A crowd of people stood on both sides of the street to view a 4th of July Parade.
The length of the parade was 3 miles long and 15 feet deep on each side of the street.
If 5 people can fit into a 25 ft^2 area.
Estimate the size of the crowd.
(1mile = 5280ft)

Answer:

G. Carla, Brenda, Marci, Susan

Step-by-step explanation:

The time given for all participants are in decimals except for that of Marci and Carla which are given in the form of mixed fractions.

Convert the mixed fractions into decimals, then compare the figures together to do the ranking.

Marci = [tex] 46\frac{49}{50} = \frac{2,349}{50} = 46.98 [/tex]

Carla = [tex] 46\frac{9}{10} = \frac{469}{10} = 46.9 [/tex]

The first four finishers from the 1st to the 4th are:

1. Carla - 46.9

2. Brenda - 46.97

3. Marci - 46.98

4. Susan - 47.21

answer.next time out the graph

Step-by-step explanation:

Answer:

It's A, an odd function

Answer : 4.5 × 10⁴ square inches can be washed per hour.

Step-by-step explanation :

As we are given that an area can be washed at a rate of 4,900 cm²/min. Now we have to determine the square inches can be washed per hour.

Given conversions are:

1 cm = 0.39 in    and    1 hr = 60 min

As, 1 cm² = (0.39)² in²    and    1 min = 1/60 hr

So, [tex]1cm^2/min=(0.39)^2\times 60in^2/hr[/tex]

[tex]1cm^2/min=9.126in^2/hr[/tex]

Now we have to determine the square inches can be washed per hour.

As, [tex]1cm^2/min=9.126in^2/hr[/tex]

So, [tex]4900cm^2/min=\frac{4900cm^2/min}{1cm^2/min}\times 9.126in^2/hr=44717.4in^2/hr=4.5\times 10^4in^2/hr[/tex]

Therefore, 4.5 × 10⁴ square inches can be washed per hour.

LCM = 30

15 = 3×5

2 = 2¹

10 = 2×5

LCM = 2×3×5 = 30

Answer:

The average is:

105 cm

Step-by-step explanation:

1 m = 100cm

2m = 2*100 = 200cm

then:

(200 + 20 + 95)/3 = 315/3 = 105cm

Answer:

45

Step-by-step explanation:

Answer:

34

Step-by-step explanation:

4(2)-2(7)+40

8-14+40

-6+40=34

4a-2b+40

4x2-2x7+40

8-14+40

-6+40

34 is the answer.

Answer:

-1<x<9

(I think you notated it wrong, it should be |x-4|-2<3)

Answer:

7

Step-by-step explanation:

For any real number x, if x > 0 then |x| = x and if x < 0 then |x| = -x. In this case, x < 0 so |-7| = -(-7) = 7.

Answer:

answer is 7

Step-by-step explanation:

if its a negative, its always the positive of that number....if that makes sense

Answer:

64c^12

Step-by-step explanation:

(4c^4)^3 distribute exponents

{(4)^3 (C^12)} simplify

64c^12

Answer:

A. 38.88

Step-by-step explanation:

$540-54 is 486

486(0.08) or 486(8%) is 38.88

Answer:

$38.88

I took the test, trust me

Answer:

24x^7 y^4 √7y

Step-by-step explanation:

The value of expression would be 24x⁷y⁴√7y  which is determined by simplification of the given expression  8 √63x¹⁴y⁹.

Algebraic expressions are mathematical statements with a minimum of two terms containing variables or numbers.

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

We have been the given expression as :

8 √63x¹⁴y⁹

We can simplify as:

⇒ 8 √63x¹⁴y⁹

The square root of a number is a number that can be multiplied by itself and gives the actual number.

⇒ 8 √[3×3×7( x⁷)²x (y⁴)² y]

Assume x and y are nonnegative.

⇒ 24x⁷y⁴√7y

Hence, the value of expression would be 24x⁷y⁴√7y.

Learn more about the algebraic expression here :

brainly.com/question/21751419

#SPJ2

Answer:

2

Step-by-step explanation:

1. Start by substituting 3 for every h, so it looks like 3^2-3(3)+2

2. Do the exponent first 9-3(3)+2

3. Multiply 3(3) to get 9-9+2

4. Subtract 9-9, 0+2

5. Add 0 and 2 to get 2

Answer:

10x^3 + 6x^2 + 5x + 3

Step-by-step explanation:

F(x)=(5x+3)(2x^2+1)

= 5x*2x^2 + 5x*1 + 3*2x^2 + 3*1

= 10x^3 + 5x + 6x^2 + 3

= 10x^3 + 6x^2 + 5x + 3

Given :

Three points ,  P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) .

To Find :

The length of sides .

Given :

We know , length of two points P(x,y ,z) and Q(a,b,c) is given by :

[tex]L=\sqrt{(x-a)^2+(y-b)^2+(z-c)^2}[/tex]

Length of PQ :

[tex]PQ=\sqrt{(4-2)^2+(3-1)^2+(4-3)^2}\\\\PQ=\sqrt{4+4+1}=\sqrt{9}\\\\PQ=3[/tex]

Length of QR :

[tex]QR=\sqrt{(2-2)^2+(1-7)^2+(3-0)^2}\\\\QR=\sqrt{0+6^2+3^2}\\\\QR=\sqrt{36+9}\\\\QR=\sqrt{45}\\\\QR=3\sqrt{5}[/tex] :

Length of RP :

[tex]RP=\sqrt{(2-4)^2+(7-3)^2+(0-4)^2}\\\\RP=\sqrt{2^2+4^2+4^2}\\\\RP=\sqrt{4+16+16}\\\\RP=\sqrt{36}\\\\RP=6[/tex]

Hence , this is the required solution .

Answer:

u = 8

Step-by-step explanation:

3u + 5u = 64

8u = 64

8u/8 = 64/8

u = 8

Answer:

no solution

Step-by-step explanation:

|f-6| = |f+8|

solve absolute values

f-6 = f+8

add 6 to 8

f = f+14

subtract f from f

0=14

not true; no solution

Answer:

x=( -8)

Step-by-step explanation:

hope it helps.^-^

Answer:

38

Step-by-step explanation:

|-23| + |-15|

First find the absolute values, which are the non negative values

23 +15

Then add

38

Answer:

920

Step-by-step explanation:

$4.60×6-8

$4.60×2dimes

=920

Answer: β ≠ ±1

Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,

det [tex]\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right][/tex] ≠ 0

Determinant of a 3x3 matrix is calculated by:

det [tex]\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]\left[\begin{array}{ccc}1&\beta\\2&2\\2-2\beta&4\end{array}\right][/tex]

[tex]8(1-\beta)-[2(2-2\beta)(1-\beta)][/tex]

[tex]8-8\beta-4+8\beta-4\beta^{2}[/tex]

[tex]-4\beta^{2}+4\neq 0[/tex]

[tex]\beta^{2}\neq 1[/tex]

[tex]\beta \neq \sqrt{1}[/tex]

β ≠ ±1

For the system to have only one solution, β ≠ 1 or β ≠ -1.

Answer:

84 cm²

Step-by-step explanation:

Surface are of the net = sum of the area of each section

Area of the 2 right triangles:

base (b) = 4cm, height (h) = 3 cm

Area = 2(½*b*h) = 2(½*4*3) = 4*3 = 12 cm²

Area of rectangle with the following dimensions:

length (L) = 6 cm, width (W) = 4 cm

Area = L*W = 6*4 = 24 cm²

Area of rectangle with the following dimensions:

length (L) = 6 cm, width (W) = 5 cm

Area = L*W = 6*5 = 30 cm²

Area of rectangle with the following dimensions:

length (L) = 6 cm, width (W) = 3 cm

Area = L*W = 6*3 = 18 cm²

Surface area of the net = 12 + 24 + 30 + 18 = 84 cm²

Answer:

8

Step-by-step explanation:

La longitud del arco (s) en una circunferencia, conociendo el radio (r) y el ángulo (θ) que forman los dos radios, es:

s = r∙θ

Con el ángulo en radianes

F V7 w7 :

Answer:

The loss is $4600.

Step-by-step explanation:

The par value of the bonds = $210400

The carrying value of the bonds or the actual value of bonds = $218600

The company calls the bonds at the price = $214000

Now have to find the gain or loss from the given information. Thus, below is the calculation to find the gain or loss.  

Loss or gain on retirement = $214,000 - $218,600 = -$4,600

Thus the loss on retirement is $4600.

Answer:

Step-by-step explanation:

F(x) = 3x - 7

g(x) = -2x - 6

To find (f o g)(4) we must first find (f o g)(x)

To find (f o g)(x) substitute g(x) into f(x) that's for every x in f (x) replace it with

g (x).

We have

(f o g)(x) = 3( - 2x - 6) - 7

= - 6x - 18 - 7

We have

(f o g)(x) = - 6x - 25

To find (f o g)(4), substitute the value of x that's 4 into (f o g)(x)

We have

(f o g)(4) = - 6(4) - 25

= - 24 - 25

We have the final answer as

Hope this helps you

Answer:

[tex]\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}[/tex]

Step-by-step explanation:

Given the quadratic equation as:

[tex]2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0[/tex]

Let us put [tex]sinx=y[/tex] for simplicity of the equation:

Now, the equation becomes:

[tex]2y^2+y-1=0[/tex]

Now, let us try to solve the quadratic equation:

[tex]\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1[/tex]

So, the solution to the given trigonometric quadratic equation is:

[tex]sinx = \dfrac{1}{2}[/tex]

and

[tex]sinx=-1[/tex]

Let us try to find the values of [tex]x[/tex] in the interval [tex][0, 2\pi)[/tex].

[tex]sin\theta[/tex] can have a value equal to [tex]\frac{1}{2}[/tex] in 1st and 2nd quadrant.

So, [tex]x[/tex] can be

[tex]30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}[/tex]

For [tex]sinx=-1[/tex],

[tex]x = 270^\circ\ or\ \dfrac{3 \pi}{2}[/tex]

So, the answer is:

[tex]\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}[/tex]