A projector lens projects an image from a 6.35 cm wide LCD screen onto a
screen 3.25 m wide. If the focal length of the projector lens is 13.8 cm, the screen
must be how far from the projector

Answer:

A) 140 k

b ) 5.22 *10^3 J

c) 2910 Pa

Explanation:

Volume of Monatomic ideal gas = 1.20 m^3

heat added ( Q ) = 5.22*10^3 J

number of moles  (n)  = 3

A ) calculate the change in temp of the gas

since the volume of gas is constant no work is said to be done

heat capacity of an Ideal monoatomic gas ( Q ) = n.(3/2).RΔT

make ΔT subject of the equation

ΔT = Q / n.(3/2).R

    = (5.22*10^3 ) / 3( 3/2 ) * (8.3144 J/mol.k )

    = 140 K

B) Calculate the change in its internal energy

ΔU = Q  this is because no work is done

therefore the change in internal energy = 5.22 * 10^3 J

C ) calculate the change in pressure

applying ideal gas equation

P = nRT/V

therefore ; Δ P = ( n*R*ΔT/V )

                        = ( 3 * 8.3144 * 140 ) / 1.20

                        = 2910 Pa

A) The change in the temperature of the gas is; ΔT = 139.5 K

B) The change in internal energy of the gas is; ΔU = 5.22 × 10³ J

C) The change in pressure of the gas is; ΔP = 2899.5 Pa

We are given;

Volume of Monatomic ideal gas; V = 1.2 m³

Amount of heat added; Q = 5.22 × 10³ J

number of moles; n = 3

A) To calculate the change in temperature of the monatomic idea gas, we will use formula;

Q = ³/₂nRΔT

Where R is a constant = 8.314 J/mol.K

ΔT is the change in temperature

Making ΔT the subject of the formula;

ΔT = ²/₃(Q/(nR))

ΔT = ²/₃(5.22 × 10³)/(3 × 8.314)

ΔT = 139.5 K

B) Due to the fact that no work was done, then from first law of thermodynamics, we can say that;  

ΔU = Q

Thus;

change in internal energy; ΔU = 5.22 × 10³ J

C) The change in pressure will be calculated from the formula;

ΔP = (n*R*ΔT)/V

ΔP = (3 * 8.314 * 139.5)/1.2

ΔP = 2899.5 Pa

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Explanation:

Perspective- the art of drawing solid objects on a two-dimensional surface so as to give the right impression of their height, width, depth, and position in relation to each other when viewed from a particular point.

Genetic disorders and Parkinson's disease.

Answer:

Natural gas is non renewable energy.

Explanation:

Because they were formed from the buried reamains of plants and animals that live a million years ago. It is formed from fossil fuels.

Answer:

Explanation:

Given

Maximum height H = 300m

Range (horizontal distance) = 380m

Required

Initial speed U and the angle of the ball when it was launched.​

Range = U√2H/g

380 = U√2(300)/9.8

380 = U√600/9.8

380 = 7.8246U

U = 380/7.8246

U = 48.57m/s

The initial speed is 48.57m/s

b) Using the formula for calculating time of flight;

T = 2Usin theta/g

9 = 2(48.57)sin theta/9.8

9*9.8 = 97.14sin theta

88.2 = 97.14sin theta

88.2/97.14 = sin theta

sin theta = 0.9079

theta = sin^-1(0.9079)

theta = 65.23°

hence the angle when the ball was launched is 65.23°

Answer:

y = 6 10⁻² m

Explanation:

This is a diffraction exercise which is described by the expression

          a sin θ = m λ

we can use trigonometry to find the distance from the inside of the screen to the dark point (y)

          tan θ = y / L

angles are very small in diffraction experiments, so we can approximate

          tan θ = sin θ /cos θ = sin θ

          sin θ = y / L

substituting

         a (y / L) = m λ

Let's find the points where the intensity becomes zero

         y = m L λ / a

λ₁ = 4.0 10⁻⁷ m

m = 1

          y = 1 2.0 4.0 10⁻⁷/ 4.0 10⁻⁵

          y = 2 10⁻² m

m = 2

          y = 4 10⁻² m

λ₂ = 6.0 10⁻⁷ m

m = 1

          y = 1 2.0 6.0 10⁻⁷ / 4.0 10⁻⁵

          y = 3 10⁻² m

m = 2

          y = 6 10⁻² m

if we want a point where the two colors are dark, we set the two expressions equal

          y₁ = y₂

          m₁ L  λ₁ / a = m₂ L  λ₂ / a

          m₁/m₂ =  λ₂/λ₁

          m₁ / m₂ = 6 10⁻⁷ / 4 10⁻⁷

          m₁ / m₂ = 1.5

since the quantities m must be integers, the smallest relation that the relation fulfills is

            m₁ = 3

            m₂ = 2

the distance for this destructive interference is

           y = 3 2 4.0 10⁻⁷ / 4.0 10⁻⁵

           y = 6 10⁻² m

this is the first point where the minimum of the two wavelengths coincide

Answer:

Option 1

Explanation:

I always see animals do that

Answer:

 ΔU = 2 mg h

Explanation:

In a spring mass system the potential energy is U = m g h

where h is measured from the equilibrium point of the spring

the potential energy at the highest point is

         U₁ = m g h

the potential energy at the lowest point is

         U₂ = m g (-h)

instead in this energy it is

          ΔU = 2 mg h

In this two points the kinetic energy is zero, but there is elastic potential energy that has the same value in the two points, so its change is zero

Potential energy is defined as the energy stored in a body which may convert into kinetic energy when moved.

The Formule of the potential energy is [tex]mgh[/tex] The correct answer is 0

Hence, [tex]U = 2 mg h[/tex]

 The H stated as the measured from the equilibrium point of the spring

Therefore, the potential energy at the maximum point is  [tex]U_1 = m g h[/tex]  and the potential energy at the minimum point is    [tex]U_2 = m g (-h)[/tex]

Hence, after solving it we got

         [tex]U_1 -U_2 = 2 mg h[/tex]

Therefore, the energy change in the process is 0.

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Answer:

Arsenic (As)

Explanation:

Arsenic is the only answer choice that has five valence electrons like the electron dot structure shows.

Answer:

Arsenic (As)

Explanation:

Answer:

If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.

Explanation:

Given;

initial force exerted to hang on, F₁ = 100 N

The force exerted on the merry-go-round in order to hang on must be an inward force known as centripetal force.

Centripetal force is given by;

[tex]F_c = \frac{mv^2}{r} \\\\keeping \ "m" \ and \ "r" \ constant, we \ will \ have \ the \ following \ equation;\\\\\frac{F_c_1}{v_1^2} = \frac{F_c_2}{v_2^2} \\\\F_c_2 = \frac{F_c_1*v_2^2}{v_1^2}\\\\when \ the \ speed\ doubles \ i.e, v_2 = 2v_1\\\\ F_c_2 = \frac{F_c_1*(2v_1)^2}{v_1^2}\\\\ F_c_2 = \frac{F_c_1*4v_1^2}{v_1^2}\\\\F_c_2 = F_c_1 *4\\\\F_c_2 = 4(F_c_1)\\\\F_c_2 = 4 (100 \ N)\\\\F_c_2 = 400 \ N[/tex]

Therefore, If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.

Answer:

The total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

Explanation:

The total kinetic energy of a sphere is given by the sum of the rotational kinetic energy and the translational kinetic energy. That is,

[tex]K_{Total} = K_{R} + K_{T}[/tex]

The rotational kinetic energy [tex]K_{R}[/tex] is given by

[tex]K_{R} = \frac{1}{2}I\omega^{2}[/tex]

Where [tex]I[/tex] is the moment of inertia

and [tex]\omega[/tex] is the angular velocity

The translational kinetic energy [tex]K_{T}[/tex] is given by

[tex]K_{T} = \frac{1}{2}mv^{2}[/tex]

Where [tex]m[/tex] is the mass

and [tex]v[/tex] is the translational speed (velocity)

∴ [tex]K_{Total} = \frac{1}{2}I\omega^{2} + \frac{1}{2}mv^{2}[/tex]

But, the moment of inertia [tex]I[/tex] of a sphere is given by

[tex]I = \frac{2}{5}mr^{2}[/tex]

Where [tex]m[/tex] is mass

and [tex]r[/tex] is radius

∴ [tex]K_{Total} = \frac{1}{2}\times \frac{2}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}[/tex]

[tex]K_{Total} = \frac{1}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}[/tex]

Also, [tex]\omega = \frac{v}{r}[/tex]

∴ [tex]\omega^{2} = \frac{v^{2} }{r^{2} }[/tex]

Then,

[tex]K_{Total} = \frac{1}{5}mr^{2} \times \frac{v^{2} }{r^{2} } + \frac{1}{2}mv^{2}[/tex]

[tex]K_{Total} = \frac{1}{5}mv^{2} + \frac{1}{2}mv^{2}[/tex]

∴ [tex]K_{Total} = \frac{7}{10}mv^{2}[/tex]

From the question, [tex]v = 2.00 m/s[/tex]

Then,

[tex]K_{Total} = \frac{7}{10}m(2.00)^{2}[/tex]

[tex]K_{Total} = \frac{7}{10}m\times 4.00[/tex]

[tex]K_{Total} = 2.8m J[/tex]

Hence, the total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

Answer:

I = 2.99 A

Explanation:

magnetic field, B = 0.96 T, length of wire, l = 2.7 m, mass of wire, m = 0.79 kg.

Since it is expected that the wire would vibrate or move in the magnetic field, from Newton's second law of motion;

F = mg

where F is the force on the wire, m is the mass of the wire and g is the acceleration due to gravity.

But,

F = BIL

⇒ BIL = mg

0.96 x I x 2.7 = 0.79 x 9.8

2.592I = 7.742

I = [tex]\frac{7.742}{2.592}[/tex]

 = 2.9869

I = 2.99 A

The required minimum current is 2.99 A.

Answer:

Answer is (b) Mercury, venus and Mars.

Explanation:

i think b is correct!!

;-) :-) :-) :-)

Answer:

The maximum speed of the car is 35 m/s

The total distance traveled by the car is 658.33 m

Explanation:

Given;

initial velocity of the car, u = 15 m/s

acceleration of the car, a = 2 m/s²

time of car motion, t = 10 s

(i)

Initial distance traveled by the car is given by;

d₁ = ut + ¹/₂at²

d₁ = (15 x 10) + ¹/₂(2)(10)²

d₁ = 150 + 100

d₁ = 250 m

The maximum speed of the car during this is given by;

v² = u² + 2ad₁

v² = (15)² + (2 x 2 x 250)

v² = 1225

v = √1225

v = 35 m/s

(ii)

The final distance cover by the car during the deceleration of 1.5 m/s².

Note: the final or maximum speed of the car becomes the initial velocity during deceleration.

v² = u² + 2ad₂

where;

v is the final speed of the car when it stops = 0

0 = u² + 2ad₂

0 = (35²) + (2 x - 1.5 x d₂)

0 = 1225 - 3d₂

3d₂ = 1225

d₂ = 1225 / 3

d₂ = 408.33 m

The total distance traveled by the car is given by;

d = d₁ + d₂

d = 250 m + 408.33 m

d = 658.33 m

Answer:

With more air is more buoyancy. When deflated or released the scuba diver is less buoyant.

Explanation:

The compensator is a Buoyancy control device that has an inflatable air bladder.When we have more air out into the inflatable bladder, then one is more buoyant. If the air is released from the bladder, then one is less buoyant. We add air through an air inflation valve. Air is also then released using air-deflation valves.

Buoyancy can be defined as an upward force which is exerted on an object that is fully or partially immersed in water

when one is less buoyant than water, it means that the upward pressure is more than the downward pressure of that person and his equipment. Then he will float. In a case of negative buoyancy, we have downward pressure of this person and his equipment to be more than the upward pressure of the water. Then sinking will happen.

Answer:

 ρ = 19215 kg / m³ , the answer the correct  is D

Explanation:

All materials are sold when heated, in first approximation

              ΔV = β V₀ (T -T₀)

for this case

              ΔV = 4.20 10⁻⁶ Vo (1050 - 0)

              ΔV = 4.41 10⁻³ Vo m³

              V-Vo = 4.41 10⁻³ Vo

              V = 1.00441 Vo

density is defined by

           ρ = m / V

a T = 0ºc

            ρ₀ = m / Vo

aT= 1050ºC

           ρ = m / V

           ρ = m / (1,00441 Vo)

           ρ = 1 / 1.00441      m/Vo

          ρ = 0.9956 ρ₀

          ρ = 0.9956 19300

          ρ = 19215 kg / m³

when checking the answers the correct one is D

Answer:

[tex]0.00005202\ \text{rad}=0.003^{\circ}[/tex]

Explanation:

d = Diameter of typical neutron star = 20 km = 20000 m

D = Distance between Earth and Moon = [tex]384.4\times 10^6\ \text{m}[/tex]

Here, [tex]D>>d[/tex] so we use small angle approximation

[tex]\delta=\dfrac{d}{D}\\\Rightarrow \delta=\dfrac{20000}{384.4\times 10^6}\\\Rightarrow \delta=0.00005202\ \text{rad}=\dfrac{0.00005202\times 180}{\pi}=0.003^{\circ}[/tex]

The angular diameter of the neutron star would be [tex]0.00005202\ \text{rad}=0.003^{\circ}[/tex] from Earth.

Answer:

[tex]\boxed {\boxed {\sf a\approx -0.08 \ m/s^2}}[/tex]

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

[tex]a=\frac{v_f-v_i}{t}[/tex]

The final velocity is 3 meters per second. The initial velocity is 8 meters per second.

We need to convert the time to seconds.

So, we know that:

[tex]v_f=3 \ m/s \\v_i= 8 \ m/s\\t= 60 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{3 \ m/s - 8 \ m/s}{60 \ s}[/tex]

Solve the numerator.

[tex]a=\frac{-5 \ m/s}{60 \ s}[/tex]

Divide.

[tex]a=-0.0833333333 \ m/s/s[/tex]

Let's round to the nearest hundredth.

The 3 in the thousandth place tells us to leave the 8 in the hundredth place.

[tex]a\approx -0.08 \ m/s^2[/tex]

The cyclist's acceleration is about [tex]\boxed {-0.08 m/s^2}[/tex]

Answer:

The gravity is 87.4% as strong as at the Earth’s surface.

Explanation:

Hope this helped!

Answer:

The energy flows between the ice and the tea equally. The table below shows the temperatures of several different objects made of the same material.

Answer:

a)

Explanation:

because if in 2 seconds have 20.0 cm/2s cm in 1 second have 10.0 cm/s

Answer:

25 turns

Explanation:

Given the following data;

Input voltage = 120V

Output voltage = 5V

Number of turns in primary coil = 600 turns

[tex] \frac {Ns}{Np} = \frac {Vs}{Vp} [/tex]

Where;

Substituting into the equation, we have;

[tex] \frac {Ns}{600} = \frac {5}{120} [/tex]  

Cross-multiplying, we have;

[tex] 120*Ns = 600*5[/tex]

[tex] 120Ns = 3000[/tex]

[tex] Ns = \frac {3000}{120}[/tex]

Ns = 25 turns

Therefore, the number of turns in the secondary coil is 25 turns.

Hence, it is a step-down transformer because the number of turns on the primary coil is greater than the number of turns on the secondary coil. Consequently, the output voltage (5V) will be lesser than the input voltage (120V).

Answer:

12ft/s or 4m/s

Explanation:

Answer:

well, in my view,

In fluid mechanics, hydrostatic equilibrium or hydrostatic balance (also known as hydrostasy) is the condition of a fluid or plastic solid at rest. This occurs when external forces such as gravity are balanced by a pressure-gradient force.

Answer:

Work = Mass * Gravity * Height and is measured in Joules. Imagine you find a 2 -Kg book on the floor and lift it 0.75 meters and put it on a table. Remember, that “force” is simply a push or a pull. If you lift 100 kg of mass 1-meter, you will have done 980 Joules of work.

Explanation:

Answer:

C 1 degree

Explanation:

Answer:

(a) W₁ = 3293.06 J = 3.293 KJ

(b) W₂ = 0 J

(c) W₃ = - 506.625 J = - 0.506 KJ

(d) W₄ = 0 J

(e) W = 2786.435 J = 2.786 KJ

Explanation:

The complete question has following parts:

(a) First gas expands from a volume of 1 L to 6 L at a constant pressure of 6.5 atm

(b) Second, the gas is cooled at constant volume until the pressure falls to 1 atm

(c) Third, the gas is compressed at a constant pressure of 1 atm from a volume of 6 L to 1 L.

(d) Finally the gas is heated until its pressure from 1 atm to 6.5 atm at constant volume

(e) what is the net work?

ANSWERS:

(a)

The work done by a gas at constant pressure is given as follows:

W = PΔV

where,

W = Work done by the gas

P = Constant Pressure of the Gas

ΔV = Change in Volume of The gas

Therefore, for the first step:

P = P₁ = (6.5 atm)(1.01325 x 10⁵ Pa/1 atm) = 6.58613 x 10⁵ Pa

ΔV = ΔV₁ = 6 L - 1 L = (5 L)(0.001 m³/1 L) = 5 x 10⁻³ m³

W = W₁

Therefore,

W₁ = (6.58613 x 10⁵ Pa)(5 x 10⁻³ m³)

W₁ = 3293.06 J = 3.293 KJ

(b)

The work done at a constant volume by a gas is always zero due to no change in volume:

W₂ = P₂ΔV₂

W₂ = P₂(0)

W₂ = 0 J

(c)

For the third step:

P = P₃ = (1 atm) = 1.01325 x 10⁵ Pa

ΔV = ΔV₃ = 1 L - 6 L = (- 5 L)(0.001 m³/1 L) = - 5 x 10⁻³ m³

W = W₃

Therefore,

W₃ = (1.01325 x 10⁵ Pa)(-5 x 10⁻³ m³)

W₃ = - 506.625 J = - 0.506 KJ

(d)

The work done at a constant volume by a gas is always zero due to no change in volume:

W₄ = P₄ΔV₄

W₄ = P₄(0)

W₄ = 0 J

(e)

Hence, the net work is given as follows:

W = W₁ + W₂ + W₃ + W₄

W = 3293.06 J + 0 J + (- 506.625 J) + 0 J

W = 2786.435 J = 2.786 KJ

Answer:

A = 2.26 m

Explanation:

Given that,

The total mechanical energy of the block spring system is 512 J

Let the spring constant, k = 200 N/m

We need to find the amplitude for this oscillation. The mechanical energy of the spring mass system is given by :

[tex]E=\dfrac{1}{2}kA^2[/tex]

k is spring constant

[tex]A=\sqrt{\dfrac{2E}{k}} \\\\A=\sqrt{\dfrac{2\times 512}{200}} \\A=2.26\ m[/tex]

So, the amplitude of the oscillation is 2.26 m

Answer:

(1) 1000 N (2) 1 m/s²

Explanation:

(1) Given that,

The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal force acting on the car. The magnitude of the centripetal force is given by :

[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{1000\times (10)^2}{100}\\\\F=1000\ N[/tex]

So, the correct option is (c) i.e. 1000 N

(2).The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal acceleration of the car. The magnitude of the centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(10)^2}{100}\\\\a=1\ m/s^2[/tex]

So, the correct option is (b) i.e. [tex]1\ m/s^2[/tex]

Answer:

Image result for total velocity definition

The average speed of an object is defined as the distance traveled divided by the time elapsed.

Explanation: