The time taken for the javelin thrown at 28.5 m/s from flat ground at a 43.2 degree angle to reach the maximum height is 2.0 s
How do I determine the time taken to reach the maximum height?From projectile motion, we understand that the time taken to reach maximum height is given as:
t = uSineθ / g
Where
t is the time to reach maximum heightu is the initial velocity θ is the angle of projectiong is acceleration due to gravityNow, using the above formua, we can obtain the time taken for the javelin to reach the maximum height as follow:
Initial velocity (u) = 28.5 m/s
Angle of projection (θ) = 43.2 degrees
Acceleration due to gravity (g) = 9.8 m/s²
Time taken to reach the peak (t) = ?
t = uSineθ / g
t = (28.5 × Sine 43.2) / 9.8
t = 2.0 s
Thus, the time taken to reach maximum height is 2.0 s
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Set the cannon to have an initial speed of 25 m/s. For which situation do you think the cannon ball will be in the air for the longest time: if it is set at a 25-degree angle, or if it is set at a 35-degree angle?
Question 5 options:
25 degree
35 degree
The cannon ball will travel the highest distance when the angle of projection is 35 degrees.
What is the maximum height of a projectile?The maximum height reached by a projectile is calculated using the following formula.
H = u²sin²θ/2g
where;
u is the initial velocity of the projectile θ is the angle of pojectiong is acceleration due to gravitywhen the angle of projection is 25 degrees;
H = (25² (sin 25)²) / (2 x 9.8)
H = 5.7 m
when the angle of projection is 35 degrees;
H = (25² (sin 35)²) / (2 x 9.8)
H = 10.5 m
Thus, the cannon ball will travel the highest distance when the angle of projection is 35 degrees.
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I need help with this practice I’m struggling to solve it
The blades on the turbines transform the energy coming from the wind into rotational kinetic energy.
The blades convert wind energy into rotational energy.
To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets as shown in the figure (Figure 1). Suppose that the satellite has a mass of 1300 kg and a radius of 4.8 m , and that the rockets each add a mass of 250 kg.
a) What is the steady force required of each rocket if the satellite is to reach 46 rpm in 7.0 min , starting from rest?
The steady force required of each rocket is 27,875 N.
What is the steady force required for each rocket?
The steady force required by each rocket along the circular path is calculated as follows;
F = ma
where;
m is the mass of the each rocketa is the centripetal acceleration of each rocketThe centripetal acceleration of each rocket is calculated as follows;
a = ω²r
where;
ω is the angular velocity of the rocketr is the radius of the circular pathω = 46 rpm = 46 rev/min x 2π rad/rev x 1 min/60s = 4.82 rad/s
t = 7 min = 7 x 60 s = 420 s
a = ω²r
a = (4.82²) x 4.8 m
a = 111.5 m/s²
The steady force is calculated as follows;
F = ma
F = 250 x 111.5
F = 27,875 N
Thus, the steady force required of each rocket is determined by applying the concept of centripetal force.
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on landing the plane touches a runaway with a speed of 65 m/s the figure shows the of the speed of the plane after one second. calculate the acceleration of the plane during its landing
Answer:
Correct option is B)
Given, initial velocity is u=0m/s
Final velocity is v=88.3m/s and traveled distance, d=1365m
Let a be the acceleration of the plane.
Using v
2
−u
2
=2ad
∴ (88.3)
2
−0
2
=2a(1365)
⟹ a=2.86m/s
2
Solve any question of Motion in a Straight Line with:-
Explanation:
hope it helps
To solve this we must be knowing each and every concept related to acceleration. Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
What is acceleration?Acceleration is the rate during which velocity varies over time, both in terms of speed and direction. A point or object travelling in a straight path is accelerated if something accelerates or decelerates.
Regardless of whether the speed remains constant, motion on such a circle gets accelerated because of direction is always changing. Both tangential to acceleration in all other types of motion.
initial velocity u=0m/s
Final velocity v=88.3m/s
distance, d=1365m
v²-u²=2as
substituting all the given values in the above equation, we get
88.3²-0²=2×1365×a
a=2.86m/s²
Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
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An egg test dummy is fitted with a helmet, sealed in a plastic bag, and attached to a swing with a clamp. These items have a mass of 0.090 kg. This mass is pulled back to a height of 0.55m. The mass is then released and allowed to swing down and collide with a cement block. What is the speed of the mass at the moment before impact?
The speed of the mass at the moment before impact is 3.28 m/s.
What is the final speed of the egg?
The speed of the mass at the moment before impact is calculated from the principle of conservation of energy as shown below.
K.E(bottom) = P.E(top)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
v is the speed of the egg before the impacth is the height of the fall of the eggSubstitute the given parameters and solve for the speed of the egg before the impact.
v = √2gh
v = √(2 x 9.8 x 0.55)
v = 3.28 m/s
Thus, the speed of the mass at the moment before impact is determined by applying the principle of conservation of energy.
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A car of mass 1101 kg traveling at 18.39 m/s collides and sticks to a car with a mass of 1050 kg initially at rest. What is the resulting velocity of the two cars right after the collision, assuming that there's no friction present?
Answer: the resulting velocity of the two cars right after the collision is 9.41 m/s
Explanation:
The formula for calculating momentum is expressed as
momentum = mass x velocity
According to the law of conservation of momentum, initial momentum = final momentum
The formula for initial momentum is
m1u1 + m2u2
where
m1 = mass of first car
u1 = initial velocity of first car
m2 = mass of second car
u2 = initial velocity of second car
From the information given,
m1 = 1101
u1 = 18.39
m2 = 1050
u2 = 0 because it is at rest
Initial momentum = 1101 x 18.39 + 1050 x 0 = 20247.39
Since the cars stick together after collision, they would have a common velocity, V. Thus,
final momentum = (m1 + m2)V
final momentum = (1101 + 1050)V = 2151 V
Thus,
20247.39 = 2151 V
V = 20247.39/2151
V = 9.41
the resulting velocity of the two cars right after the collision is 9.41 m/s
Jenny experiences an average downward force of 441 N anywhere she goes on Earth. Calculate her mass
Answer:
Given,
Force = 441 N
mass = ?
Keep in mind that acceleration due to gravity is constant 10m/s.
Force = mass × acceleration due to gravity
mass = Force / acceleration due to gravity
m = 411 N /10m/s
m = 41.1 kg
Therefore her Jenny mass is 41.1 kg.
A converging lens has a focal point of 3.93 cm. If you place an apple 19.24 cm away from the lens, where would the image be formed? Submit your answer in meter.
Given
The focal length , f=3.93 cm
The object distance, u=-19.24cm
To find
The image distance
Explanation
By lens formula we have,
[tex]\begin{gathered} \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ \Rightarrow\frac{1}{v}-\frac{1}{(-19.24)}=\frac{1}{3.93} \\ \Rightarrow\frac{1}{v}=0.202 \\ \Rightarrow v=4.95cm=0.0495\text{ m} \end{gathered}[/tex]Conclusion
The image distance is 0.0495 m
Two audio speakers are placed on a vertical rail. Speaker A is placed at head-level while Speaker B is place at some variable height, Δy, above Speaker A. Both speakers receive simultaneous input from a sine-wave generator so the speakers each produce a pure sinusoidal sound wave with a wavelength of 0.880 meters. Calculate the lowest height that Speaker B can be placed above Speaker A to produce a minimum of sound heard by person standing Δx=6.38 meters directly in front of Speaker A.
The lowest height at which speaker B can be placed above speaker A to produce the lowest sound to the person standing in front of A by superposition and wave interference is ∆y ≈ 2.41 m.
What is the superposition principle?The superposition principle states that the magnitude of the resulting wave when two waves overlap is the sum of the disturbance of the individual waves.
The given parameters are;
Height of speaker B above speaker A = ∆y
Wavelength of the wave = 0.880 meters
Distance between the person standing directly in front of speaker A and speaker A, ∆x = 6.38 meters
Required;
The minimum height of speaker B above speaker A that produces the minimum sound to the person in front of speaker A
Solution;
The minimum sound is given when there is destructive interference of the waves produced by the speakers
When there is destructive interference, the peak of the wave from speaker A coincides with the through of the wave from speaker B which gives;
Distance between a peak and the through of a wave = 0.5 × The wavelength
Therefore, for minimum sound, we have;
Distance from the person to speaker B = 6.38 m + 0.5 × (The wavelength)
Which gives;
Distance from the person to speaker B = 6.38 m + 0.5 × 0.88 m = 6.82 m
Pythagorean theorem is used to find the height of speaker B above speaker A as; ∆y = √(6.82² - 6.38²) ≈ 2.41
The height of speaker B above A is approximately 2.41 meters
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The lowest height that Speaker B can be placed above Speaker A to produce a minimum of sound heard by a person standing Δx=6.38 meters directly in front of Speaker A is
[tex]\Delta y=1.62m[/tex]
This is further explained below.
What is the lowest height?Generally, For a person, to hear sound minimum, sound waves from speakers A and B should meet at point P, in opposite phases, so path diff. should be
[tex]x=(2 n+1) \frac{\lambda}{2},[/tex]
[tex]\lambda[/tex]= wavelength
[tex]for $\Delta y$ to be minimum $\Rightarrow x=\frac{\lambda}{2}$ \\\\from figure, in $\triangle A B P$$$\Delta x^2+\Delta y^2=\Delta x^{\prime 2}=\text { (2) }$$[/tex]
Path diff. will be x=B P-A P
[tex]\begin{aligned}& \quad x=\Delta x^{\prime}-\Delta x \\\\&\Delta x^{\prime}-\Delta x=\frac{\lambda}{2} \quad x=\frac{\lambda}{2} \quad \text { from eq (1) } \\\\&\left.\Delta x^2+\Delta y^2-3.01=0.41 \quad \quad \quad \quad \lambda=0.820 \mathrm{~m}\right] \\\\&\Delta x^2+\Delta y^2=3.42 \\\\&\Delta y^2=(3.42)^2-(3.01)^2 \quad \Delta x=3.01 \mathrm{~m} \\\\&\Delta y=1.62 \mathrm{~m}\end{aligned}[/tex]
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When light is reflected, the incident rays are bent and change direction.
Given
When light is reflected, the incident rays are bent and change direction
To find
Whether the given statement is true
Explanation
When we flash a light on the mirror, the light changes its direction and move in another way. So the incident light changes direction when reflected
Conclusion
The given statement is TRUE
Alyse runs to her classroom which is 20 meters away. She forgets her physics book in her locker and must return 20 meters in the direction from whence she came. If her total trip takes 3 minutes, what is Alyse’s average velocity? NEED HELPP ASAPPPP!!!!!
The average velocity of Alyse is 0 m/s.
What is the average velocity of an object or a person?The average velocity of a person is the average of all the velocities of moving as it moves.
Velocity on its own is the ratio of the displacement of a body and the time taken for that displacement.
Mathematically:
Average velocity = total displacement / time takenDisplacement is a vector quantity that measures the distance traveled by a moving body in a specific direction.
Hence, average velocity and velocity are both vector quantities.
Displacement takes a measure of the shortest possible distance along a straight line from the beginning of the motion until the end of the motion.
Calculating the average velocity of Alyse:
Assuming the initial direction is positive and n=backeard direction is negative:
Total displacement = 20 m + - (20 m)
Total displacement = 0 m
total time = 3 minutes
Average velocity = 0 m/ 3
Average velocity = 0 m/s
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A 5.9 x 104-kg space probe is traveling at a speed of 14000 m/s through deep space. Retrorockets are fired along the line of motion to
reduce the probe's speed. The retrorockets generate a force of 1.4 x 104 N over a distance of 3700 km. What is the final speed of the
probe?
Answer:
there are 6 circles and 2 triangles. what is the simplelest ratio of triangles to circles
Which of the following examples is NOT an example of energy transfer?bringing water to a boilba boat being accelerated by the force of the enginecrain falling from a clouddwaves in the ocean
Rain falling from a cloud is not an example of energy transfer.
You can buy 50 rolls of toilet paper for $12.50. Write a ratio showing the unit rate of rolls per $1.
Answer:
[tex]\frac{4R}{1D}\Rightarrow\text{ 4 rolls per \$1}[/tex]Explanation: We need to find the unit rate or rate of rolls per $1:
[tex]50\text{rolls }\Rightarrow\text{ 4=\$12.50}[/tex]To find the number of rolls per one dollar we simply need to take the ratio of the two as follows:
[tex]\frac{50R}{12.50D}\Rightarrow(1)[/tex]Simplifying (1) gives the answer as follows:
[tex]\begin{gathered} \frac{50R}{12.50D}=\frac{4R}{1D} \\ \end{gathered}[/tex]The answer therefore is:
[tex]\text{4 rolls per \$1}[/tex]free fall is any motion of a body where is the only force acting upon it
A. Thermal to Chemical to Electrical to MechanicalB. Mechanical to Chemical to Electrical to Thermal C. Electrical to Chemical to Mechanical to ThermalD. Chemical to Thermal to Mechanical to Electrical
Given:
Coal-fired power plant
Required:
Energy transformation in coal-fired power plant.
Explanation:
Coal has chemical energy.
When the coal is heated, the chemical energy transforms into thermal energy.
Thermal energy is used to rotate the blade of the turbine, so thermal energy transforms into mechanical energy.
The rotating blades produce electricity, so mechanical energy transforms into electrical energy.
Final Answer: The energy transformation of a coal-fired power plant is chemical to thermal to mechanical to electrical.
What is the acceleration of a car,
moving along a straight line, that
increases its velocity from 0 to 15
m/s in 10 s?
A car goes from rest to velocity of 108 km/h north in 0.2 hours. What is the car's acceleration?
Answer:
21.6
Explanation:
bc acceleration is equal to 108 times 0.2
A 55 kg skater rolls along a U-shaped half pipe starting at rest from a height of 15 m. The skater rolls to the other side of the half pipe at a height of 12 m before stopping. What is the work done by friction?
The work done by friction is -1617 J
What is work done?Work done is the product of force and distance moved in the direction of the force.
What is friction?Friction is the opposition to motion between two surfaces
What is the work done by friction?From the lwa of conservation of energy, the work done by friction, W equals the change in potential energy of the skater, ΔU.
So, ΔU = W
mgΔh = W
mg(h₂ - h₁) = W where
m = mass of skater = 55 kg, g = acceleration due to gravity = 9.8 m/s², h₁ = initial height of skater = 15 m and h₂ = final height of skater = 12 m.So, substituting the values of the variables into the equation for the work done, we have
W = mg(h₂ - h₁)
= 55 kg × 9.8 m/s²(12 m - 15 m)
= 55 kg × 9.8 m/s² × (-3 m)
= 539 kgm/s² × (-3 m)
= -1617 J
So, the work done is -1617 J
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A train car with a mass of 14 kg and speed of 30 m/s is traveling to the right. Another train car with a mass of 26kg is moving with an unknown velocity. After the collision, the 14 kg train car is stuck to the 26 kg train car with a combined velocity of 12 m/s
From the Law of Conservation of Linear Momentum, when two particles get stuck together after a collision, it follows that:
[tex]m_1v_1+m_2v_2=(m_1+m_2)v_f[/tex]In this case, the initial velocity of the second particle is unknown. Isolate it from the equation:
[tex]v_2=\frac{(m_1+m_2)v_f-m_1v_1}{m_2}[/tex]Replace the given data to find the value of v₂:
[tex]\begin{gathered} m_1=14kg \\ v_1=30\frac{m}{s} \\ \\ m_2=26kg \\ v_2=\text{ unknown} \\ \\ v_f=12\frac{m}{s} \\ \\ \Rightarrow v_2=\frac{(14kg+26kg)(12\frac{m}{s})-(14kg)(30\frac{m}{s})}{26kg}=2.3077...\frac{m}{s} \\ \\ \therefore v_2\approx2.3\frac{m}{s} \end{gathered}[/tex]Therefore, the initial velocity of the 26-kg car is approximately 2.3m/s.
how can earthquakes be more destructive than tsunamis
Buildings can be destroyed by earthquakes or knocked down, trapping people underneath.
Only regions close to the water are susceptible to tsunamis, but anybody may be affected anywhere by earthquakes. Buildings can be destroyed by earthquakes or knocked down, trapping people underneath. Uneven surfaces and damaged roadways can result from the shifting and cracking of the Earth during earthquakes. When two chunks of the ground abruptly slide past one another, an earthquake results. The fault or fault plane is the area where they slide. Sudden movement along Earth's fault lines causes earthquakes. The motion releases "elastic strain" energy that has been accumulated in the form of seismic waves, which travel through the Earth and cause the earth to tremble.
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What is the force between two protons that are separated by 1.0 mm? The
charge of a proton is 1.6 x 10-19 C
5.3 x 10^-50 N
2.3X10^-25 N
2.3 X 10^-22 N
1.4 X 10^-3 N
The charge of a proton is 2.3 X 10^-22 N. Option C.
The force between two protons is the electrostatic repulsion. The electrostatic force is the force that develops between electric charges. This is called the strong nuclear force. It is one of the basic strengths. The amount of strong nuclear force acting between two protons is the same as the amount of strong nuclear force acting between two neutrons.
The nuclear force is the force acting between the protons and neutrons of an atom. The nuclear force is the force that binds protons and neutrons within the nucleus. This force can exist between protons and protons neutrons and protons or neutrons and neutrons. This force holds the core together. nuclear power. Nuclear forces act between all particles in the nucleus between two neutrons between two protons and between neutrons and protons.
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Which of the Figures correctly represents the force diagram to solve the problem?
ANSWER
Figure 1
EXPLANATION
We want to identify the correct force diagram acting on the object on the inclined plane.
When an object is moving on an inclined plane, there are four forces acting on it:
1. Friction force, Fr
2. Normal force, FN
3. Component of weight acting parallel to the inclined plane = Wsinθ
4. Component of weight acting perpendicular to the inclined plane = Wcosθ
Therefore, the correct option is Figure 1.
A flowerpot falls from a window sill 34.6 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? Choose upwards to be
the positive y direction. The acceleration of
gravity is 9.81 m/s²
The velocityof the flowerpot when it strikes the ground is 26.04.
What is velocity.
velocity is the prime indicator of the position as well as the rapidity of an object. It can be defined as distances covered by an object in unit of the time. velocity can defined as the displacement of the object in unit of the time .
Sol- As we know when the object is simply falls it's initial velocity is 0.
Therefore u=0
Given question is flowerpot traveled 34.6 before striking the ground.
Therefore s=34.6
We have to find v?
v^2= u^2+2gs
v^2= 0+2gs
v=√2gs
v=√2×9.81×34.6
v=26.04
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A marble is rolled down a ramp. The ramp has a slope of 0.2 for the first meter and then 0.1 for the second meter. Describe how the acceleration and velocity of the marble will be different when it has traveled 1.5 meters as compared to when it has traveled 0.5 meters
The velocity and acceleration of the marble will be greater when it travels 1.5 m compared to 0.5 m.
What is velocity?
The velocity of an object is the rate of change of displacement with time.
The velocity of the marble after it has travelled the given distance is calculated as follows;
v² = u² + 2as
where;
v is the final velocity of the marbleu is the initial velocity of the marbles is the distance travelled by the marblea is the acceleration of the marbleAssuming the marble started from rest, without initial velocity, our final equation becomes.
v² = 0² + 2as
v² = 2as
v = √2as
From the final equation, the velocity of the marble increases with increase in the distance travelled by the marble.
Also, since acceleration is defined as the rate of change of velocity with time. As the velocity increases, the acceleration of the marble increases as well.
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Which statement below best describes how scientists explain gravity's role in the formation of
our Solar System? and Why?
A. The combined gravitational attraction between our planets was so large that it pulled the
Sun away from a nearby star cluster into the center of our Solar System.
B.The eight planets in our Solar System were originally orbiting a nearby star, and the Sun's
gravity was large enough to pull those planets into orbit around the Sun.
C. Due to the expansion of neighboring solar systems, the gravitational attraction of our
planets to those solar systems forced the formation of the planets around our Sun.
D.As the Sun was forming, the force of gravity caused surrounding dust grains to collide and
stick together, forming dust granules into increasingly larger bodies that became planets.
D. As the Sun was forming, the force of gravity caused surrounding dust grains to collide and stick together, forming dust granules into increasingly larger bodies that became planets.
About 4.6 billion years ago, the Solar System was a cloud of dust and gas known as the Solar Nebula.
The gravitational forces of the planets push gases out of their atmospheres and form a star at the center of the solar system.Gravity compresses the gases in the center of the solar nebula until temperatures are high enough for nuclear fusion to occur.It collapsed the material in on itself as it began to rotate, forming the sun at the center of the nebula.As the sun rose, the remaining material began to clump together.Gravity is the force that pulls a body toward the center of the Earth or any other physical body that has mass.
Therefore "As the Sun was forming, the force of gravity caused surrounding dust grains to collide and stick together, forming dust granules into increasingly larger bodies that became planets", best describes scientists explain gravity's role in the formation of our Solar System.
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Misrepresentations of physical stimuli are known as
Misrepresentations of physical stimuli are known as Absolute Threshold
What is stimulus?
A stimulus is a measurable change in the physical or chemical structure of an organism's internal or external environment in physiology. Sensitivity refers to an organism's or organ's ability to perceive external stimuli and respond appropriately (excitability). Sensory receptors can receive information from both inside and outside the body, such as touch receptors in the skin or light receptors in the eye, as well as chemoreceptors and mechanoreceptors. When a sensory receptor detects a stimulus, it can generate a reflex via stimulus transduction. A homeostatic control system's first component is frequently an internal stimulus. External stimuli, such as the fight-or-flight response, are capable of eliciting systemic responses throughout the body.
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What is the resistance (in Ω) of a 17.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter?
In order to calculate the resistance of this wire, we can use the formula below:
[tex]R=\frac{\rho d}{A}[/tex]Where p is the resistivity, d is the length and A is the cross-sectional area of the wire.
The resistivity of the copper is 1.72 * 10^-8 ohms*m, so we have:
[tex]\begin{gathered} R=\frac{1.72\cdot10^{-8}\cdot17.5}{\frac{\pi\cdot(1.15\cdot10^{-3})^2}{4}}\\ \\ R=\frac{30.1\cdot10^{-8}\cdot4}{\pi\cdot1.3225\cdot10^{-6}}\\ \\ R=\frac{120.4\cdot10^{-8}}{4.1547563\cdot10^{-6}}\\ \\ R=28.98\cdot10^{-2}\text{ ohms}\\ \\ R=0.2898\text{ ohms} \end{gathered}[/tex]How does a ramp make it easier to move a heavy object a certain distance?A by decreasing the distance the object movesB by decreasing the amount of work required to move the objectC by changing the direction in which the object movesDby decreasing the amount of force required to move the object
When lifting an object we are required to produce a force that is greater or equal than the weight of the object in order to be lifted:
When we use a ramp we have the following distribution of forces:
In the ramp, the force decomposes into two components. A component that is parallel to the ramp and a component that is perpendicular to the ramp. Now the force must be greater or equal to the parallel component of the ramp therefore, the amount of force required must be less. Therefore, the ramp makes it easier by decreasing the amount of force required to move the object.
By Decreasing the amount of force required to move an objectExplanation:
Objects, especially simple machines, make work easier. They do not decrease the amount of work done, but actually decrease the amount of force applied. The less force applied, the easier it is to do work. Simple machines and other objects that help make work easier decrease the amount of force required to move an object.
So the answer is-
A ramp makes work easier by decreasing the amount of force required to move an object
what is the acceleration of a car, moving along a straight line, that increases its velocity from 0 to 15 m/s in 10s?
Acceleration = Change in Velocity / Time Interval
So,
A=15/10
A=1.5m/s.
Acceleration is defined as the rate of change of velocity over time. Acceleration is a vector quantity because it has both magnitude and direction. It is also the second derivative of position with respect to time or the first derivative of velocity with respect to time. Acceleration is the name we give to the process of changing velocity. Because speed is speed and direction.
There are only two ways to accelerate. Either change speed change direction or change both. Acceleration is the rate of change of velocity. At any point in the orbit, the magnitude of the acceleration is given by the rate of change of magnitude and direction of velocity at that point. Velocity is the primary measure of object position and velocity. It can be defined as the distance traveled by an object in a unit of time.
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