A. Express each Fraction in Decimal form. Round off your answers into
thousandths place.
1. 3/4​

Metals typically lose electrons to complete their octet in a reaction with non-metals, whereas non-metals typically acquire electrons to complete their octet. Ionic compounds are typically formed via reactions between metals and nonmetals. The given compound barium hydroxide is ionic.

Ions with the opposite charge are carefully packed together to form crystalline solids. Ionic compounds typically result from reactions between metals and non-metals. The electrostatic interaction between the positive and negative ions holds ionic solids together.

Baryta, commonly known as barium hydroxide, has the chemical formula Ba(OH)₂. It is an odorless, clear-white powder. It has a toxic disposition. It is ionic in nature, with two hydroxide ions per molecule of barium hydroxide (Ba(OH)₂ in an aqueous solution an example.

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Answer:

CaCl₂ (aq) + 2NaOH (aq) —> Ca(OH)₂ (s) + 2NaCl (aq)

Explanation:

The equation for the reaction is given below:

CaCl₂ (aq) + NaOH (aq) —> Ca(OH)₂ (s) + NaCl (aq)

The above equation can be balance by as follow:

CaCl₂ (aq) + NaOH (aq) —> Ca(OH)₂ (s) + NaCl (aq)

There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front NaCl as shown below:

CaCl₂ (aq) + NaOH (aq) —> Ca(OH)₂ (s) + 2NaCl (aq)

There are 2 atoms of Na on the right side and 1 atom on the left side. It can be balance by putting 2 in front of NaOH as shown below:

CaCl₂ (aq) + 2NaOH (aq) —> Ca(OH)₂ (s) + 2NaCl (aq)

Now, the equation is balanced.

Answer:

A hurricane can cause extreme damage to the biosphere and the geosphere. A hurricane can leave water standing therefore sinking itself into the geosphere. The biosphere can be permanently effected because it can kill, injure, and destroy the biosphere and what the biosphere creates (buildings, parks).

Explanation:

Answer:

Explanation:

In order to find out the mass of KOH to be used we use the formula

where

m is the mass

c is the concentration in mol/dm³

M is the molar mass

v is the volume in dm³

From the question

c = 2.8 M

v = 700 mL = 0.7 dm³

Mr( K) = 39 , Mr(O) = 16 , Mr(H) = 1

we have

Molar mass of KOH = 39 + 16 + 1

= 56 g/mol

So we have

m = 2.8 × 56 × 0.7

We have the final answer as

Hope this helps you

Answer:

Long term condition of the atmosphere

Explanation:

I think this is right.

I hope this helps! (✿◕‿◕✿)

Answer:

acceleration = force/mass

                 = (68.6+mg)/7

                 = 19.6 m/s²

Explanation:

9.8 m/s² is the acceleration acting on 7 kg mass if force of 68.6 N  is used to move it towards earth.

Force is defined as a cause which is capable of changing the motion of an object. It can cause an object which has mass to change it's velocity. It is also simply a push or a pull . It has both magnitude as well as direction.Hence, it is a vector quantity.

It has SI units of Newton and is represented by'F'.Newton's second law states that force which acts on an object is equal to momentum which changes with time. If mass of object is constant, acceleration is directly proportional to net force acting on an object.

The concepts which related to force are thrust and torque .Thrust increases the velocity of an object and torque produces change in rotational speed of an object.

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Answer:

1 Faraday

Explanation:

This question seeks to test proper understanding of Faraday's second law of electrolysis which states when the same quantity electricity passes through a solution of different electrolytes, the mass of the substance deposited is directly proportional to there chemical equivalence.

This law hints at the charges of ions being the chemical equivalence and also been represented as the unit for the quantity of electricity in faraday, F. Hence, a metal with the charge of 1+ can be displaced by 1F (which is equal to 96, 500 coloumbs). This charge also represents one molecule of electron, thus 1 faraday corresponds to one mole of electrons.

NOTE: It should be noted that a metal with the charge of 2+ can be displaced by 2F and so on.

Answer:

0.05 g/cm^3.

Explanation:

The volume of the block = 9*2*6 = 108 cm^3.

Density = mass/volume

= 5.4 / 108

= 0.05 g/cm^3.

Answer:I think it would be the third one.

Explanation:

Answer:

10 moles of water are produced,

Explanation:

Given data:

Moles of H = 10 mol

Moles of O = 6 mol

Water obtained = ?

Solution:

Balance chemical equation:

2H₂ + O₂    →    2H₂O

Now we will compare the moles of H₂ and O₂ with water from balance chemical equation.

                            H₂             :          H₂O

                             2              :            2

                             10             :           10

                            O₂             :          H₂O

                             1              :            2

                             6             :           2×6 = 12

Number of moles of water produced by hydrogen are less so hydrogen will be limiting reactant and it will limit the yield of water thus, 10 moles of water are produced.

Answer:

its natural gas because i had something like this

Explanation:

The renewable energy sources, such as biomass, geothermal resources, water, wind, etc. are called the natural resources. These can be converted into clean and usable energy. The correct option is D.

The energy which is derived from the natural sources which are replenished at a higher rate than they are consumed is defined as the Renewable energy. The renewable energy generating produce lower emissions than burning the fossil fuels.

The word biomass refers to the organic plant matter which is converted into fuel and used as an energy source. The biomass fuel is considered as an important renewable and sustainable source of energy. It is used for the production of electricity.

The organic materials like wood, agricultural wastes, etc. acts as the excellent sources to produce biomass fuel. It is possible to burn the biomass fuel directly and later converted into methane and ethanol biofuels.

Thus the correct option is D.

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Explanation:

Phosphorus (P) because of the 5 valence electrons total, 3 of them are in the 3p sublevel, and according to Hund's rule, they "single-fill" each orbital first.

Answer:

It's called Evaporation.

Answer:

ΔG° = -1.45 × 10⁵ J

Explanation:

Step 1: Given data

Step 2: Calculate the standard Gibbs free energy change (ΔG°)

We will use the following expression.

ΔG° = -n × F × E°cell

ΔG° = -1 mol e⁻ × 96,485 C/mol e⁻ × 1.50 V

ΔG° = -1.45 × 10⁵ J

By apply Gibbs's free energy, the value of delta G is equal to -144727.5 Joules.

Given the following data:

To determine the value of delta G, we would apply Gibbs's free energy:

Mathematically, Gibbs's free energy is given by the formula:

[tex]\Delta G^\circ = -nFE^{ \circ}_{cell}[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]\Delta G^\circ = -1 \times 96485 \times 1.50[/tex]

[tex]\Delta G^\circ = -144727.5[/tex]

Delta G = -144727.5 Joules

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Answer:

The value is  [tex]V_2  =   0.246 \  m^3/h[/tex]  

Explanation:

From the question we are told that

  The temperature at which the gas enters the compressor is  

         [tex]T_i = 298 \  K[/tex]

  The pressure  at which the gas enters the compressor is  

       [tex]P_I =  1.0 \ atm[/tex]

  The volumetric rate at which the gas enters the compressor is

      [tex]V  =  127 m^3/h[/tex]

   The temperature to which the gas is compressed to is  

      [tex]T_f  =  358 \ K[/tex]

  The pressure  to which the gas is compressed to is  

     [tex]P_f=  1000 \  atm[/tex]

Generally the volumetric flow rate of compressed oxygen is evaluated from the compressibility-factor equation of state as

    [tex]V_2  =  V_1 *\frac{z_2}{z_1} * \frac{T_2}{T_1} * \frac{P_1}{P_2}[/tex]

Here [tex]z_1[/tex] is the inflow compressibility factor with value [tex]z_1 = 1[/tex]

Here [tex]z_1[/tex] is the outflow compressibility factor with value [tex]z_2 = 1.61[/tex]

So

    [tex]V_2  =  127*\frac{1.61}{1} * \frac{358}{298} * \frac{1}{1000}[/tex]  

    [tex]V_2  =   0.246 \  m^3/h[/tex]  

Answer:

Weather radar is used to locate and track severe storm.

Answer:

Explanation:

Answer:

0.75 moles of CO2

Explanation:

molar mass of CO2⇒ 44.01 g/mol

molar mass Oxygen ⇒ 31.998 g/mol

divide the mass given by molar mass of oxygen  so

48÷31.998= 1.50009376 moles of O

then you use the ration of oxygen to carbon to find the moles of CO2 which is one mole of CO2 for 2 moles of oxygen

1.50009376 moles of O ×[tex]\frac{1}{2}[/tex] = 0.75004688

with sig figs

0.75 moles of CO2

Answer:

7.5%

Explanation:

I just know it's that

Answer:

SBr2

Electron geometry-tetrahedral; molecular geometry-trigonal pyramidal

PI4+

Electron geometry-tetrahedral; moleculargeometry-tetrahedralr

IBr2

Electron geometry - tetrahedral ; molecular shape - bent

Explanation:

We have to carefully consider the issues in question 2.

First of all, the compound SiF4 is an AX4 molecule so both it's electron domain geometry and molecular geometry are tetrahedral. The molecule has no lone pairs.

For SeF4, the compound is a molecule of the type AX4E, its molecular geometry is trigonal bipyramid but its molecular geometry is see-saw because of the presence of a lone pair of electrons on the central atom, selenium.

For XeF4, the electron domain geometry is octahedral but its molecular geometry is square planar. The molecule is of the type AX4E2 and the two lone pairs are positioned above and below the plane of the square.

Answer:

A. the wave is a mechanical wave

C. the wave moves energy through matter

F: the wave transfers energy perpendicular to the motion of the wave.

Answer:

[tex]T_f=25.0\°C[/tex]

Explanation:

Hello.

In this case, considering that the sample of hot copper is submerged into the water and the container is isolated, the heat lost by the copper is gained by the water so we can write:

[tex]Q_{Cu}=-Q_w[/tex]

In terms of mass, specific heat and temperature we write:

[tex]m_{Cu}C_{Cu}(T_f-T_{Cu})=-m_wC_w(T_f-T_w)[/tex]

Whereas the final temperature is the same for both copper and water because they are in contact until thermal equilibrium is reached. In such a way, the required maximum temperature no more than the equilibrium temperature and is computed as shown below:

[tex]T_f=\frac{m_{Cu}C_{Cu}T_{Cu}+m_wC_wT_w}{m_{Cu}C_{Cu}+m_wC_w}[/tex]

Thus, plugging the given data in the formula, we obtain:

[tex]T_f=\frac{10.3g*0.385\frac{J}{g\°C}*100\°C +47.0g*4.184\frac{J}{g\°C}*23.5\°C }{10.3g*0.385\frac{J}{g\°C}+47.0g*4.184\frac{J}{g\°C}}\\\\T_f=25.0\°C[/tex]

Which is a small change considering the initial one, because the mass of water is greater than the mass of copper as well as for the specific heats.

Best regards!

The maximum temperature of the water in the insulated container after the copper metal is added is 25 °C

From the question given above above, the following data were obtained:

Mass of water (Mᵥᵥ) = 47 g

Temperature of water (Tᵥᵥ) = 23.5°C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Mass of copper (M꜀) = 10.3 g

Temperature of copper (M꜀) = 100 °C

Specific heat capacity of copper (C꜀) = 0.385 J/gºC

The equilibrium temperature of the mixture can be obtained as follow:

Heat loss by copper = Heat gained by water

Q꜀ = Qᵥᵥ

M꜀C꜀(M꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ– Mᵥᵥ)

10.3 × 0.385 (100 – Tₑ) = 47 × 4.184 (Tₑ – 23.5)

3.9655 (100 – Tₑ) = 196.648 (Tₑ – 23.5)

Clear bracket

396.55 – 3.9655Tₑ = 196.648Tₑ – 4621.228

Collect like terms

396.55 + 4621.228 = 196.648Tₑ + 3.9655Tₑ

5017.778 = 200.6135Tₑ

Divide both side by 200.6135

Tₑ = 5017.778 / 200.613

Thus, the equilibrium temperature of the mixture is 25 °C. Therefore, the maximum temperature of the water in the insulated container is 25 °C

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Answer:

about 0.13 mol

Explanation:

To find number of mols when given grams you first have to find the molar mass of the compound. This is done by adding up the atomic masses of the element in the compound. So Sr= 88 g/mol S=32 g/mol and O=16 g/mol. Then 88+32+(16x4)=184. Then using this you can convert from grams to mols by dividing the grams by the molar mass. So, 24.23/184 equals about 0.13 mol.

Answer: The particles are moving fast but close together.

Answer:

its in the explanation.

Explanation:

1.In liquids, particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

2.It assumes the shape of the part of the container which it occupies particles can move/slide past one another.

Hope this helps. :)

Answer:

Pb, Cr, Fe

Explanation:

The metals that can react with hydrochloric acid are; Sn, Cr and Ni.

The electrochemical series shows the reactivity of elements. An element can only replace another element in solution when that element is higher in the electrochemical series.

The metals that can replace hydrogen in a solution of hydrochloric acid must be metals that are above hydrogen in the electrochemical series. These metals are; Sn, Cr and Ni. Hg is a noble metal hence it does not replace hydrogen in an acid solution.

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Answer:

iodine pentachloride

Explanation:

Answer:

The noble gases (Group 18) are located in the far right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactive. The noble gases were characterized relatively late compared to other element groups.

The History

The first person to discover the noble gases was Henry Cavendish in the late 180th century. Cavendish distinguished these elements by chemically removing all oxygen and nitrogen from a container of air. The nitrogen was oxidized to  NO2  by electric discharges and absorbed by a sodium hydroxide solution. The remaining oxygen was then removed from the mixture with an absorber. The experiment revealed that 1/120 of the gas volume remained un-reacted in the receptacle. The second person to isolate, but not typify, them was William Francis (1855-1925). Francis noted the formation of gas while dissolving uranium minerals in acid.

Argon

In 1894, John William Strutt discovered that chemically-obtained pure nitrogen was less dense than the nitrogen isolated from air samples. From this breakthrough, he concluded that another, unknown gas was present in the air. With the aid of William Ramsay, Strutt managed to replicate and modify Cavendish's experiment to better understand the inert component of air in his original experiment. The researchers' procedure differed from the Cavendish procedure: they removed the oxygen by reacting it with copper, and removed the nitrogen in a reaction with magnesium. The remaining gas was properly characterized and the new element was named "argon," which originates from the Greek word for "inert."

Helium

Helium was first discovered in 1868, manifesting itself in the solar spectrum as a bright yellow line with a wavelength of 587.49 nanometers. This discovery was made by Pierre Jansen. Jansen initially assumed it was a sodium line. However, later studies by Sir William Ramsay (who isolated helium on Earth by treating a variety of rare elements with acids) confirmed that the bright yellow line from his experiment matched up with that in the spectrum of the sun. From this, British physicist William Crookes identified the element as helium.

Neon, Krypton, Xenon

These three noble gases were discovered by Morris W. Travers and Sir William Ramsay in 1898. Ramsay discovered neon by chilling a sample of the air to a liquid phase, warming the liquid, and capturing the gases as they boiled off. Krypton and xenon were also discovered through this process.

Radon

In 1900, while studying the decay chain of radium, Friedrich Earns Dorn discovered the last gas in Group 18: radon. In his experiments, Dorn noticed that radium compounds emanated radioactive gas. This gas was originally named niton after the Latin word for shining, "nitens". In 1923, the International Committee for Chemical Elements and International Union of Pure Applied Chemistry (IUPAC) decided to name the element radon. All isotopes of radon are radioactive. Radon-222 has the longest half-life at less than 4 days, and is an alpha-decay product of Radium-226 (part of the U-238 to Pb-206 radioactive decay chain).

The Electron Configurations for Noble Gases

Helium 1s2

Neon [He] 2s2 2p6

Argon [Ne] 3s2 3p6

Krypton [Ar] 3d10 4s2 4p6

Xenon [Kr] 4d10 5s2 5p6

Radon [Xe] 4f14 5d10 6s2 6p

Explanation: