A girl throws a pebble into a deep well at 4.0 m/s (downward). It hits the water in 2.0 s. How far below the ground is the water's surface? What is the pebble's average velocity?

Answer:

11025 N / m²

Explanation:

Los siguientes datos se obtuvieron de la pregunta:

Área (A) = 400 cm²

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Presión (P) =?

A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Fuerza (F) =.?

F = m × g

F = 45 × 9,8

F = 441 N

A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:

1 cm² = 0,0001 m²

Por lo tanto,

400 cm² = 400 cm² × 0,0001 m² / 1 cm²

400 cm² = 0,04 m²

Por tanto, 400 cm² equivalen a 0,04 m².

Finalmente, determinaremos la presión ejercida de la siguiente manera:

Área (A) = 0.04 m².

Fuerza (F) = 441 N

Presión (P) =?

P = F / A

P = 441 / 0,04

P = 11025 N / m²

Por tanto, la presión ejercida es 11025 M / m²

Here is the missing information.

An exhausted bicyclist pedal somewhat erraticaly when exercising on a static bicycle. The angular velocity of the wheels takes the equation ω(t)=at − bsin(ct) for t≥ 0, where t represents time (measured in seconds), a = 0.500 rad/s2 , b = 0.250 rad/s and c = 2.00 rad/s .

Answer:

0.793 rad

Explanation:

From the given question:

The angular velocity of the wheel is expressed by the equation:

[tex]\omega (t) =\dfrac{d\theta}{dt}[/tex]

The angular velocity of the wheels takes the description of the equation ω(t)=at−bsin(ct)

SO;

[tex]\dfrac{d \theta}{dt} = at - b \ sin \ ct[/tex]

dθ = at dt - (b sin ct) dt

Taking the integral of the above equation; we have:

[tex]\int \limits^{\theta}_{0} \ d \theta = \int \limits ^{t=2}_{0} at \ dt - (b \ sin \ ct) \dt[/tex]

[tex][\theta] ^{\theta}_{0} = a \bigg [\dfrac{t^2}{2} \bigg]^2_0 - \bigg[ -\dfrac{b}{c} \ cos \ ct \bigg] ^2_0[/tex]

where;

a = 0.500 rad/s2 ,

b = 0.250 rad/s and

c = 2.00 rad/s

[tex]\theta = (0.500 \ rad/s^2 ) \bigg [\dfrac{(2s)^2}{2} \bigg] - \bigg[ -\dfrac{0.250 \ rad/s}{2.00 \ rad/s} \ cos \ (2.00 \ rad/s )( 2.00 \ s) \bigg] - \bigg [ \dfrac{0.250 \ rad/s}{2.00 \ rad/s}\bigg ] cos 0^0[/tex]

[tex]\mathbf{\theta = 0.793 \ rad}[/tex]

Hence, the angular displacement after two seconds = 0.793 rad

Answer:

If you increase the temperature, the position of equilibrium will move in such a way as to reduce the temperature again. It will do that by favouring the reaction which absorbs heat. In the equilibrium we've just looked at, that will be the back reaction because the forward reaction is exothermic.

Explanation:  

Answer:

-150 kg m/s

Explanation:

The change of momentum is calculated as ;

Δp= m*Δv where

where

Δp= change in momentum

Δv = vf-vi

m= mass of the object

Change in momentum is also calculated when using the formula;

Δp = F * Δt   when F is the net force applied and Δt is the time of action.

In this case;

m= 15 kg

vf=  -10 m/s

vi= 0 m/s

Taking rightward direction to be positive, then leftward will be negative.

Applying the formula as;

Δp = m*Δv

Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s

Answer: vf = g * t

Explanation:

G represents the acceleration of gravity.

T represents time so multiply the acceleration of gravity times time.

Answer:

What was your sleep situation like during your time in space? Did you get more or fewer hours of sleep than when you were on earth? I would be very interested in learning about their answer because they still have to perform tasks that require energy and obviously they would need to sleep but do they have to strap themselves down on a bed so they don't float away? Is it easy to fall asleep in space or would your body be confused because time is so much different that it doesn't even follow the same time zones as on earth? That is why I find this to be interesting for them to answer.

Did you have any activities to do aside from researching and your tasks that were mandatory? What would they have done in their free time? I can’t imagine simply doing work the whole time, did they get to bring along certain games or time wasters to do while in space? I would just be really curious to find out how they occupied their free time or if they even had free time.

What was the most difficult part about being in space? Was it terrifying or was the work overwhelming? Was it scary thinking about returning to earth or staying in space for too long? There are so many ways to answer this question so I would be very interested in understanding their fears and their reason for being afraid.

Explanation:

Answer:

the correct answer is

D.Remaining well-hydrated while exercising is best

Answer:

s₁ = 240,000 km

Explanation:

The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,

s = s₁ + s₂

where,

s = total distance between the focuses = ?

s₁ = distance between f1 and moon = 200,000 km

s₂ = distance between f₂ and moon = 300,000 km

Therefore,

s = 200,000 km + 300,000 km

s = 500,000 km

Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:

s = s₁ + s₂

500,000 km = s₁ + 260,000 km

s₁ = 500,000 km - 260,000 km

s₁ = 240,000 km

Answer:

What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

Explanation:

The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.

Answer:

y = (-1/3)x + 5

Explanation:

the gradient of required equation (m2)

the gradient of given equation (m1) = 3

m1*m2 = -1 ( they are perpendicular)

3*m2 = -1

m2 = -1/3

required equation

y = m2 + c

( 9,2) satisfy the above equation

2 = (-1/3)*9 + c

c = 5

y = (-1/3)x + 5

Answer:

water boiling point is usually 100°C so I think we subtract 18 degrees Celsius from 100 degrees Celsius to get 82 degrees Celsius to be the energy needed

Answer:

D. Nuclear energy

Explanation:

A nucleus is the result of nuclear energy if it is split into an other the same result shall happen it being nuclear energy.

Answer:

I think it c

Explanation:

Answer:

Atraining for an athletic competition

Answer: 14

Explanation:

Force(normal)*coefficient

The static friction force is a force that prevents motion of an object kept on a surface, due to the interaction of the surface of the object and the surface on which it is kept

Reason:

The known parameter are;

The weight of the block, W = 35 N

The static friction of the surface of the table surface, [tex]\mu_s[/tex] = 0.40

Required:

To find the minimum force to start the block moving

Solution:

The force required to start the block moving is given by the frictional force that needs to be surpassed

Force required, F = Force of friction

Force of friction = Normal reaction × Coefficient of static friction

On a flat surface, the normal reaction = The weight of the object

∴ Force of friction, [tex]F_f[/tex] = Weight of the object × Coefficient of static friction

Which gives;

[tex]F_f = W \times \mu_s[/tex]

[tex]F_f = 35 \, N \times 0.40 = 14 \, N[/tex]

Force required, F = Force of friction, [tex]F_f[/tex] = 14 N

The minimum force required to start the block moving, F = 14 N

Learn more about the static friction force here:

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Answer:

T kinda waky tho -_-----_-----_-////_----_---///

Explanation:

Answer:

true

Explanation:

Answer: For #1, 7.3 m/s2.

Explanation: See this wikipedia screenshot for explanation, it's complicated.

Answer:

(from top to bottom)

350 N, 80 kg, 10 m/s^2, 80 kg, -15 m/s^2, -3000 N

Explanation:

Force = Mass*Acceleration (aka F = ma)

Using algebra, you can find the variables/unknown values.

Answer:

31.6

Explanation:

velocity÷ time

212 ÷ 6.7 = 31.6m/s

If you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate of 150 N, then the acceleration of the crate would be 5 m / s² .

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem if you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate in 150 N.

The net force acting on the crate = 400 N - 150 N

                                                        = 250 N

The acceleration of the crate = 250 / 50

                                                 = 5 m / s²

Thus, the acceleration of the crate would be 5 m / s² .

Learn more about Newton's second law here, refer to the link given below ;

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Answer:

False, Boiling water is an example of a physical change and not a chemical change

Answer:

yes

Explanation:

cos from the boiling water, you can still get another change

Answer:

Explanation:

the quality or state of being malleable: such as. a : capability of being shaped or extended by hammering, forging, etc. the malleability of tin.

Answer:

earth is 4.54 billion years old

for an organism to survive they would have to change ( mutate )

A mutation is any permenant change in dna of a gene or chromosome

some mutations are bad and some can be good

Explanation:

Answer: Wavelength

Explanation:

Answer:

C) wavelength

Explanation:

I hope this is right, have a nice day!

Answer:

31.86m

Explanation:

recall that one of the equations of motion can be written

v² = u² + 2as

where

u = initial velocity = 25m/s

v = final velocity = 0m/s because at maximum height, the ball will momentary stop moving (i.e have zero velocity)

a = acceleration = -9.81m/s²  (i.e a deceleration as it moves upwards equal to the magnitude of the gravitational acceleration)

s = distance (we are asked to find this)

substituting these into the equation:

v² = u² + 2as

0² = 25² + 2(-9.81)s

0 = 625 - 19.62s

19.62s = 625

s = 625 / 19.62

s = 31.86m

Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity.

It is a vector quantity and it's SI unit is m/s².

It is usually denoted by the symbol g.

Formula of Acceleration due to Gravity:

[tex] \boxed{ \bf{g = \dfrac{GM}{r^2}}}[/tex]

G → Universal Gravitational Constant [tex] \sf (6.67 \times 10^{-11} \ Nm^2/kg^2) [/tex]

M → Mass of the Asteroid (1 × 10⁴ kg)

R → Radius of the Asteroid (20 m)

By substituting values in the equation, we get:

[tex] \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11} \times 1 \times {10}^{4} }{20^2} \\ \\ \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11 + 4} }{400} \\ \\ \rm \longrightarrow g = 0.016675 \times {10}^{ - 7} \\ \\ \rm \longrightarrow g = 1.6675 \times {10}^{ -9} \: m {s}^{ - 1} [/tex]

[tex] \therefore [/tex] Acceleration due to gravity on the surface of small asteroid named ‘B612’ = [tex] \sf 1.6675 \times 10^{-9} \ m/s [/tex]

Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity. Acceleration due to gravity on the surface of small asteroid named ‘B612’ = 1.776 * 10 9 m/s2.

A free-falling item is one that is falling solely as a result of gravity, as was discovered in the previous section of this course. A free-falling object experiences a downward acceleration of 9.8 m/s. (on Earth).

The acceleration of any object moving only as a result of gravity is referred to as the acceleration of gravity.

In fact, this quantity, known as the acceleration of gravity, is so significant to physics that it has its own distinctive symbol, the letter g. The most precise measurement of the gravitational acceleration is 9.8 m/s.

To learn more about acceleration due to gravity, refer to the link:

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