A local band sells out for their concert. They sell all 1,175 tickets for a total purse of $28,112.50. The tickets were priced at $20 for student tickets, $22.50 for children, and $29 for adult tickets. If the band sold twice as many adult as children tickets, how many of each type was sold

Answer:

Step-by-step explanation:

(y + 3) = (1/8)(x - 2)

Answer:

Step-by-step explanation.

The Distributive Property shows that 6(p + q) is equivalent to 6p + 6q

The distributive property tells us how to solve expressions in the form of a(b + c).  The distributive property is sometimes called the distributive law of multiplication and division. It is given by:

a(b + c) = ab + ac

Given the expression:

6(p + q)

Using the distributive property:

= 6p + 6q

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Answer:

Diagonal and horizontal lines

Step-by-step explanation:

To answer this question it is first important to know what a function is. A function is a relationship that has a singular y value for each x-value. This means that x-values will never repeat.

Linear functions are functions that increase in a constant way. Meaning that the slope of the line is constant and there is a common difference between the points. Because the change is constant, there is no change in direction. Thus, the function will be one straight line.

This line can obviously be diagonal because a diagonal line has unique x and y values. However, the line can also be horizontal. Horizontal lines many have repeating y-values but because the x-values don't repeat it is still a function. This reason is also why vertical lines are the only straight line to not be a liner function. In vertical lines, the x-values repeat. So, it does not work as a function.

Answer:

Step-by-step explanation:

total of 15(36) = 540 person•hours was used

540 / 30 = 18 people

18 - 15 = 3 people need to be added

Answer:

188.571

if you did directly answer may differ

Step-by-step explanation:

you can see it from the picture above

The area of the cross-section formed by slicing the cylinder down the center and perpendicular to the bases is 120 square inches.

"A cylinder is a three-dimensional solid that holds two parallel bases joined by a curved surface, at a fixed distance".

For the given situation,

The diameter of the cylinder, d = 10 inches

The height of the cylinder, h = 12 inches

The area of the cross-section formed by slicing the cylinder down the center and perpendicular to the bases is a rectangle.

So, the length of the rectangle, l = 12 inches.

The breadth of the rectangle, b = 10 inches

The formula for the area of the rectangle is A= l × b

⇒ [tex]A=12[/tex] × [tex]10[/tex]

⇒ [tex]A=120[/tex]

Hence we can conclude that the area of the cross-section formed by slicing the cylinder down the center and perpendicular to the bases is 120 square inches.

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1/27

Explanation:

You would multiply to get to the answer.                                                                                    

[tex]1)3k - 2k \\ = k(3 - 2) \\ = k(1) \\ = k[/tex]

[tex]2) {5x}^{2} - 10x - {8x}^{2} + x \\ = {5x}^{2} - {8x}^{2} - 10x + x \\ = - 3 {x}^{2} - 9x \\ = - 3x(x - 3)[/tex]

[tex]3) - (m + n) + 2(m - 3n) \\ = - m - n + 3m - 6n \\ = - m + 2m - n - 6n \\ = m - 7n [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

1/1

Step-by-step explanation:

I'll do the first two parts to get you started.

=====================================================

Part (i)

We can show that the operation [tex]\nabla[/tex] is not commutative by picking two random and different real numbers for a,b. In other words, I'm using a counter-example.

Let's say we go for a = 1 and b = 2

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\1 \nabla 2 = \frac{3*1+2}{5} - 1\\\\1 \nabla 2 = \frac{5}{5} - 1\\\\1 \nabla 2 = 1 - 1\\\\1 \nabla 2 = 0\\\\[/tex]

Now let's swap the values. We'll try a = 2 and b = 1

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\2 \nabla 1 = \frac{3*2+1}{5} - 1\\\\2 \nabla 1 = \frac{7}{5} - 1\\\\2 \nabla 1 = 1.4 - 1\\\\2 \nabla 1 = 0.4\\\\[/tex]

We can see that [tex]1 \nabla 2[/tex] and [tex]2 \nabla 1[/tex] are not the same value. In general, [tex]a \nabla b \ne b \nabla a[/tex] Therefore, the operation [tex]\nabla[/tex] is not commutative.

The only time [tex]a \nabla b = b \nabla a\\\\[/tex] is true is when [tex]a = b[/tex], since,

[tex]\frac{3a+b}{5}-1 = \frac{3b+a}{5}-1\\\\\frac{3a+a}{5}-1 = \frac{3a+a}{5}-1\\\\\frac{4a}{5}-1 = \frac{4a}{5}-1\\\\[/tex]

It's when [tex]a \ne b[/tex] is where the operation becomes noncommutative.

Another way to arrive at the [tex]a = b[/tex] condition is to solve the original equation for either 'a' or b.

=====================================================

Part (ii)

Using the previous part as inspiration, we'll do a counter-example to show that the operation is not associative. Pick 3 random values for a,b,c. Here are the values I'll pick.

Then,

[tex]d = b \nabla c = \frac{3b+c}{5}-1 = \frac{3*2+3}{5}-1 = 0.8\\\\a \nabla (b \nabla c) = a \nabla d = \frac{3a+d}{5}-1 = \frac{3*1+0.8}{5}-1 = -0.24\\[/tex]

Next, we can say:

[tex]d = a \nabla b = \frac{3a+b}{5}-1 = \frac{3*1+2}{5}-1 = 0\\\\(a \nabla b) \nabla c = d \ \nabla c = \frac{3d+c}{5}-1 = \frac{3*0+3}{5}-1 = -0.4[/tex]

Let's compare the two outputs:

[tex]a \nabla (b \nabla c) = -0.24\\\\(a \nabla b) \nabla c = -0.4[/tex]

They don't match up, so [tex]a \nabla (b \nabla c) \ne (a \nabla b) \nabla c[/tex] when (a,b,c) = (1,2,3).

In general, the operation is not associative in R.

Answer: [tex]f(x) = 5(x+1)^{2} - 13[/tex]

Vertex = (-1, -13)

Step-by-step explanation:

[tex]f(x) = 5x^{2} + 10x - 8\\f(x) = 5(x^{2}+2x)-8\\f(x) = 5(x^{2}+2x+1-1)-8\\f(x) = 5((x+1)^{2}-1)-8\\f(x) = 5(x+1)^{2}-5-8\\f(x) = 5(x+1)^{2}-13[/tex]

Vertex = (h, k) = (-1, -13)

Answer:

ur mom

Step-by-step explanation:

ur mom + 3= 69

The volume of the storage tank to the nearest hundredth is 2840.04 m³.

Given that, the conical tank has a height of 23.7 meters and a diameter of 21.4 meters.

The volume of a cone is the amount of space occupied by a cone in a three-dimensional plane. A cone has a circular base, which means the base is made of a radius and diameter.

The volume of a cone formula is 1/3 πr²h.

Put h=23.7 meters and radius = 21.4/2 = 10.7 meters in the volume of a cone formula

That is, 1/3 × 3.14 × (10.7)² × 23.7

= 2840.0389 m³

≈ 2840.04 m³

Therefore, the volume of the storage tank to the nearest hundredth is 2840.04 m³.

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Answer:

three hours every 1 book

Step-by-step explanation:

36-12

6-2

3-1

Answer:

25cm^2

Step-by-step explanation:

A square has 4 equal sides so each side will be 20/4 = 5cm

Easily calculate the area by taking 5 x 5 = 25cm^2

Answer:

n=22.23

Step-by-step explanation:

21+n=43.23

-21 to both sides

0+n=22.23

n=22.23

Answer:

66

Step-by-step explanation:

66 is the only number between 63 and 68 that is divisible by both 2 and 11.

66/2=33   66/11=6

Answer:

1428485748586384858858

Answer:

Step-by-step explanation:

trapezoid is a 4-sided figure with one pair of parallel sides. For example, in the diagram to the right, the bases are parallel. To find the area of a trapezoid, take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2, The formula looks like this:

area_trapezoid1.gif or area_trapezoid2.gif

Where b1.gif is base1.gif, b2.gif is base2.gif, h.gif is height and · means multiply.

Each base of a trapezoid must be perpendicular to the height. In the diagram above, both bases are sides of the trapezoid. However, since the lateral sides are not perpendicular to either of the bases, a dotted line is drawn to represent the height.

Answer:

132 in /12 in/ft + 3 yd(3ft/yd) = 11 + 9 = 20 ft

Step-by-step explanation:

Answer:

20 ft

Step-by-step explanation:

12 inches = 1 foot

12 : 1 = 132 : y

[tex]\frac{132:y}{12:1}[/tex]

12 × y = 132 × 1

12y = 132

12y ÷ 12 = 132 ÷ 12

y = 11

11 ft

1 yard = 3 feet

1 : 3 = 3 : y

[tex]\frac{1:3}{3:y}[/tex]

1 × y = 3 × 3

1y = 9

y = 9

9 ft

11 ft + 9ft = 20 ft

The answers are:

5x + 3y = 41

2x + 3y = 20

           -2x - 3y = -20

Therefore, the answers are:

Hoped this helped

[tex]-BrainiacUser1357-[/tex]

Answer:

Step-by-step explanation:

It looks like you need to solve this system of equations.

That means we need to find a value for x and a value for y that makes both equations true.

Since both equations have a 3y in them, this system is ready to use a method called "elimination method"

Since the x terms are lined up, and the y terms are lined up, the equal signs are lined up, and the constants are lined up...you can subtract the bottom equation from the top equation.

5x + 3y = 41

2x + 3y = 20

Subtract and you will get

3x + 0y =21

We don't need to write that 0y, because it is 0.

3x = 21, now divide by 3

x = 7, almost finished!

Use x = 7 in either of the original equations to find y.

5x + 3y = 41 and x = 7

5•7+ 3y = 41

35 + 3y = 41

-35 -35

3y =6

y = 2

So the solution is x=7 and y=2

That can also be written as an ordered pair (7, 2)

Answer:

a

Step-by-step explanation:

(x-2)(x-11) less than or equal to 0

which means x is between 2 and 11 when it is less than 0

Answer:

7 hours

Step-by-step explanation:

Answer:

she could park there for 7 hours

Step-by-step explanation:

13-4=9 9/1.50=6

Answer:

Yes, this is a function

Step-by-step explanation:

You know this because it passes the vertical line test.

I hope this helps!

Answer:

Function

Step-by-step explanation:

Answer:

[tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]

Step-by-step explanation:

[tex]tan^2x+7tanx+8=0,[0^{\circ},360^\circ)[/tex]

[tex]tan^2x+7tanx+8=0[/tex]

[tex]u=tanx[/tex] <-- U-substitution

[tex]u^2+7u+8=0[/tex]

[tex](u+7)(u+1)=0[/tex]

[tex](tanx+7)(tanx+1)=0[/tex] <-- Replace u with tanx

[tex]tanx+7=0[/tex]

[tex]tanx=-7[/tex]

[tex]x=98.13^\circ,278.13^\circ[/tex]

[tex]tanx+1=0[/tex]

[tex]tanx=-1[/tex]

[tex]x=135^\circ,315^\circ[/tex]

Therefore, [tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]

Answer: B

Step-by-step explanation: Jacob doesn't know either colleges' actual price. Bayside could still be equal to or more expensive than Lakeshore.

Answer:

the answer is A)5+0.5n=11

Step-by-step explanation:

5 is increased by half a number, so half of. a number(n) is added to 5

Answer:

D is correct

Step-by-step explanation:

I hope this helps

5 increased by half a number is 11.

5 increased by half a number is 11. 5 + 1/2n = 11 where n is the unknown number. 1/2n = 11 - 5 = 6 n = 6 * 2 = 12 The number is 12.

Using it's formula, it is found that the slope of the line formed from the two given places is of [tex]\mathbf{\frac{6}{7}}[/tex]

Given two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex], the slope is given by change in y divided by change in x, that is:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

In this problem:

Hence, applying the formula for the slope, considering [tex](x_1, y_1) = (-1, -4)[/tex] and [tex](x_2,y_2) = (6,2)[/tex]:

[tex]m = \frac{2 - (-4)}{6 - (-1)} = \frac{6}{7}[/tex]

The slope is of [tex]\mathbf{\frac{6}{7}}[/tex]

A similar problem is given at https://brainly.com/question/5427529

Answer:

Focus on planting trees and and getting healthier soil, improve energy efficiency and not use so much pesticides using natural ways to plant things.

Step-by-step explanation:

Answer:

Step-by-step explanation:

=> 3x + 4y + 6z = 15

=> 3x + 4y + 6z - 4y = 15 - 4y

=> 3x + 6z = 15 - 4y

=> 3x + 6z - 6z = 15 - 4y - 6z

=> 3x = 15 - 4y - 6z

[tex] = > \frac{3x}{3} = \frac{15 - 4y - 6z}{3} [/tex]

[tex] = > x = 5 - \frac{4}{3} y - 2z \: (ans)[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{QUESTIONS:}[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{ANSWER:}[/tex]

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{SOLUTION:}[/tex]

[tex]3 \orange{+ 4y + 6z = 15}[/tex]

Move the variables to the right-hand side and change their signs.

[tex]3x = 15 \orange{ - 4 - 6z}[/tex]

Divide both sides of the equation by 3

[tex]\orange{3x = 15 - 4 - 6z}[/tex]

[tex]↓[/tex]

[tex]\orange{x = 5 - \frac{4}{3} y - 2z}[/tex]

The x-intercepts of 3x+4y+6z=15 is

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

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if we can assume the ball is being thrown from the ground upwards, then we can say that the inital height of it is 0, whilst its initial velocity is 80 ft/s, thus

[tex]~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&80\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&0\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-16t^2+80t+0\implies h(t)=-16t^2+80t[/tex]