concrete in footings = 140 cubic yards
a. Price of using crane and bucket = $225 per hour
Number of hours required for this setup = 7 hours
Transportation of the crane = $390
Therefore, total cost under this alternative = $1,965 (($225*7) + $390)
Cost per cubic yard = $14.04 ($1,965/140)
b. Price of using a concrete pump = $295 per hour
Number of hours required for this setup = 6 hours
Transportation of the pump = $290
Therefore, total cost under this alternative = $2,060 (($295*6) + $290)
Cost per cubic yard = $14.71 ($2,060/140)
A large room contains moist air at 30oC, 102 kPa. The partial pressure of water is 1.5 kPa. Determine(a) the relative humidity(b) the humidity ratio, in kg(vapor) per kg(dry air)(c) the dew point temperature, in oC(d) the mass of dry air, in kg if the mass of water vapor is 10 kg
Solution :
Given :
Dry bulb temperature, T = 30 degree C
Absolute pressure, P = 102 kPa
Partial pressure of water vapor, [tex]$P_v$[/tex] = 1.5 kPa
a). Relative humidity is given by
[tex]$\phi = \frac{P_v}{P_{sat}}$[/tex]
At T = 30 degree C, from the steam table, we have saturation temperature as 4.2469 kPa.
[tex]$\phi = \frac{1.5}{4.2469}$[/tex]
= 0.35319
= 35.31 %
b). Humidity ratio,
[tex]$w= 0.622 \times \frac{P_v}{P-P_v}$[/tex]
[tex]$w= 0.622 \times \frac{1.5}{102-1.5}$[/tex]
w = 0.009283 kg per kg of dry air
c). Dew point temperature is the saturation temperature at vapor pressure of air (can be found from steam table)
At [tex]$P_v$[/tex] = 1.5 kPa, saturation temperature = 1.02 degree C
∴ Dew point temperature = 13.02 °C
d). Humidity ratio can be be defined as the ratio of mass of water vapor to the mass of dry air.
i.e. [tex]$w=\frac{m_v}{m_a}$[/tex]
[tex]$0.009283 =\frac{10}{m_a}$[/tex]
∴ [tex]m_{a}[/tex] = 1077.170 kg of dry air
What is the output? for num in range(3): print (num + 5)
Answer: 5 6 7
Explanation:
you can run this in python and get this result
The output for the given program is: 5 6 7
What is Python Programming Language?This refers to the high-level language that was created and is used for data structures due to its OOP (object-oriented programming).
Hence, this python code asks for an array of numbers in the range of 3 and when that is found, it should make a display of the number and increment it.
Read more about python programming here:
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Suppose to build RSA crypto system you picked primes "p" and "q" as 3 and 7 and "e" as 5 what are the public and private keys? What is the encryption of a message whose integer equivalent is 12. Show that the decryption gives back the message 12.
Answer:
1) Public key of the receiver is (e, n) is (5, 21) and Private key of the receiver (d, n) is (5 , 21) ,
2) the encryption of a message whose integer equivalent is 12 is 3
3) Decryption of the message ⇒ P = C^d mod n
⇒ P = 3⁵ mod 21
⇒ P = 243 mod 21
⇒ 12
Explanation:
Given that,
p = 3
q = 7
e = 5
1)
Now, n = pq = 3 × 7 = 21
Ø(n) = (p-1) × (q-1) = 2 × 6 = 12
Public key of the receiver is (e, n) is (5, 21)
and private key of the receiver is (d, n)
we have to find 'd' by using the expression
ed = 1 + kmodØ(n)
d = 1 + kmodØ(n) / e
now to get 'd' , we need to choose the least positive integer 'k', by substituting different values of ‘k’ from 0,
so for k =0 , d = (1+0) / 5 = 0.2 not an integer.
for k =1 , d = (1+12) / 5 = 13/5 = 2.6 not an integer.
for k =2 , d = (1+24) / 5 = 5 , now 5 is an integer
So k = 2 and d = 5
Private key of the receiver (d, n) is (5 , 21)
2)
Now the encryption of a message whose integer equivalent is 12?
