A cube of wood having an edge dimension of 19.5 cm and a density of 651 kg/m3 floats on water.

Required:
a. What is the distance from the horizontal top surface of the cube to the water level?
b. What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface?

Answers

Answer 1

Answer:

a)   y ’= 0.068 m ,  b)   m_lead = 2,599 kg

Explanation:

a) To solve this exercise, let's use Archimedes' law, which establishes that the pressure of the water is equal to the weight of the dislodged liquid.

Let's write the forces in the equilibrium condition

            B - W = 0

            B = W

Thrust is

            B = ρ_liquid g V_water

Body weight is

             W = m g

the definition of density

           ρ_body = m / V

we substitute

            W = ρ_body g V_body

The volume of the body is

          V_body = L³

The volume of water is

          V_agua = y L²

we substitute

           ρ_liquid g and L2 = rho_body g L3

           ρ_liquid y = ρ_body L

           y = L ρ_body /ρ_liquid

let's calculate

          y = 651/100 0.195

          y = 0.1269 m

this is the distance from the bottom of the cube, the distance from the top of the cube

          y ’= 0.195 -y

          y '= 0.195 - 0.1269

          y ’= 0.068 m

b) In this case the equilibrium equation is

          B - W_body - W_lead = 0

          B = W_body + W_lead

          ρ_liquido g V_liquido = ρ_body g V_body + m_lead g = 0

          ρ_liquid L3 = ρ_body L3 + m_lead = 0

          m_lead = L3 (ρ_liquid - ρ_body)

           

let's calculate

          m_lead = 0.195 3 (1000 - 651)

          m_lead = 2,599 kg


Related Questions

Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.

Answers

Answer:

K = ρL²g

Explanation:

Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;

Then:

F = upthrust ( restoring force) = weight of the liquid displaced.

[tex]F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g[/tex]

where;

A = L²

[tex]\rho_{\omega} = \rho[/tex]

F = ky.

Then,

[tex]Ay \rho g = ky[/tex]

[tex]L^2y \rho g = ky[/tex]

Divide both sides by y

K = ρL²g

?
_2. Region surrounding the nucleus where electrons are found.
?
_3. Positively charged center of an atom.
?
4. Particles that differ in number between isotopes.

Answers

Answer:

Electron shell

Nucleus

Neutrons

Explanation:

An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.

Protons are the positively charged particles. Neutrons do not carry any charges. Both protons and neutrons are found in the tiny nucleus at the center of that atom. The electrons are negatively charged. They are found outside the nucleus in electronic shells.

A 2 kg block slides with constant velocity along a horizontal tabletop. A horizontal applied force of 10 N and a downward applied force of 5 N act on the block, as shown. The coefficient of friction between the block and tabletop is most nearly... ​

Answers

Answer:

huh

Explanation:

Answer:

what are we finding?

Explanation:

A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?
A.
velocity and wavelength
OB.
velocity and frequency
Ο Ο Ο Ο
OC.
frequency and wavelength
OD.
frequency and phase
E.
wavelength and phase

Answers

Answer:

Velocity and frequency

Explanation:

A person weighs 780N on earth. What is his mass on earth, mass on moon? What is his weight on the moon?

Answers

Answer:

79.6kg  

127.5N

Explanation:

Given parameters:

Weight of the person on earth = 780N

 Now, we are to find;

Mass on earth;

Mass on moon;

Weight on moon

Solution:

The mass on earth and on the moon are the same. Mass is the amount of matter in a substance.  

   Weight  = mass x acceleration due to gravity

     780  = mass x 9.8

           mass  = [tex]\frac{780}{9.8}[/tex]   = 79.6kg

Mass on earth and moon  = 79.6kg  

The acceleration due to gravity on the moon is 1.6m/s²

  Weight on moon = 79.6 x 1.6  = 127.5N

The diagram shows the electrical circuit inside a flashlight when the switch is
open and closed.

Which series of energy transformations occurs when the switch is closed?

A. Chemical energy - Electrical energy - Light energy
B. Mechanical energy - Light energy - Electrical energy
C. Electrical energy Light energy - Mechanical energy
D. Light energy - Electrical energy - Chemical energy

Answers

Answer:

A.

Explanation:

I got it right ;)

Answer:

Chemical energy ---> Electrical energy ---> Light energy

Explanation:

Which Energy transformation will occur when this rubber band is let go elastic energy -chemical energy mechanical energy -electrical energy chemical energy -mechanical energy elastic energy mechanical- energy elastict

Answers

Elastic Energy - Mechanical Energy

What makes the atmosphere an important part of Earth’s system?

Answers

Answer:

water exchange carbon dioxide is taken away and oxygen is made

The Earths atmosphere protects and sustains the plants inhabitants by providing warmth and absorbing harmful solar rays. In addition to containing the oxygen and carbon dioxide, which living things need to survive, the atmosphere traps the suns energy and wards off many of the dangers of space.

Hope I helped ❤️
Plz mark me brainiest? :)

A small truck has a mass of 2085 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 13.0 m/s on a level road?

Answers

Answer:

Work required is 328387.5 Joules.

Explanation:

Given the following data;

Mass = 2085kg

Initial velocity, Vi = 13m/s

Final velocity, Vf =22m/s

To find the workdone;

We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.

Mathematically, it is given by the equation;

W = Kf - Ki

Where;

W is the work required.

Kf is the final kinetic energy possessed by the object.

Ki is the initial kinetic energy possessed by the object.

But Kinetic energy = ½MV²

W = ½MVf² - ½MVi²

Substituting into the equation, we have;

W = ½(2085)*22² - ½(2085)*13²

Simplifying the equation, we have;

W = 1042.5 * 484 - 1042.5 * 169

W = 504570 - 176182.5

W = 328387.5J

Therefore, the work required to decrease the speed of the vehicle is 328387.5 Joules.

If a 28-N force causes a rock to accelerate at 4 m/s/s, what is the mass of the rock?

Answers

Answer:

7kg

Explanation:

Given parameters:

Force on the rock  = 28N

Acceleration  = 4m/s²

Unknown:

Mass of the rock  = ?

Solution:

According to newton's second law of motion;

           Force  = mass x acceleration

Insert the given parameters to find the mass;

         28  = mass x 4

             mass  = [tex]\frac{28}{4}[/tex]   = 7kg

In Einstein’s theory of gravitation, gravity is due to:
A)the acceleration of the universe
B)the presence of mass
C)the rotation of the universe
D)the curvature of spacetime
E)the speed of light

Answers

Answer:

B,  caused by the presence of mass

Explanation:

Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflection is the angle between the reflected ray and the normal, which is the surface of the mirror.

Which statement corrects an error on the site?

Answers

Answer:

A

Explanation:

Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.70 m. The ball is going 7.33 m/s.

If the speed is tripled, what happens to its centripetal force?
a)The new centripetal force is 1/3 what it was
b)The new centripetal force is 9 times more
c)The new centripetal force is 1/9 what it was
d)The new centripetal force is 3 times more

Answers

Answer:

b)The new centripetal force is 9 times more

Explanation:

The formula to apply in this case is that of tension force on a spring which is equal to the centripetal force.

T= mv²/r --------i

where T is the tension on the spring

v= velocity/speed of the ball = 7.33 m/s

m= mass of the ball , 0.015 kg

r= radius of circle , 0.70 m

Use the values in the formula as;

T= {0.015 * 7.33² } / 0.70

T= 0.8059335 / 0.70

T= 1.15 N ---------i

If the speed is tripled then;

v= 21.99 m/s

T= 0.015 * 21.99² / 0.70

T= 10.36 N ------ii

Check the changes by dividing i and ii as ;

10.36 / 1.15 =  9.01

This is 9 times more hence if the speed is tripled ,the new centripetal force is 9 times more.

Read each scenario below. Then select the answer choices that complete the sentences,

A car engine has

power than a house because a car engine does the same amount of work in

time,

Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height

and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,

Raj applied

power than Yaskrin because his stacking took turve to do the same amount of

Answers

Answer:

Higher

Lesser

Lesser

Longer

Explanation:

Search...

54

ryanzl6659

14 hours ago

Physics

College

Read each scenario below. Then select the answer choices that complete the sentences,

A car engine has HIGHER power than a house because a car engine does the same amount of work in LESSER time,

Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,

Raj applied LESSER power than Yaskrin because his stacking took LONGER to do the same amount of

Answer:

More

Less

Less

More

Explanation:

i got all correct

A barge is pulled by two tugboats. If the resultant of the forces exerted by the
tugboats is 5kN force directed along the axis of the barge, determine the tension in
each of the ropes for α = 45

Answers

Answer:

Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.

Explanation:

Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.

Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.  

The first direction is parallel to resultant force on the barge.

The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \cos(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \cos(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].

These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].

The second direction is perpendicular to the resultant force on the barge.

The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \sin(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \sin(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].

These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.

That gives a system of two equations and two unknowns:

[tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}} = 5\; \rm kN[/tex], and[tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}} = 0[/tex].

The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:

[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].

Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].

In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].

The tension in each of the rope is 3,535.5 N

The given expression:

the resultant force, R = 5 kN = 5000 N

the angle in between the forces, α = 45

To find:

the tension in each of the ropes

The tension in  each of the ropes  is calculated as follows;

The tension in vertical direction

[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]

The tension in horizontal direction;

[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]

Thus, the tension in each of the rope is 3,535.5 N

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The ___ of a wave is the reciprocal of its frequency.

Answers

Answer:

time period of the wave

Answer:

The Frequency of a wave is the reciprocal of its Period

The Period of a wave is the reciprocal of its frequency

Explanation:

A P E X

Mass is sometimes described as the difficulty of acceleration of an object. How does Newton's second law agree with this description?

Answers

Answer:

Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.

If the mass increases, it's harder to accelerate

Because force tends to rise with mass while mass tends to decrease with force, mass is sometimes referred to as the difficulty of accelerating an item. As a result, the greater mass's inverse effect balances out the larger force exerted on more massive objects.

Newton's second law agreement with difficulty of acceleration of an object-While acceleration tends to decrease as mass increases, it tends to increase as force increases. As a result, the bigger force acting on more massive objects is balanced off by the greater mass's inverse effect.As a result, all things fall in free fall at the same rate of acceleration regardless of mass. As the mass increases, accelerating becomes more difficult.Newton's second law of motion is applicable when there are unbalanced forces acting on an object.The second law states that an object's rate of acceleration depends on both its mass and the net force acting on it.An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.An object's acceleration increases as the amount of force exerted on it does.A decreasing acceleration is caused by a rise in an object's mass.The acceleration of an item caused by a net force is inversely proportional to the mass of the object and directly proportional to the magnitude of the net force in the same direction.

To learn more about Newton's second law of motion click here-

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#SPJ2

help please! thank you! please dont plagiarism my teacher checks for plagiarism ;-;

Answers

Answer:

the reason why the crate won't move to the direction of the force being applied (F app). is because the (Fgravity) is pulling it down making it heavy to move

what is an emergent curriculum

Answers

Answer:

Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.

You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.

a. Greater than your true weight
b. Equal to your true weight
c. Less than your true weight
d. It's impossible to determine

Answers

Answer: A

Explanation: Your body gets pulled down, causing ur body to have more weight but not mass.

Less than true weight

George got a bad grade on the test because he decided he would rather sleep than study. this is an example of a __ attribution

Answers

the right answer for this question would be dispositional

Answer:

dispositional

Explanation:

what happens at a transform boundary

Answers

Transform boundaries are places where plates slide sideways past each other.

I hope

Answer:

Answer is "two tectonic plates slide past eachother" ( for a pe x)

Explanation:

A force is exerted on a charge carrying particle by a ________ _____ only when the particle moves ________the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is__________.

Answers

Answer:

  force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO

Explanation:

This complementation exercise refers to the magnetic force that the formula has

         F = q v x B

where the bold letters indicate vents and the x the vector product. The module of this product is

         F = qv B sin θ

where θ  is the angle between the speed and direction of the magnetic field.

It can be seen that for the force to be different from zero, the angle must not be parallel θ  = 0

        sin 0 = 0

the maximum value is obtained for an angle of θ  = 90º

       sin 90 = 1

Using these concepts we see that the missing words are.

  force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO_______

A value that describes how heavy an object is and is related to the force of gravity is:

Answers

The weight of an object

Answer: B) weight

Got it right on E2020

If the speed of a roller coaster at the bottom of a hill is 20.0 m/s , what is the tallest hill the coaster can climb, assuming no friction losses ?

Answers

Answer:

20.4 meters

Explanation:

KE = 1/2 m v^2 = mgh = PE (convert all kinetic energy to potential energy, because at the highest point the coaster can climb, it will be stopped!)

=> h = (1/2 m v^2) / (mg) = v^2/(2*g) = (20 m/s)^2 / (2*9.8 m/s^2) = 20.4 m

The tallest height that the roller coaster can climb is 20 m.

A roller coaster is a device in which energy conversions from potential to kinetic energy takes place. Hence the roller coaster can easily be used to demonstrate the conversion of mechanical energy from one form to another.

Given that the velocity of the roller coaster at the bottom of the hill is  20.0 m/s, potential energy is converted into kinetic energy.

Hence;

mgh = 1/2mv^2

gh =1/2v^2

h = 1/2v^2/g

h = 0.5 × (20)^2/10

h = 20 m

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what is the surface pressure of Venus?

Answers

answers 93 bar

The atmosphere of Venus is the layer of gases surrounding Venus. It is composed primarily of carbon dioxide and is much denser and hotter than that of Earth. The temperature at the surface is 740 K (467 °C, 872 °F), and the pressure is 93 bar (9.3 MPa), roughly the pressure found 900 m (3,000 ft) underwater on Earth.

If a rock hits the ground with a KE of 33,000 J, falling from a height of 10 m, what is its weight? Remember, weight is measured in newtons (N), and is equal to mass times gravity.
A. 330 N
B. 33 N
C. It can't be computed from this information
D. 3,300 N​

Answers

Answer is 3,300N

Explanation

List four safety measures one should take when there is a cyclone warning.​

Answers

Answer:

I'm gonna give you more than 4 So u can choose.

Turn off all electricity, gas and water.

Unplug all electrical appliances.

Keep your emergency kit close at hand.

If the building starts to collapse, protect yourself with mattresses, rugs.

Stay tuned to the radio for updates.

Stay inside until told it is safe to go outside.

What is matter made of


Answers

Answer: Matter is made up of atoms that also come together to form molocules. Atoms contain Electrons (Negetive), nutronons (nuaetral), and protons (positive).

Let the force of the Moon on the Earth be F1. Let the force of the Earth pulling on the Moon be F2. Which of the following is greater?

Answers

they are both the same because of newton’s third law
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