The distance traveled by the pool ball is 0.376 m.
To calculate the distance traveled by the ball, we need to first find the resultant velocity of the ball.
What is resultant velocity?This is the single velocity obtained when two or more velocities are combined.
To calculate the resultant velocity, we use the formula below.
Formula:
Vr = √(Vx²+Vy²)............. Equation 1Where:
Vr = Resultant velocity.From the question,
Given:
Vx = 0.5 m/sVy = 0.8 m/sSubstitute these values into equation 1
Vr = √(0.5²+0.8²)Vr = √(0.25+0.64)Vr = √(0.89)Vr = 0.94 m/sFinally, to calculate the total distance, we use the formula below.
Formula:
d = (Vr)t.......... Equation 2Where:
d = Distance traveled by the ballt = timeFrom the question,
Given:
Vr = 0.94 m/st = 0.4 sSubstitute into equation 2
d = 0.4×0.94d = 0.376 mHence, the distance traveled by the pool ball is 0.376 m.
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Classify each characteristic as either a metal or a nonmetal.
shiny surface
dull surface
good conductor of electricity
good conductor of heat
poor conductor of electricity
poor conductor of heat
malleable
brittle
Answer:
metal, non, metal, metal, non, non, metal, non
Explanation:
knowledge
Discuss the role of oxygen in air supply.
T he role of oxygen in air supply is to keep all the ling beings live and healthy.
What is Oxygen?Oxygen is the most important gas required for the living of human beings, animals, birds and the whole ecosystem.
Oxygen is fundamental for breath on the grounds that the body utilizes it to 'consume' food atoms. Creatures take in oxygen while breathing in and radiate carbon dioxide while breathing out. Oxygen makes up practically 21% of the all out gases in air, with the majority of the excess gas being physiologically latent nitrogen.
Oxygen assumes a basic part in breath, the energy-delivering science that drives the digestion systems of most living things. We people, alongside numerous different animals, need oxygen in the air we inhale to remain alive. Oxygen is created during photosynthesis by plants and many sorts of organisms.
Thus, the air supply needs oxygen on the majority.
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As a wave travels through a medium, the particles of the medium vibrate in a direction perpendicular to the direction of the wave’s motion. What kind of wave is this? Longitudinal Wave, Pulse Wave, Transverse Wave, Pressure Wave, or Electromagnetic Wave?
you can only apply a 200n force but u need to make a 20 kg wagon of mulch travel at a speed of 10 m/s. How long do you have to push the wagon before its speed reaches 10m/s if it starts at rest
Time for which the wagon is pushed before it speed reaches 10m/s from rest.
What is momentum?The momentum is the product of mass of an object and its velocity.
Let the impact force is applied for time t. The impulse is equal to the change in momentum.
F.t = m(Vf -Vi)
where Vf =10 m/s, Vi =0 m/s, m =20kg and F =200N, then time for the force applied will be
200 x t = 20 x (10)
t =1s
Thus, the time for which the wagon is pushed before it speed reaches 10m/s from rest is 1s.
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Sunlight hits the black asphalt pavement on a sunny,
summer day. The pavement becomes excessively hot.
What wave behavior is demonstrated by this
phenomenon?
Why is it important to to find information about if if crabs can or can't see the plankton, they eat near the ocean floor
Answer:
One possible explanation students can make: The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.
Friction can only occur between solids and ________
Friction can only occur between solids, liquids and gas.
What is friction?Friction can be defined as the force that a moving object encounters when sliding over a surface.
The various phases of matter include solid, liquid and gases and friction occurs in all the three phases of matter.
Therefore, Friction can only occur between solids, liquids and gas.
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When a force of 450N pushes on a 20kg box as
shown, the acceleration of the box up the incline is
0.70m/s2. Find the coefficient of sliding friction
between the box and the incline.
Answer:
ma+mgsinh0+f=F∴(25)(0.75)+(25)(10)sinh0+μkN=F∴18.75+(250)(0.6h)+μk(mgcosh0=F⟹18.75+150+μk((25)(10)(0.76))=500∴168.75+μk(190)=500⟹μk(190)=331.25⟹μk=1.74
Explanation:
A rock is dropped from a bridge to the water below. It takes 2.40 s for the rock to hit the water (a) find the speed in m/s of the rock as it hits the water. (b) how high in metres is the bridge above the water
Answer: I think Its the Height is 11.76 Meters (38.582677 Feet) between the bridge and the ground
Explanation: Supposing that where not counting air resistance in the equation, the equation [tex]D = ut+\frac{1}{2} at^{2}[/tex] states that 1/2 multiplied by earths gravitational acceleration multiplied by the amount of time to reach the bottom: 2.4 seconds equals 11.76 meters of height between the bridge and the ground.
An object of volume 2.0×10^4cm³ is under water .calculate the buoyant force of water on the object (Density of water=1000kg/m³)
An object of volume 2.0×10^4cm³ is underwater, the buoyant force of the water on the object
Fb= 1.962 *10^7N
What is the buoyant force?Generally, the equation for buoyant force is mathematically given as
Fb = g * p * V
Therefore
Fb=9.81* 2.0*10^4 *1000
Fb= 1.962 *10^7N
In conclusion, the buoyant force
Fb= 1.962 *10^7N
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why do electrons flow threw a wire
Answer:
When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.
An infinitely long line of charge has a linear charge density of 8.00*10^−12 C/m. A proton is at distance 19.0 cm from the line and is moving directly toward the line with speed 1200 m/s. How close does the proton get to the line of charge?
Hi there!
To solve, we need to find the distance traveled by the proton at which the proton's velocity reaches 0 m/s. This indicates the point at which the repulsive force caused by the line of charge and its consequential acceleration causes the proton to stop for an instant and be repelled back in the opposite direction.
For this, we can use the work-energy theorem to solve.
Recall the following equations:
[tex]W = \Delta KE[/tex]
[tex]W = \int F \cdot dx\\\\KE = \frac{1}{2}mv^2[/tex]
We will integrate along the path from the point 19.0 cm (0.19 m) from the line up to a point 'z' at which the proton has no kinetic energy (v = 0 m/s). This means that the wire will be doing NEGATIVE work on the proton as it is decreasing the proton's kinetic energy.
The equation for a force acting on a charged particle is given as:
[tex]F_E = qE[/tex]
For an infinite line of charge, the electric field is given as:
[tex]E = \frac{2k\lambda}{r}\\\\F_E = \frac{2k\lambda q}{r}[/tex]
**λ = Linear charge density (C/m)
To set up our integral:
[tex]W = \Delta KE = \int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2[/tex]
Integrate using the following natural log rule:
[tex]\int {\frac{1}{r}} \, dr = ln(r) + C[/tex]
[tex]\int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2\\\\2k\lambda q ln(r) \left \| {{z} \atop {0.19}} \right. = -\frac{1}{2}mv^2\\\\2k\lambda q (ln(z) - ln(0.19) = -\frac{1}{2}mv^2\\\\2k\lambda q ln(\frac{z}{0.19}) = -\frac{1}{2}mv^2[/tex]
Now, we can begin solving for 'a'.
Move coefficients to one side:
[tex]ln(\frac{z}{0.19}) = -\frac{mv^2}{4k\lambda q }[/tex]
Take the base 'e' of both sides:
[tex]e^{ln(\frac{z}{0.19})} = e^{-\frac{mv^2}{4k\lambda q }}\\\\\frac{z}{0.19} = e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{(1.67*10^{-27})(1200^2)}{4(8.99*10^9)(8.00*10^{-12}) (1.6*10^{-19}) }}\\\\\boxed{z = 0.1803 m= 18.03 cm}[/tex]
It will reach a distance 18.03 cm from the wire before it temporarily loses all of its kinetic energy (at rest) and begins to speed up in the opposite direction.
You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using electric fields. The physical setup is shown in the figure below.
You are working for a manufacturing company, which is mathematically given as
[tex]m=3\sqrt{2}[/tex][tex]m=\frac{15\sqrt{5}}{16}[/tex]x=0.747a[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]What is the value of m that will place the movable bead in equilibrium at x-a a ....?
a)
Generally, the equation for the force of equilibrium is mathematically given as
F=2fcos\theta
Therefore
[tex]K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3[/tex]
[tex]m=3\sqrt{2}[/tex]
b)
By force equilibrium
[tex]K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}[/tex]
Therefore
[tex]n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\[/tex]
[tex]m=\frac{15\sqrt{5}}{16}[/tex]
c)
[tex]K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}[/tex]
x^2+a^2=(14/3)^{2/3}x^2
x=a/1.338
x=0.747a
d)
By force equilibrium
[tex]K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}[/tex]
[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]
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(For example, if you used a lunch meat that claimed to be 97% fat-free, were just 3% of its calories provided by fat?) If the manufacturer made such claims, how do you explain the difference between the manufacturer's claims and your findings?
Salmon
The difference between the manufacturer's claims and your findings is, the manufacturer is concerned about amount of fat in the meat while you are concerned about calories.
Difference between your findings and the manufacturers claimYour findings concluded that only fat can provide calories needed in the body, perhaps other classes of food or nutrients in the meat can provide calories as well.
In the manufacturer's claim there are about 3% fat in the lunch meat and doesn't necessary mean that all the calories needed is the 3% fat.
Thus, there are lots of difference between your findings and the manufacturer's claim. The manufacturer is concerned about amount of fat in the lunch meat while you are concerned about calories in the meat.
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Is the ability to discriminate between two close objects.
Answer:
resolution
Explanation:
That is the definition of resolution
What keeps the Moon from falling directly to Earth?
OA. The Moon is balanced between the gravitational pulls from both
Earth and the Sun.
OB. The Moon's gravitational force balances the gravitational pull from
Earth.
OC. The Moon's rotation about its own axis creates centripetal force
that balances Earth's pull.
OD. The Moon has a large tangential velocity that causes it to "miss"
Earth as it falls toward it.
The reason why the moon does not fall back to the earth is that the Moon's rotation about its own axis creates centripetal force
that balances Earth's pull.
What is the gravitational force?The gravitational force is the force that keeps the solar system together. All the members of the celestial bodies are held in place by gravity.
Thus, the reason that keeps the moon from falling back to the earth is because the Moon's rotation about its own axis creates centripetal force that balances Earth's pull.
Hence, their tangential velocity is sufficient to ensure that the flight path misses the object being orbited. The centripetal force is enough to bend the otherwise straight path into an ellipse.
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Answer:
D. The Moon has a large tangential velocity that causes it to "miss" Earth as it falls toward it.
Explanation:
You want to know what keeps the Moon from falling directly to Earth.
OrbitThe Moon does not fall directly to Earth because the direction of motion is more or less perpendicular to the direction of Earth from the Moon. That is, the large tangential velocity causes it to "miss" Earth.
Additional comment
One object will orbit another if their mutual gravitational attraction provides enough acceleration (change in speed and/or direction) to bend the path into a circular or elliptical one. If the acceleration is too little, the path may be bent, but no orbit will be established. If the acceleration is too great, the path may be bent to a curve that ultimately causes the objects to collide.
In general, the multi-body dynamics present in the solar system mean that the orbits of various objects are chaotic. In the short term, they are fairly predictable, but short-term behavior may not be predictive of long-term behavior.
In-Class Problem #2
at
at
A 79.5 kg defensive end tackles a 60 kg
running back going north at 5 m/s. After the
hit both players move together at 2.5 m/s
south. How fast was the defensive end
running before the tackle?
on
ne ta
EAOLES
62
v = 8.16 m/s south
-0
362
Answer:
8.16m/s south
Explanation:
North is the negative direction.
60kg*(-5m/s)+79.5kg*v=(79.5kg+60kg)*(2.5m/s)
-300kgm/s+79.5kg*v=348.75kgm/s
79.5kg*v=648.75kgm/s
v=8.16m/s
The graph below shows the conservation of energy for a skydiver jumping out
of a plane and landing safely on the ground. Which energy is represented by
line C?
Answer:
Kinetic energy
Explanation:
You drive a car east on the highway at 26 m/s. Another car passes you moving east traveling at 32 m/s. How fast do you view the car passing you?
The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
Relative velocity of the carThe speed of the car passing you is determined by applying relative velocity principle as shown below;
Vr = Va - Vb
Vr = 26 m/s - 32 m/s
Vr = -6 m/s
Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
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If a 75 resistor is connected to a 18 V battery, how much current passes
through the resistor?
Answer:
0.24 A
Explanation:
Voltage is given by the equation :
V = I × R
Voltage = Current × Resistance
Rearrange to make Current/I the subject :
18 = I × 75
I = 18÷75
I = 0.24 A
Hope this helped and brainliest please
Why is digital forensics important?
Hi! digital forensics is important because not only does digital forensics allow cyber security organisations to develop technologies that can prevent hackers from accessing devices, websites and networks but can lead businesses in the direction of understanding exactly what data is compromised.
when solving for t you used sin theta instead of cos theta?
Looking out from a vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse , while cos(θ) is the ratio of the adjacent side to the hypotenuse . No matter the size of the triangle, the values of sin(θ) and cos(θ) are the same for a given θ, as illustrated below.
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how much force is required to accelerate an 8.6kg wagon by 15 m/s ?
The amount of force required to accelerate the given mass of the wagon is 129 Newtons.
What is force?A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.
From Newton's Second Law, force is expressed as;
F = m × a
Where is mass of object and a is the acceleration.
Given the data in the question;
Mass of the rock m = 8.6kgAcceleration a = 15m/s²Force F = ?F = 8.6kg × 15m/s²
F = 129kgm/s²
F = 129N
Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.
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A 10.0-kg test rocket is fired vertically. When the engine stops firing, the rocket’s kinetic energy is 1960 J. After the fuel is burned, to what additional height will the rocket rise?
Answer:
20m
Explanation:
So the formula for PE(Potential Energy) = Mass x Acceleration x Height
So we are given the following
PE = 1960
Mass = 10Kg
Acceleration = 9.8m/s^2 (The reason we have an acceleration is due to gravity)
Height = ?
So to calculate height we will use the same formula
1960 = 10 x 9.8 x h
1960 = 98 x h
1960 = 98h
we divide 98 on both sides
H = 20m
Hope this helped.
(b) The graph display a load against extension plot for a metal wire of diameter 1.5 mm and original length
1m. When the load reached the value at a point A, the wire broke. From the graph deduce values of
i)force constant
ii)the youngs modulus for the metal of the wire
From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is 6.4 * 10^7 .
What is Hookes law?According to Hooke's law, the force is directly proportional to the extension of the wire.
Given that;
F = Ke
F = 240N
e = 0.8 mm or 0.0008m
K = F/e
K = 240N/0.0008m
K = 3.0 * 10^5 N/m
Now;
Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3
= 6.4 * 10^7
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Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate .
An employee will display by adhering to professional standards of the workplace and encouraging co-workers to do the same.
Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.
Who is a leader?A person taking the charge of the organization and leading a team under him is known as a leader.
"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."
Options:
First Blank: work ethic
First Blank: self-representation
First Blank: diversity awareness
Second Blank: leadership skills
Second Blank: nonverbal skills
Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.
By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.
Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.
An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.
Hence, self-representation and leadership skills are the correct answer.
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Two large parallel metal plates carry opposite charges. They are separated by 0.20 m and the p.d. between them is 500 V. What is the magnitude of electric field, if it is uniform, in the region between them.
Hi there!
We can use the following relationship between the Potential Difference and the Electric field:
[tex]V = E d[/tex]
V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)
We can rearrange the equation to solve for the electric field:
[tex]E = \frac{V}{d}\\\\[/tex]
Plug in the given values.
[tex]E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}[/tex]
Of the following, which is the best reason for why a woman's risk for cardiovascular disease increases after menopause?
Answer:
The best reason for the increased risk of cardiovascular diseases in women after menopause is the significant decrease in the levels of Estrogen in the body.
Detailed answer:
Due to the approach of menopause the estrogen levels in the blood decrease drastically. Estrogen helps in relaxing the vessels and keeping them in their natural diameter. But due to a drastic decrease in its level due to menopause, there is a high chance of cholesterol building up on the walls of the artery in the heart, which can cause many cardiovascular diseases.which image shows an example of kinetic energy
Answer:
Hello there seems to be no Images in this question but Kinetic energy is a push or a pull force which has to do with motion if you just need to know what t is. Next time be sure to add the pictures for it.
Explanation:
Thank you!
Hello the other person (#Sonichj123), was indeed correct there appears to be no picture in your question. Although there is no picture in your question, If you have another question I will be gladly to help you!
Explanation:
Thank you so much! (≥ФωФ≤)
A sewing machine uses 1.6kWh of electricity in one day. If electricity costs 9p per unit, what is the total cost in pence of using the sewing machine that day? Give your answer to 3 significant figures.
Answer:
[tex]\huge\boxed{\sf 1.6\ units = 14.4p}[/tex]
Explanation:
Since,
1 kWh = 1 unitSo,
1.6 kWh = 1.6 units
If,
1 unit = 9p1.6 units = 9p × 1.6
1.6 units = 14.4p
[tex]\rule[225]{225}{2}[/tex]