The volume of the gas after it is heated is approximately 0.0417 liters.
To find the volume of the gas after it is heated, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law is expressed as:
(P₁V₁) / T₁ = (P₂V₂) / T₂
Where:
P₁ and P₂ are the initial and final pressures of the gas (in kPa)
V₁ and V₂ are the initial and final volumes of the gas (in liters)
T₁ and T₂ are the initial and final temperatures of the gas (in Kelvin)
Given:
Initial volume (V₁) = 3.56 L
Initial temperature (T₁) = ST (which is typically 273.15 K)
Final temperature (T₂) = 400 K
Final pressure (P₂) = 125 kPa
Now we can plug these values into the combined gas law equation and solve for V₂:
(P₁V₁) / T₁ = (P₂V₂) / T₂
(1 * 3.56) / 273.15 = (125 * V₂) / 400
(3.56 / 273.15) = (125 * V₂) / 400
Cross-multiplying and solving for V₂:
3.56 * 400 = 273.15 * 125 * V₂
1424 = 34143.75 * V₂
V₂ = 1424 / 34143.75
V₂ ≈ 0.0417 L
As a result, the heated gas has a volume of approximately 0.0417 litres.
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A 52-card deck contains 13 cards from each of the four suits: clubs ♣, diamonds ♦, hearts ♥, and spades ♠. You deal four cards without replacement from a well-shuffled deck so that you are equally likely to deal any four cards.
What is the probability that all four cards are clubs?
13/52 ⋅ 12/51 ⋅ 11/50 ⋅ 10/49 ≈0.0026
13/52 ⋅ 12/52 ⋅ 11/52 ⋅ 10/52 ≈0.0023
1/4 because 1/4 of the cards are clubs
The probability that all four cards are clubs is approximately 0.0026. Option A.
To understand why, let's break down the calculation. In a well-shuffled deck, there are 13 clubs out of 52 cards.
When dealing the first card, there are 13 clubs out of the total 52 cards, so the probability of getting a club on the first draw is 13/52.
For the second card, after the first club has been removed from the deck, there are now 12 clubs left out of the remaining 51 cards. Therefore, the probability of getting a club on the second draw is 12/51.
Similarly, for the third card, after two clubs have been removed, there are 11 clubs left out of the remaining 50 cards. The probability of drawing a club on the third draw is 11/50.
Finally, for the fourth card, after three clubs have been removed, there are 10 clubs left out of the remaining 49 cards. The probability of drawing a club on the fourth draw is 10/49.
To find the probability of all four cards being clubs, we multiply the probabilities of each individual draw:
(13/52) * (12/51) * (11/50) * (10/49) ≈ 0.0026.
This calculation takes into account the fact that the deck is being dealt without replacement, meaning that the number of available clubs decreases with each draw.
The third option, 1/4, is incorrect because it assumes that each card dealt is independent and has an equal probability of being a club. However, as cards are drawn without replacement, the probability changes with each draw. So Option A is correct.
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Note the complete question is
A 52-card deck contains 13 cards from each of the four suits: clubs ♣, diamonds ♦, hearts ♥, and spades ♠. You deal four cards without replacement from a well-shuffled deck so that you are equally likely to deal any four cards.
What is the probability that all four cards are clubs?
A.) 13/52 ⋅ 12/51 ⋅ 11/50 ⋅ 10/49 ≈0.0026
B.) 13/52 ⋅ 12/52 ⋅ 11/52 ⋅ 10/52 ≈0.0023
C.) 1/4 because 1/4 of the cards are clubs
joan’s finishing time for the bolder boulder 10k race was 1.81 standard deviations faster than the women’s average for her age group. there were 410 women who ran in her age group. assuming a normal distribution, how many women ran faster than joan? (round down your answer to the nearest whole number.)
Question #4
Find the measure of the indicated arc.
160 °
D
R
?
U
S
56°
T
Answer:
D. 48
Step-by-step explanation:
When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.
56 = 1/2(160 - ?)
112 = 160 - ?
? = 160 - 112 = 48
A national dog show had two types of poodles. This table
shows height data, in inches, for the two types of poodles.
Heights of Poodles
Type of Poodle
Miniature
Standard
Number of Dogs
18
24
Mean Height Variation in Height
(inches)
(inches)
13
23
2
2
What number completes the sentence?
The difference in inches, between the mean height for the two
types of poodles is
times the variation for
either type.
Enter your answer in the space provided.
