A one dimensional object with no endpoint is a?
A.ray
B.line segment
C.line
D.point

Answers

Answer 1

Answer:

its line fjfjfjjejjdjdj

Answer 2

As per the given condition, the required one dimensional object with no end point is a line.

What is a ray?

"In geometry, a ray can be defined as a part of a line that has a fixed starting point but no end point. It can extend infinitely in one direction.

On its way to infinity, a ray may pass through more than one point. When naming a ray, it is denoted by drawing a small ray on top of the name of the ray. "

What is a line segment?

"A line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints."

What is a line?

"A line is a one-dimensional object, which has length but no width. A line is made of a set of points which is extended in opposite directions infinitely. It is determined by two points in a two-dimensional plane. "

What is a point?

"A point is a primitive notion that models an exact location in the space, and has no length, width, or thickness. In modern mathematics, a point refers more generally to an element of some set called a space."

Given, a one dimensional object with no endpoint.

Therefore, the require object is a line.

Learn more about a line here: https://brainly.com/question/27560536

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Related Questions

What Is It HomeWork*.

Answers

Answer:

sumthing that we hate doing

Step-by-step explanation:ughhhhhhhhhh

The inequalities is 6 is greater than or equal to 6

can anyone help with the vertical angles

Answers

Answer:

Step-by-step explanation:

do the ones that are congruent and right in front of eachother

Answer: Choice A

[tex]\angle JLK \ \ \& \ \ \angle MLN\\\\\angle JLM \ \ \& \ \ \angle KLN[/tex]

See the diagram below. I've marked the angles in question using different colors. Angles JLK and MLN are in red. Angles JLM and KLN are in blue.

Vertical angles are opposite one another when we have an X shape like this. Vertical angles are always congruent.

now? A)12 years b] 15 years
c] 194 years d] 21 years
472) The ratio of
heir age arier
471) Ratio of Aashok's age to sandeep's age is 4:3. Ashok will be 26 years old after 6 years. How old is Sandeep

Answers

Answer:

Sandeep would be 15 years old.

Step-by-step explanation:

If Ashok is 26 in 6 years he is 20. We need to simplify 20 to 4.

20/4 = 5

So that means Sandeep’s age would be 5 x 3

5 x 3 = 15

20:15 simplified is 4:3

Bob is hiking down a 12-mile country trail. He could hike at 3 mph for the first two hours and then go the rest of the way at 5 mph or he could just go the whole way at 4 mph. How long would each of these options take? Which option is the faster?
Answer:
The first option would take:
The second option would take:
The faster option is the:

Answers

Answer: The first option would take: 3.2 hr

The second option would take: 3 hr

The faster option is the: second

Step-by-step explanation:

Answer:

Below in bold.

Step-by-step explanation:

Speed = distance / time.

First option:

Walking at 3mph for 2 hours will give 2*3 = 6 miles.

So for 6 miles travelling at 5 mph he will take 6/5 = 1.2 hours.

Total time = 3.2 hours.

Second option:

Walking for 12 miles at 4 mph will take him 12/4 = 3 hours.

The fastest option is the second one.

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8) lies on its terminal side

Answers

Answer:

cosФ = [tex]\frac{1}{\sqrt{65}}[/tex] , sinФ = [tex]-\frac{8}{\sqrt{65}}[/tex] , tanФ = -8, secФ = [tex]\sqrt{65}[/tex] , cscФ = [tex]-\frac{\sqrt{65}}{8}[/tex] , cotФ = [tex]-\frac{1}{8}[/tex]

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = [tex]\frac{x}{r}[/tex]sinФ = [tex]\frac{y}{r}[/tex]tanФ = [tex]\frac{y}{x}[/tex]secФ = [tex]\frac{r}{x}[/tex]cscФ = [tex]\frac{r}{y}[/tex]cotФ = [tex]\frac{x}{y}[/tex]Where r = [tex]\sqrt{x^{2}+y^{2} }[/tex] (the length of the terminal side from the origin to point (x, y)You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = [tex]\sqrt{x^{2}+y^{2} }[/tex]

∵ x = 1 and y = -8

∴ r = [tex]\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}[/tex]

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = [tex]\frac{x}{r}[/tex]

∴ cosФ = [tex]\frac{1}{\sqrt{65}}[/tex]

∵ sinФ = [tex]\frac{y}{r}[/tex]

∴ sinФ = [tex]-\frac{8}{\sqrt{65}}[/tex]

∵ tanФ = [tex]\frac{y}{x}[/tex]

∴ tanФ = [tex]-\frac{8}{1}[/tex] = -8

∵ secФ = [tex]\frac{r}{x}[/tex]

∴ secФ = [tex]\frac{\sqrt{65}}{1}[/tex] = [tex]\sqrt{65}[/tex]

∵ cscФ = [tex]\frac{r}{y}[/tex]

∴ cscФ = [tex]-\frac{\sqrt{65}}{8}[/tex]

∵ cotФ = [tex]\frac{x}{y}[/tex]

∴ cotФ = [tex]-\frac{1}{8}[/tex]

The neighborhood swimming pool drains at a rate of 99 gallons every 3 hours. At this rate, how many gallons are
emptied each hour?
Helllllpppppp meeee

Answers

Answer:

33mph

Step-by-step explanation:

because if u divide 99 by 3 that is the answer

PLEASE HELP ASAP!!
There are 800 students who attend Park Middle School. There are 1.5 times as many boys as there are girls.
x is boys
y is girls
800=1.5x=y
Determine how many boys and girls attend Park Middle School. Round to the nearest whole number if necessary. Show your work.