Encryption of the message ⇒ C = P^e mod n
⇒ C = 12⁵ mod 21
⇒ 248832 mod 21
⇒ 3
3)
Also the decryption gives back the message 12.
Decryption of the message ⇒ P = C^d mod n
⇒ P = 3⁵ mod 21
⇒ P = 243 mod 21
⇒ 12
The formation of faults in Earth's crust is an effect. What causes faults to form in the crust? Global Positioning System sensors beds shaking across New York City the movement of tectonic plates landslides across the Midwest
Answer: The movement of tectonic plates
Explanation:
Tectonic plates are the part of the earth's crust that both the ocean and land rest on. These plates are constantly moving as a result of currents in the mantle.
These movements cause stress on the surface which has the effect of fracturing rocks and thereby creating/ forming faults in the earth's crust. Sometimes faults form when these plates move away from each other and sometimes they are formed when they push into each other.
25points and brainliest if correct A, B, C, D
Which option distinguishes the most appropriate action to take next in the following scenario?
Lisa is a new worker on a farm. She needs to access an area of the farm at the top of the hill on a tractor. She tries backing the tractor up the slant and finds that it will not make the ascent.
A. Lisa should drive across the hill at an angle to get to the top.
B. Lisa should reach the top of the hill by finding a less steep path.
C. Lisa should drive forward up the hill at a slow pace to get to the top.
D. Lisa should reach the top of the hill by finding a more experienced driver.
Answer:A
Explanation:
B - it never talked about a steep path or not.
C- it never stated the speed.
d- more experienced driver makes a little bit of sence since she is new but she is new at the farm not driving.
thats my guess.
Answer:
b is the answer
Explanation:
20 points and brainliest is it A, B, C, D
Using your Greek roots and context clues, figure out the meaning of “fissures” in this sentence and select the best definition:
“Look at these recent fissures in the granite roof”
A. an opening made by splitting
B. a crack made from crushing
C. a line made from evaporation
D. a line made from sediment deposits
Answer:
B
Explanation:
Write a python script using while loop which display the number list with an increment of 3 between 1 and 25. Display the output in one row as shown.
Answer:
num_count = 0
while num_count < 25:
print(num_count)
num_count += 3
Explanation:
A while loop statement is defined in the python source code above. An integer variable 'num_count' is defined and continuously incremented by three in the loop until it is greater than 25. the output of the while loop between 1 and 25 is print on the screen.
In the NiTi system, there are a number of invariant transformations and solid state phases. How many degrees of freedom are there in the two phase regions and at the invariant points?
Answer:
we have zero degree of freedom (F = 0) at the first phase region and one degree of freedom (F = 1) at the second phase region
Explanation:
given the diagram;
C = 2 { Ti and Ni}, N = 1 {Pr is constant}, P = 3 { L and B}
For degree of freedom,
Gibbs phase rule is applied for invariant point (ex.A)
P + F = C + N
3 + F = 2 + 1
F = 3 - 3
F = 0
For the second phase region ( ex.B)
C = 2, N = 1, P = 2
P + F = C + N
2 + F = 2 + 1
F = 3 - 2
F = 1
Therefore we have zero degrees of freedom (F = 0) at the first phase region and one degrees of freedom (F = 1) at the second phase region
Ignoring reflection at the air-soil boundary, if the amplitude of a 3-GHz incident wave is 10 V/rn at the surface of a wet soil medium, at what depth will it be down to 1 mV/m? Wet soil is characterized by µr = 1, εr = 9, and σ = 5 × 10–4S/m.
Answer:
5 multiply by 10 S/M
Based on the calculations, the incident wave would be down to 1 mV/m at a depth of 287.82 meters.
How to calculate the depth of the wet soil medium.Since the medium is a wet soil, it is characterized by the following:
Dielectric constant, µr = 1.Relative permitivitty, εr = 9.Electrical conductivity, σ = 5 × 10⁻⁴ S/m.Next, we would determine loss tangent, so as to know if the wet soil is a low-loss medium:
For a low-loss medium; ε''/ε' = σ/ωε < 0.01.
[tex]\frac{\sigma}{\omega \epsilon} = \frac{5 \times 10^{-4} \;\times\; 36 \pi}{2\pi \;\times \;3 \times 10^9\; \times\; 10^{-9} \times \;9} \\\\\frac{\sigma}{\omega \epsilon} =3.32 \times 10^{-4}[/tex]
Therefore, the wet soil medium is a low-loss dielectric and its absorption (attenuation) coefficient is calculated by using this formula:
Note:
[tex]\alpha = \frac{\sigma}{2}\sqrt{\frac{\mu}{\epsilon}} \\\\\alpha = \frac{\sigma}{2} \times \frac{120\pi}{\sqrt{\epsilon_r} } \\\\\alpha =\frac{5 \times 10^{-4} \times 120\pi}{2 \times \sqrt{9} } \\\\[/tex]
α = 0.032 Np/m.
Now, we calculate the depth:
[tex]E(z) = E_oe^{-\alpha z} = 10e^{-\alpha z}\\\\10^{-3}=10e^{-0.032 z}\\\\ln(10^{-4})=-0.032 z\\\\-9.21 \times 10^9=-0.032z\\\\z=\frac{-92.1 0}{-0.032}[/tex]
z = 287.82 meters.
Read more on low-loss dielectric here: https://brainly.com/question/14167707
A 18-ft thick clay layer in the field (drained on one side) is normally consolidated. When the pressure is increase from 0.75 ton/ft^2 to 1.5 ton/ft^2, the void ratio decreases from 1.12 to 0.98. The hydraulic conductivity, k, of the clay during the above loading range was found to be 4.3 times 10^-7 cm/sec. a. How long (in days) will it take for the clay layer to reach 70% reach 70% consolidation? b. What is the settlement at that time (that is, at 70% consolidation)?
Answer:
a) 294.34 days
b) Δh = 25.361 cm
Explanation:
Given data:
Thickness of clay layer = 18 ft
initial pressure = 0.75 ton/ft^2
final pressure = 1.5 ton/ft^2
Δp = 0.75 ton/ft^2
eo = 1.12
e1 = 0.98
k = 4.3 * 10^-7 cm/sec
A ) determine how long it will take to reach 70% consolidation
attached below is the detailed solution
T( time in days ) = 294.34 days
B) determine settlement at 70%
attached below is the detailed solution
Δh = 25.361 cm
Suppose the working pressure for a boiler is 10 psig, then what is the corresponding absolute pressure?
Answer:
The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.
Explanation:
From Fluid Mechanics, we remember that absolute pressure ([tex]p_{abs}[/tex]), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is:
[tex]p_{abs} = p_{atm}+p_{g}[/tex] (1)
Where:
[tex]p_{atm}[/tex] - Atmospheric pressure, measured in pounds per square inch.
[tex]p_{g}[/tex] - Working pressured of the boiler (gauge pressure), measured in pounds per square inch.
If we suppose that [tex]p_{atm} = 14.696\,psi[/tex] and [tex]p_{g} = 10\,psi[/tex], then the absolute pressure is:
[tex]p_{abs} = 14.696\,psi+10\,psi[/tex]
[tex]p_{abs} = 24.696\,psi[/tex]
The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.
20 points and brainliest is it A, B, C, D
Which option identifies the informational resource that would be best to use in the following scenario?
When Daniel reached for a container of oil that someone had left on a high, hard-to-reach shelf, he accidently knocked over another container of liquid that spilled onto the floor. He was unsure of the second chemical's properties or how to clean it up.
