a passive, first-order, high pass filter has the following transfer function: please answer questions 17 to 20 based on the above transfer function.

side length of square=10

Now,

perimeter of square =4l

=4×10

=40m

Answer:

114

Step-by-step explanation:

To find - Find the sum of all the two-digit numbers that divide 170 with a remainder of 5.

Proof -

The 2 digit number is 11

170 = 11(15) + 5

The two digit number is 15

170 = 15(11) + 5

The two digit number is 33

170 = 33(5) + 5

The two digit number is 55

170 = 55(3) + 5

∴ we get

The two digit numbers are

11, 15, 33, 55

Their sum is equals to

11 + 15 + 33 + 55 = 114

Value of y[1] = 0.5 and y[2] = 0.5.

The given discrete-time system is:

y[k-1] + 2y[k] = [k]with y(0) = 0.

Substituting k = 0 in the above equation:

y[-1] + 2y[0] = [0] y[-1] = 0

Substituting k = 1 in the given equation:

y[0] + 2y[1] = [1]

Substituting the value of y[0] from the above equation in this equation, we get:

2y[1] = [1] - y[0]

Substituting the value of y[0] = 0 in the above equation:

2y[1] = [1]y[1] = [1]/2 = 0.5

Substituting k = 2 in the given equation:

y[1] + 2y[2] = [2]

Substituting the value of y[1] from the above equation in this equation, we get:

2y[2] = [2] - y[1]

Substituting the value of y[1] = 0.5 in the above equation:

2y[2] = [2] - 0.5y[2] = [2]/2 - 0.5 = 0.5

Therefore, y[1] = 0.5 and y[2] = 0.5.

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Consider the inequality -20.2 > 0y. Which of the following must be true? Check all that apply.

You cannot divide by zero.

The inequality is equivalent to -20.2 > 0, which is false.

The solution is y > 0.

The solution is 0 > y.

The solution is y = 0.

Answer:

24x-36y+48

hope this helps :)

24x - 36y + 48 is equivalent to 12(2x-3y+4)

Given:

The figure of a parallelogram.

To find:

The measure of angle Z.

Solution:

We know that, the consecutive interior angles of a parallelogram are supplementary angles, it means there sum is 180 degrees.

In the given figure angle W and angle Z are supplementary angle. So,

[tex]m\angle W+m\angle Z=180^\circ[/tex]

[tex](18b-11)^\circ+(9b+2)^\circ=180^\circ[/tex]

[tex](27b-9)^\circ=180^\circ[/tex]

[tex](27b-9)=180[/tex]

Adding 9 on both sides, we get

[tex]27b=180+9[/tex]

[tex]27b=189[/tex]

[tex]b=\dfrac{189}{27}[/tex]

[tex]b=7[/tex]

Now,

[tex]m\angle Z=(9b+2)^\circ[/tex]

[tex]m\angle Z=(9(7)+2)^\circ[/tex]

[tex]m\angle Z=(63+2)^\circ[/tex]

[tex]m\angle Z=65^\circ[/tex]

Therefore, the correct option is C.

Answer:

z= 4-x-y

z= -1+4x-y

z= 2-x

Step-by-step explanation:

z = 2-x

y = -1-z +4x

substitute

x -1 -2+x +4x + 2 -x = 4

-1 + 5x = 4

5x = 5

x = 1

z = 1

1+y+1 = 4

y = 2

Answer:

x = 6

hope this is the answer you are looking for

Step-by-step explanation:

Answer:

X=6

Step-by-step explanation:

Firstly subtract 2x from both sides = x+2=8

Then subtract 2 from both sides and you'll get x=6.

A linear equation is an equation in which the highest power of an unknown quantity is 1. Among the given options, the equation y = 6x + 8 is linear.

Hence, the correct option is a. y = 6x + 8.

An equation is linear if and only if it can be written in the form y = mx + c, where m and c are real numbers. In the given options, the equation y = 6x + 8 can be written in the form y = mx + c where m = 6 and c = 8, so it is linear. On the other hand, the equation y – x = 8x2 can be rearranged to give y = 8x2 + x, so the highest power of x is 2. Hence, this equation is not linear.Similarly, the equation 4y = 8 can be rearranged to give y = 2, which is a constant, and so it is also not linear.Finally, the equation y7 = 3x is not linear because the exponent 7 on y is greater than 1 and makes the equation non-linear. Therefore, the correct answer is option a. y = 6x + 8.

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Answer: b

Step-by-step : not needed

Answer:

Step-by-step explanation:

Sum of the interior angles of a regular polygon:

Pentagon has sum of angles:

Sum the given angles and find x:

Hexagon has sum of angles:

Sum the given angles and find x:

Answer: 424

Step-by-step explanation:

Answer:

x = 1

Step-by-step explanation:

The integral of 8(3x - 2)³ dx is 2(3x - 2)⁴ + C, where C is the constant of integration.

To find the integral of 8(3x - 2)³ dx, we can apply the power rule of integration. According to the power rule, the integral of xⁿ dx is (xⁿ⁺¹ / (n + 1)) + C, where n is a constant and C is the constant of integration.

In this case, we have (3x - 2)³ as the integrand. We can rewrite it as 8(3x - 2)³ to simplify the expression. Since 8 is a constant multiplier, it can be factored out of the integral.

Using the power rule, we integrate each term separately. The integral of (3x - 2)³ is [(3x - 2)⁴ / 4] + C, where C is the constant of integration. Multiplying by the constant 8, we get 8[(3x - 2)⁴ / 4] + C.

Simplifying further, we can simplify the expression to 2(3x - 2)⁴ + C, where C is the constant of integration.

Therefore, the integral of 8(3x - 2)³ dx is 2(3x - 2)⁴ + C.

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Answer:

A

Step-by-step explanation:

Think about the square root of 64, which is 8. It will only be slightly higher than 8, which will not even be .5, so 8 is the closest number.

Answer:

 25

Step-by-step explanation:

Answer:

2b^2 + 22

Step-by-step explanation:

2b(b + 11)

2b ×b + 2 × 11

2b^2 + 22

Answer:

the jacket price was reduced by 40%.

Step-by-step explanation:

if $50 is 100% then every one dollar is 2%.

Percentage of the reduction of price of the jacket is 40%.

Percentage is defined as the parts of a number per fraction of 100.

Percentage is usually denoted by the symbol '%'.

We have to divide a number with it's whole and then multiply with 100 to calculate the percentage of any number.

Given that,

Original price of the jacket = $50

Let x be the percentage of reduction of the price of the jacket.

50 - (x × 50) = 30

50x = 50 - 30

50x = 20

x = 20 / 50

x = 0.4

Percentage = 0.4 × 100 = 40%

Hence the percentage reduction is 40%.

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(a) The exact value of sinh(log(6) - log(5)) is 11/60.

To calculate sinh(log(6) - log(5)), we can use the identity: sinh(x) = ([tex]a^n[/tex] - [tex]e^-x[/tex])/2

So, substituting x = log(6) - log(5), we get:

sinh(log(6) - log(5)) = ([tex]e^(log(6)[/tex] - log(5)) - [tex]e^-(log(6)[/tex] - log(5)))/2

= (([tex]e^log(6)[/tex])/([tex]e^log(5)[/tex]) - ([tex]e^-log(6)[/tex])/([tex]e^-log(5)[/tex]))/2

= ((6/5) - (5/6))/2

= (36/30 - 25/30)/2

= 11/60

Therefore, sinh(log(6) - log(5)) = 11/60.

(b) The exact value of sin(arccos(76)) is undefined.

To calculate sin(arccos(76)) exactly, we can use the Pythagorean identity [tex]sin^2[/tex](x) + [tex]cos^2[/tex](x) = 1.

Let's assume arccos(76) = x. Applying the cosine function to both sides, we have cos(arccos(76)) = cos(x).

