A photon of blue light has a wavelength of 4.62 x 10m (462 nm). Calculate the energy of this photon

Answers

Answer 1

Answer:

[tex]E=4.3\times 10^{-19}\ J[/tex]

Explanation:

Given that,

The wavelength of a photon of blue light is 462 nm

We need to find the energy of this photon. The formula for the energy of a photon is given by :

[tex]E=\dfrac{hc}{\lambda}\\\\E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{462\times 10^{-9}}\\\\=4.3\times 10^{-19}\ J[/tex]

So, the energy of this photon is [tex]4.3\times 10^{-19}\ J[/tex].


Related Questions

A runner wants to run 10.4 km k m . She knows that her running pace is 8.0 mi/h m i / h .

Answers

Answer:

Approximately 49 minutes.

Explanation:

1 mile = 1.6 km

So 8.0 x 1.6 km

Minutes required: [tex]\frac{10.4 times 60 }{8.0 times 1.6}[/tex]= 48.75 minutes

I hope this helped :)

how is black oxide converted into red oxide​

Answers

Answer:

The usual way of converting black oxide to red oxide involves treating the black oxide with sulphuric acid and then roasting the intermediate product thus formed. lt is known that the amount of acid can be considerably less than the stoichiometric amount needed to convert all the black oxide to a sulphate.

Hope it helps :9

Draw the product or products that are obtained from the reaction of HCl with 1-butene and with 2-butene. Show the relative stereochemistry if the product has two or more stereocenters.

Answers

Delete me please!!!!!!

why is there not a corresponding drop in ionization energies between Bi and Po in the sixth period as N and O?

and why is there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B?

Answers

Answer:

See explanation

Explanation:

According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be  anomalous......It has been claimed that spin– orbit coupling by the Russell–Saunders scheme would lower  the ground state of Bi+ ..."

However, the involvement of  d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.

The same argument could be extended to explain the reason why  there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.

What is the answer? Please

Answers

Cells is the answer can I have brainliest
The answer is living cells

You have two pure substance that you cannot identify. Each sample is solid at room temperature. Describe at least five steps in the appropriate sequence that you would take to be able to identify the substance. ​

Answers

Answer:

pue like ad

Explanation:

For the two pure substance that you cannot identified , The steps taken in the right sequence are:

When two pure substance are places before you. you have to visually anaylse the sample, note the various colors that they have. It can tell you if it's an anions or cations.

You can use reactants to precipitate the cations of the sample you have

We then add a reactant to the sample and you did not see any precipitate, it corresponds to any of the elements or compound. If you do not see a precipitate, you can add other reactant.

You then observe the color of this precipitate. example if the color changes to green, it will tell you that the substance is Ni(OH)₂ etc.

One can also find out through the melting and boiling point of the two substances.

Pure substance are regarded as substance that does not have impurities. one common way of finding out the purity of a substance is by its melting and boiling point determination.

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Suppose the current flowing from a battery is used to electroplate an object with silver. Calculate the mass of silver that would be deposited by a battery that delivers 1.65 A·hr of charge.

Answers

Answer:

m = 0.00659 kg = 6.59 g

Explanation:

From Faraday's Law of Electrolysis, we know that:

m = ZQ

where,

m = mass of silver deposited = ?

Q = charge supplied = (1.65 A-hr)(3600 s/1 hr) = 5940 C

Z = electrochemical equivalent of silver = 1.18 x 10⁻⁶ kg/C

Therefore,

m = (1.11 x 10⁻⁶ kg/C)(5940 C)

m = 0.00659 kg = 6.59 g

The mass of silver that would be deposited by a battery is 6.65 grams

The precipitation of Ag requires the removal of one electron. The reduction process for silver electrode at the cathode is as follows:

[tex]\mathbf{Ag^+ + e^- \to Ag(s)}[/tex]

The current flowing in the battery = 1.65 A = 1.65 C/sThe time at which the current is flowing = 1 hr = 3600sec

The charge Q = Current (I) × time (t)Charge Q = 1.65 C/s × 3600 sCharge (Q) = 5940 C

In one mole of an electron, the charge carried = 96500 C

Recall that:

The atomic mass of silver (Ag) = 108 g

The mass of silver that would be deposited in a 5940 C can be computed as:

[tex]\mathbf{=5940\ C \times \dfrac{108 \ g }{96500 \ C}}[/tex]

= 6.65 grams

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is pasta and water magnetism, state of matter, or solubility?
please helpp!!​

Answers

Answer:

solubility

Explanation:

The atomic of nitrogen is 7. The number of electrons a neutral atom has is_, and its atomic mass is approximately_amu.

Answers

Electrons - 7

Atomic mass - 14

For future reference, you can find the number of Electrons by subtracting the number of protons (7) from the element's mass number (14

We know, Atomic Number = Number of Electrons (In a neutral atom).

& Atomic mass = Number of protons + Number of Neutrons

The atomic number of nitrogen is 7. The number of electrons a neutral nitrogen atom has is "Seven (7)", and its atomic mass is approximately "Fourteen(14)" amu

Hope this helps!

A tank contains 7.0 moles of a mixture of nitrogen gas and oxygen gas. The total
pressure exerted by the gas mixture is 530 kPa. The partial pressure exerted by the
oxygen is 140 kPa. How many moles of NITROGEN gas are present in the tank?

Answers

Answer:

5.2 mol

Explanation:

Step 1: Given data

Total number of moles (n): 7.0 molTotal pressure (P): 530 kPaPartial pressure of oxygen (pO₂): 140 kPa

Step 2: Calculate the mole fraction of oxygen

We will use the following expression.

pO₂ = P × X(O₂)

X(O₂) = pO₂ / P

X(O₂) = 140 kPa / 530 kPa

X(O₂) = 0.264

Step 3: Calculate the moles of oxygen

We will use the definition of mole fraction of oxygen.

X(O₂) = n(O₂) / n

n(O₂) = X(O₂) × n

n(O₂) = 0.264 × 7.0 mol

n(O₂) = 1.8 mol

Step 4: Calculate the moles of nitrogen

The total number of moles is equal to the sum of moles of the individual gases.

n(O₂) + n(N₂) = n

n(N₂) = n - n(O₂)

n(N₂) = 7.0 mol - 1.8 mol

n(N₂) = 5.2 mol

A music performance takes place in an enclosed arena. A person sitting a distance of 20.0 m from the speaker experiences a sound intensity of 0.32 W/m2. What is the power of the speaker? (Assume that the area over which the speaker transmits sound is given by A = 4πd2, where d is the distance from the speaker.)
A.
100 W
B.
550 W
C.
1,200 W
D.
1,600 W

Answers

Vybbybybtbyyybybybybybbynununununynynynynynynynynynynynynynynynynynynunynynynynyninununununununnunubynununununununu

What might happen if you mixed a strong acid with an equally strong base? Question 2 options:
A.You'd wind up with a pH-neutral salt and water.
B.You would see an explosive chemical reaction.
C.The base would destroy the acid.
D.The acid would destroy the base.

Answers

Answer:

b  

Explanation:

The correct answer is B

How many seconds are in 100 years(factor label conversion)

Answers

Answer:

0.0166

Explanation:

This conversion of 100 seconds to minutes has been calculated by multiplying 100 seconds by 0.0166 and the result is 1.6666 minutes.

I hope this helps,

even a little bit

0. 0166 is how many seconds are in the year

why does 3-methylcyclohexene elute before
1-methylcyclohexene in gas chromatography?

Answers

Answer: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%. This is because 1-methylcyclohexene is the major product with the more stable carbocation intermediate and 3-methylcyclohexene is the minor product with the less stable carbocation intermediate.

Explanation: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%

the eye is a substance of which major body system

Answers

Answer:

the visual system would be the answer

Balance the following equation.
C3H8(g) + O2(g) → CO2(g) + H2O(l)

Answers

Explanation:

C3H8+5O2----->3CO2+4H2O

Answer:

C3H8+5O2----->3CO2+4H2O

Explanation:

Which trophic level has the most calorie count

Answers

Answer:

producer

Explanation:

The trophic level with the most calorie count is the producer.

A trophic level is a hierarchical level of the food chain with each level consisting of organisms that share the same feeding role in the ecosystem. A typical trophic level consists of the producers which occupy the base level, the primary, secondary, tertiary consumers respectively, and the decomposers.

The highest amount of energy exists at the base of the trophic level and decreases as we move up the trophic level, forming a kind of pyramid at the end. The producers have the highest amount of energy by directly converting energy from the sun to chemical energy. The consumers at subsequent levels are only able to utilize only about 10% of the chemical energy in their own foods.

A reaction vessel is charged with 0.50 atm of A and 0.030 atm of B. Once the reaction reaches equilibrium, what is the equilibrium partial pressure of B? Kp for this reaction is 67.2A (g) ⇌ 2 B (g)

Answers

Answer:

1.000 atm

Explanation:

Step 1: Write the reversible reaction

A(g) ⇌ 2 B(g)

Step 2: Calculate the reaction quotient

Q = [B]²/[A]

Q = 0.030²/0.50

Q = 0.0018

since Q < Kp, the reaction will proceed to the right

Step 3: Make an ICE chart

       A(g) ⇌ 2 B(g)

I      0.50      0.030

C       -x          +2x

E    0.50-x    0.030+2x

Step 4: Find the value of "x"

We will use the definition of the pressure equilibrium constant.

Kp = 67.2 = [B]²/[A] = (0.030+2x)²/0.50-x

33.6 - 67.2x = 0.0009 + 0.12x + 4x²

4x² + 67.32x -33.5991 = 0

We solve this quadratic equation and we get x=0.485112  and x=−17.3151 (neglected).

Step 5: Find the partial pressure of B at equilibrium

pB = 0.030+2x = 0.030+2(0.485112) = 1.000 atm

The equilibrium partial pressure of B would be:

[tex]1.000 atm[/tex]

Reversible Reaction

Given that,

Reaction

[tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex]

Charge on the reaction vessel [tex]= 0.50 atm[/tex] of A

[tex]0.030 atm[/tex] of B

To find,

Reaction quotient first

[tex]= B^2/A\\= (0.030)^2/0.50\\= 0.0018[/tex]

This shows that the reaction quotient is greater than Kp.

Through the reaction [tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex], ICE can be drawn

I      [tex]0.50[/tex]      [tex]0.030[/tex]

C    [tex]-x[/tex]        [tex]+2x[/tex]

E    [tex]0.50-x[/tex]   [tex]0.030+2x[/tex]

Now,

We will determine the value of [tex]x[/tex],

Kp [tex]= 67.2[/tex]

[tex]= [B]^2/[A][/tex]

[tex]= (0.030+2x)^2/0.50-x[/tex]

⇒ [tex]33.6 - 67.2x[/tex] [tex]= 0.0009 + 0.12x + 4x^2[/tex]

⇒ [tex]4x^2 + 67.32x -33.5991 = 0[/tex]

∵ [tex]x = -17.3151[/tex]

Therefore, Equilibrium Partial Pressure

[tex]= 0.030+2x[/tex]

[tex]= 0.030+2(0.485112)[/tex]

= [tex]1.000[/tex] atm

Learn more about "Partial Pressure" here:

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What’s the order can someone help?

Answers

Foam, Paper, Tin

(That’s from lowest to highest don’t get confused) :)

At what power of ten are we able to view the entire Earth in space?

Answers

Answer:

If I remember correctly it should be 10^7 meters.

Explanation:

The power of ten are we able to view the entire Earth in space is 10^8. This is further explained below.

What power of ten are we able to view the entire Earth in space?

Generally, A telescope is simply defined as a device that magnifies views of faraway things

In conclusion, The power of the telescope will be at 10^8.

Read more about Earth

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Which periodic group has the smallest atomic radius ?
-alkali metals
- halogens
- Nobel gases
- transition metals

Answers

nobel gasses o think

The Nobel gases, Group 8 elements  have the  smallest atomic radIi in the periodic table.

Atomic radius decreases as you move across a period. This is because Within  a period, a new electron is being added to the same shell , and at the same time a new proton is added , This causes an attraction and causes the electron to pull nearer to the nucleus causing the radius to shrink and reduce in size.

In decreasing order of atomic radius, we have alkali metals>halogens> transition metal  > Nobel gases

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Calculate how many grams of sodium hypochlorite can be theoretically formed when 1.23 mol of sodium hydroxide is combined with 1.36 mol of chlorine.

Answers

Answer:

45.78 g NaClO

Explanation:

The reaction that takes place is:

2NaOH + Cl₂ → NaCl + NaClO + H₂O

In order to react completely, 1.36 moles of chlorine would require (2*1.36) 2.72 moles of NaOH. There are more moles than that, so NaOH is the limiting reactant.

We calculate the moles of NaClO formed, from the limiting reactant:

1.23 mol NaOH * [tex]\frac{1molNaClO}{2molNaOH}[/tex] = 0.615 mol NaClO

Finally we convert NaClO moles to grams, using its molecular weight:

0.615 mol NaClO * 74.44 g/mol = 45.78 g NaClO


Which of these is NOT evidence that a chemical change has taken place?

temperature rising when 2 substances are mixed

gas production

color change

melting

Answers

melting, that’s the sign on a physical change

A carbocation is an example of a(an) ____. Does a carbocation accept a pair of electrons, or does it donate a pair of electrons?
A. Electrophile. The carbocation accepts a pair of electrons.
B. Nucleophile. The carbocation accepts a pair of electrons.
C. Electrophile. The carbocation donates a pair of electrons.
D. Nucleophile. The carbocation donates a pair of electrons.

Answers

Answer:

Option A. The carbocation accepts a pair of electrons.

Explanation:

A carbocation is defined as a positively charged carbon, which is bound to 3 substituents. Since it has no electrons  nonbonding, it only has six electrons in its valence shell. With only six electrons in its valence shell, a carbocation is a powerful electrophile (and Lewis acid) and can react with any nucleophile that is found.

Carbocations are proposed as intermediates in many  organic reactions. They also work like free radicals, which are electron-deficient species.

Same as free radicals, the carbocations are stabilized by alkyl substituents.

In the metallurgic industry one of the processes to get pure iron takes tree steps.


a) CaCO3→CaO + CO2


b) CO2 + C → CO


c) Fe2O3 + CO → Fe + CO2


Calculate the kilograms of iron that would be produced from 1340 g of calcium carbonate.

Answers

Mass of Iron produced : 1.5 kg

Further explanation

Reaction

a) CaCO3→CaO + CO2

b) CO2 + C → 2CO

c) Fe2O3 + 3CO → 2Fe + 3CO2

From the reaction above : 1 mol CaCO₃ = 2 mol Fe

mol CaCO₃ :

1340 : 100 g/mol = 13.4

mol Fe :

2 x 13.4 = 26.8

mass Fe :

26.8 x 56 g/mol=1500.8 g⇒1.5 kg

A 2kg metal cylinder is supplied with 1600J of energy to heat it from 5*C to 13*C. What is the SHC of the metal?

Answers

Answer:

100Jkg/°C

Explanation:

Given parameters:

Mass of metal  = 2kg

Amount of heat energy  = 1600J

Initial temperature  = 5°C

Final temperature = 13°C

Unknown:

Specific heat capacity of the metal  = ?

Solution:

Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.

  H  = m x C x (T₂ - T₁ )

H is the amount of heat

m is the mass

C is the unknown specific heat capacity

T is the temperature

     Insert the parameters and solve;

  1600 = 2 x C x (13 - 5)

   1600  = 16C

        C = 100Jkg/°C

Where do karst regions occur?

Answers

Answer:

Image result for Where do karst regions occur?

Karsts are found in widely scattered sections of the world, including the Causses of France; the Kwangsi area of China; the Yucatán Peninsula; and the Middle West, Kentucky, and Florida in the United States.

Explanation:

Answer:

Middle West Kentucky.

Explanation:

Karst are found in widely scatter sections of the world.

what is aluminum’s nuclear charge?

Answers

Answer:All six of the ions contain 10 electrons in the 1s, 2s, and 2p orbitals, but the nuclear charge varies from +7 (N) to +13 (Al)

Explanation:

hope this helped if it did may i have brainliest

What they said^^^^^^^

The volume of a gas with an initial pressure of 380 mmHg increases from 5.0 L to 8.0 L. What is the final pressure of the gas, in atm, assuming no change in moles or temperature?

a. 238 atm
b. 2.4 atm
c. 0.31 atm
d. 0.80 atm
e. 8.0 atm

Answers

It’s C. 0.31 atm

I hope this helped out! Have a nice day :)

Calculate the number of S atoms in 0.670 mole of S.

Answers

Answer:

4.03 × 10²³ atoms

Explanation:

The number of S atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.67 × 6.02 × 10²³

We have the final answer as

4.03 × 10²³ atoms

Hope this helps you

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