Chemistry High School

A sample of (NH4)2SO3 that contains 6 000 oxygen atoms must also contain how many hydrogen atoms?
Select one:
O a. 16 000
O b. 8 000
O c. 4000
O d. 6 000

Answers

Answer 1

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

In 1 molecule of [tex] \sf{(NH_4)_2SO_3} [/tex] has 3 molecules of Oxygen. but it is given that the sample contain 6000 Oxygen atoms. therefore, the number of molecules in the sample is ~

[tex]\qquad \sf  \dashrightarrow \: \dfrac{6000}{3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: 2000 \: \:molecules[/tex]

Now, there are 8 atoms of Hydrogen in each molecule, so total number of H - atoms in 2000 molecules of the given compound would have ~

[tex]\qquad \sf  \dashrightarrow \: 2000 \times 8[/tex]

[tex]\qquad \sf  \dashrightarrow \: 16000 \: \: H-atoms[/tex]

Related Questions

Which conclusion could be made from Ernest Rutherford’s gold foil experiment?
Atoms are made up of mostly empty space.
Atoms are mainly solid and block alpha particles.
The volume of the nucleus is large compared to the rest of the atom.
The mass of the nucleus is small compared to the rest of the atom.

Answers

Answer:

a. atoms are made up of mostly empty space.(this is because most of the atoms were able to pass through the gold foil undeflected)

Explanation:

Answer:

a. atoms are made up of mostly empty space

importance of mole ratio in solvey process

Answers

Answer:

Sry i accidently clicked on ''SAVE''.

U can remove it or report it...

Explanation:

Why is the earth so round

Answers

Answer:

Cause why not?

Explanation:

Because the waves of the North Pole and the South Pole keeps the shape of the Earth in balance.

If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
the new volume to the correct number of significant digits is:
O 3 ml
O 12mL
O 24 ml
O 13 ml
O none of these choices

Answers

Answer:

E. None of these

Explanation:

We know, By GAS laws,

PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

[tex]\frac{P1V1}{RT1}[/tex] = [tex]\frac{P2V2}{RT2}[/tex]

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

[tex]\frac{1*20}{R*10} = \frac{10*V2}{R*100}[/tex]

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

[tex]\frac{1*20*100}{10*10} = V2[/tex]

∴ V2 = [tex]\frac{2000}{100}[/tex]

∴ V2 = 20mL

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