Use the formulas to answer this question.
One leg of a right triangle has length 11 and all sides are whole numbers. Find the lengths of the other two sides.
The other leg = and the hypotenuse =
The lengths of the other two sides of the right triangle are 36 and 85, respectively.
To find the lengths of the other two sides of a right triangle when one leg has a length of 11, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
Let's denote the lengths of the other leg and the hypotenuse as x and y, respectively.
According to the Pythagorean theorem, we have:
x² + 11² = y²
To find the values of x and y, we need to find a pair of whole numbers that satisfy this equation.
We can start by checking for perfect squares that differ by 121 (11^2). One such pair is 36 and 85.
If we substitute x = 36 and y = 85 into the equation, we have:
36² + 11² = 85²
1296 + 121 = 7225
This equation is true, so the lengths of the other two sides are:
The other leg = 36
The hypotenuse = 85
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Pls help I beg thank you
Answer:
8cm
Step-by-step explanation:
perimiter A = 11+11+4+4=30
perimiter B = 4+4+8+8=24
24+30=54
perimeter c =4+8+8+4+11+7+4=46
so perimiter of c is 8cm shorter than A and B total
hope this helps
Which of the following is equal to the fraction below? (7/4)11
Answer:
It's A
Step-by-step explanation:
Use the following models to show the equivalence of the fractions 35 and 610 a) Set model
Use the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set modelUse the following models to show the equivalence of the fractions 35 and 610 a) Set model
F(x)=square root of 9-kx^2/k show your work
Sure! Here’s the solution:
F(x)=k9−kx2
First, let’s square both sides to get rid of the square root:
F(x)2=k9−kx2
Now, let’s multiply both sides by k to isolate the term with x^2:
kF(x)2=9−kx2
Next, let’s move all terms to one side of the equation:
kF(x)2+kx2=9
Finally, let’s factor out x^2:
x2(k+kF(x)2)=9
And solve for x^2:
x2=k+kF(x)29
Answer:
√((9 - kx^2) / k)Step-by-step explanation:
To show the work for evaluating the function f(x) = √(9 - kx^2) / k, we can follow these steps:
Step 1: Simplify the expression under the square root:9 - kx^2
Step 2: Divide the expression by k:(9 - kx^2) / k
Step 3: Take the square root of the expression:√((9 - kx^2) / k)
Note: It is important to consider any domain restrictions or assumptions about the values of k and x that would make the expression valid. For example, if k is negative, the expression would have an imaginary result.If the left-hand limit of is equal to the right-hand limit of as x approaches 10, the limit of as x approaches 10 is and the value of k is .
The limit of f(x) as x approaches 10 is 315 and The value of k is 250.
The function f(x) is a piecewise function, so we need to evaluate it separately for x < 10 and x >= 10.
[tex]f(x)= { \frac{(0.1x(2)+20x+15,x < 10)}{(0.25x(3)+k,x > 10)}[/tex]
For x < 10, the function is equal to 0.1x^2 + 20x + 15. So the left-hand limit of f(x) as x approaches 10 is equal to 0.1(10)^2 + 20(10) + 15 = 315.
For x >= 10, the function is equal to 0.25x^3 + k. So the right-hand limit of f(x) as x approaches 10 is equal to 0.25(10)^3 + k = 250 + k.
Since the left-hand limit and the right-hand limit are equal, the limit of f(x) as x approaches 10 is also equal to 315, and the value of k is equal to 250.
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(a) The average cost in 2011 is $2247.64.
(b) A graph of the function g for the period 2006 to 2015 is: C. graph C.
(c) Assuming that the graph remains accurate, its shape suggest that: A. the average cost increases at a slower rate as time goes on.
How to estimate the average cost in 2011?Based on the information provided, we can logically deduce that the average annual cost (in dollars) for health insurance in this country can be approximately represented by the following function:
g(x) = -1736.7 + 1661.6Inx
where:
x = 6 corresponds to the year 2006.
For the year 2011, the average cost (in dollars) is given by;
x = (2011 - 2006) + 6
x = 5 + 6
x = 11 years.
Next, we would substitute 11 for x in the function:
g(11) = -1736.7 + 1661.6In(11)
g(11) = $2247.64
Part b.
In order to plot the graph of this function, we would make use of an online graphing tool. Additionally, the years would be plotted on the x-axis while the average annual cost would be plotted on the x-axis of the cartesian coordinate as shown below.