Since arccos and cosine are inverse functions, cos(arccos(76)) simplifies to 76.

Now, using the Pythagorean identity, we can calculate sin(x):

sin(x) = sqrt(1 - [tex]cos^2[/tex](x)) = sqrt(1 - 76^2) = sqrt(1 - 5776) = sqrt(-5775).

The square root of -5775 is an imaginary number, which cannot be expressed exactly without using complex numbers or numerical methods.

Therefore, the exact value of sin(arccos(76)) cannot be determined without using a calculator or numerical methods.

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Answer:

15.46 gallons per minutes

Step-by-step explanation:

Garden hose was running for 1000 minutes

Volume of the pool = 15,460 gallons

What is the approximate rate at which water leaves the garden hose?

Rate at which water leaves the garden hose = Volume of the pool / running time of the hose

= 15,460 gallons / 1000 minutes

= 15.46 gallons per minutes

Rate at which water leaves the garden hose = 15.46 gallons per minutes

Felipe's age is ≥ 5

Step-by-step explanation:

Difference of F's age and 4: f - 4

Twice: 2 (f -4) ≥ 2

2f - 8 ≥ 2

2f ≥ 10

f ≥ 5

Answer:

Step-by-step explanation:

To find out the single payment that is economically equivalent to the payment stream of $2,500 due today, $3,000 due 100 days from today, and $3,500 due 240 days from today, we have to follow the below-given steps:

Step 1: Calculate the Future Value (FV) of each payment. Let's assume that "P" is the single payment we need to find out and "i" is the annual interest rate (5%)P = FV × [1 / (1 + i/365)^n] where n is the number of days between today and the payment date. For the first payment of $2,500 that is due today, the future value is $2,500 because it is already available today. Hence, no calculation is required for it. For the second payment of $3,000 that is due 100 days from today, Future Value (FV) = $3,000 × [1+(0.05/365)]^100 ≈ $3,093.29For the third payment of $3,500 that is due 240 days from today, Future Value (FV) = $3,500 × [1+(0.05/365)]^240 ≈ $3,701.85

Step 2: Calculate the Present Value (PV) of the payment stream by discounting each FV to 80 days from today. The formula for the present value of a future amount is PV = FV × [1 / (1 + i/365)^n] where "n" is the number of days between the date of the future amount and the date on which it is to be discounted. Here, we need to discount all three payments to 80 days from today. The number of days between today and 80 days from today is 80. So, we put n = 80 in the above formula.

For the first payment of $2,500 that is already available today, there is no need for any discounting. Hence, its present value is the same as its future value, i.e., $2,500.For the second payment of $3,093.29 that is due 100 days from today, Present Value (PV) = $3,093.29 × [1 / (1 + 0.05/365)^80] ≈ $2,893.16For the third payment of $3,701.85 that is due 240 days from today, Present Value (PV) = $3,701.85 × [1 / (1 + 0.05/365)^80] ≈ $3,243.11

Step 3: Add up the present values of all three payments to find the present value of the payment stream Present Value of the payment stream = $2,500 + $2,893.16 + $3,243.11 = $8,636.27

Step 4: Calculate the single payment that is economically equivalent to the payment stream by calculating its future value at the end of 80 days. FV = PV × (1 + i/365)^n where n = 80, i = 0.05, and PV = $8,636.27FV = $8,636.27 × (1 + 0.05/365)^80 ≈ $9,040.07Therefore, the single payment that is economically equivalent to the payment stream is $9,040.07.

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1. She would use Facial electromyography

2. She would use smiling

3. She would use  Subjective Happiness Scale

It is common practice to evaluate subjective experiences, including happiness, using self-report measures. The Subjective Happiness Scale (SHS) is a popular tool for gauging happiness.

The SHS is a self-report survey that asks participants to rate how much they agree with statements about their personal experiences of happiness. It consists of four things and is frequently utilized in studies.

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The dispersion of a Normal distribution is less dispersed than the T-distribution.

The dispersion of a distribution is measured by the standard deviation (or variance) of the distribution.

For a Normal distribution, the standard deviation is always known.

On the other hand, for a t-distribution, the standard deviation of the population is not known and is estimated using the sample standard deviation.

This means that the t-distribution has more uncertainty, which leads to more dispersion compared to the Normal distribution.

The t-distribution is often used when the sample size is small or when the population standard deviation is unknown. As the sample size increases, the t-distribution approaches the Normal distribution.

Therefore, for large sample sizes, both distributions become more or less similar.

In conclusion, the Normal distribution is less dispersed than the t-distribution.

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Answer:

Side x = 2.12132 = 3√2/2

Step-by-step explanation:

I used a triangle calculator to find side x

The relation C is defined on the set of real numbers (R) as xCy if [tex]x^2[/tex] + [tex]y^2[/tex] = 1 is not reflexive, not symmetric, and not transitive.

To determine if the relation C is reflexive, we need to check if every element x in R is related to itself. However, for any real number x, [tex]x^2[/tex] + [tex]x^2[/tex] = 2[tex]x^2[/tex] ≠ 1. Therefore, C is not reflexive.

For symmetry, we need to check if whenever xCy, then yCx. However, if we take x = 0 and y = 1, we have [tex]x^2[/tex] + [tex]y^2[/tex] = [tex]0^2[/tex]+ [tex]1^2[/tex] = 1, which satisfies the condition for C. But for yCx, we have [tex]y^2[/tex] + [tex]x^2[/tex] = [tex]1^2[/tex] + [tex]0^2[/tex] = 1, which also satisfies the condition. Therefore, C is symmetric.

To test for transitivity, we need to check if whenever xCy and yCz, then xCz. However, if we consider x = 0, y = 1, and z = -1, we have [tex]x^2[/tex] +[tex]y^2[/tex] = [tex]0^2[/tex]+ [tex]1^2[/tex] = 1 and [tex]y^2[/tex] + [tex]z^2[/tex] =[tex]1^2[/tex] + [tex](-1)^2[/tex] = 2. Since 1 + 2 ≠ 1, the condition for transitivity is not satisfied. Thus, C is not transitive.

In conclusion, the relation C is not reflexive, symmetric, or transitive.

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All interior angle degrees must add up to 180 degrees.

the little square means that it is a right angle (90 degrees)

30 + 90 = 120

Y = 60

Answer:

radius of the base of cylinder = 4 in

Step-by-step explanation:

Volume of cylinder = pi x r² × h

502.4 = 3.14 x r² x 10

502.4 = 31.4 x r²

r² = 502.4/31.4

r² = 16

r = 4 in

Answer:

A. 261.8

Step-by-step explanation:

espero ayudar sorry

Based on the given options, the additional information that could be used to prove congruence using AAS or ASA is:

Option 1: B ≅ P and BC ≅ PQ

To prove that two triangles are congruent using AAS (Angle-Angle-Side) or ASA (Angle-Side-Angle) postulates, we need specific conditions met. Let's examine the given options:

1. B ≅ P and BC ≅ PQ:

This condition satisfies the AAS postulate since we have two angles and a corresponding side that are congruent.

2. A ≅ T and AC = TQ = 3.2 cm:

This condition satisfies the ASA postulate since we have two angles and the included side that are congruent.

3. A ≅ T and B ≅ P:

This condition alone does not satisfy either the AAS or ASA postulate, as we need to have at least one side congruent or an included side congruent to prove congruence.

4. AC = TQ = 3.2 cm and CB = QP = 2.2 cm:

This condition alone does not satisfy either the AAS or ASA postulate, as we need to have congruent angles as well.

Based on the given options, the additional information that could be used to prove congruence using AAS or ASA is:

- Option 1: B ≅ P and BC ≅ PQ

This satisfies the AAS postulate, and with the given information, we can conclude that the triangles are congruent.

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