A grocery store purchases cantaloupes from two warehouses, A and B. The
distribution of the diameters from Warehouse A is approximately normal with a
mean of 120 mm and standard deviation of 6 mm.
(a) For a cantaloupe selected at random from Warehouse A, what is the
probability that the cantaloupe will have a diameter greater than 127 mm?
A randomly selected cantaloupe from Warehouse B has the probability of 0.763
that it will have a diameter greater than 127 mm. The grocery store purchases
40% of their cantaloupes from Warehouse B.
(b) For a cantaloupe selected at random from the grocery store, what is the
probability that the cantaloupe will have a diameter greater than 127 mm?
(c) If the randomly selected cantaloupe's diameter is greater than 127 mm, what
is the probability the cantaloupe came from Warehouse B?

Answers

Answer 1
A grocery store purchases cantaloupes from two warehouses, A and B. The
distribution of the diameters from Warehouse A is approximately normal with a
mean of 120 mm and standard deviation of 6 mm.
(a) For a cantaloupe selected at random from Warehouse A, what is the
probability that the cantaloupe will have a diameter greater than 127 mm?
A randomly selected cantaloupe from Warehouse B has the probability of 0.763
that it will have a diameter greater than 127 mm. The grocery store purchases
40% of their cantaloupes from Warehouse B.
(b) For a cantaloupe selected at random from the grocery store, what is the
probability that the cantaloupe will have a diameter greater than 127 mm?
(c) If the randomly selected cantaloupe's diameter is greater than 127 mm, what
is the probability the cantaloupe came from Warehouse B?
Answer 2

A: The probability of cantaloupe having dia. more than 127 is 0.12167.

B: Cantaloupe selected at random from the warehouse, then the probability that has a diameter of more than 127 mm is 0.3782.

C: The probability that the cantaloupe will be from warehouse B given randomly selected cantaloupe's diameter is greater than 127 mm, is 0.8069.

What is probability?

The probability formula is defined as the possibility of an event happening being equal to the ratio of the number of favorable outcomes and the total number of outcomes. Probability is a measure of the likelihood of an event occurring.  Also, the favorable number of outcomes cannot be negative.

Given two warehouses, A and B

mean for warehouse A = μ = 120 mm

The standard deviation for warehouse A = σ = 6mm

A:  a cantaloupe selected at random from Warehouse A

to find the probability of cantaloupe having a diameter greater than      127 mm = P(x > 127)

P(x > 127) = 1 - P(x ≤ 127)

P(x ≤ 127) = P((x - μ)/σ)

P(x ≤ 127) = P((127 - 120)/6)

P(x ≤ 127) = P(z ≤ 1.66)

P(x ≤ 127) = 0.87833

P(x > 127) = 1 - P(x ≤ 127)

P(x > 127) = 1 - P(x < 127) = 0.12167

probability of cantaloupe having dia. more than 127 is 0.12167.

B: Let event A for distributor A and  let event B for distributor B

and event C for a diameter greater than 127 mm.

and given A randomly selected cantaloupe from Warehouse B has a probability of 0.763 that it will have a diameter greater than 127 mm,

and the percentage of cantaloupe provided by B is 40%

rest 60% for A,

therefore, for cantaloupe selected at random, the probability of having a diameter greater than 127 mm is

P(C) = P(C|A)P(A) + P(C|B)P(B)

=  0.12167(0.6) + 0.763(0.4)

= 0.073 + 0.3052

P(C) = 0.3782

cantaloupe selected at random from the warehouse, then the probability that has a diameter of more than 127 mm is 0.3782.

C:   the probability the cantaloupe came from Warehouse B, given that the randomly selected cantaloupe's diameter is greater than 127 mm,

P(B|C) = P(B ∩ C)/P(C)

P(B|C) = (P(C|B)P(B))/P(C)

substitute values

P(B|C) = ((0.763)(0.4))/0.3782

P(B|C) = 0.3052/0.3782

P(B|C) = 0.8069

The probability that the cantaloupe will be from warehouse B given randomly selected cantaloupe's diameter is greater than 127 mm, is 0.8069.

Hence the probabilities are,

A;  0.12167

B; 0.3782

C; 0.8069.

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Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Step-by-step explanation:

Step 1: Define

(4x + 2)(x - 5) / 2

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Answers

Answer:

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so

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or  

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[tex]x = -2[/tex]

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Answer:

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Answer:

Step-by-step explanation:

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Answer:

the last one I think

Step-by-step explanation:

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Write an equation in slope-intercept form for the line that passes through (6,- 3) and is parallel to y = -2x + 4.

__________________________________________________________

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__________________________________________________________

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[tex]y=2x-9[/tex]

The answer to your question is [tex]\bf \displaystyle y=2x-9[/tex].

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Step-by-step explanation:

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