Answers

Answer:

320 boys; 480 girls

Step-by-step explanation:

Here is the correct system of equations you can write for this equation:

1.5x=y

x+y=800

x+1.5x=800

2.5x=800

x=320

320+y=800

y=480

Find the general solution of y''' + 9y'' + y' − 111y = 0 if it is known that y1 = e−6x cos(x) is one solution.

Answers

Answer:

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

Step-by-step explanation:

The objective of this question is to solve:

[tex]\dfrac{dy(x)}{dx}+ 9\dfrac{d^2y(dx)}{dx^2}+\dfrac{d^3y(x)}{dx^3}-111y(x) = 0 :[/tex]

Suppose the general solution is proportional to [tex]e^{\lambda x}[/tex] for [tex]\lambda[/tex] is constant; Then:

Let's replace [tex]y(x) = e^{\lambda\ x}[/tex] into the above equation:

i.e.

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )+ 9 \dfrac{d^2}{dx^2}(e ^{\lambda x} ) + \dfrac{d}{dx}(e ^{\lambda x} )- 111 \ e ^{\lambda x} = 0[/tex]

To Replace:

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )[/tex] with [tex]\lambda^3 e ^{\lambda x }[/tex]

[tex]\dfrac{d^2}{dx^2}(e ^{\lambda x} ) \ with \ \lambda^2 e^{\lambda\ x}[/tex]

[tex]\dfrac{d}{dx}(e ^{\lambda x} ) \ with \ \lambda e ^{\lambda \ x}[/tex]

Thus;

[tex]\lambda^3 e ^{\lambda x }[/tex] + [tex]9 \lambda^2 e^{\lambda\ x}[/tex] + [tex]\lambda e ^{\lambda \ x}[/tex] - 111 [tex]e ^{\lambda \ x}[/tex] = 0

[tex]e ^{\lambda \ x} (\lambda ^3 + 9 \lambda ^2 + \lambda - 111 )= 0[/tex]

∴

In as much as [tex]e^{ \lambda x}\neq 0[/tex] for any finite [tex]\lambda[/tex]; Then:

[tex]\lambda ^3 + 9 \lambda ^2 + 111 = 0[/tex]

By Factorization:

[tex](\lambda - 3) ( \lambda ^2 + 12 \lambda + 37) = 0[/tex]

[tex]\lambda = -6 + i \ or\ \lambda = -6 - i \ or \ \lambda = 3[/tex]

However;

The root [tex]\lambda = -6 \pm i[/tex] yield;

[tex]y_1 = (x) = c_1 e ^ {(-6+i)x}[/tex]

[tex]y_2 (x) = c_2e^{(-6-i)x}[/tex]

The root [tex]\lambda = 3[/tex] yield;

[tex]y_3(x) = c_3 e^{3x}[/tex]

∴

The general solution is:

[tex]y(x) = y_1(x) + y_2(x) + y_3(x) = \dfrac{c_1}{c^{(6-i)}x}+\dfrac{c_2}{c^{(6+i)}x}+ c_3e^{3x}[/tex]

Using Euler's Identity ;

[tex]e^{\alpha+i \beta} = e^\alpha \ cos (\beta ) + i \ e^\alpha \ sin ( \beta)[/tex]

[tex]y(x) = c_1 ( \dfrac{cos (x) }{e^{6x}}+ \dfrac{i \ sin x }{e^{6x} }) + c_2 ( \dfrac{cos (x)}{e^{6x}}- \dfrac{-i \ sin (x)}{e^{6x}})+c_3 e^{3x}[/tex]

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

If cost of 3 kg of sugar is Rs 240. What is rate of cost of sugar

Answers

Rs80 for each 1kg sugar

I need help ASAP due rn!

Solve the equation by completing the square. Show all your steps
X^2-6x+13=0

Answers

There are no real solutions

HELP PLSSSSS AAAAAAAAAAAAAAAAAAAAAA ILL GIVE BRAINLIEST B(

Answers

Answer:

a(n) = (3/5)a(n-1), where a(1) = 10 and n is 2 or greater.

Step-by-step explanation:

determine the common factor...The first term (10) by 3/5 results in the given second term (6); the third term is 3/5 of the second term (6), resulting in 18/5 (equivalent to 36/10 or 3.6/1, or just 3.6. Resulting in a(n) = (3/5)a(n-1).

the third term is 3.6, which, if mult. by (3/5), produces 2.16, as expected.

Thus, the recursive formula for this geometric sequence is a(n) = (3/5)a(n-1).

This is good only for a(1) = 10 and n = 2, 3, ....

Hope this helps you

Answer: