a. pattern:
b. recursive equation:

Answer:

2x - 6y + 16

3rd option

Step-by-step explanation:

Step 1: Write out expression

2(x - 3y + 8)

Step 2: Distribute

2x - 6y + 16

Since there is no other like terms to combine, that is our final answer.

Answer:

[tex] \frac{7}{5} (7f - 5)[/tex]

Answer:

-9.8f - 7

Explanation:

You distribute the negative to the 9.8f to make it -9.8f, and the 7 to make it -7.

(-9.8f + (-7)) = -9.8f - 7

Answer: 50

Step-by-step explanation: 42x12=504. 504-4=500. 500/10=50.

Answer:

Hey there!

V=lwh/3

315=lwh

315=15(7)w

315=105w

width=3

Hope this helps :)

The width of the rectangular base of the pyramid is W = 3 centimeters

The volume of a pyramid, is the product of the area of its base with the height of the pyramid, and divide by 3. We express this product with the formula V = ( 1/3) ×B×h, where B is the area of the base of the pyramid, and h is its height.

Volume of Pyramid = ( 1/3 )a²H

Given data ,

Let the volume of the pyramid be represented as V

Now , the value of V is

V = 105 cm³

And , the length of the pyramid L = 7 cm

The height of the pyramid is H = 15 cm

Let the width of the pyramid be W

And , Volume of Pyramid = ( 1/3 ) ( L x W x H )

105 = ( 1/3 ) ( W x 15 x 7 )

On simplifying , we get

105 ( W ) ( 1/3 ) = 105

Divide by 105 on both sides , we get

W / 3 = 1

Multiply by 3 on both sides , we get

W = 3 cm

Therefore , the value of W is 3 cm

Hence , the width of pyramid is 3 cm

To learn more about volume of pyramid click :

https://brainly.com/question/17615619

#SPJ3

Answer:

11 cartons.

Step-by-step explanation:

Since only 48 bears can be fitted into 1 carton, we need to find how many cartons approximately 500 bears can fit in:

500/48 = 10.4167 cartons

We can't have 4/10ths of a carton. Makes no sense in the real world. Therefore, we need a total of 11 cartons to pack 500 bears, even if one box isn't full.

Answer:

It's of science not of mathematics

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{10 \: N}}}}}[/tex]

Step-by-step explanation:

Given,

Load distance ( LD ) = 2m

Load ( L ) = 800 N

Effort distance ( ED ) = 160 m

Effort ( E ) = ?

Finding the Effort applied

Apply the principal of simple machine :

[tex] \boxed{ \sf{L \times LD = E\times ED}}[/tex]

[tex] \longrightarrow{ \sf{800 \times 2 = E \times 160}}[/tex]

[tex] \longrightarrow{ \sf{1600 = 160 \: E}}[/tex]

[tex] \longrightarrow{ \sf{160E = 1600}}[/tex]

[tex] \longrightarrow{ \sf{ \frac{160E}{160} = \frac{1600}{160} }}[/tex]

[tex] \longrightarrow{ \sf{E = 10 \: \: newton}}[/tex]

Effort applied = 10 N

Hope I helped!

Best regards! :D

Answer:

2.35 hrs

If she merged the highway at 1 pm, then she'll leave the highway by 3:21 pm

Step-by-step explanation:

distance traveled = 94 miles

cruise speed = 40 mph

time taken = ?

time taken = distance/speed = 94/40 = 2.35 hours

2.35 hrs = 2 hrs + (0.35 x 60) = 2 hrs + 21 min

If she merged the highway at 1 pm, then she'll leave the highway by 3:21 pm

Answer:

2

Step-by-step explanation:

Answer: 3 lbs per week were lost

Step-by-step explanation:

Answer:

Step-by-step explanation:

x·x·x·x·x=x^5

x multiplied 5 times

Answer:

(-13, -12)

Step-by-step explanation:

The midpoint (x,y) between two points ([tex]x_1,y_1[/tex]) and ([tex]x_2,y_2[/tex]) on the coordinate plane is given by:

[tex]x=\frac{x_1+x_2}{2};\\\\y=\frac{y_1+y_2}{2}[/tex]

Hence given that house A is at (3, 6) and house B is at (-5, -3). Since house B is placed at the middle of house A and house B, let the coordinates of house C be ([tex]x_2,y_2[/tex]). Hence:

[tex]-5=\frac{3+x_2}{2\\} \\3+x_2=-10\\\\x_2=-10-3\\\\x_2=-13[/tex]

[tex]-3=\frac{6+y_2}{2\\} \\6+y_2=-6\\\\y_2=-6-6\\\\y_2=-12[/tex]

Therefore house C is at (-13, -12)

Answer:

Answer is A - (1, 3) and (2, 6)

Step-by-step explanation:

(1, 3) • 2

= (1 • 2, 3 • 2)

= (2, 6)

Ratio: 2/2, 6/2

Therefore, the answer is A.  

Answer:

a

Step-by-step explanation:

Answer:

33h

Step-by-step explanation:

first you distribute the three:    3 x 5 + 3 x 6h

then you multiply:    3 x 5 = 15   3 x 6h = 18h

then you add:    15 + 18h = 33h

                           (just add 15 and 18 then add h on the end)  

Answer:

b = (A - lw) / 0.5h

Step-by-step explanation:

The formula for area of the enclosed place is

A=lw+0.5bh

Where,

A= Area of the enclosed space

l= length of the rectangle

w= width of the rectangle

b= base of the triangle

h= height of the triangle

A=lw+0.5bh

Solve for b

A=lw+0.5bh

Subtract lw from both sides

A - lw = lw + 0.5bh - lw

A - lw = 0.5bh

Divide both sides by 0.5h

(A - lw) / 0.5h = (0.5bh) / 0.5h

(A - lw) / 0.5h = b

Therefore,

b = (A - lw) / 0.5h

Answer:

b= A-lw over 0.5h

Step-by-step explanation:

Answer:

⇒  [tex]1\frac{1}{3}m-1\frac{1}{2}n-4\frac{1}{2}[/tex]

Step-by-step explanation:

Answer:

i doubt you still need the answer but first step is to create like demononators

Step-by-step explanation:

Answer:

1.58 *h=50.5 * 2.9

1.58 *h = 146.45

divide by 1.58

h=92.68987= 92.69

Step-by-step explanation:

Step-by-step explanation:

(x+4)3=2

3x+12=2

3x=-12+2

3x=-10

divide both sides by 3

x=-10/3

Answer:

36

Step-by-step explanation:

(x + 6)(x+6)

F.O.I.L.

x^2 +6x + 6x + 36

X^2 + 12x + 36

Answer:

36

Step-by-step explanation:

● x^2 + 12x

● 1 × x^2 + 2 × 1 × 6 × x

Notice that the third term is 6

So we will add 36 (6^2)

● x^2 + 12x + 36

● (x+6)^2

Answer:

angle FG=EU

angle EU=FG

FG:EU

FE=GU

Answer:

Amount of NaCl = 23.376 gram

Step-by-step explanation:

Given:

Molarity = 4M

Volume of solution = 100 ml

Find:

Amount of NaCl

Computation:

Molar mass of Na = 22.99 g/mole

Molar mass of Cl = 35.45 g/mole

Molar mass of NaCl =  22.99 + 35.45

Molar mass of NaCl  = 58.44 g/mole

Molarity = [moles of solute / volume of solute(ml)]1,000

4 = [moles of solute / 100]1000

Moles of solute = 0.4

moles of solute = Mass of solute / molar mass

0.4 = Amount of NaCl / 58.44

Amount of NaCl = 23.376 gram

Answer:

Length of route that passes the mall= 11 miles

Length of route that passes the theater= 13 miles

Step-by-step explanation:

route to school that passes the mall (highlighted in red)

= (x +1) +(x +2)

= 2x +3

route to school that passes the theater (in yellow)

= (2x +1) +x

= 3x +1

Since the first is 2 miles shorter,

2x +3= 3x +1 -2

Simplify:

2x +3= 3x -1

Bring constants to 1 side, x terms to the other:

3x -2x= 3 +1

x= 4

Substitute x=4 to find the length of each route:

Length of the route that passes the mall

= 2x +3

= 2(4) +3

= 8 +3

= 11 miles

Length of route that passes the theater

= 3x +1

= 3(4) +1

= 12 +1

= 13 miles

Alternatively, length of route that passes the theater

= 11 +2= 13 miles since it is 2 miles longer than that which passes the mall.

Answer:

D

Step-by-step explanation:

Hope this helps

Answer:

Step-by-step explanation:

5

Answer:

If the discriminant is greater than zero, this means that the quadratic equation has two real, distinct (different) roots. ... If the discriminant is equal to zero, this means that the quadratic equation has two real, identical roots.

Step-by-step explanation:

Answer:

161y - 45

Step-by-step explanation:

Answer:

-129

Step-by-step explanation:

f(x) = 4x +7

Answer:

3x^2 + 3x - 7

Step-by-step explanation:

Given:

(6x^2 – 4x – 5 ) – (3x^2 – 7x + 2)

The correct way of subtracting the polynomial is by changing the sign of each term of the second polynomial. Like this

= 6x^2 – 4x – 5 – 3x^2 + 7x - 2

Collect like terms

= 6x^2 - 3x^2 - 4x + 7x - 5 - 2

Simplify

= 3x^2 + 3x - 7

(6x^2 – 4x – 5 ) – (3x^2 – 7x + 2) = 3x^2 + 3x - 7

From the answer, the coefficient of x^2 is 3, coefficient of x is 3

Answer:

[tex]Weight = \frac{23}{2}[/tex]

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

[tex]Candies = \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}[/tex]

Take LCM

[tex]Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}[/tex]

[tex]Candies = \frac{70}{8}[/tex]

Simplify:

[tex]Candies = \frac{35}{4}[/tex]

Next; Add the weight of the candies to the weight of pinata

[tex]Weight = Candies + Pinata[/tex]

[tex]Weight = \frac{35}{4} + \frac{11}{4}[/tex]

Take LCM

[tex]Weight = \frac{35 + 11}{4}[/tex]

[tex]Weight = \frac{46}{4}[/tex]

Simplify

[tex]Weight = \frac{23}{2}[/tex]

Hence, the weight of the Pinata after it is filled with candies is 23/2 lb

Answer: The ratio of candy to fruit in a pinatas is 1/2 pound to 3/4. if we fill two pinatas and use 4 pounds of candy. how many pounds of will we need? Explain?

Step-by-step explanation:hey I know this isn’t what we’re talking about but MrRoyal I really need you help for this please :(

Answer:

Greater than

Step-by-step explanation:

First, I solved the expressions.

3(4x-1)=12x-3

2(4-x)=8-2x

12x-3>8-2x

As we can see, 12x-3 is greater than 8-2x.

Step-by-step explanation:

12x - 3 (expand 3(4x-1))

8-2x (expand 2(4-x))

if you assume that x=1 then 12x-3 would be 12(1)-3 then it would be 9 for the first

for the second equation, 8-2x, it would be 8- 2(1) or 6

9>6 so, 3(4x-1) > 2(4-x)