A projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. The projectile strikes the ground after time at horizontal distance from the base of the platform. [Neglect friction.]
Calculate the vertical distance, h, if the projectile's total time of flight is 4.5 seconds. You must show work to earn full credit with the minimum 3 steps:
1. Equation used
2. Substitution with correct units
3. Final answer with correct units
Answers
Answer:1
Explanation:t=rad2h/g
The launch of projectiles allows to find the height of the body launched horizontally is:
The height is 99.2 m
Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is the gravity acceleration.
In the attachment we see a diagram of the movement, as the body is thrown horizontally, its initial vertical speed is zero.
y = y₀ + [tex]v_o_y[/tex] t - ½ g t²
Where y, y₀i are the current and initial heights, respectively, [tex]v_{oy}[/tex] the vertical initial velocity, g the acceleration of gravity and t the time.
0 =y₀ + 0 - ½ g t²
y₀ = ½ g t²
let's calculate
y₀ = ½ 9.8 4.5²
y₀ = 99.2 m
y₀ = h = 99.2 m
This is the initial height of the object when it is thrown.
In conclusion using the projectile launch we can find the height of the horizontally launched body is:
The height is 99.2 m
Learn more here: brainly.com/question/10903823
Related Questions
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Answer:
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calculate the height from from which a body is released from rest if its velocity just before hitting the ground is30m\s
Answers
Answer:
height = 45 m
Explanation:
Initial velocity = 0 m/s
Final velocity = 30 m/s
Acceleration due to gravity = +10m/s^2 ( because ball is going down )
Using the eqn of motion
[tex] {v}^{2} - {u}^{2} = 2gh[/tex]
where v= final velocity ; u = initial velocity ; g = acceleration due to gravity ; h = height
So,
[tex] {30}^{2} - {0}^{2} = 2 \times 10 \times h[/tex]
[tex] = > 20h = 900[/tex]
[tex] = > h = \frac{900}{20} = 45[/tex]
1. A plane flying horizontally at an altitude of 490 meters and having a velocity of 250 meters per second east, drops a supply packet to a work crew on the ground. It falls freely without a parachute. [Assume no wind and negligible air resistance.] A. Calculate the time required for the packet to hit the ground. (25 pts)
Answers
Answer:
t = 10 s
Explanation:
Given :
Altitude, h = 490 m
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To find :
The time required for the packet to hit the ground. When it hits the ground its velocity will be 0. Let t is the required time. It can be calculated as follows :
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Answers
Answer:
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Answers
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