A. the MSDS binder
B. the OSHA hotline
C. the poison control center
D. the machine shop manager
Answer:
c
Explanation:
A cylinder with a height-to-diameter ratio of unity solidifies in 10 minutes in a sand casting operation. What is the solidification time if the cylinder height is doubled? What is the time if the diameter is doubled? Use n=1.5.
Answer:
a) 13 mins
b) 18 mins
Explanation:
solidification time = 10 minutes
height-to-diameter ratio = 1
applying the expression for calculating solidification time
t = B [tex](\frac{V}{A} ) ^n[/tex] --------- ( 1 )
n = 1.5
B = ?
t = 10 minutes
V = [tex]\frac{\pi d^2}{4} H[/tex]
A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex]
back to equation 1
making B subject of the formula ; B = [tex]\frac{147}{d^{1.5} }[/tex]
a) Determine the solidification time if the cylinder height is doubled
t = B [tex](\frac{V}{A} ) ^n[/tex]
substitute : B = [tex]\frac{147}{d^{1.5} }[/tex] , H = 2D , V = [tex]\frac{\pi d^2}{4} H[/tex] , A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex] , n = 1.5
therefore ; t ( solidification time when height is doubled ) ≈ 13 mins
b) Determine the time if the diameter is doubled
t = B [tex](\frac{V}{A} ) ^n[/tex]
substitute ; B = [tex]\frac{147}{h^{1.5} }[/tex] , D = 2H , n = 1.5 , V = [tex]\frac{\pi d^2}{4} H[/tex], A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex]
therefore ; t ( solidification time when diameter is doubled ) ≈ 18 mins
What do engineers spend up to 25 percent of their design process formulating and analyzing?
the team that will work on the project
if a material is malleable
if a design will need a functional or superficial improvement
the perfect material for their design
Answer:
Engineers spend up to 25 percent of their design process formulating and analyzing
the team that will work on the project.
Explanation:
During the design engineering stage of a project, the team is a very important decision item because determining the required team also determines the cost and the technical skill requirements of the project. The cost depends, to a large extent, on the technical skills of those that will work on the project. When the technical skill requirements are not met, the project will be massively jeopardized.
Answer:
the team that will work on the project.
Explanation:
The beam below will be subjected to a live load of 600 lb/ft, a concentrated live load of 25 kip, and a dead load of 300 lb/ft. a) What is the maximum positive moment that can be produced at G? b) What is the maximum negative moment that can be produced at G?
Answer:
hello some part of your question is missing below is the complete question
answer :
A) 162750 Ib.ft
B) - 64950 Ib.ft
Explanation:
Applying Muller-Breslau's law
we will make assumptions which include assuming an imaginary hinge at G
therefore the height of I.LD for B.M at G = ( 12 * 8 ) / 20 = 4.8
height of I.L.D at C = 2.4 ( calculated )
height of I.L.D at F = 1.5 ( calculated )
A) Determine Maximum positive moment produced at G
[tex]M ^+[/tex] = [ (1/2 * 20 * 4.8 ) ( 600 + 300 ) ] + [ ( 25 * 4.8 * 10^3 ) ] - [ ( 1/2 *2.4*20 ) * 300 ] + [ (1/2 * 1.5 * 10 ) ( 600 + 300 ) ]
= 162750 Ib.ft
B) Determine the maximum negative moment produced at G
[tex]M ^-[/tex] = [ ( 1/2 * 20 * 4.8 ) * 300 ] - [ ( 1/2 * 2.4 * 20 ) ( 600 + 300 ) ] - [ (2.5 * 10^3 * 2.4 ) ] + [ ( 1/2 * 1.5 * 10) * 300 ]
= - 64950 Ib.ft
Ground effect is felt at a height that is equal to the plane's wingspan.
True or False
Answer:
True
Explanation:
What is one step taken when solving a computer software problem? making sure the power cord is plugged in properly scanning the computer and deleting any viruses searching for any spills or damage to the computer taking a look at all the cables and connectors when students have computer trouble they usually are expected to make any simple fixes on their own. solve complex issues by themselves. drop their school work until it is resolved. pay a technician a high fee to fix the issue.
Answer:
Answer: B) Scanning the computer and deleting any viruses.
Explanation:
Some of the feedback I hear from new developers working on a programming problem revolves around uncertainty of where to start. You understand the problem, the logic, basics of the syntax, etc. If you see someone else’s code or have someone to guide you, you can follow along. But maybe you feel uncertain about doing it yourself and have trouble turning your thoughts into code at first even though you understand the syntax or logic. Here’s my process and some tips to tackling a sample problem that hopefully some of you may find helpful in your journey.
If you need further expenation then:
Some of the feedback I hear from new developers working on a programming problem revolves around uncertainty of where to start. You understand the problem, the logic, basics of the syntax, etc. If you see someone else’s code or have someone to guide you, you can follow along. But maybe you feel uncertain about doing it yourself and have trouble turning your thoughts into code at first even though you understand the syntax or logic. Here’s my process and some tips to tackling a sample problem that hopefully some of you may find helpful in your journey.
May i please have brainliest
Answer:
B. scanning the computer and deleting any viruses
Explanation:
I took the test on edge, and this makes most sense to me. Good luck:)
A cyclist is turning the pedals of his bicycle at a speed of 60RPM while exerting a torque of 1 lb-ft. The input sprocket has 40 teeth. What is the number of teeth on the output sprocket, if the driven wheel is rotating at 240 RPM?
Answer:
10
Explanation:
The speed of the chain is the same for both sprockets.
vᵢ = vₒ
ωᵢ rᵢ = ωₒ rₒ
The sprockets have the same pitch, so the radius is proportional to the number of teeth. So we can say:
ωᵢ nᵢ = ωₒ nₒ
Plugging in values:
(60 rpm) (40) = (240 rpm) nₒ
nₒ = 10
The output sprocket has 10 teeth. This makes sense, if the output sprocket is 4 times smaller, it will turn 4 times faster than the input sprocket.
Answer: it is 10 teeth and the guy under me already explained soo
Explanation:
A steel rod of circular cross section will be used to carry an axial load of 89 kips. The maximum stresses in the rod must be limited to 31 ksi in tension and 14 ksi in shear. Determine the required diameter for the rod.
Answer:
d = 1.9 in
Explanation:
Since, the tension force is greater than the shear force. Hence, the area of cross-section shall be limited by the tension:
Tension = Force/Area
Area = Force/Tension
Area = 89 kips/31 ksi
Area = 2.87 in²
but,
Area = πd²/4
2.87 in² = πd²/4
(2.87 in²)(4)/π = d²
d = √(3.65 in²)
d = 1.9 in
A spur gearset has a module of 6 mm and a velocity ratio of 4. The pinion has 16 teeth. Find the number of teeth on the driven gear, the pitch diameters, and the theoretical center-to-center distance
Answer:
NG=64 teeth
dG=384mm
dP=96mm
C=240mm
Explanation:
step one:
given data
module m=6mm
velocity ratio VR=4
number of teeth of pinion Np=16
Step two:
Required
1. Number of teeth on the driven gear
[tex]N_G=N_P*V_R\\\\N_G=16*4\\\\N_G=64[/tex]
The driven gear has 64 teeth
2. The pitch diameters
The driven gear diameter
[tex]d_G=N_G*m\\\\d_G=64*6\\\\d_G=384[/tex]
The driven gear diameter is 384mm
The pinion diameter
[tex]d_P=N_P*m\\\\d_P=16*6\\\\d_P=96[/tex]
Pinion diameter is 96mm
3. Theoretical center-to-center distance
[tex]C=\frac{d_G+d_P}{2} \\\\C=\frac{384+96}{2} \\\\C=\frac{480}{2}\\\\C=240[/tex]
The theoretical center-to-center distance is 240mm
The results are listed below:
The driven gear has 64 teeth.The pinion has a diameter of 96 millimeters and the driven gear has a diameter of 384 millimeters.The theoretical center-to-center distance is 240 millimeters.First, we proceed to find the number of teeth of each gear ([tex]N_{D}, N_{P}[/tex]) based on the fact that gear only fit when they have the same module ([tex]m[/tex]). The velocity ratio ([tex]r_{v}[/tex]) is defined by the following relationship:
[tex]r_{v} = \frac{N_{D}}{N_{P}}[/tex] (1)
If we know that [tex]r_{v} = 4[/tex] and [tex]N_{P} = 16[/tex], then the number of teeth of the driven gear is:
[tex]N_{D} = r_{v}\cdot N_{P}[/tex]
[tex]N_{D} = 4\cdot (16)[/tex]
[tex]N_{D} = 64[/tex]
The driven gear has 64 teeth.
The pitch diameter ([tex]D[/tex]) is obtained by multiplying the number of teeth ([tex]N[/tex]) by module ([tex]m[/tex]), in milimeters.
Pinion
[tex]D_{P} = m\cdot N_{P}[/tex] (2)
([tex]m = 6\,mm[/tex], [tex]N_{P} = 16[/tex])
[tex]D_{P} = (6\,mm)\cdot (16)[/tex]
[tex]D_{P} = 96\,mm[/tex]
Driven gear
[tex]D_{D} = m\cdot N_{D}[/tex] (3)
([tex]m = 6\,mm[/tex], [tex]N_{D} = 64[/tex])
[tex]D_{D} = (6\,mm)\cdot (64)[/tex]
[tex]D_{D} = 384\,mm[/tex]
The pinion has a diameter of 96 millimeters and the driven gear has a diameter of 384 millimeters.
Lastly, the theoretical center-to-center distance is calculated by the following formula:
[tex]d = \frac{1}{2}\cdot (D_{P}+D_{D})[/tex] (4)
([tex]D_{P} = 96\,mm[/tex], [tex]D_{D} = 384\,mm[/tex])
[tex]d = \frac{1}{2}\cdot (96\,mm + 384\,mm)[/tex]
[tex]d = 240\,mm[/tex]
The theoretical center-to-center distance is 240 millimeters.
To learn more about gears, we kindly invite to check this verified question: https://brainly.com/question/15541463
A car is driven over a curb twice—once very slowly and once quite rapidly. What would you need to know about the car in the second case that you did not need to know in the first case if you were required to find the tire force that resulted from going over the curb?
Answer:
You'd need to know things like the weight of the car, the spring constant of the suspension springs.
Explanation:
Driving over the curb slowly does not have much of an "impact" because of the small potential energy it has but to find the force that results from going over the curb at a much higher speed, you would need to know the weight of the car since it directly impact the force that it applies. You also would need to know about the car's suspension, the spring material, how stiff the springs are and their spring constant to calculate the force they absorb.
I hope this answer helps.
Define ways in which you would go about networking to explore opportunities in your career field and obtain more information for yourself. If applicable, explain ways in which you have already done that and how you will expand going forward. Choose one person in your career field that you would like to have a conversation with. What do you think you can learn from this person?
Answer:
mmmmmm
Explanation:
ffmfmfmmfmfmmfmfmfmfmfmffmfmfmfmfmfmfmfmfmfmfmfmfffmmfmffmmmfmfmfmfmfmfmfmfffmfmfmfmfmfmmfmfmmfmfmfmfmfmfffmfmfffmfmfmfmffmmfmfmffmfmfmfmfffmfmfmfmfmmmmfmfmfmfmfmfmfmmmfmfmfmfmfmfmfmfmmfmfmfmfmfmfmfmfmfmfmffmfmfmfmfmfmmfmfmmmmmfmfmfmffmfmfmfmffmffmfm
A rigid tank contains 2 kg of N2 and 4 kg of Co2 at temperature of 25 C and 1 MPa. Find the partial pressure of each gas respectively?
Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: Dalton's Law of Partial Pressure states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:
[tex]P_{total} = P_{1}+P_{2}+...[/tex]
The proportion of each individual gas in the total pressure is expressed in terms of mole fraction:
[tex]X_{i}[/tex] = moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
Nitrogen gas:molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank: [tex]n=\frac{2000}{14}[/tex] = 142.85mols
Carbon Dioxide:molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank: [tex]n=\frac{4000}{44}[/tex] = 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:
[tex]P_{i}=P_{total}.X_{i}[/tex]
For Nitrogen gas:
[tex]P_{N_{2}}=1.\frac{142.85}{233.76}[/tex]
[tex]P_{N_{2}}[/tex] = 0.6
For Carbon Dioxide:
[tex]P_{total}=P_{N_{2}}+P_{CO_{2}}[/tex]
[tex]P_{CO_{2}} = P_{total}-P_{N_{2}}[/tex]
[tex]P_{CO_{2}}=1-0.6[/tex]
[tex]P_{CO_{2}}=[/tex] 0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.
Which of the following is used to estimate the size of a room?
A) Drop ceilings
B) Window frames
C) Bricks
D) Room trim
Answer:
I think the answer is drop ceilings
Explanation:
In powershell what commands do these:1. How can we find out the different membertypes (e.g. properties and methods) of the Get-Process cmdlet?2. How can we load the Storage module to the current session?3. How can we gather a list of only the SingularNoun for all the cmdlets currently available in our PS session? Please limit the list to only show the unique noun4. How can we display a list of all available modules that ends with the word "server"?
Answer:
Following are the solution to this question:
Explanation:
In question 1:
It Cmdlet gets the representatives of items, its features including their methods. Now use a variable (InputObject) and pipe the object to Even getting Member for both the purpose of specifying the object. It static variable utilizes their class members, not the case, to gather information regarding static members. Just use the (MemberType) parameter and receive only some forms of participants, such example NoteProperties.
In question 2:
Its Purchase cmdlet allows us to import components through our process. It can import components via remote sessions through the local client beginning with Window PowerShell 3.0.
In question 3:
The Syntax query to have all cmdlets lists it in the cmdlet title alphabetical order, but instead shows them in noun clauses.
Command:
[tex]\text{Type Cmdlet } | \text{Sort-Object -Property Noun} | \text{Format-Table -GroupBy Noun}[/tex]
In question 4:
Syntax:
[tex]\text{Get node} | \text{format list} | \text{Selection process, device forms, route group title all}[/tex]
[tex]| \text{Layout Table} | \text{Selection process}[/tex]
[tex]\$ s[/tex] = New-PSSession -ComputerName Server
Get-Module -PSSession [tex]\$ s[/tex] -ListAvailable
Water flows with an average velocity of 1.0 m/s and a normal depth of 0.5 m in a wide rectangular channel. Is the flow subcritical or supercritical?
Answer:
Subcritical
Explanation:
To compute the grouse number
We use this formula
F = v/√gy
From this question
V = 1 m
G = 9.81m/sec²
Y = 0.5
When we insert this into the grouse formula
F = 1m/s / √ 9.8m/sec² x 0.5m
= 0.451< 1
Therefore we conclude that the grouse is less than 1 and so the flow is subcritical.
which term describes how a mineral looks when it breaks apart in an irregular way
Answer:
Fracture.
Explanation:
Fracture describes how a mineral looks when it breaks apart in an irregular way.
Answer:
Fracture.
Explanation:Fracture describes how a mineral looks when it breaks apart in an irregular way.
When your workplace obtains new materials, you should add them to the chemical list:
Answer:
immediately
Explanation:
The larger the displacement of an engine, the less power it produces true or false
Answer: False
Explanation: