A group of students performed a compression experiment where they placed weights on top of a cylinder of material and measured the change in the cylinder’s height. The cylinder had a radius of 2 cm, and an initial height of 10 cm. This group of students would like to know what kind of material their cylinder was. Based on their data shown below, and the Young’s modulus values shown, which of the materials below could the cylinder be made from? Select all that apply.
Answers
Based on the calculated Young’s modulus of the material, the material the cylinder could most likely be made of is butyl rubber which has a Young’s modulus of 0.001 to 0.002 GPa.
What is Young’s modulus?Young's modulus, Y is a measure of a solid's ability to resist deformation in its length under stress or strain.
Mathematically,
Young’s modulus Y = stress/strainwhere:
stress = Force/areastrain = extension/original lengthY = Fl/Ae
Area of the cylinder = πr^2where;
π = 3.14
r = 2 cm = 0.02
Area of the cylinder = 3.14 × 0.02^2 = 0.00125 m^2
When a mass 5 kg was placed on the cylinder:
F = 5 × 10 = 50 N
l = 10 cm = 0.1 m
e = 10 - 7.73 = 0.39 cm = 0.0039 m
A = 0.00125 m^2
Using Y = Fl/Ae
Y = (50 × 0.1)/(0.00125 × 0.0039)
Y = 1025641.026 N/m^2
1 N/m^2 = 1 × 10^-9 GPa
Y = 0.001025 Gpa
When a mass 50 kg was placed on the cylinder:
F = 50 × 10 = 500 N
l = 10 cm = 0.1 m
e = 10 - 7.73 = 2.27 cm = 0.0227 m
A = 0.00125 m^2
Using Y = Fl/Ae
Y = (500 × 0.1)/(0.00125 × 0.0227)
Y = 1762114.537 N/m^2
1 N/m^2 = 1 × 10^-9 GPa
Y = 0.00176 Gpa
The Young’s modulus of the material is between 0.001025 Gpa and 0.00176 Gpa.
Therefore, the material the cylinder could most likely be made of is butyl rubber which has a Young’s modulus of 0.001 to 0.002 GPa.
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The material that the cylinder is made from is Butyl Rubber.
What is Young's modulus?
Young's modulus, or the modulus of elasticity in tension or compression, is a mechanical property that measures the tensile or compressive strength of a solid material when a force is applied to it.
Area of the cylinderA = πr²
[tex]A = \pi \times (0.02)^2 = 0.00126 \ m^2[/tex]
Young's modulus of the cylinder[tex]E = \frac{stress}{strain} \\\\E = \frac{F/A}{e/l} \\\\E = \frac{Fl}{Ae} \\\\[/tex]
Where;
e is extensionWhen 5 kg mass is applied, the extension = 10 cm - 9.61 cm = 0.39 cm = 0.0039 m.
[tex]E = \frac{(5\times 9.8) \times 0.1}{0.00126 \times 0.0039} \\\\E = 9.97 \times 10^5 \ N/m^2\\\\E = 0.000997 \times 10^9 \ N/m^2\\\\E = 0.000997 \ GPa\\\\E \approx 0.001 \ GPa[/tex]
When the mass is 50 kg,
extension = 10 cm - 7.73 cm = 2.27 cm = 0.0227 m
[tex]E = \frac{(50\times 9.8) \times 0.1}{0.00126 \times 0.0227} \\\\E = 1.7 \times 10^6 \ N/m^2\\\\E = 0.0017 \times 10^9 \ N/m^2\\\\E = 0.0017 \ GPa\\\\E \approx 0.002 \ GPa[/tex]
The Young's modulus is between 0.001 GPa to 0.002 GPa
Thus, the material that the cylinder is made from is Butyl Rubber.
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Related Questions
Water has 10 times the specific heat capacity compared to iron. How much water would be needed to absorb the same amount of heat as a piece of iron?
100 times the mass of iron
10 times the mass of iron
1/100th the mass of iron
1/10th the mass of iron
Answers
Answer: Water has 10 times the specific heat capacity compared to iron. How much water would be needed to absorb the same amount of heat as a piece of iron?
Explanation:
The answer is: 1/10th the mass of iron.
So sorry about that other clown above me, that point farming clown needs to gtfo off the internet.
Two point charges of 9μC and 4μC are placed a distance of 4 m apart.
1) Calculate the magnitude of the force, in Newtons, on a positive 5μC charge at the midpoint between the two charges.
2) Find the point, measured in meters from the 9μC charge, between the two charges where the force on the 5μC charge is 0?
Answers
Hi there!
1)
Since the charge placed in the middle is positive, we know that the particle is being repelled.
The particle experiences a greater repelling force by the 9μC charge. We can use the equation for electric force:
[tex]F_E = \frac{kq_1q_2}{r^2}[/tex]
k = Coulomb's Constant
q₁, q₂: Charges (C)
r = distance between charges (m)
This is a VECTOR quantity, so we must subtract the forces since they point in opposite directions.
Force from 9μC particle:
[tex]F_E = \frac{k(.000005)(.000009)}{2^2} = .101\\\\[/tex]
Force from 4μC particle:
[tex]F_E = \frac{k(0.000005)(0.000004)}{2^2} = 0.0450[/tex]
Subtract:
[tex].101 - 0.0450 = \boxed{0.561 N}[/tex]
2)
We can find a position by setting the two equations equal to one another. (Both repelling forces must be EQUAL for the force = 0 N)
Let the distance between the 9μC and 5μC charge equal 'x', and the distance between the 4μC and 5μC charge equal '4 - x'.
[tex]\frac{k(0.000009)(0.000005)}{x^2} = \frac{k(0.000004)(0.000005)}{(4 - x)^2}[/tex]
Cancel out 'k' and the 5μC value.
[tex]\frac{0.000009}{x^2} = \frac{0.000004}{(4 - x)^2}[/tex]
Solve for 'x' using a graphing utility.
[tex]\boxed{x = 2.4 m}[/tex]
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Answer:
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Explanation:
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Answer:
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Answer:
the answer is D
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Answer:
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Question explained in the photo attached
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Answer:
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Explain why scientists replace an old scientific model with a new model.
Include an example from Physics in your answer.
₊˚ ଘ Answer:A scientific model is created to understand the concepts and explain the reason behind unexplained observations.
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[tex]\boxed{\huge \text{Hope this helps! :)}}[/tex]
[tex]\huge \text{Happy president's day! :)}[/tex]
-InLoveWithNature-
The model was used by scientists to predict the results of their investigations. The data frequently did not support their forecasts. This required a modification to the model.
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In a range of scientific disciplines, from chemistry and science to ecology and also the Earth sciences, scientific models are employed to explain and forecast the behavior of real things or systems.
Though modeling is an essential part of contemporary science, scientific models are, at best, approximations rather than perfect representations of the systems and things they represent. As a result, scientists are always trying to enhance and improve models.
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Answers
[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Here's the solution ~
As we know, Displacement =
[tex]\qquad \sf \dashrightarrow \: velocity \times time[/tex]
[tex]\qquad \sf \dashrightarrow \: 6.8 \times 250[/tex]
[tex]\qquad \sf \dashrightarrow \: 1700 \: m[/tex]
OR[tex]\qquad \sf \dashrightarrow \: 1.7 \: km[/tex]
The car travelled 1700 meters ( 1.7 km )
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Answers
Answer:
The same
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Answer:
Centre is the Answer hope its is right and helpfull
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Answer:
Dying
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Answer:
mainline current
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Current that flows from and back to the power supply in a parallel circuit. Fuse. A type of circuit protection device.
Mainline current
What is Kirchhoff law?
Kirchhoff's Current Law states that the total current entering a junction or a node equals the charge leaving the node as no charge is lost.
According to Kirchhoff Current Law for parallel circuits,
The pair of leads connecting all the branches to the voltage source terminals is the main line. All the current in the circuit must come from one side of the voltage source and return to the opposite side for a complete path. The amount of current in the main line is equal to the total of the branch currents. The total current that flows from the power supply and back.The total current in the main line is equal to the sum of the branch currents.This is known as Kirchhoff’s current law (KCL).It applies to any number of parallel branches, whether the resistances in those branches are equal or not.Therefore,
The current that flows from and back to the power supply in a parallel circuit is called Mainline current current.
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