a rectangle with a perimeter of 30 centimeters is twice as long as it is wide. what is the area of the rectangle in square centimenters?

prefix kilo means 1000

so 1 kilogram = 1000 grams

14 kilograms = 14000 grams

14000 g > 1600 g

Maria's suitcase has a greater mass because 14,000 grams is greater than 1,600 grams.

Answer:

5 inches

Step-by-step explanation:

the length of painting is 56/7 = 8in. to find the length of the 2nd painting divide the area by the width: 40/8 = 5

The surface area of the cube with a side length of 2 units is 24 units squared

The side length of the cube is given as:

l = 2

The surface area is calculated as:

Surface area = 6l^2

This gives

Surface area = 6 *2^2

Evaluate

Surface area = 24

Hence, the surface area of the cube is 24 unit squared

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LSA

The coordinate grid of the ordered pair is gotten from the combination of the y and X axis of the graph.

Using the coordinates, an ordered pair for the given point is:

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Answer:

around 904.78

Step-by-step explanation:

i got 904.78 but i cant read the answers properly so choose the closest one

This is an identity used to determine the measure of sides and angles of a triangles. The value of x from the given diagram is 7.18 units

This is an identity used to determine the measure of sides and angles of a triangles

From the given triangle

Opposite =  5.5

Hypotenuse = x

According to the theorem

sin 50 = 5.5/H

x = 5.5/sin50

x = 7.18units

Hence the value of x from the given diagram is 7.18 units

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Answer:

[tex]\boxed{ \sf x=\dfrac{4\pm\sqrt{43}}{2}}[/tex]

Explanation:

[tex]\rightarrow \sf \dfrac{1}{x-5}+\dfrac{3}{x+2}=4[/tex]

make the denominators same

[tex]\rightarrow \sf \dfrac{1(x+2)}{(x-5)(x+2)}+\dfrac{3(x-5)}{(x+2)(x-5)}=4[/tex]

join the fractions together

[tex]\rightarrow \sf \dfrac{x+2+3x-15}{(x-5)(x+2)}=4[/tex]

cross multiply

[tex]\rightarrow \sf x+2+3x-15=4(x-5)(x+2)[/tex]

simplify

[tex]\rightarrow \sf 4x-13=4x^2-12x-40[/tex]

group the variables

[tex]\rightarrow \sf 4x^2-16x-27 = 0[/tex]

use quadratic formula

[tex]\rightarrow \sf x = \dfrac{-\left(-16\right)\pm \sqrt{\left(-16\right)^2-4\cdot \:4\left(-27\right)}}{2\cdot \:4}[/tex]

simplify the following

[tex]\rightarrow \sf x=\dfrac{4\pm\sqrt{43}}{2}[/tex]

Answer:

[tex]x=\dfrac{4 \pm \sqrt{43}}{2}[/tex]

Step-by-step explanation:

Given equation:

[tex]\dfrac{1}{(x-5)}+\dfrac{3}{(x+2)}=4[/tex]

Make the denominators of the algebraic fractions the same, then combine them into one fraction:

[tex]\begin{aligned}\implies \dfrac{1}{(x-5)} \cdot \dfrac{(x+2)}{(x+2)}+\dfrac{3}{(x+2)}\cdot \dfrac{(x-5)}{(x-5)} & =4\\\\\implies \dfrac{x+2}{(x-5)(x+2)}+\dfrac{3(x-5)}{(x-5)(x+2)} & = 4\\\\ \implies \dfrac{x+2+3(x-5)}{(x-5)(x+2)} & = 4\\\\ \implies \dfrac{4x-13}{(x-5)(x+2)} & = 4 \end{aligned}[/tex]

Multiply both sides of the equation by [tex](x-5)(x+2)[/tex]:

[tex]\begin{aligned}\implies \dfrac{(4x-13)}{(x-5)(x+2)}\cdot (x-5)(x+2) & = 4(x-5)(x+2)\\\\\dfrac{(4x-13)(x-5)(x+2)}{(x-5)(x+2)} & = 4(x-5)(x+2)\\\\4x-13 & = 4(x-5)(x+2)\\\\4x-13 & =4x^2-12x-40\\\\4x^2-16x-27 & = 0\end{aligned}[/tex]

Solve using the Quadratic Formula:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when}\:ax^2+bx+c=0[/tex]

[tex]\implies a=4\\\implies b=-16\\\implies c=-27[/tex]

Therefore:

[tex]\implies x=\dfrac{-(-16) \pm \sqrt{(-16)^2-4(4)(-27)} }{2(4)}[/tex]

[tex]\implies x=\dfrac{16 \pm \sqrt{688}}{8}[/tex]

[tex]\implies x=\dfrac{16 \pm 4 \sqrt{43}}{8}[/tex]

[tex]\implies x=\dfrac{4 \pm \sqrt{43}}{2}[/tex]

Step-by-step explanation:

2.718281828459045…

Euler's Number 'e' is a numerical constant used in mathematical calculations. The value of e is 2.718281828459045…so on. Just like pi(π), e is also an irrational number.

(a) The precision of this measurement is 17.64 mm ± 0.01 mm.

(b) he uncertainty of the measurement is 0.057%.

(c) The tolerance of the measurement is 0.02 mm.

(d) The acceptable diameter in the format, nominal value uncertainty is 17.64 mm ± 0.057%.

A micrometer screw gauge is used in the measurement of a wire. The measuring accuracy of a micrometer screw gauge is 0.01 mm.

The precision of the measurement is 17.64 ± 0.01 mm.

The uncertainty of the measurement is calculated as follows;

uncertainty = (error/actual measurement) x 100%

uncertainty =  (0.01/17.64) x 100% = 0.057%

Tolerance = maximum measurement - minimum measurement

                 = (17.64 + 0.01)mm - (17.64 - 0.01)mm

                 = 0.02 mm

0.057% of 17.64 mm = 0.01 mm

Range of uncertainty = (17.64 mm - 0.01 mm) to (17,64 mm + 0.01 mm)

                                    = 17.63 mm to 17.65 mm

Acceptable diameter format, = 17.64 mm ± 0.057%

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When Leonardo and his wife file married filing jointly in 2021, the average tax rate will be 15.63 percent

In the question above, Leonardo's taxable income = $80,000

Theresa's taxable income = $15,000

Total taxable income for both of them will be:

$ 80,000 + $ 50,000 = $ 130,000

When you make use of the Schedule Y-1,

The amount of the tax on total income shall be said as:

Tax liability = $9,086 + (($130,000 - $78,950) * 22%)

= $9,086 +($51,050 * 22%)

= $9,086 + $11,231

= $ 20,317

To get the Effective tax rate, it will be:

= tax liability / Total taxable income Effective tax rate

= [tex]\frac{20,317}{30000}[/tex]  that is also written as $20,317/ $130,000

So, the  average tax rate is = 15.63%

Therefore, the average tax rate will be = 15.63 percent

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Answer: The original price of the fridge is $585

Explanation:

Given she discounts all prices of the fridges by 20%

This 20% is the reduced price of the original cost.

Solve for per unit:

20% ⇒ $117

1% ⇒ $(117/20) = $5.85

Recall, the original price is always of 100%

100% ⇒ $5.85 × 100 = $585

Answer:

$585

Step-by-step explanation:

If there is a discount of 20% and the price is reduced by $117, then that means :

Since both α and β are in the first quadrant, we know each of cos(α), sin(α), cos(β), and sin(β) are positive. So when we invoke the Pythagorean identity,

sin²(x) + cos²(x) = 1

we always take the positive square root when solving for either sin(x) or cos(x).

Given that cos(α) = √11/7 and sin(β) = √11/4, we find

sin(α) = √(1 - cos²(α)) = √38/7

cos(β) = √(1 - sin²(β)) = √5/4

Now, recall the sum identity for cosine,

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

It follows that

cos(α + β) = √11/7 × √5/4 - √38/7 × √11/4 = (√55 - √418)/28

Answer: 8.5

Step-by-step explanation:

By the intersecting chords theorem,

[tex]17(12)=24x\\204=24x\\x=\boxed{8.5}[/tex]

Answer:

The angle Sita here is called Amplitude

Answer:

8

Step-by-step explanation:

martha conto 10 de 20 personas con ojos cafes, eso quiere decir que 50 por ciento de los contados tenien ojos cafès, 50 porciento de 16 es 8

Answer: 15120

Step-by-step explanation:

Given: The number of players at point guard = 10

The number of players at shooting guard = 12

The number of players at small forward = 7

The number of players at power forward = 2

The number of players at center = 9

Then, the number of different teams William could draft is given by :-

10∗12∗7∗2∗9=15120

Hence, William could draft 15120 different teams.

Answer:

1600

Step-by-step explanation:

[tex]\text{Number of terms}, ~n = 40\\\\\text{Sum of n odd integers} = n^2 = 40^2 = 1600[/tex]

The value of the expression 7xy-y+x-1, when x = -2 and y = -1 is 12.

To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number.

To evaluate the given mathematical expression, we substitute the values of the unknown into the expression.

Substitute these values into the expression

Therefore,

Applying BODMAS,

Hence, the evaluation of  7xy-y+x-1 is 12

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Answer:

414

Step-by-step explanation:

312+352+480+392+368+352+416+640 divided by 8 = 414

Answer:

Multiply:

[tex](x+y)by (x+y)[/tex]

[tex] : \implies(x + y)(x + y)[/tex]

[tex] : \implies \: x(x + y) + y(x + y)[/tex]

[tex] : \implies {x}^{2} + xy + xy + {y}^{2} [/tex]

[tex] : \implies{x}^{2} + 2xy + {y}^{2} [/tex]

Multiply:

[tex]a+b \: by \: a^2-b^2[/tex]

[tex]: \implies( {a}^{2} + {b}^{2} ) \times (a + b)[/tex]

[tex]: \implies \: {a}^{2} (a + b) - {b}^{2} (a + b)[/tex]

[tex]: \implies \: {a}^{3} + {a}^{2} b - {ab}^{2} - {b}^{3} [/tex]

Multiply:

[tex](a+5) by (a^2-2a-3)[/tex]

[tex]: \implies{(a + 5) \times ( {a}^{2} - 2a - 3) }[/tex]

[tex]: \implies \: a({a}^{2} - 2a - 3) + 5( {a}^{2} - 2a - 3)[/tex]

[tex]: \implies(a \times {a}^{2} - a \times 2a - a \times 3) + (5 \times {a}^{2} - 5 \times 2a - 5 \times 3)[/tex]

[tex]: \implies{a}^{3} - {2a}^{2} - 3a + 5 {a}^{2} - 10a - 15 [/tex]

[tex]: \implies{ {a}^{3} + {3a}^{2} - 13a - 15}[/tex]

Multiply:

[tex](a^2-ab+b^3) by (a+b)[/tex]

[tex]: \implies{(a + b) \times ( {a}^{2} - ab + {b}^{3} )}[/tex]

[tex]: \implies \: a( {a}^{2} - ab + {b}^{3}) + b( {a}^{2} - ab + {b}^{3} ) [/tex]

[tex]: \implies {a}^{3} - {a}^{2} b + a {b}^{3} + {a^2b} - {ab}^{2} + {b}^{4} [/tex]

[tex]: \implies{ {a}^{3}+ab^3 - ab^2+ {b}^{4} }[/tex]

Step-by-step explanation:

[tex] \blue{ \frak{Seolle_{aph.rodite}}}[/tex]

Answer:

2 hours

Step-by-step explanation:

Mike has a six hour head start so he is    6 x 2 = 12 miles ahead

 their 'closing speed' is  8-2 = 6 m/hr

    it will take Kim   12 / 6  = two hours to catch Mike

Step-by-step explanation:

I hope this will help you

Answers:

Problem #1: Option C, 166 yards cubed

Problem #2:  Option A, 10

Step-by-step solution:

The first problem may seem a lot more confusing that it really is and this actually happened to me when I looked at it.  Just because the cylinder is slanted that actually doesn't change any of the volume that we would have if it was straight up with the same diameter and height.

Using what we know about cylinders, let us plug all the information inside of the formula to determine the volume of the cylinder.  However, before doing that we need to determine the radius of the circle from the diameter that was given.

Divide the diameter by two to get the radius

Plug in the values

Simplify the exponent

Simplify the expression

Therefore, after simplifying the expression using the cylinder volume formula and the given information we were able to determine that the option that best fits the description of our answer is option C, 166 cube yards.

Now that we completed the first question, we can move onto the second question.  In this question we are given a figure along with 3 numbers and one unknown, x, which we need to find the value of.  We need to use the Secant-Secant Power Theorem to help determine our solution.

Make an expression to represent the scenario

We know have an expression which we can now simplify and get the value of the unknown easily.  The first step would be to distribute the 32 and 28.

Distribute both sides

Simplify the expression

We now have a simple expression where we can now subtract both sides by 1024 to help isolate x with its coefficient.

Subtract 1024 from both sides

The final step that we have to help fully isolate x by itself is to divide both sides by 32 which would remove the coefficient from x.

Divide both sides by 32

After simplifying the expression completely, we are able to see that the best option that fits our description is option A, 10.

The kind of annuity does Lila own is: variable immediate annuity.

Variable immediate annuity can be defined as the type of annuity that vary or fluctuate based on the type of investment you choose or pick.

In this type of annuity the payment you will receive will not be fixed  reason being that payments that will made to you will always increase or decrease.

Therefore the kind of annuity does Lila own is: variable immediate annuity.

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The amount of the interest with simple interest of 6.9% will be $ 10.35.

Simple interest is the concept that is used in many companies such as banking, finance, automobile, and so on.

Miguel Rodriguez borrowed ​$300 from his brother Julio to pay for books and tuition.

He agreed to pay Julio in 6 months with simple annual interest at ​6.9%

Then the amount of the interest will be

Amount = P x R x T / 100

We have

P = $ 300

R = 6.9%

T = 6 months = 0.5 years

Then we have

P = (300 x 6.9 x 0.5) / 100

P = $ 10.35

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[tex](\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{(-2)}}} \implies \cfrac{-2}{5 +2} \implies \cfrac{ -2 }{ 7 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-\cfrac{2}{7}}(x-\stackrel{x_1}{(-2)}) \implies y-4=-\cfrac{2}{7}(x+2) \\\\\\ y-4=-\cfrac{2}{7}x-\cfrac{4}{7}\implies y=-\cfrac{2}{7}x-\cfrac{4}{7}+4\implies y=-\cfrac{2}{7}x+\cfrac{26}{7}[/tex]