A go-cart is traveling at 15 mi/hr. How long does it take the go-cart to travel 3 miles?

Answers

Answer 1

Answer:

12 min

Explanation:every 4 minutes is 1 mile


Related Questions

a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel during 30 seconds of rotation?​

Answers

Answer:

Wait lang po sandali po wait lang

A car driver spends 3hrs driving at an average speed of 80km/hr, stops for 30 minutes to
have some rest, and then drives at an average speed of 90km/hr for 2 hours.
Calculate the average speed during the whole journey​

Answers

Answer:

The average speed throughout the journey was 76.36 kilometers per hour.

Explanation:

Given that a car driver spends 3hrs driving at an average speed of 80km / hr, stops for 30 minutes to have some rest, and then drives at an average speed of 90km / hr for 2 hours, to determine the average speed during the whole journey the following calculation must be performed:

80 km / h x 3 = 240 km

90 km / h x 2 = 180 km

240 + 180 = 420 km

3 + 2 + 0.5 = 5.5 hours

420 / 5.5 = 76.36

Thus, the average speed throughout the journey was 76.36 kilometers per hour.

What fuel does a main-sequence star use for nuclear fusion?
oxygen (0)
petroleum
helium (He)
hydrogen (H)

Answers

Answer:

A main sequence star is powered by fusion of hydrogen into helium in its core

Explanation:

An 80.0-kg skydiver jumps out of a balloon at an altitude of 1,000 m and opens his parachute at an altitude of 200 m. A. Assuming the total friction (resistive) force on the skydiver is constant at 50.0 N with the parachute closed and constant at 3,600 N with the parachute open, find the speed of the skydiver when he lands on the ground. B. At what height should the parachute be opened so that the final speed of the skydiver when he hits the ground is 5.00 m/s

Answers

Answer:

[tex]24.9\ \text{m/s}[/tex]

[tex]206.7\ \text{m}[/tex]

Explanation:

m = Mass of skydiver = 80 kg

[tex]x_1[/tex] = Height for which the parachute is closed = 1000-200 = 800 m

[tex]x_2[/tex] = Height for which the parachute is open = 200 m

[tex]f_1[/tex] = Resistive force when parachute is closed = 50 N

[tex]f_2[/tex] = Resistive force when parachute is open = 3600 N

v = Velocity of skydiver on the ground

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

h = Height from which the skydiver jumps = 1000 m

The energy balance of the system will be

[tex]mgh-f_1x_1-f_2x_2=\dfrac{1}{2}mv^2\\\Rightarrow 80\times 9.81\times 1000-50\times 800-3600\times 200=\dfrac{1}{2}\times 80\times v^2\\\Rightarrow v=\sqrt{\dfrac{2(80\times 9.81\times 1000-50\times 800-3600\times 200)}{80}}\\\Rightarrow v=24.9\ \text{m/s}[/tex]

The velocity fo the skydiver when he lands will be [tex]24.9\ \text{m/s}[/tex]

x = Height where the person opens the parachute

v = 5 m/s

[tex]mgh-f_1x_1-f_2x_2=\dfrac{1}{2}mv^2\\\Rightarrow 80\times 9.81\times 1000-50\times (1000-x)-3600\times x=\dfrac{1}{2}\times 80\times 5^2\\\Rightarrow 80\times 9.81\times 1000-50000+50x-3600x=\dfrac{1}{2}\times 80\times 5^2\\\Rightarrow x=\dfrac{80\times 9.81\times 1000-50000-\dfrac{1}{2}\times 80\times 5^2}{3550}\\\Rightarrow x=206.7\ \text{m}[/tex]

The height at which the parachute is to be opened is [tex]206.7\ \text{m}[/tex]

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:__________.

Answers

Complete question is;

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:

garage door openers: 40.0 MHz

standard cordless phones: 40.0 to 50.0 MHz

baby monitors: 49.0 MHz

FM radio stations: 88.0 to 108 MHz

cell phones: 800 to 900 MHz

Global Positioning System: 1227 to 1575 MHz

microwave ovens: 2450 MHz

wireless internet technology: 2.4 to 2.6 GHz

Which of the following statements correctly describe the various applications listed above? Check all that apply.

a.) All these technologies use radio waves, including low-frequency microwaves.

b.) All these technologies use radio waves, including high-frequency microwaves.

c.) All these technologies use a combination of infrared waves and high-frequency microwaves.

d.) Microwave ovens emit in the same frequency band as some wireless Internet devices.

e.) The radiation emitted by wireless Internet devices has the shortest wavelength of all the technologies listed above.

f.) All these technologies emit waves with a wavelength in the range of 0.10 to 10.0 m.

g.) All the technologies emit waves with a wavelength in the range of 0.01 to 10.0 km.

Answer:

B, D, E, F are the correct statements.

Explanation:

Looking at the options;

A) This is true because radio waves are electromagnetic radiation being used today in television, mobile phones, radios and other areas of communication technologies. And the examples given to us fall in the category of technologies that use radio waves.

B) microwaves usually have long wavelengths and low frequencies. However, sometimes they could have high frequencies usually more than radio waves. Thus, this option is correct.

C) This option is wrong because it's not all the listed technologies that use combination of infrared waves and high-frequency microwaves.

D) we are given the frequency of microwave ovens as 2450 MHz.

Converting to GHz gives; 2.45 GHz.

We are told that wireless internet technology has frequency between 2.4 to 2.6 GHz. Thus, microwave frequency falls in the same range as wireless internet technology and thus the statement is true.

E) we know that wavelength is inversely proportional to frequency. This means that the higher the frequency, the shorter the wavelength.

In the frequencies given to us, wireless internet technology have the highest frequency which means they have the shortest wavelength. The statement is true.

F) from the frequencies given to us, the smallest is garage door openers = 40.0 MHz = 40 × 10^(6) Hz while the biggest is 2.6 GHz = 2.6 × 10^(9) Hz

Formula for wavelength is;

Wavelength = speed of light/frequency

Speed of light = 3 × 10^(8) m/s

Thus;

Wavelength = (3 × 10^(8))/(40 × 10^(6))

Or wavelength = (3 × 10^(8))/(2.6 × 10^(9))

So,wavelength = 7.5 m or 0.12 m

This falls into the given range of 0.10 to 10.0 m.

Thus, the statement is true.

Question 10 (10 points)
Listen
In an ionic solution, 5.0x1015 negative ions with charge -e pass to the right each
second while 8.0x1015 positive ions with charge +2e pass to the left. What are the
magnitude and direction (+ or -) of current in the solution? (to the right is the +
direction, to the left is the - direction)
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
x10
Answer
units

Answers

Answer:

Please I do not understand the instructions given at the end of the question

A vertical straight conductor X of length 0.5m is held along the positive X-axis and situated in a uniform horizontal magnetic field of 0.1T which is pointing towards the positive Y-axis. (i) Calculate the magnitude and direction of force on X, when a current of 4A is passed through it. (ii) Through what angle must X be turned in a vertical plane so that the force on X is halved

Answers

Answer:

i. 0.2 N ii. 30°

Explanation:

(i) Calculate the magnitude and direction of force on X, when a current of 4A is passed through it.

The magnetic force F = BILsinФ where B = magnetic field strength = 0.1 T, I = current = 4 A and L= length of conductor = 0.5 m. Since the conductor X of length 0.5m is held along the positive X-axis and situated in a uniform horizontal magnetic field of 0.1T which is pointing towards the positive Y-axis, both B and L are perpendicular to each other. So, Ф = 90°

So, F = BILsinФ

F = 0.1 T × 4 A ×0.5 m × sin90°

F = 0.1 T × 4 A ×0.5 m × 1

F = 0.2 N

(ii) Through what angle must X be turned in a vertical plane so that the force on X is halved

If F' = BILsinФ' where Ф'=the new angle, and BIL = F

F'/F = sinФ'

Since F'/F = 1/2

sinФ' = 1/2

Ф' = sin⁻¹(1/2) = 30°

Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believed to be a very large number of planets that can be found this way, actually finding one takes time and luck; and finding one planet does not help at all with finding planets of other stars in the same part of the sky. Audrey is good at it, and finds one planet at a time, on average once every three months. a.) Find the expected value and

Answers

Answer:

- the expected value is 8

- the standard deviation is 2.8284

Explanation:

Given the data in the question;

The model N(t), the number of planets found up to time t, as a poisson process,

∴ N(t) has distribution of poisson distribution with parameter (λt)

so

the mean is;

λ = 1 every month = 1/3 per month

E[N(t)] = λt

E[N(t)] = (1/3)(24)

E[N(t)] = 8

Therefore, the expected value is 8

For poisson process, Variance and mean are the same,

Var[N(t)] = Var[N(24)]

Var[N(t)] = E[N(24)]

Var[N(t)] = 8

so the standard deviation will be;

σ[N(24)] = √(Var[N(t)] )

σ[N(24)] = √(8 )

σ[N(24)] = 2.8284

Therefore, the standard deviation is 2.8284

You are at a train yard observing trains (because why not). You see a train car (let's call it car 1) moving to the right ( x direction) towards a stationary train car (let's call this one car 2). Car 1 has an initial velocity of 15.0 m/s. A helpful train employee tells you that Car 1 also has a mass of 1,825 kg and Car 2 has a mass of 2,645 kg. Car 1 gently collides with Car 2, allowing them to connect. After the collision the two train cars stay connected. You can assume that there is no friction in the system. If you have never see train cars connect, you can watch the first 25ish seconds of this video to see two train cars couple. However, these cars have friction, so they stop - unlike our problem. What is the Final Velocity of the system consisting of Car 1 and Car 2

Answers

Answer:

6.12 m/s

Explanation:

Using the law of conservation of momentum

momentum before collision = momentum after collision

m₁v₁ + m₂v₂ = (m₁ + m₂)V    (since the train cars become attached to each other) where m₁ = mass of car 1 = 1,825 kg, m₂ = mass of car 2 = 2,645 kg, v₁ = initial velocity of car 1 = + 15.0 m/s (positive since it is moving in the positive x direction), v₂ = initial velocity of car 2 = 0 m/s (since it is initially stationary) and V = velocity of both cars after collision,

So, m₁v₁ + m₂v₂ = (m₁ + m₂)V  

m₁v₁ + m₂(0 m/s) = (m₁ + m₂)V  

m₁v₁ + 0 = (m₁ + m₂)V  

V = m₁v₁/(m₁ + m₂)

substituting the values of the other variables into the equation, we have

V = 1,825 kg × 15.0 m/s/(1,825 kg + 2,645 kg)

V = 27375 kgm/s/ 4470kg

V = 6.124 m/s

V ≅ 6.12 m/s

The spaceship Enterprise 1 is moving directly away from earth at a velocity that an earth-based observer measures to be 0.62c. A sister ship, Enterprise 2, is ahead of Enterprise 1 and is also moving directly away from earth along the same line. The veolcity of Enterprise 2 relative to Enterprise 1 is 0.30c. What is the velocity of Enterprise 2

Answers

Answer:

The answer is "0.92 c"

Explanation:

[tex]v_1\ (earth) = 0.62 \ c \\\\v_2\ ( enterprise ) = -0.30[/tex]

so,

[tex]v_2 \ (earth) = 0.62 \ c - (-0.30 \ c) \\\\[/tex]

               [tex]= 0.62 \ c +0.30 \ c\\\\= 0.92 \ c[/tex]

Can someone tell me How many wavelength is in the picture

Answers

I am pretty sure that the answer is 3

Rasheeda made a model of a plant cell and labeled parts of the cell that are not found in animal cells. Which other part of the cell should Rasheeda label?
A) cytoplasm
B) large central vacuole
C) lysosomes
D) mitochondria

Answers

Answer:

Cytoplasm

Explanation:

We have seen that the voltage of a concentration cell can be affected by the concentrations of aqueous components and/or temperature. The identity of the redox pair also affects the observed voltage of a concentration cell in a somewhat subtle way. Carefully consider the Nernst equation. Rank the redox pairs below from greatest (1) to smallest (3) voltage in a concentration cell, assuming equal values of T and Q for all cells. Assume multimeter leads are connected to that measured voltages are positive.

a. Copper metal/copper(l) ion
b. Aluminum/aluminum ion
c. Magnesium metal/magnesium ion

Answers

Answer:

1) Magnesium metal/magnesium ion

2) Aluminum/aluminum ion

3)  Copper metal/copper(l) ion

Explanation:

The activity series is a series that shows the ease of reactivity of substances in an electrochemical cell.

The substances that are higher up in the series are more reactive in electrochemical cells.

Magnesium is the first element in the series that has the most negative redox potential  then followed aluminium.

Hence, according to Nernst,

1) Magnesium metal/magnesium ion

2) Aluminum/aluminum ion

3)  Copper metal/copper(l) ion

a 4.5 Hz wave has a wavelength of 0.8m. what is the speed
0.18 m/s
5.6m/s
5.3m/s
3.6m/s ​

Answers

Answer:

   

Explanation

Hi, here it is!
I hope this help.

Step-by-step explanation

λ= 0,8m
f(frequency)= 4,5Hz

v = f × λ
v = 4,5 × 0,8
v = 3,6m/s

What is the unit of measurement of mass and weight? ​

Answers

the unit of measurement for mass & weight is kilograms (kg)

Answer:

kilogram

In the International System of Units (SI), the kilogram is the basic unit of mass, and the newton is the basic unit of force. The non-SI kilogram-force is also a unit of force typically used in the measure of weight.

Will give brainliest!

Describe how heat is moving in the image and label each as Radiation, Conduction, or Convection.

Radiation / Conduction / Convection ​

Answers

Answer:

well in the pot there is conventional heat, the pot itself is giving off conductable heat, and the radiational heat is coming from the stove.

Which one the answer to this question

Answers

The second bubble is the answer:)

volcano has both useful and harmful effects give reason​

Answers

Answer:

harmful effects

1. that will cause air pollution

2. that will destroy our earth

Answer:

useful effects of volcano are :-

it makes soil fertile it provides valuable nutrients for the soil

harmful effects of volcano are:-

it makes air polluted it destroy the environment .

hope it is helpful to you ☺️

a 7 kg object moving 10 m/s Right collides with a 14 kg object at rest. If after the collision the 7kg object is at rest and the 14 kg object is moving, what is the velocity of the 14 kg object after the collision?

Answers

Answer:

v2(final)=5 m/s

Explanation:

we are going to use the conservation of momentum here

m1*v1(initial)+m2*v2(initial)=m1*v1(final)+m2v2(final)

m1=7 kg  v1(initial)=10 m/s

m2=14 kg  v2(initial)=0 m/s (bc initially it is at rest)

v1(final)= 0 m/s (m1 stops moving after the collision)

v2(final)=?

7*10+14*0=7*0+14*v2(final)

70=14v2(final)

v2(final)=70/14 m/s=5 m/s

g A thin-walled hollow cylinder and a solid cylinder, both have same mass 2.0 kg and radius 20 cm, start rolling down from rest at the top of an incline plane. The height of top of the incline plane is 1.2 m. Find translational speed of each cylinder upon reaching the bottom and determine which cylinder has the greatest translational speed upon reaching the bottom. Moment of inertia of hollow cylinder about its axis passing through the center is mr2 and for solid cylinder mr2/2

Answers

Answer:

a. i. 3.43 m/s ii. 2.8 m/s

b. The thin-walled cylinder

Explanation:

a. Find translational speed of each cylinder upon reaching the bottom

The potential energy change of each mass = total kinetic energy gain = translational kinetic energy + rotational kinetic energy

So, mgh = 1/2mv² + 1/2Iω² where m = mass of object = 2.0 kg, g =acceleration due to gravity = 9.8 m/s², h = height of incline = 1.2 m, v = translational velocity of object, I = moment of inertia of object and ω = angular speed = v/r where r = radius of object.

i. translational speed of thin-walled cylinder upon reaching the bottom

So, For the thin-walled cylinder, I = mr², we find its translational velocity, v

So, mgh = 1/2mv² + 1/2Iω²

mgh = 1/2mv² + 1/2(mr²)(v/r)²  

mgh = 1/2mv² + 1/2mv²

mgh = mv²

v² = gh

v = √gh

v = √(9.8 m/s² × 1.2 m)

v = √(11.76 m²/s²)

v = 3.43 m/s

ii. translational speed of solid cylinder upon reaching the bottom

So, For the solid cylinder, I = mr²/2, we find its translational velocity, v'

So, mgh = 1/2mv'² + 1/2Iω²

mgh = 1/2mv² + 1/2(mr²/2)(v'/r)²  

mgh = 1/2mv'² + mv'²

mgh = 3mv'²/2

v'² = 2gh/3

v' = √(2gh/3)

v' = √(2 × 9.8 m/s² × 1.2 m/3)

v' = √(23.52 m²/s²/3)

v' = √(7.84 m²/s²)

v' = 2.8 m/s

b. Determine which cylinder has the greatest translational speed upon reaching the bottom.

Since v = 3.43 m/s > v'= 2.8 m/s,

the thin-walled cylinder has the greatest translational speed upon reaching the bottom.

An artificial satellite circling the Earth completes each orbit in 126 minutes. (a) Find the altitude of the satellite.

Answers

Answer:

Explanation:

Time period of rotation

T = 2πR/ V where R is radius of orbit and V is orbital velocity

Orbital velocity V = √ ( GM/R ) , m is mass of the earth .

T = 2πR √R / GM

T² = 4π²R³ / GM

Putting the values

( 126 x 60 )² = 4 x 3.14² x R³ / 6.67 x 10⁻¹¹ x 5.97 x 10²⁴

57.15 x 10⁶ = 39.44 x R³ / 39.82 x 10¹³

R³ = 577 X 10¹⁸

R = 8.325 x 10⁶ m

= 8325 km

Radius of earth = 6400 km

height of satellite = 8325- 6400 = 1925 km .

Irrigation channels that require regular flow monitoring are often equipped with electromagnetic flowmeters in which the magnetic field is produced by horizontal coils embedded in the bottom of the channel. A particular coil has 100 turns and a diameter of 6.0 m. When it's time for a measurement, a 4.5 A current is turned on. The large diameter of the coil means that the field in the water flowing directly above the center of the coil is approximately equal to the field in the center of the coil. The field is directed downward and the water is flowing east. The water is flowing above the center of the coil at 1.5 m/s

Required:
a. What is the magnitude of the field at the center of the coil?
b. What is the direction of the force on a positive ion in the water above the center of the coil?

Answers

Answer:

A) B = 9.425 × 10^(-5) T

B) North direction

Explanation:

A) We are given;

Current in coil; I = 4.5 A

Number of turns; N = 100 turns

Radius;R = diameter/2 = 6/2 = 3 m

Formula for the magnetic field at the center of the coil is given by;

B = (μ_o•N•I)/2R

Where μ_o is a constant = 4π × 10^(-7) H/m

Thus;

B = (4π × 10^(-7) × 100 × 4.5)/(2 × 3)

B = 9.425 × 10^(-5) T

B) The direction of the force on a positive ion in water can be gotten by the application of flemmings right hand rule.

From flemmings right hand rule, we know that;

- The thumb indicates the direction of the motion of the force which is in the north direction.

- The Index finger indicates the direction of the magnetic field which is in the east direction

- The middle finger indicates the direction of magnetic field which is downwards in the west direction.

Therefore, the direction of the force as seen from flemmings right hand rule is in the north direction


Please help I will mark you brainliest

Answers

I believe the answer is a

The correct answer is D, that is the point of the lowest elevation on the map.

need help ASAP!!!!!!!!!!!

Answers

Answer:

The equation says that due to variation in temperature is

delt T = .59 m/s / C = 16 C * .59 m/s = 9.44 m/s

So v = 332 m/s + 9.44 m/s = 341 m/s (to three significant figures)

Question 7 of 11
>
A 1655 kg car drives down the highway. If the car has a momentum of 61250 kg. m/s, what is the velocity of the car?

Answers

Answer:

velocity = 37.01 m/s

Explanation:

momentum = mass * velocity

61250 = 1655 * x

x = 61250 / 1655

x = 37.0090634441

You put a diode in a microelectronic circuit to protect the system in case an untrained person installs the battery backward. In the correct forward-bias situation, the current is 255 mA with a potential difference of 116 mV across the diode at room temperature (300 K). If the battery were reversed, so that the potential difference across the diode is still 116 mV but with the opposite sign, what would be the magnitude of the current in the diode

Answers

Answer:

The current in the new circuit is 0

Explanation:

A diode is an electronic component that allows the electric current to go only in one direction. If in the first case the current was 255 mA, and the battery was changed ( change in polarity ) no current will flow through the circuit. That change is similar or equivalent to change the diode to the no pass position

I need help with this review question.

Answers

Answer:

The acceleration of the football is greatest

Explanation:

The more mass the more acceleration

It turns out that the depth in the ocean to which airborne electromagnetic signals can be detected grows with the wavelength. Therefore, the military got the idea of using very long wavelengths corresponding to about 30 Hz to communicate with submarines throughout the world. If we want to have an antenna that is about one-half wavelength long, how long would that be

Answers

Wavelength = speed / frequency.

Wavelength = 3x10^8 m/s / 30 hz

Wavelength = 10 million meters

1/2 wavelength = 5 million meters

(that's about 3,100 miles)

I'm pretty sure the frequency is wrong in the question.

I think it's actually 30 kHz, not 30 Hz.

That makes the antenna about 3.1 miles long.

A 20 ft ladder leans against a wall. The bottom of the ladder is 3 ft from the wall at time t=0 and slides away from the wall at a rate of 2ft/sec. Find the velocity of the top of the ladder at time t=1.

Answers

Answer: 0.516 ft/s

Explanation:

Given

Length of ladder L=20 ft

The speed at which the ladder moving away is v=2 ft/s

after 1 sec, the ladder is 5 ft away from the wall

So, the other end of the ladder is at

[tex]\Rightarrow y=\sqrt{20^2-5^2}=19.36\ ft[/tex]

Also, at any instant t

[tex]\Rightarrow l^2=x^2+y^2[/tex]

differentiate w.r.t.

[tex]\Rightarrow 0=2xv+2yv_y\\\\\Rightarrow v_y=-\dfrac{x}{y}\times v\\\\\Rightarrow v_y=-\dfrac{5}{19.36}\times 2=0.516\ ft/s[/tex]

To increase the potential energy of the system, what did you have to do?

Answers

Answer:

You can use work to add kinetic energy to a system or to increase potential energy in the system.

Explanation:

Potential energy stored in any system can be released as kinetic energy. Kinetic energy can be transformed to do work or to increase potential energy.

hope this helped

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Determine and Use Overhead RateThe following selected ledger accounts of Cameron Company are for February (the second month of its accounting year):Materials InventoryFeb. 1 balance63,000February credits226,000February debits208,000Manufacturing OverheadFebruary debits274,400Feb. 1 balance23,200February credits272,700Work in Process InventoryFeb. 1 balance44,800February credits690,000February debits:Direct material190,000Direct Labor303,000Man. overhead272,700Wages PayableFebruary debits387,000Feb. 1 balance90,000February credits354,000Finished Goods InventoryFeb. 1 balance153,000February credits767,400February debits690,000a. Determine the amount of indirect material requisitioned for production during February.$Answerb. How much indirect labor cost was apparently incurred during February?$Answerc. Calculate the manufacturing overhead rate based on direct labor cost.Answer %d. 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Aclaim made under an umbrella policy will pay only after the limits of the relevant underlying policy are exhausted. [13-14] Hamilton Company uses job-order costing. Manufacturing overhead is applied using a predetermined rate of 150% of direct labor cost. Any over- or underapplied manufacturing overhead is closed t In the nuclear transmutation represented by Pu(He,n), what is the product? A. uranium-242 B. curium-245 C. curium-242 D. uranium-245 E. uranium-243 Let the current spot rate be $1.25/, and assume that one month from now the spot rate will be either $1.30/ or $1.20/. Let the dollar interest rate be 0.4% per month, and let the euro interest rate be 0.3% per month. Develop a portfolio that replicates the payoff on a one-month euro call option that allows us to buy stocks for a strike price of $1.25/. Develop a portfolio that replicates the payoff of the option. Evaluate the series below: _ (31) Type your answer___ Evaluate the series below: $-(3; 9) Type your answer___ Evaluate the series below using summation properties (8i - 1) Type your answer___ Berea Resources is planning a $75 million capital expenditure program for the coming year. Next year, Berea expects to report to the IRS earnings of $40 million after interest and taxes. The company presently has 25 million shares of common stock issued and outstanding. Dividend payments are expected to increase from the present level of $8 million to $12 million. The company expects its current asset needs to increase from a current level of $23 million to $28 million. Current liabilities, excluding short-term bank borrowings, are expected to increase from $17 million to $21 million. Interest payments are $5 million next year, and long-term debt retirement obligations are $9 million next year. Depreciation next year is expected to be $15 million on the company's financial statements, but the company will report depreciation of $18 million for tax purposes. How much external financing is required by Berea for the coming year? A formula of order 4 for approximating the first derivative of a function gives: f(0) = 0.08248 for h = 1 f(0) = 0.91751 for h = 0.5 By using Richardson's extrapolation on the above values, a better approximation of f'(o) is: Subgame perfection is a refinement of Nash Equilibrium that requiresSelect one:a. perfect and skilled play by all playersb. credibility/rationality at every point/path in the game, regardless of whether those points/paths are actually part of the Nash equilibriumc. focalness in equilibriumd. firms do not cheat on their output agreementse. credibility/rationality only along the equilibrium path The developer for a new filter for filter-tipped cigarettes claims that it leaves less nicotine in the smoke than does the current filter. Because cigarette brands differ in a number of ways, he tests each filter on one cigarette of each of nine brands and records the difference between the nicotine content for the current filter and the new filter. The mean difference for the sample is 1.321 milligrams, and the standard deviation of the differences is s=2.35 mg.A) Carry out a significance test at the 5% level.B) Construct a 90% confidence interval for the mean amount of additional nicotine removed by the new filter. What part of the money supply does the fed have direct control over? Do students who attend more lectures get better exams results? I need a hypothesis test for the mean The number of millions of visitors that a tourist attraction gets can be modeled using the equation y = 2.3 sin[0.523(x + 1)] + 4.1, where x = 1 represents January, x = 2 representsFebruary, and so on.a) Determine the period of the function and explain its meaning.b) Which month has the most visitors?c) Which month has the least visitors?Please explain answers thank you! If you wish to accumulate $40,000 in 10 years, how much must you deposit today in an account that pays a quoted annual interest rate of 7.5% with semi-annual compounding of interest? What is the surface area of the cylinder with height 8 ft and radius 4 ft Let aj, a2, a3 , ... be a sequence defined by a1 = 1 and ak = 2a -1 . Find a formula for an and prove it is correct using induction. calculate the equilibrium constant at 25c from the free-energy change for the following reaction: substance (kj/mol) 65.52 147.0 78.87 77.12 (enter your answer to two significant figures.) x(t)= C0 + C1*cos(w*t+phi1) + C2*cos(2*w*t+phi2) x(t)= A0 + A1*cos(w*t) + B1*sin(w*t) + A2*cos(2*w*t) + B2*sin(2*w*t) C0= 6, C1=5.831, phi1=-59.036 deg, C2=8.944, phi2=-26.565 deg, w=400 rad/sec. Determine A0, A1, B1, A2, B2