A. Given the following statements Let x e N, where N = {1,2,3,4,5). = a) VX EN,x + 4 < 2. b) 3x E N. x + 2 > 5. 1. Find the truth value of a) and b). 2. What is the negation of a) and b). B. Prove the following assertions (Using either direct or indirect proof) 1. If x is even and y is odd, then x + 2y is even. 2. If x and y are odd, then (x + 3) + y is odd. +2 n(n+1)

Answer:

B) 7x - 3 = 4

Step-by-step explanation:

3x - 12 = -9

3x = 3

x = 1

A) NOPE

x - 5 = -6

x = -1

B) YES

7x - 3 = 4

7x = 7

x = 1

Answer:

no because it is not factorable

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

[tex] \frac{3}{4} \div \frac{2}{5} \\ \\ = \frac{3}{4} \times \frac{5}{2} \\ \\ = \frac{3 \times 5}{4 \times 2} \\ \\ = \frac{15}{8} [/tex]

Answer:

2.8

Step-by-step explanation:

√(4² - 2²) = √12

=> √[(√12)² - 2²] = √8 ≈ 2.8

Answer:

not really good at maths. 15.33

Step-by-step explanation:

3(x-5)-7=3×8

3x-15-7=24

3x =24+15+7

3x = 46

Three will divide it's self to give you one and divide 46 to give you 15.333

(correct me if i'm wrong)

Answer:

7

Step-by-step explanation:

Answer:

7 units north

Step-by-step explanation:

Count from 3,4 to 10,4 and there are seven units

An A is a -algebra over X and A ∪ Ag is not a -algebra over X.

In this case, let's analyze the properties of the sets in question:

X = {a, b, c}

A = {4, X, {a}, {b, c}}

Ag = {4, X, {b}, {a, c}}

To determine if An A is a -algebra over X, we need to check if it satisfies the three conditions of a -algebra:

1. X ∈ An A: In this case, X = {a, b, c} ∈ An A, since X is a subset of itself.

2. An A is closed under complementation: For any set E ∈ An A, we need to ensure that its complement, X \ E, is also in An A. Let's check the sets in A:

- {4} ∈ An A: The complement is X \ {4} = {a, b, c}, which is not in An A.

- X ∈ An A: The complement is X \ X = ∅, which is in An A.

- {a} ∈ An A: The complement is X \ {a} = {b, c}, which is in An A.

- {b, c} ∈ An A: The complement is X \ {b, c} = {a}, which is in An A.

Since not all sets in A have complements in An A, An A is not closed under complementation and therefore not a -algebra over X.

Now let's analyze A ∪ Ag to determine if it is a -algebra over X:

1. X ∈ A ∪ Ag: Since X is a subset of itself, X ∈ A ∪ Ag.

2. A ∪ Ag is closed under complementation: For any set E ∈ A ∪ Ag, we need to ensure that its complement, X \ E, is also in A ∪ Ag. Let's check the sets in A and Ag:

- {4} ∈ A ∪ Ag: The complement is X \ {4} = {a, b, c}, which is in A ∪ Ag.

- X ∈ A ∪ Ag: The complement is X \ X = ∅, which is in A ∪ Ag.

- {a} ∈ A ∪ Ag: The complement is X \ {a} = {b, c}, which is in A ∪ Ag.

- {b, c} ∈ A ∪ Ag: The complement is X \ {b, c} = {a}, which is in A ∪ Ag.

Since all sets in A and Ag have complements in A ∪ Ag, A ∪ Ag is closed under complementation and is a -algebra over X.

In conclusion, option b is the correct answer: An A is a -algebra over X, and A ∪ Ag is not a -algebra over X.

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Answer:

1st: x-120

2nd: 0

3rd: x+12

4th: 120 + x

5th: x+12

im pretty sure that's right...?

I won't get brainliest lol

Answer:

count the unit squares

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

the total angles can only add up to 180°, therefore 35 + 70 = 105, 180 - 105 = 75°. 75° = A.

Answer:

a graph showing the relationship between two sets of data

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

it is

Answer:

8

Step-by-step explanation:

1/4 of 32

1/4 = 25%

25% of 32

32 × 25 ÷ 100

= 8

or

32 ÷ 4 =8

Using Cramer's rule the solutions to the system of equations are:

X1 = 21 / (-J2 - 9)

X2 = -12 / (-J2 - 9)

Using Cramer's rule, we can solve the system of equations:

J2X1 - X2 - 3 = 0

X1 + 3X2 - 7 = 0

3X1 + 2X2 - 1 = 0

4X1 + 5X2 = 14

The values of X1 and X2, we'll calculate the determinants.

Let D be the determinant of the coefficient matrix:

D = |J2 -1 0| = J2(-1) - 3(3) = -J2 - 9

D1 is the determinant obtained by replacing the first column of the coefficient matrix with the constants:

D1 = |0 -1 0| = 0(-1) - (-7)(3) = 21

D2 is the determinant obtained by replacing the second column of the coefficient matrix with the constants:

D2 = |J2 0 0| = J2(0) - 3(4) = -12

Now, we can calculate the values of X1 and X2 using the determinants:

X1 = D1 / D = 21 / (-J2 - 9)

X2 = D2 / D = -12 / (-J2 - 9)

Therefore, the solutions to the system of equations are:

X1 = 21 / (-J2 - 9)

X2 = -12 / (-J2 - 9)

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The magnitude of the vertical force applied to the horizontal leg in the equivalent force system.

To determine the magnitude of the vertical force applied to the horizontal leg, we need to find the vertical component of the given force system. Looking at the diagram, we observe that the force system consists of a vertical force at point A and a horizontal force at point B. We can use trigonometry to find the vertical component of the force at point A.

Let's denote the magnitude of the force at point A as F_A and the angle it makes with the horizontal leg as θ. The vertical component of the force can be calculated using the formula: Vertical component = F_A * sin(θ).

Since the vertical component of the force should be equal to the force we are trying to find, we can set up the equation: Vertical component = F_vertical.

Now, we can substitute the given values into the equation and solve for F_vertical. Once we have the value, we can round it off to the nearest whole number, as instructed.

Please note that without specific values or angles provided in the problem statement or accompanying diagram, it is not possible to provide a precise numerical answer.

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Answer:

109°

Step-by-step explanation:

sum of angles of a quadrilateral=360°

45+95+111+fourth angle=360

fourth angle=360-251=109°

Answer:

<WZY = 31°

Step-by-step explanation:

First, we can see that <XZW is equal to <WZY.

Given that, we know we can set the two equations equal to each other to find "x".

8x - 1 = 5x + 11

Now that the two equations are set equal to each other, all we have to do is simplify to find x.

Bring 5x over and subtract it from 8x.

3x - 1 = 11

Bring -1 over and add it to 11.

Since you're subtracting a negative, it becomes positive allowing you to add it to 11.

3x = 12

Now you need to get x by itself. Do do that, you need to divide three by itself, and whatever you do to one side, you must do to the other.

3x/3 = 12/3

Now you have:

x = 4

____________________________________________________

Now that you know the value of x, all you need to do is plug x back into the equation for <WZY

5(4) + 11

20 + 11

31.

And there is your answer - <WZY = 31°

The terminal point is (0, -1) if in a unit circle the angle is 3π/2 option (D) is correct.

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

We have:

In a unit circle, θ = 3π/2 radians.

r = 1

Angle θ = 3π/2

The terminal point is (rcosθ, rsinθ)

= (cos3π/2, sin3π/2)

= (0, -1)

Thus, the terminal point is (0, -1) if in a unit circle the angle is 3π/2 option (D) is correct.

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Answer:

Population (t=-3)= 50,000

Step-by-step explanation:

Giving the following information:

Annual growth rate (g)= 10%

Number of periods (n)= 3 years

Present Value (PV)= 66,550 people

To calculate the population three years ago, we need to use the following formula:

Population (t=-3)= PV / (1 + g)^n

Population (t=-3)= 66,550 / (1.1^3)

Population (t=-3)= 50,000

Options:

A. 18, 20, 20, 22, 25

B. 20, 20, 20, 25, 25

C. 16, 19, 21, 22, 22

D. 20, 20, 21, 22, 22

Answer:

A. 18, 20, 20, 22, 25

Step-by-step explanation:

Required

Which list has a mean of 21 and median of 20

Each of the list have 5 numbers and they've all been sorted.

The median is the number at the 3rd position (i.e. the middle number)

So, list C and D are out because they do not have a median of 20.

Next, calculate the mean of lists A and B

[tex]\bar x = \frac{\sum x}{n}[/tex]

A. 18, 20, 20, 22, 25

[tex]\bar x = \frac{18 + 20 + 20 + 22 + 25}{5}[/tex]

[tex]\bar x = \frac{105}{5}[/tex]

[tex]\bar x = 21[/tex]

B. 20, 20, 20, 25, 25

 [tex]\bar x = \frac{20 + 20 + 20 + 25 + 25}{5}[/tex]

[tex]\bar x = \frac{110}{5}[/tex]

[tex]\bar x = 22[/tex]

Only list A has a median value of 20 and a mean value of 21

Answer : Null Hypothesis (H0) The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is equal to or greater than the national average of 4%.”

Alternative Hypothesis (Ha) The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is significantly lower than the national average of 4%.”

Explanation :

a. Null Hypothesis (H0) is a statement which suggests that there is no significant difference between two populations or samples in the study. In this scenario, the null hypothesis can be stated as follows:“The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is equal to or greater than the national average of 4%.”

b. Alternative Hypothesis (Ha) is a statement that counters the null hypothesis by suggesting that there is a significant difference between two populations or samples in the study. In this scenario, the alternative hypothesis can be stated as follows:“The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is significantly lower than the national average of 4%.”

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By the Fundamental Theorem of Calculus where F(x) = ∫f(x) then F'(x) = f(x).

We are looking for the function F whose derivative is x^(2/3) + 4x.

By the power rule, the function F (whose derivative is x^(2/3) + 4x) would have to be an x³ and an x² function since the power rule reduces the exponent by 1.

The derivative of x^3 is 3x² and the derivative of 2x² is 4x. As F'(x) = x^(2/3) + 4x.

But notice that if it was just x^3 and x^2 then the derivative of that would be 3x² and 2x while f(x) is x^(2/3) + 4x.

That means F(x) must be composed of x^(2/3+1)/(2/3+1) and 2x^1/(1+1) so the derivative turns out right.Hence, the function F(x) = 3x^(5/3)/5 + 2x^2/2 = 3x^(5/3)/5 + x^2.

The Fundamental Theorem of Calculus also states that ∫(from 0 to b) f(x)dx = F(b) - F(0).

Therefore we can say 0∫b f(x)dx = (b^(3/9) + 2b²) - (0^(3/9) + 2(0)²) which is just b^(3/9) + 2b².

Hence, the answer is b^(3/9) + 2b².

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Answer:

between 32 and 37

Step-by-step explanation:

that's my answer

Answer:

17*10^-3 miles

Step-by-step explanation:

Given data

Speed= 8.5×10^−6 miles per second

Time taken=2×10^3 seconds

We know that the expression for the speed is given as

speed= distance/time

distance= speed* time

substitute

distance= 8.5×10^−6* 2×10^3

distance= 8.5*2*(10^-6+3)

distance= 17*10^-3 miles

Answer:

-31/8. That's the answer to your question

Answer:

8

Step-by-step explanation:

The degree of a polynomial refers to the term with the highest exponent.  Thus the highest exponent in a degree 3 polynomial is x3; for a degree 5 polynomial, it's x5.  When you multiply

x3*x5 = x3+5 = x8.  

So the product of a degree 3 polynomial and a degree 5 polynomial is a degree 8 polynomial.

Your leading term will result from the 3-degree term of the first polynomial, and the 5-degree term of the second.  So you'll have something like ax3 * bx5.  That will result in x3*x5=x8, so your product will have degree 8.

The total number of choices for selecting 6 representatives without any two occupying neighboring seats is 77597520 .

(a) The number of ways to arrange 5 parents, 5 students, and 1 teacher in a circular arrangement around a table such that no student sits next to another student and no parent sits next to another parent, we can use the principle of inclusion-exclusion.

First, let's consider the arrangements without any restrictions. We have a total of 11 people to arrange around the table (5 parents + 5 students + 1 teacher), which can be done in (11 - 1)! = 10! ways.

Now, let's consider the arrangements where at least two students sit next to each other. We can treat the two adjacent students as a single entity, resulting in 10 entities to arrange around the table (4 parents + 5 student pairs + 1 teacher). This can be done in (10 - 1)! = 9! ways. However, within each student pair, the students can be arranged in 2! ways. Therefore, the total number of arrangements with at least two students sitting next to each other is 9! × 2! ways.

Similarly, we consider the arrangements where at least two parents sit next to each other. Again, we treat the two adjacent parents as a single entity, resulting in 10 entities to arrange around the table (4 parent pairs + 5 students + 1 teacher). This can be done in (10 - 1)! = 9! ways. Within each parent pair, the parents can be arranged in 2! ways. Therefore, the total number of arrangements with at least two parents sitting next to each other is 9! × 2! ways.

By the principle of inclusion-exclusion, the number of valid arrangements is given by

Valid arrangements = Total arrangements - Arrangements with at least two students sitting next to each other - Arrangements with at least two parents sitting next to each other

Valid arrangements = 10! - 9! × 2! - 9! × 2!

Valid arrangements = 2177280

(b) The number of choices for selecting 6 representatives out of 20, where no two chosen representatives occupy neighboring seats, we need to use a combination of counting techniques.

First, choose 6 seats out of the 20 seats in which the representatives will be seated. This can be done in C(20, 6) ways.

Now, since no two chosen representatives can occupy neighboring seats, we can think of the remaining 14 seats as dividers between the chosen representatives. We need to place these dividers in such a way that each chosen representative occupies a separate section.

To ensure that no two representatives occupy neighboring seats, we need to place the dividers such that each section contains at least one seat. We have 6 chosen representatives, so we need to place 5 dividers among the 14 remaining seats. This can be done in C(14, 5) ways.

Therefore, the total number of choices for selecting 6 representatives without any two occupying neighboring seats is given by:

Total choices = C(20, 6) × C(14, 5)

Total choices =  38760 × 2002

Total choices = 77597520

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