Part c.
Assuming the graph remains accurate, the shape of the graph suggest that the average cost of health insurance increases at a slower rate as time goes on.
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PLS HELP WILL GIVE BRAINLIEST IF CORRECT (NO LINKS)
Identity m∠PKJ.
Answer:
measure of arc JL = 55°
measure of angle PKJ = 27.5°
what is the period of y=cos x?
The cosine function repeats its pattern every 2π radians (or 360 degrees), we can say that the period of y = cos(x) is 2π.
The period of the function y = cos(x) is 2π.
To understand the period of the cosine function, we need to examine its graph. The cosine function is a periodic function that oscillates between -1 and 1 as x varies. It repeats its pattern over regular intervals.
The cosine function completes one full cycle from 0 to 2π radians (or 0 to 360 degrees). This means that within this interval, the cosine function goes through one complete oscillation, starting from its maximum value of 1, then going through its minimum value of -1, and returning back to 1.
Since the cosine function repeats its pattern every 2π radians (or 360 degrees), we can say that the period of y = cos(x) is 2π.
This means that for any value of x, the value of cos(x) will repeat after an interval of 2π.
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Answer:
(a) The graph is entirely above the x-axis and rises from left to right, more steeply than the graph of y = 5^x.
(b) The second coordinate of the point with first coordinate 0 is 2.
The second coordinate of the point with first coordinate 1 is 10.
measure abc bac=40degree abc=20degree ab=7cm
The length of side BC is approximately 3.725 cm.
In triangle ABC, we are given that angle BAC is 40 degrees, angle ABC is 20 degrees, and side AB measures 7 cm. We need to find the length of side BC.
To solve this problem, we can use the law of sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides.
Applying the law of sines, we have:
sin(ABC) / BC = sin(BAC) / AB
Since sin(ABC) = sin(20 degrees) and sin(BAC) = sin(40 degrees), we can substitute these values into the equation:
sin(20 degrees) / BC = sin(40 degrees) / 7 cm
Now, we can rearrange the equation to solve for BC:
BC = (7 cm * sin(20 degrees)) / sin(40 degrees)
Using a calculator to evaluate the trigonometric functions, we find that sin(20 degrees) ≈ 0.3420 and sin(40 degrees) ≈ 0.6428. Substituting these values into the equation:
BC ≈ (7 cm * 0.3420) / 0.6428
BC ≈ 3.725 cm
Therefore, the length of side BC is approximately 3.725 cm.
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The group of individuals fitting a description is the _____
A.census
B.sample
C.parameter
D.population
The group of individuals fitting a description is called option D: Population, this is because, in statistics, a population is seen as am entire group of individuals, items, or elements that tends to have or share a common characteristics.
What is population?The term "population" describes the complete group of people or things that you are interested in investigating. It is the group of individuals or thing(s) about which you are attempting to draw conclusions.
There are infinite and finite populations. A population with a set quantity of people or things is said to be finite. An endless population is one that has an infinite amount of people or things.
Therefore, the correct option is D
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See full text below
A group of individuals fitting a description is the _____
Which of the term below fit the description above.
A.census
B.sample
C.parameter
D.population
The expression
28 (78-14)9-13(78-49)9
can be
rewritten as
(X-y)" (262 + y? + gxy). Whatis the value of p?
Answer:
p =1 0
Step-by-step explanation:
x³(x - y)⁹ - y³(x - y)⁹ = (x - y)⁹[x³ - y³]
= (x - y)⁹(x - y)(x² + y² + xy)
= (x - y)¹⁰(x² + y² + xy)
where p = 10 and q = 1
Answer:
p = 10
Step-by-step explanation:
Given expression:
[tex]x^3(x-y)^9 - y^3(x-y)^9[/tex]
Factor out the common term (x - y)⁹:
[tex](x-y)^9(x^3- y^3)[/tex]
[tex]\boxed{\begin{minipage}{5cm}\underline{Difference of two cubes}\\\\$x^3-y^3=(x-y)(x^2+y^2+xy)$\\\end{minipage}}[/tex]
Rewrite the second parentheses as the difference of two cubes.
[tex](x-y)^9(x-y)(x^2+y^2+xy)[/tex]
[tex]\textsf{Apply\:the\:exponent\:rule:} \quad a^b\cdot \:a^c=a^{b+c}[/tex]
[tex](x-y)^{9+1}(x^2+y^2+xy)[/tex]
[tex](x-y)^{10}(x^2+y^2+xy)[/tex]
Comparing the rewritten original expression with the given expression:
[tex](x-y)^{10}(x^2+y^2+xy)=(x-y)^p(x^2+y^2+qxy)[/tex]
We can see that [tex](x-y)^p[/tex] corresponds to [tex](x-y)^{10}[/tex] in the given expression.
Therefore, we can conclude that p = 10.
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21. Determine whether CD || AB. Explain your reasoning.
Reason:
If CD was parallel to AB, then triangles CDE and ABE would be similar. In turn it would mean that EA/EC = EB/ED is a true proportion.
Let's calculate each side separately.
EA/EC = 28/(28+20) = 0.5833EB/ED = 16/(16+10) = 0.6154Both decimal values are approximate.
The two values don't match up which makes EA/EC = EB/ED to be false.
Since EA/EC = EB/ED is false, we know that triangles CDE and ABE are not similar. Therefore, CD is not parallel to AB.
Answer:
CD is not parallel to AB
Step-by-step explanation:
According to the Side Splitter Theorem, if a line parallel to one side of a triangle intersects the other two sides, then this line divides those two sides proportionally.
Therefore, if CD is parallel to AB, then EA : AC = EB : BD.
Substitute the values of the line segments into the equation:
[tex]\begin{aligned}EA : AC &= EB : BD\\\\28:20&=16:10\\\\\dfrac{28}{20}&=\dfrac{16}{10}\\\\1.4 &\neq 1.6\end{aligned}[/tex]
As 1.4 does not equal 1.6, then CD is not parallel to AB.
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The perimeter of a shape is 15 cm and the area is 25 cm^2
Find the area of the larger shape if it is being enlarged by a scale factor of 6
Answer:
900 cm²--------------------------
Area is the product of two dimensions hence the ratio of areas of similar figures is the square of the scale factor.
Let the area of the enlarged shape be A, and the scale factor be k = 6.
Then we have the area of the larger shape:
A = 25*k²A = 25*6²A = 900 cm²Evaluate. -15 +7-(-8)
The answer options are
16
0
-16
-3
Answer:
To evaluate -15 + 7 - (-8), we can simplify the expression by first removing the double negative.
-15 + 7 + 8 = 0
Therefore, the answer is 0.
Step-by-step explanation:
The answer is:
0Work/explanation:
Remember the integer rule,
[tex]\bullet\phantom{4444}\sf{a-(-b)=a+b}[/tex]
Similarly
[tex]\sf{-15+7-(-8)}[/tex]
[tex]\sf{-15+15}[/tex]
Simplify fully.
[tex]\sf{0}[/tex]
Therefore, the answer is 0.6
Dani makes a picture of a tree.
The tree is made up of a green triangle,
two congruent green trapeziums
and a brown square.
Find the area of the green part of the tree.
12 cm
6 cm
4 cm
7 cm
cm²
The area of the green part of the tree is 55. 5cm²
How to determine the areaThe formula for area of a triangle is given as;
Area = 1/2bh
Substitute the values, we have;
Area = 1/2 × 6 × 7
Area = 21cm²
Area of trapezium is expressed as;
Area = a + b/2 h
Substitute the values, we have;
Area = 5 + 7/2 (3) + 4 + 7/2 (3)
expand the bracket, we have;
Area = 18 + 16.5
Area = 34.5 cm²
Total area = 34.5 + 21 = 55. 5cm²
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[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Answer:
[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Step-by-step explanation:
[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Answer:
[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[
Step-by-step explanation:
what this is?
Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 95 degrees and the low temperature of 75 degrees occurs at 6 AM. Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.
Answer:
Yes, a sinusoidal function is a great way to model temperatures over a 24-hour period because the pattern of temperature changes tends to be cyclic.
A sinusoidal function can be written in the general form:
D(t) = A sin(B(t - C)) + D
where:
- A is the amplitude (half the range of the temperature changes)
- B is the frequency of the cycle (which would be `2π/24` in this case because the temperature completes a full cycle every 24 hours)
- C is the horizontal shift (which is determined by the fact that the minimum temperature occurs at 6 AM)
- D is the vertical shift (which is the average of the maximum and minimum temperature)
Given the information you've provided, let's fill in the specifics:
- The high temperature for the day is 95 degrees.
- The low temperature is 75 degrees at 6 AM.
The amplitude, A, is half the range of temperature changes. It's the difference between the high and the low temperature divided by 2:
A = (95 - 75) / 2 = 10
The frequency, B, is `2π/24` because the temperature completes a full cycle every 24 hours.
The horizontal shift, C, is determined by the fact that the minimum temperature occurs at 6 AM. The sine function hits its minimum halfway through its period, so we want to shift the function to the right by 6 hours to make this happen. In our case, this means C = 6.
The vertical shift, D, is the average of the maximum and minimum temperature:
D = (95 + 75) / 2 = 85
So the equation for the temperature, D, in terms of t (the number of hours since midnight) is:
D(t) = 10 sin((2π/24) * (t - 6)) + 85
This equation represents a sinusoidal function that models the temperature over a day given the information provided.
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Please help with 35
Answer:
x = 4
Step-by-step explanation:
By property, if two tangents are drawn from an external point , then they are equal
⇒ 2x + 3 = 11
⇒ 2x = 11 - 3
⇒ 2x = 8
⇒ x = 8/2
⇒ x = 4
Answer:
x = 4
Step-by-step explanation:
To find the value of x, we can use the Two-Tangent Theorem.
The Two-Tangent Theorem states that if two tangent segments are drawn to a circle from the same external point, the lengths of the two tangent segments are equal.
Therefore:
[tex]\begin{aligned}AD &= AB\\\\2x+3&=11\\\\2x+3-3&=11-3\\\\2x&=8\\\\\dfrac{2x}{2}&=\dfrac{8}{2}\\\\x&=4\end{aligned}[/tex]
Therefore, the value of x is 4.
Determine the surface area and volume
The surface area of the cone is: 213.66 cm²
The volume of a cone is: 7.33 cm³
How to find the surface area and volume?The formula for the surface area of a cone is:
T.S.A = πrl + πr²
where:
r is radius
l is slant length
From the diagram and using Pythagoras theorem,we have:
l = √(7² + 5²)
l = √74
Thus:
TSA = (π * 5 * √74) + (π * 5²)
TSA = 213.66 cm²
Formula for the volume of a cone is:
V = ¹/₃πr²
V = ¹/₃π * 7
V = 7.33 cm³
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Seventy-Two Inc., a developer of radiology equipment, has stock outstanding as follows: 80,000 shares of cumulative preferred 3% stock, $20 par and 410,000 shares of $25 par common. During its first four years of operations, the following amounts were distributed as dividends: first year, $31,000; second year, $73,000; third year, $80,000; fourth year, $120,000. Determine the dividends per share on each class of stock for each of the four years. Round all answers to two decimal places. If no dividends are paid in a given year, enter "0.00". 1st Year 2nd Year 3rd Year 4th Year Preferred stock (dividends per share) $fill in the blank 1 $fill in the blank 2 $fill in the blank 3 $fill in the blank 4 Common stock (dividends per share)
I'm unable to solve question 1 and 3 could anyone help me?
Answer:
Step-by-step explanation:
pic is not clear
Which property is illustrated by the following statement? If A ABC = A DEF,
and ADEF=AXYZ, then AABC=AXYZ.
B.
A
с
E
D
O A. Reflexive
O B. Symmetric
O C. Transitive
O D. Commutative
F
Z
The property that is illustrated by the statements is Transitive. Option C
How to determine the propertyUsing the principle of transitivity, if two objects are equal to a third, they are also equal to one another.
From the information given, we have that;
< ABC = <DEF
< DEF = < XYZ
This simply proves that < ABC and < XYZ are both equivalent to < DEF in this situation.
By using the transitive property, we can determine that A ABC and A XYZ are also equal. This attribute enables us to construct relationships between many elements based on their equality to a shared third element and to connect logically equalities.
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Five angels of a hexagon are 123,124,118,130’110. Calculate the six angle
Answer:
The sixth angle is 115°.
Step-by-step explanation:
Number of sides in a hexagon = n =6
Sum of interior angles = (n−2)180°
= (6−2)180 ∘
= 720
∴ Let the six angle of hexagon be x.
⇒ x + 123 + 124 + 118 + 130 + 110 = 720°
⇒ x + 605 = 720°
⇒ x = 720 - 605
⇒ x = 115
The statement of cash flows for Baldwin shows what happens in the cash account during the year. It can be seen as a summary of the sources and uses of cash. Pleas answer which of the following is true if Baldwin issues bonds
In December 2016 the average price of unleaded