The coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C
What is the coefficient of volume expansion of the liquid?The amount of volume that a substance expands by per unit of its original volume for each degree that its temperature rises is known as the coefficient of volume expansion.
As we know, The coefficient of volume expansion of the liquid
= change in volume/(original volume × temperature difference)
= (V₂ - V₁)/[V₁ × (T₂ - T₁)]
Change in volume = (V₂ - V₁)
Here, V₂ ( final volume) = 1.31 L
V₁ (initial volume)= 1.55 L
T₂ (final temperature) = 14.7 degrees
T₁ (initial temperature) = 96 degrees
The coefficient of volume expansion of the liquid
= (1.31 - 1.55) / [1.5 × (14.7- 96)]
= 1.97 × 10⁻³ /⁰C
Thus, the coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C
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Which statements describe acceleration? Check all that apply. Negative acceleration occurs when an object slows down in the positive direction. Negative acceleration occurs when an object slows down in the negative direction. Negative acceleration occurs when an object speeds up in the negative direction. Positive acceleration occurs when an object speeds up in the positive direction. Positive acceleration occurs when an object speeds up in the negative direction. Positive acceleration occurs when an object slows down in the negative direction.
All of the true statements that describe acceleration include the following:
A. Negative acceleration occurs when an object slows down in the positive direction.
C. Negative acceleration occurs when an object speeds up in the negative direction.
D. Positive acceleration occurs when an object speeds up in the positive direction.
F. Positive acceleration occurs when an object slows down in the negative direction.
What is an acceleration?In Science, an acceleration can be defined as the rate of change of the velocity of a physical object or body with respect to time.
How to calculate the acceleration of an object?Mathematically, the acceleration of a physical object or body can be calculated by using this formula:
a = (V - U)/t
Where:
a represents the acceleration.V represents the final velocity.U represents the initial velocity.t represents the time measured in seconds.Generally speaking, a physical object would experience positive acceleration when it either speeds up in the positive direction or slows down in the negative direction.
On the other hand (conversely), a physical object would experience negative acceleration when it either speeds up in the negative direction or slows down in the positive direction.
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Need to fill in the blank
Neglecting drag, the cannonball's initial height, and its horizontal motion, the maximum height rise is 110.45 metres, the time it takes for the ball to rise is 4.7 seconds, and the overall flight duration is 9.4 seconds.
Equation:
A pupil propels a cannonball 47.0 metres per second vertically upward.
assuming that the acceleration brought on by gravity is 10 m/s2.
Using the equation U2 = 2gH, the cannonball's highest point will be determined.
where H is the height the cannonball reaches.
When all the figures are put together, 47*47 = 2*10*H
H = 110.45 metres.
The cannonball's ascent time would be given by t=(2H/g).
When all the values are put together, t = (2*110.45/10)t = 4.7 seconds.
The cannonball's total flight time, T, is equal to the sum of its rise and descent times.
The ratio of ascent to descent is time.
Time of ascension = 4.7 Seconds since there is no other acceleration present and it is motion under gravity.
T = 2×(time of ascent) (time of ascent)
9.4 seconds are equal to T = 2*4.7.
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The Sun radiates energy at a rate of about 4×1026W. Earth is about 150×106km from the Sun.
Estimate the energy coming to Earth from the Sun each second. The radius of Earth is about 6400 km .
The average intensity received on the Earth's surface is [tex]12.6*10^{10} W/m^{2}[/tex]
[tex]Intensity = Rate of energy radiated/4\pi R^{2}[/tex]
where R is the distance of the earth from the sun.
[tex]I=4*10^{26}/4\pi *[150*106*10^{3}]^{2}[/tex]
[tex]I=0.12597*10^{12}[/tex]
[tex]I=12.6*10^{10} W/m^{2}[/tex]
What is the meaning of the intensity of sunlight?
Sun intensity refers to the amount of incoming solar energy, or radiation, that reaches the Earth's surface. The angle at which the rays from the sun hit the Earth determines this intensity.
What is the average intensity received on the Earth's surface?
The average intensity received on the Earth's surface is given by:
[tex]I=rate of energy radiated/4\pi R^{2}[/tex]
Thus, the average intensity received on the Earth's surface is [tex]12.6*10^{10} W/m^{2}[/tex]
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A kid is standing on a merry-go-round 1.14 m from the center rotating at 2.38 rad/s. What is his linear velocity?
Answer:
[tex]\huge\boxed{\sf v = 2.7\ m/s}[/tex]
Explanation:
Given data:Radius = r = 1.14 m
Angular velocity = ω = 2.38 rad/s
Required:Linear velocity = v = ?
Formula:v = rω
Solution:v = (1.14)(2.38)
v = 2.7 m/s[tex]\rule[225]{225}{2}[/tex]
Review what you learned in the unit about attribution theory. Explain in your own words what it is. Describe how attributions affect the way we explain behavior. In what way can attribution theory be harmful? In what way can it be helpful?
Attribution theory describes how an individual says or thinks that something is a as a result of a person's deed or an action of an external factor.
The cause of behavior is attributed to some internal characteristic of a person rather than external forces.
It can be harmful because attributing a person's character to a mistake can lead to underestimation of an individual.
Attribution helps an individual to understand the reason behind another person's behavior and thinking.
What is Attribution theory?Attribution theory is related to how ordinary people explain the causes of behavior and events that follow it. This helps them understand how they receive, interpret action, and how they give form an opinion of them.
When an person displays certain behaviors, they are usually attributed to certain internal characteristics. This theory can be harmful to explaining behavior because mistakes are attributed to character instead of external factors leading to underestimating people. On the other hand, it is beneficial to understanding people.
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A 50 g ball of clay traveling at speed Vo hits and sticks to a 1.0 kg block sitting at rest on a frictionless surface. What is the speed of the block after the collision? What percentage of the ball's initial energy is "lost"?
0.048 v₀ is the speed of the block after the collision and 95.2 percentage of the ball's initial energy is "lost".
How does collision happen?Particles, groups of particles, or solid objects that are moving in the same direction collide when they are sufficiently close to one another.
Briefing:Ball mass, m1 = 50 g = 0.05 kilogram
ball's velocity, = v₀
brick's mass, m2 Equals 1 kilogram
Let v be the brick's speed following the collision.
Utilize the idea of linear momentum conservation;
m1v0 + m2u2 = v(m1 + m2)
0.05v₀ + 0 = v(1 + 0.05)
0.05v₀ = 1.05 v
v = 0.05v0 / 1.05
v = 0.048 v₀
Consequently, the brick's speed following the contact is 0.048v0.
The entire kinetic energy at rest;
K.E. = 1 / 2 * 1.05 * (0.048 v₀)²
K.E. = 0.012v₀²
How much mechanical energy was lost during the impact;
= 0.025v₀² - 0.012 v₀² / 0.025v₀² * 100%
= 95.2 %
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A person is pushing a couch that has a mass of 20 kg. The couch initially accelerates at a rate of 1.5 m/s2. According to Newton’s second law of motion, what is the magnitude of the net force on the couch?
The magnitude of the net force on the couch will be equal to 30 N.
What is force?Force acting on an object can be defined as the effect that changes the state of the body of motion or rest. The force's SI unit is Newton and force is a vector parameter.
The force can be determined from the product of the mass (m) and acceleration (a).
F = ma
Given, the mass of the couch, m = 20 Kg
The couch is accelerating, a = 1.5 m/s²
According to Newton’s second law of motion, the magnitude of the net force on the couch can be calculated as:
F = ma = 20 ×1.5
F = 30 N
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Two satellites of masses m1 and m2 orbit a planet of mass M in circular orbits. The satellites travel in opposite directions with speeds v1 and v2. Their orbital radii are R1 and R2, respectively. Assume M>>m2>m1. What is the ratio of the speeds v1/v2?
The ratio of the speeds V_1/V_2 =√(R_2/R_1 )
From the question, we have
Orbital speed is,
V=√(GM/R)
Where h= gravitational constant
r= radius of orbit
M= mass
⇒V_1=√(GM/R_1 ) *V_2
⇒V_1/V_2=√(GM/R_2 )
⇒V_1/V_2 =√(R_2/R_1 )
The ratio of the speeds V_1/V_2 =√(R_2/R_1 )
Orbital speed :
The speed at which one body orbits the other body is known as the orbital velocity. The term "orbit" refers to an object's consistent circular motion around the Earth. The distance between the object and the earth's center determines the orbit's velocity. The gravitational pull between the planet and the Sun must alter if the planet's distance from the Sun changes as it orbits. The acceleration of the planet must rise, leading to a higher orbital speed, if the force that the Sun exerts on the planet increases (as the planet gets closer).
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the beam has a rectangular cross section and is subjected to the loadings shown. determine the principal stresses at point a and point b, which are located just to the left of the 20-kn load. show the results on elements located at these points.
To determine the principal stresses at points A and B, we need to consider how these forces are distributed over the surface of the volume element. The principal stresses are the stresses that act along the directions of maximum and minimum stress on the element.
To determine the principal stresses at points A and B, we need to consider the forces acting on a small volume element located at these points.
The stress on a volume element is defined as the force acting on the element per unit area. The stress components at a point can be represented by a stress tensor, which is a 3x3 matrix with nine elements. The diagonal elements of the stress tensor represent the normal stress components, while the off-diagonal elements represent the shear stress components.
In this case, we are given that the beam has a rectangular cross-section and is subjected to the loadings shown. There is a vertical force F acting on the beam at point A, as well as a horizontal force P. The beam is also subjected to a moment M about the z-axis.
To find the principal stresses, we can first calculate the normal stress components and shear stress components at the points of interest. Then, we can use the equations of mechanics to determine the principal stresses by finding the eigenvalues of the stress tensor.
To do this, we need to know the dimensions of the volume element, as well as the magnitudes of the forces and moments acting on the beam. With this information, we can use the equations of statics to solve for the stress components at points A and B, and then use the equations of mechanics to determine the principal stresses at these points.
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Which of the following is a natural resource for humans?
O Cars
O Electricity
O Houses
O Wood
Which of the following is a natural resource for humans?
O Cars
O Electricity
O Houses
O Wood
Wood
Answer:
wood is a natural resources to man because it is not created by man
A skateboarder with a mass of 67.0 kilograms (including the skateboard) rolls down from the top of a ramp, reaching a velocity of 7.30 meters per second at the bottom of the ramp. Assuming friction is 0, what was the potential energy of the skateboarder at the top of the ramp?
1,785 J.
59.70 J.
74.30 J.
489.1 J.
The potential energy of the skateboarder at the top of the ramp is
489.1 J.
Is kinetic energy always equal to potential energy?The amount of kinetic energy change and the amount of potential energy change are equal in all physical processes that take place in closed systems. When the kinetic energy rises, the potential energy falls, and vice versa.
Potential energy is the stored energy in any object or system as a result of its position or component arrangement. However, external factors like air or height have no effect on it. The energy of a moving object or system is referred to as kinetic energy.
Potential energy = kinetic energy
Potential energy = 1/2mv²
Potential energy = 1/2 × 67×7.3
Potential energy = 489.1 J.
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When A student connects Cd" (2 M) I cd(s) half-cell to the red lead attached t0 the Cu electrode the cell potential read by the voltmeter, Ea' is +77 V. a) What is the reduction half-reaction at the cathode (red lead)? b) What is the oxidation half-reaction at the anode (black lead)? c) What is the overall cell reaction? d) Write the expression for the thermodynamic reaction quotient;, Q, and calculate its value for this celle) Use the Nernst equation to find the standard cell potential, E? ." 0252 In Q (at 25*C) f) Knowing that the standard reduction potential, E?rd' ofthe Cu" |Cu(s) half-cell is +0.34 V, (or knowing that the standard oxidation potential, E" ofthe Cu(s) Cu? half-cell is -0.34 V), what is the potential of the cadmium half-cell? Is this E?red or E?g) What is the standard reduction potential (SRP, E? ofthe Cd?-(0.20 M)lcd(s) half-cell?
We know that in electrochemical series copper has standard reduction potential +0.34 V which is higher than Cadmium(-0.40) .is Cd(s)+Cu2+(aq) -===Cd2+(aq)+Cu(s)
What is electrochemical?
The field of physical chemistry known as electrochemistry studies how a recognisable chemical change and an electrical potential difference interact as a measurable and quantitative phenomenon, with the potential difference either resulting from or being a cause of the chemical change.
Hence a cell contain copper and cadmium ion Copper half cell always reduction reaction occurs and in cadmium half cell oxidation takes place. E0 cell=Ecathode-E anode=+0.34-(-0.44)=0.78~0.77V
a) Reduction half reaction at cathode
Here cu2+ reduced to metallic Cu Cu2+(aq)+2e-------> Cu (s) (Reduction)
b) Oxidation half cell reaction at anode
Here Cd oxidized into Cd2+ Cd(s)---------->Cd2+(aq)+2e-
Overall cell reaction
Cd(s)+Cu2+(aq) -===Cd2+(aq)+Cu(s)
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Choose the one which is False.
1. If the speed changes, the velocity also changes.
2. If the speed changes, there is acceleration.
3. If the speed does not change, but the direction changes, there will be acceleration.
4. Motion with constant velocity is accelerated motion.
5.
Motion along a straight line is Linear motion.
Answer:
4
Explanation:
1 is true. Speed is the magnitude of velocity so if the magnitude of velocity(speed) changes, then velocity changes itself.
2 is true.
[tex]a _{avg} = \frac{v _{f} - v _{i} }{t} [/tex]
Since speed changes, the inital and final speeds are different, therefore we will have some nonzero acceleration because the numerator does not equal zero.
3 is correct, acceleration is a vector so it has direction, meaning if the direction of speed changes then we will have acceleration.
4. is false, a constant velocity has a acceleration of 0.
5 is correct, motion along a straight line is linear.
The half-life of chromium-51 is 28 days. If the sample contained 510 grams, how much chromium (in grams) would remain after 1 year?
Answer: 0.061gm
Explanation:
What will be the purple spring's change in length if a 311 g mass is hung from the bottom?
The change in length of the purple spring be 6.77 cm.
What is spring constant?The spring stiffness is how we define the term "spring constant." In other words, we can define the spring constant as the force that was used to cause the spring's displacement to be one unit. It follows that a spring's spring constant would increase as it becomes more rigid.
Given parameters:
Spring constant: k = 45 N/m.
Mass of the load: m = 311 g = 0.311 kg.
So, weight of the load: w = mg = 0.311 × 9.8 N = 3.0478 N.
Hence, the purple spring's change in length be = w/k = 3.03478/45 m = 0.0677 m = 6.77 cm.
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I have found a small piece of rock that I believed is actually gold. The density of gold is 19.3 g/cc. Is there a way that I could find the density of the piece of rock I found? How would I find the density?
You can measure its mass and volume and use the equation density=mass/volume
In the above figure, a ray of light is incident upon the interface between two media having indices of refraction n1 = 1.2 and n2 = ???. The known angles are f2 = 60° and f3 = 34°. (Note that the angles in the diagram may not be accurate.) What is the speed of light in the second medium?
n₂ = 1.196. A light beam strikes the boundary between two mediums with different indices of refraction.
How does refraction work?When light waves cross the border between two materials with different densities, like air and glass, their speed changes. They alter direction as a result, which is a phenomenon known as refraction. Refraction is the shift in a wave's direction when it travels through one medium and then another.
What two refractions are there?Absolute refractive index is the comparison between the speed of light in vacuum and the light speed in another medium. Relative refractive index is the ratio of one medium's light speed to a different medium's light speed.
Briefing:Snell's law = n₁sinθ₁= n₂sinθ₂
and the velocity of light, N = C/ Vn
n₁ = 1.2
n₂ = 1.196
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a person travels 5 meter east in 20 second and 12 meter north in 45 second. Find its speed and velocity
Answer:
The car goes 100 metres in the east direction,in 4 seconds.
The car goes 50 metres in the west direction,in 1 second.
to find :
The average velocity and average speed of the car.
Explanation:
Speed is a scalar unit which means, direction is not necessary in this case. We can simply divide the total covered distance by the total taken time,in order to calculate the average speed.
So, average speed = (100 m + 50 m)/(4sec + 1sec) = (150m/5sec) = 30m/s
Now, velocity is a vector unit,which means direction is necessary in this case. We need to find the displacement (distance between starting point and ending point of the journey) and we need to divide the displacement with total taken time.
Here,east and west are opposite directions.
So, displacement = 100 m - 50 m = 50 m in east direction
Average velocity = 50m/5sec = 10m/sec
Hence,the average speed is 30m/s and the average velocity is 10m/sec.
Welcome.
A spring is compressed 0.48 m inside a dart gun. What is the potential
energy of the spring? (k = 800 N/m)
Answer:
92.16J
Explanation:
E = ½ke²
E = ½(800)(0.48)²
E = 400 x 0.48²
E = 92.16
If you know how to do physics i would appreciate if you help me. i am extremely confused
Answer: position E
Explanation:
After the ball is thrown it has a negative acceleration (it's slowing down) at a rate of 9.8 m/s2 (round that to 10 m/s2), which is g, the rate of acceleration due to gravity. The position of the ball is shown every 1 second. At position B, the ball has a speed of 40 m/s, at C = 30 m/s, at D = 20 m/s, and at E = 10 m/s. Every 1 second, the ball slows down by 10 m/s. At F, the top, the instantaneous speed = 0 m/s. Then the ball will then speed up by 10 m/s every second, until it reaches K, where the speed is back at 50 m/s.
A 2.5 kg sledge hammer hit a cement block with a force of 6.0 Newtons.
How does the force the sledge hammer exerted on the cement block compare with the force the cement block exerted on the sledge hammer?
Responses
The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
HURRY HURRY HURRY !!!The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.
When a 2.5 kg sledgehammer hit a cement block with a force of 6.0 Newtons. The force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.
What are opposite forces?This refers to forces that act on an object in opposite directions. The net force is gotten by solving for the difference between the two forces.
When the opposing forces are equal or balanced, the net force is zero. The sledgehammer hits with a force and the cement block is receiving the impart as a stationary object.
Obviously, the force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.
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A skateboarder with a mass of 120 kilograms (including the skateboard) is traveling at a speed of 5.00 meters per second upon reaching the bottom of a ramp. Between the top of the ramp and the bottom, the skateboarder lost 150 joules of thermal energy due to friction. What was the potential energy of the skateboarder at the top of the ramp?
6,150 J.
5,850 J.
1,650 J.
1,350 J.
The potential energy of the skateboarder at the top of the ramp was 1650 joule.
What is laws of conservation of energy?The law of conservation of energy asserts, in essence, that: The total energy of the system is preserved in a closed system, or a system that is separated from its surroundings.
Given that: A skateboarder with a mass of 120 kilograms (including the skateboard) is traveling at a speed of 5.00 meters per second upon reaching the bottom of a ramp.
So, his kinetic energy = 1/2×mass×speed² = 1/2 × 120 × 5² = 1500 Joule.
Loss of energy due to friction = 150 joule.
So, the potential energy of the skateboarder at the top of the ramp be = 1500 Joule + 150 joule = 1650 joule.
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Why are S-H bonds longer than O-H bonds?
Answer: S-H bonds are typically longer than O-H bonds because sulfur is larger than oxygen. The size difference between the two atoms means that the electrons in the bond are farther apart in an S-H bond, resulting in a longer bond length. Additionally, sulfur is less electronegative than oxygen, which means that the electrons in the bond are less strongly attracted to the sulfur atom and are therefore more likely to be found in the region between the two atoms, further increasing the bond length.
Explanation:
Answer:
Describe the differences between the O-H and S-H bond lengths. Due to its stronger shielding, which lessens the nuclear pull for the bonding electrons and causes a longer bond length, sulfur is a bigger atom than oxygen.
Explanation:
Part E Explain how you obtain your answer. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Terms:
- decreasing
- oppose
- increasing - support
Sentences:
- When the current in the wire is decreasing the oppose magnitude of the magnetic flux in the loops is ___
- Induced currents in the loops and the forces exerted on them are directed so they ____ this change
When the current in the wire is decreasing the oppose magnitude of the magnetic flux in the loops is decreasing.
Induced currents in the loops and the forces exerted on them are directed so they oppose this change
Magnetic flux is a size of the entire magnetic subject which passes thru a given region. it's far a useful device for helping describe the outcomes of the magnetic pressure on some thing occupying a given location.
Magnetic flux through a surface is the surface integral of the ordinary element of the magnetic subject B over that floor. it is also denoted Φ or ΦB. The SI unit of magnetic flux is the weber, and the CGS unit is the maxwell.
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The picture below shows a prominence in the sun's atmosphere.
The picture shows the surface of the sun with a curved layer of flame representing prominence rising from the surface of the sun.
Which of these events is most likely to occur as a result of the prominence?
the corona would become visible
the auroras would become visible
the sun's photosphere would be blocked
the sun's magnetic effect would decrease
Since the surface of the Sun has a curved layer of flame that represent prominence rising from the surface of the Sun, an event which is most likely to occur as a result of the prominence is: B. the auroras would become visible.
What is the Sun?In Science, the Sun can be defined as an astronomical or celestial body that is typically found within the solar system around which planetary (astronomical) bodies orbit, and whose light shines on planet Earth to differentiate day and night.
What is a solar prominence?A solar prominence is also known as filament and it can be defined as a large, bright, dense cloud of luminous ionized gas such as hydrogen, sodium calcium, etc., that erupts and extends from the surface of the Sun.
Based on astronomical records, a solar prominence can linger in the corona for a very long time, reaching hundreds of thousands of kilometers into the Sun's atmosphere (space). Consequently, this solar prominence would make the auroras (polar lights) to become visible.
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1. What type of plate boundary is at the point labeled "A"?
2. When an ocean plate converges with another plate, what is created on the seafloor at the line of convergence?
3. What type of plate boundary is being formed at the point labeled "B"?
4. What process is occurring at the points labeled "C "and "D"?
5. How do some rocks store information about Earth's magnetic field?
A specific spot on a tectonic plate border is represented by Point A.
what is tectonic plate border ?
An enormous slab of solid rock with an uneven form known as a tectonic plate is often made up of both continental and oceanic lithosphere rocks. Tectonic plates can be anything from a few hundred and a few thousand kilometres across in size. Among the biggest plates on the earth are the Pacific and Antarctic Plates.
Numerous smaller or less significant tectonic plates are also present. Despite being smaller, the minor plates play a smaller role in forming the earth's surface characteristics. The tectonic plates move like a conveyor belt due to currents in the molten rocks underneath the plates. The interaction where the plates meet or split is where the majority of geologic activity occurs. The plates barely shift a few millimetres annually, though.
A specific spot on a tectonic plate border is represented by Point A. Major tectonic plates are represented by plates X and Y. Labeling has been done for the Hellenic Trench, the minor tectonic plate Anatolian Plate, and the island of Crete. The relative directions of plate motion are shown by arrows.
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Where is Ohio ?!?!?!?!??!?!?!?!
Answer:
In america
Explanation:
Ohio is a state in the Midwestern region of the United States. Of the fifty U.S. states, it is the 34th-largest by area, and with a population of nearly 11.8 million, is the seventh-most populous and tenth-most densely populated.
It is also known for it's weirdness as it doesn't exist
Answer:
Ohio is bordered by Lake Erie to the north, Pennsylvania to the east, West Virginia to the southeast, Kentucky to the southwest and his home to creatures like this
Explanation:
Add voltmeters to measure the voltage across each bulb and the power source for a total of 4 voltmeters. On the correct circuit, label positive + and negative - on the battery and label the bulbs 1, 2, 3
A volt/ohm meter, commonly referred to as a multimeter or multitester, is an electronic measuring device that integrates multiple measurement capabilities into a single unit. Voltage, current, and resistance measurements are among the things that a typical multimeter may be able to do.
What voltmeters measure the voltage across each bulb?Connect the voltmeter to the circuit in a specific method in order to utilize it to measure the potential difference. Wire 1, or the portion of the circuit before the bulb, must be connected to the voltmeter's one end.
Therefore, The circuit after bulb, or wire 2, must be linked to the other end of the voltmeter.
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Consider electromagnetic waves in free space. What is the wavelength of a wave that has the following frequencies? (a) 4.86 times 10^11 Hz m (b) 8.80 times 10^16 Hz m
The wavelength of a wave for 4.86 times 10^11 Hz m is [tex]6.17 * 10 ^-^4 m[/tex] and for 8.80 times 10^16 Hz m is [tex]3.4 * 10 ^-^9 m[/tex]
What are electromagnetic waves?
The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves, or EM waves. In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves.
What is wavelength?
The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction.
It is measured by λ = c/f.
where,
λ = wavelength
c = speed of light
f = frequency
Subsituting the values in equation:
(a) for f = 4.86 times 10^11 Hz m
λ = [tex]\frac{3 * 10^8}{ 4.86 * 10^1^1}[/tex] = [tex]6.17 * 10 ^-^4 m[/tex]
(b) for f =8.80 times 10^16 Hz m
λ = [tex]\frac{3 * 10^8}{ 8.80 * 10^1^6}[/tex] = [tex]3.4 * 10 ^-^9 m[/tex]
The wavelength of a wave for 4.86 times 10^11 Hz m is [tex]6.17 * 10 ^-^4 m[/tex] and for 8.80 times 10^16 Hz m is [tex]3.4 * 10 ^-^9 m[/tex]
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Calculate the potential V(r) for r < r. (Hint the net potential is the sum of the potentials due to the individual spheres.) Express your answer in terms of the given quantities and appropriate constants. Submit My Answers Give Up Correct Part B Calculate the potential V(r) for Ta < r < Express your answer in terms of the given quantities and appropriate constants. Submit Mv Answers Give Up Correct Part C Calculate the potential V(r) for rTb. Express your answer in terms of the given quantities and appropriate constants. V(r) 0
Potential is constant throughout the sphere. So, the distance we take is the radius of the sphere.
The electric potential inside the sphere at r < r is:
V =[tex]V_{a} +V_{b}[/tex]
= [tex]\frac{k(q)}{r_{a} } + \frac{k(-q)}{r_{b} }[/tex]
= kq [tex]\left[\begin{array}{ccc}\frac{1}{r_{a} }-\frac{1}{r_{b} } \end{array}\right][/tex]
Part b
The electric potential in between [tex]r_{a}[/tex] and [tex]r_{b}[/tex] is:
[tex]V = V_{a} +V_{b}[/tex]
[tex]\frac{k(q)}{r_{a} } + \frac{k(-q)}{r_{b} }[/tex]
[tex]= kp\left[\begin{array}{ccc}\frac{1}{r_{a} }-\frac{1}{r_{b} } \end{array}\right][/tex]
Part c
The electric potential inside the sphere at r < [tex]r_{b}[/tex] is:
[tex]V = V_{a} +V_{b}[/tex]
[tex]\frac{k(q)}{r_{a} } + \frac{k(-q)}{r_{b} }[/tex]
[tex]= kp\left[\begin{array}{ccc}\frac{1}{r_{a} }-\frac{1}{r_{b} } \end{array}\right][/tex]
= 0
A voltmeter is used to measure the potential difference between two points. A voltmeter has a high resistance and is connected in parallel with an electrical component that measures the potential difference. The net potential energy between two adjacent ions EN.whose values depend on the particular ionic system.
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