A line passes through (-5, -3) and is parallel to -3x - 7y = 10. The equation of the line in slope-intercept form is _____.

Answer: 45%

From my common sense

If the graph line goes up, she wins.

If the graph line goes down, she loses.

1. Count the amounts of times which the graph line goes up.

(btw the first game she won because the graph line started at 1)

= 9

2. Calculate the winrate of her 20 games

= 9/20 * 100

= 45%

Answer:

t+c ≤ 55

Step-by-step explanation:

t+c is the total pieces of furniture and it must be at most (less than or equal to) 55 so t+c ≤ 55 is the equality that represents the possible values.

Answer:

Step-by-step explanation:

m=-2/3

b=-7

First, find the slope-intercept form.

y=mx+b

You know what the m and b values are, so simply plug them into the equation.

Slope-Intercept Form

y=-2/3x-7

From there, let's find the point-slope equation.

An easy way to find a coordinate point that the line crosses is to set one of the x or y variables equal to 0.

So let's set the x to 0.

y=-2/3x-7

y=-2/3(0)-7

y=-7

Therefore, when x is 0, y is equal to -7. We can now write our point. (0,-7)

Use the point-slope formula to write the point-slope equation.

y-y1=m(x-x1)

Point-Slope Equation

y-(-7)=-2/3(x-0)

Now, to find the standard form equation, let's find it using our slope-intercept equation. The formula to find standard form is

ax+by=c

y=-2/3x-7

Standard Form Equation

2/3x+y=-7

[tex](3-5i)^2\\\\=3^2-2(3)(5i) + (5i)^2\\\\=9-30i +25i^2\\\\=9-30i +25(-1)~~~~;[i^2=-1]\\\\=9-30i-25\\\\=-16-30i[/tex]

Answer:

This is the graph of a sine function

The y-intercept of the graph is the function value y=0

The smallest positive x-intercept of the graph is located at x=pi/2

The greatest value of y is y=2

For x between x=-pi and x=pi/2, the function value y=>0

Step-by-step explanation:

Answer:

1) terminating decimal

2) 0.7 is a terminating decimal

3) a non-terminating, non-repeating decimal

4) a rational number

Step-by-step explanation:

Answer:

[tex]g(x)=\frac{1}{8} x^{3} -\frac{3}{2} x^{2} +6x-5[/tex]

Step-by-step explanation:

[tex]x=2\sqrt[3]{y-3} +4[/tex]

switch the x and y, then use order of opperations

Answer:

4 assignments per day.

Step-by-step explanation:

Answer:

3 .

Step-by-step explanation:

464 / 130

it’s not exactly like this,

if Im wrong!

Answer:

y = -2x - 1

Step-by-step explanation:

Put y on the left and everything else on the right

Answer:

Y = 10x + 20

Step-by-step explanation:

sorry if im wrong

Answer:

y = 2x - 4

Step-by-step explanation:

10x - 5y = 20

Subtract 10x both sides

-5y = 20 + (-10x)

Divide by -5

y = -4 + 2x

y = 2x + (-4)

Answer:

4x-12

Step-by-step explanation:

2x-5[2x-7(5)}=2x+2x-7-5

4x-12

negative integers are added to each other

Answer:

The answer is 75ft. Hope this helps.

Answer:

Scale is 1/2

Step-by-step explanation:

5*1/2=5/2

12*1/2=6

g(x) as given has no inverse because there are instances of two x values giving the same value of g(x). For instance,

x = -1   ⇒   g(-1) = 4 (-1 + 3)² - 8 = 8

x = -5   ⇒   g(-5) = 4 (-5 + 3)² - 8 = 8

Only a one-to-one function can have an inverse. g(x) is not one-to-one.

However, if we restrict the domain of g(x), we can find an inverse over that domain. Let [tex]g^{-1}(x)[/tex] be the inverse of g(x). Then by definition of inverse function,

[tex]g\left(g^{-1}(x)\right) = 4 \left(g^{-1}(x) + 3\right)^2 - 8 = x[/tex]

Solve for the inverse:

[tex]4 \left(g^{-1}(x) + 3\right)^2 - 8 = x[/tex]

[tex]4 \left(g^{-1}(x) + 3\right)^2 = x + 8[/tex]

[tex]\left(g^{-1}(x) + 3\right)^2 = \dfrac{x + 8}4[/tex]

[tex]\sqrt{\left(g^{-1}(x) + 3\right)^2} = \sqrt{\dfrac{x + 8}4}[/tex]

[tex]\left| g^{-1}(x) + 3 \right| = \dfrac{\sqrt{x+8}}2[/tex]

Recall the definition of absolute value:

[tex]|x| = \begin{cases}x & \text{if }x\ge0\\-x&\text{if }x<0\end{cases}[/tex]

This means there are two possible solutions for the inverse of g(x) :

• if [tex]g^{-1}(x) + 3 \ge 0[/tex], then

[tex]g^{-1}(x) + 3 = \dfrac{\sqrt{x+8}}2 \implies g^{-1}(x) = -3+\dfrac{\sqrt{x+8}}2[/tex]

• otherwise, if [tex]g^{-1}(x)+3<0[/tex], then

[tex]-\left(g^{-1}(x) + 3\right) = \dfrac{\sqrt{x+8}}2 \implies g^{-1}(x) = -3-\dfrac{\sqrt{x+8}}2[/tex]

Which we choose as the inverse depends on how we restrict the domain of g(x). For example:

Remember that the inverse must satisfy

[tex]g\left(g^{-1}(x)\right) = x[/tex]

In the first case above, [tex]g^{-1}(x) + 3 \ge 0[/tex], or [tex]g^{-1}(x) \ge -3[/tex]. This suggests that we could restrict the domain of g(x) to be [tex]x \ge -3[/tex].

Then as long as [tex]x \ge -3[/tex], the inverse is

[tex]g^{-1}(x) = -3+\dfrac{\sqrt{x+8}}2[/tex]

Answer:

h = 60˚

Step-by-step explanation:

Look at where it shows the 120˚, and its verticle angle. Verticle angles are congruent, or the same meaning it's also 120˚.

Then go to its corresponding angle, which is next to the h. Corresponding angles are also congruent, or the same. I'll call this angle m to save time and hopefully confusion.

Now, h and m are supplementary angles, meaning they add up to 180˚.

180˚ - 120˚, or 60˚ is your answer.

h = 60˚

The solution is, the value of h is, h = 60˚

In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle. The two rays are called the sides of an angle, and the common endpoint is called the vertex.

here, we have,

from the given figure, we get,

Look at where it shows the 120˚, and its vertical angle.

Vertical angles are congruent, or the same meaning it's also 120˚.

now, we have,

Then go to its corresponding angle, which is next to the h. Corresponding angles are also congruent, or the same.

We call this angle m to save time and hopefully confusion.

Now, h and m are supplementary angles,

meaning they add up to 180˚.

so, we have,

180˚ - 120˚,

or 60˚ is your answer.

i.e.

h = 60˚

Hence, The solution is, the value of h is, h = 60˚

To learn more on angle click:

brainly.com/question/28451077

#SPJ7

Answer:

2 stops, 30 min

Step-by-step explanation:

to figure this out we have to divide B's time by A's time. 30÷15 is 2.

Answer:

The distance between [tex](7,1)[/tex] and [tex](-4,-5)[/tex] is [tex]\sqrt{157}[/tex] units

Step-by-step explanation:

Use the distance formula [tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex] where [tex]d[/tex] is the positive distance between [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]:

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

[tex]d=\sqrt{(-5-1)^2+(-4-7)^2}[/tex]

[tex]d=\sqrt{(-6)^2+(-11)^2}[/tex]

[tex]d=\sqrt{36+121}[/tex]

[tex]d=\sqrt{157}[/tex]

Therefore, the distance between [tex](7,1)[/tex] and [tex](-4,-5)[/tex] is [tex]\sqrt{157}[/tex] units

Answer: The distance between (7,1), and (-4, -5) is 12.53.

Answer:  Child is $1 and Adult is $3, per person.

Step-by-step explanation:

We have two unknowns, so we need at least two equations.  Let C and A stand for the price of a ticket for a child and an adult, respectively.

The income for Monday and Tuesday can be calculated:

Monday:   16C + 42A = $142

Tuesday:  24C + 26A = $102

Rearrange the second equation to isolate one of the variables.  I'll pick C:

24C + 26A = $102

C  = ($102 - 26A)/24

Now use this expression for C in the first equation

16C + 42A = $142

16(($102 - 26A)/24) + 42A = $142

16(($102 - 26A)/24) + 42A = $142

(1632 - 416A)/24 + 42A = $142

(68 - 17.3333A + 42A = $142

24.6667A = 74

A = 3  [The price of an adult pool admission is $3]

Use this value in either equation to find the price of a child's admission:

24C + 26A = $102

24C + 26*($3) = $102

24C = 102 - 78

C = $1   [The price of a child's admission to the pool is $1]

Check to see if these prices satisfy both equations:

Monday:   16C + 42A = $142

Tuesday:  24C + 26A = $102

---

Monday:   16*(1) + 42*(3)  = $142   ?   YES

Tuesday:  24*(1) + 26*(3) = $102   ?    YES

Child is $1 and Adult is $3, per person.

Answer:

i am not to sure but i think its 5/13 or 5/40

Answer:

a=100

b=1

Step-by-step explanation:

18a+65b=1865

23a+7b=2314

We need to make one of the variables equal to the other

So...

The LCM for 65 and 7 is 455

So multiply 7 with 18a+65b=1865

and Multiply 65 with 23a+7b=2314

7 times 18a+65b=1865 is 126a+455b=13055

65 times 23a+7b=2314 is 1495a+455b=150410

So Subtract 126a+455b=13055 and 1495a+455b=150410

So 1369a=137355

Divide:

Which is about 100 (The actual value is 100.3323594)

Thus a=100

Substitute:

b=1

Hope this helps!

(The answer is rounded)

Answer:

[tex]\huge\color{pink}\boxed{\colorbox{black}{Answer♡}}[/tex]

The reason that a heavy body doesn't fall faster than a light body is because the greater gravitational force on the heavier body (its weight), acts on a correspondingly greater mass (inertia). The ratio of gravitational force to mass is the same for every body—hence all bodies in free fall accelerate equally.

hope helpful~

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a.

The required equation is  23p + 19.50 = 180.50

Let p represent the number of people who can go to the amusement park.

Since the ticket costs $23 per person, the total amount paid for ticket is rate × number of person = $23 × p = 23p.

Since we pay $19.50 for parking, the total amount spent is T = 23p + 19.50

Since the total amount equals $180.50. T = 180.50

So, 23p + 19.50 = 180.50

The required equation is  23p + 19.50 = 180.50

b.

Solving 23p + 19.50 = 180.50, we have

23p = 180.50 - 19.50

23p = 161

p = 161/23

p = 7

So, the number of people who can go to the amusement park is 7.

Learn more about linear equations here:

https://brainly.com/question/24307397

Answer:

[tex]c=\frac{1}{16}[/tex]

Step-by-step explanation:

[tex]f(x)=\sqrt{2x}[/tex]

[tex]f'(x)=\frac{\sqrt{2x}}{2x}[/tex]

[tex]f'(1)=\frac{\sqrt{2}}{2}[/tex]

[tex]f'(c)=\frac{\sqrt{2c}}{2c}[/tex]

[tex]f'(c)=4f'(1)[/tex]

[tex]\frac{\sqrt{2c}}{2c}=4(\frac{\sqrt{2}}{2})[/tex]

[tex]\frac{\sqrt{2c}}{2c}=2\sqrt{2}[/tex]

[tex]\sqrt{2c}=4c\sqrt{2}[/tex]

[tex]2c=32c^2[/tex]

[tex]2=32c[/tex]

[tex]\frac{1}{16}=c[/tex]

Answer:

Well a midpoint makes the cutter segment or Line in exactly in half. So the two lines cutted are equal. In this case t is the midpoint. PT and TQ are equal. So you have two expressions, make then equal to each other since they are congruent.

6x+4=8x-8

12=2x

x=6

Now PT is 6x+4

So we subsitute x for 6 since x=6

6*6+4

40

PT is 40