A container holds 3.41×10−3mol of carbon dioxide (CO2). After the addition of 8.41×10−4mol of carbon dioxide, the volume of the container increases to 95.2mL, with the temperature and pressure remaining constant. What was the initial volume of the container?

Answer:

Distance measures length. For example, the distance of a road is how long the road is. In the metric system of measurement, the most common units of distance are millimeters, centimeters, meters, and kilometers.

Explanation:

Answer:

2

Explanation:

C⁴H¹⁰ + 2O² —> 4CH²O + H²

Answer:

See explanation

Explanation:

According to Bohr's theory, when external energy is supplied to an atom, its electrons absorb energy and move from a lower energy level to a higher energy level.They quickly return to their original level and re-radiate the absorbed energy as a photo of light.

Hence, when an atom in ground state receives external energy, it becomes excited because energy is transferred to its electrons and they move from lower to higher energy level.

The electron after getting the energy would jump to an orbital further away from the nucleus.  

• Ground state refers to the lowest energy state an atom can be at. When an electron in an atom captivates energy it is considered to be in an excited state.  

• An excited atom becomes unstable and seem to align itself to move back to its lowest energy state.  

• When an atom in its ground state is supplied with an external energy, the energy is absorbed by the atom and the electron becomes excited and jumps to an orbit , that is, distant from the nucleus.  

• It can be said that electron attains higher energy state, with the absorption of more energy by the atom, the electron further moves to higher state till it becomes a free electron and no longer remains the part of the atom.  

Thus, the electron after getting the energy would jump to an orbital further away from the nucleus.

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Answer:

[tex]7.22 \times 10^{23}e^{-}[/tex]

[tex]1.16 \times 10^{5}C[/tex]

Explanation:

Step 1: Write the reaction for the electrochemical reduction of copper.

Cu²⁺(aq) + 2 e⁻ → Cu(s)

Step 2: Calculate the number of electrons required in the reduction of 0.600 moles of Cu²⁺

We will use the following relationships:

[tex]0.600molCu^{2+} \times \frac{2mole^{-} }{1molCu^{2+} } \times \frac{6.02 \times 10^{23}e^{-} }{1mole^{-}} = 7.22 \times 10^{23}e^{-}[/tex]

Step 3: Calculate the Coulombs corresponding to [tex]7.22 \times 10^{23}e^{-}[/tex]

We will use the following relationships:

[tex]7.22 \times 10^{23}e^{-} \times \frac{1 mol e^{-}}{6.02 \times 10^{23}e^{-}} \times \frac{96486C}{1 mol e^{-}} =1.16 \times 10^{5}C[/tex]

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = [tex]\frac{1.5}{106}[/tex]   = 0.014mol

Answer:

Percent yield = 91%

Explanation:

Given data:

Theoretical yield of SF₆ = 124.3 G

Actual yield of SF₆ = 113.7 g

Percent yield of SF₆ = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield)× 100

By putting values,

Percent yield = (113.7 g/ 124.3 g) × 100

Percent yield = 0.91 × 100

Percent yield = 91%

Answer:

[tex]1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^5[/tex]

Explanation:

Hello!

In this case, since electron configurations allows to understand how the electrons in an atoms are arranged depending on the energy levels from 1 to 7 and subshells s, p d and f, considering the attached picture, if we want an element for which the last term in its electrons configuration was 3d⁵, we write:

[tex]1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^5[/tex]

It means that the element has 25 electrons, therefore, it should be manganese.

Best regards!

Answer: it's A the same answer as the dude above me not trying to type all that

Explanation: took the test for ap

Answer: ?L=250 mL × 1L =0.25L 1000 mL

0.150 M = moles of solute moles of solute = 0.038 mol.

Explanation:

Answer:

5 moles of iron formed

Explanation:

Given data:

Moles of iron formed = ?

Moles of iron oxide react = 2.50 mol

Solution:

Chemical equation:

Fe₂O₃ + 2Al     →     Al₂O₃ + 2Fe

Now we will compare the moles of iron with iron oxide.

                  Fe₂O₃        :           Fe

                      1             ;            2

                  2.50          :          2×2.50 = 5 mol    

Answer: d

Explanation:because it makes sence i think

The normality of the solution which is prepared by dissolving 75 grams of citric acid in water to make 250 ml solution is 4.68 N. Thus, the correct option is C.

Normality is a measure of the concentration of a solution. Normality of a solution is the number of grams equivalent to solute which is present in a given volume of the solution.

Normality of a solution can be calculated by the formula:

N = Gram eq. of solution/ Volume of solution in liters

N = Weight of the solution/ Equivalent weight ×1000/ Volume of solution

N = 75/ 64.4 × 1000/ 250

N = 1.16 × 4

N = 4.64

The normality of the citric acid solution is approximately 4.68 N.

Therefore, the correct option is C.

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Answer:

The correct option is b

Explanation:

Firstly, the compound is ClF₃ and not ClF₃ClF₃. The name of the compound ClF₃ is chlorine trifluoride. It's electron geometry is trigonal bipyramidal (with the chlorine at the center and the atoms of the fluorine forming a triangular bipyramid around it) with a bond angle of 175° with an hybridization of sp³d.

Answer:

270 mL

Explanation:

First we convert the child's weight to kg:

So the total mass of morphine sulfate that should be injected is:

Finally we calculate the volume that should be injected, using the concentration of the available solution:

The accurate millilitre is 268 mL.

First of all, we must obtain the mass of the child in kilograms;

1 Ib = 0.45 Kg

85 lb = 85 lb × 0.45 Kg/1 Ib

= 38.25 Kg

If 1 Kg takes 35.0 mcg/kg/dose

38.25 Kg takes 38.25 Kg × 35.0 mcg/kg/dose/1 Kg

= 1338.75 mg/dose

Hence;

1338.75 mg/dose/5.0-mg/mL  = 268 mL

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compound is formed when potassium reacts with chlorine, which forms ions with a negative charge. The formula of this compound would therefore be KCl.

The molecular formula if potassium and chlorine reacted to form a neutral compound will be KCI.

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Answer:

Their atoms obey the octet rule

Explanation:

Chemical compounds are formed when atoms combine with one another in order to comply with the octet rule. The octet configuration gives an atom stability in electronic structure.

Answer:

The change in entropy of the carbon dioxide is [tex]1.183\times 10^{-3}[/tex] kilojoules per Kelvin.

Explanation:

By assuming that carbon dioxide behaves ideally, the change in entropy ([tex]\Delta S[/tex]), measured in kilojoules per Kelvin, is defined by the following expression:

[tex]\Delta S = m\cdot \bar c_{v}\cdot \ln \frac{T_{f}}{T_{o}}+m\cdot \frac{R_{u}}{M}\cdot \ln \frac{V_{f}}{V_{o}}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the gas, measured in kilograms.

[tex]\bar c_{v}[/tex] - Isochoric specific heat of the gas, measured in kilojoules per kilogram-Kelvin.

[tex]T_{o}[/tex], [tex]T_{f}[/tex] - Initial and final temperatures of the gas, measured in Kelvin.

[tex]V_{o}[/tex], [tex]V_{f}[/tex] - Initial and final volumes of the gas, measured in liters.

[tex]R_{u}[/tex] - Ideal gas constant, measured in kilopascal-cubic meter per kilomole-Kelvin.

[tex]M[/tex] - Molar mass, measured in kilograms per kilomole.

If we know that [tex]T_{o} = T_{f}[/tex], [tex]m = 0.010\,kg[/tex], [tex]R_{u} = 8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K}[/tex], [tex]M = 44.010\,\frac{kg}{kmol}[/tex], [tex]V_{o} = 6.15\,L[/tex] and [tex]V_{f} = 11.5\,L[/tex], then the change in entropy of the carbon dioxide is:

[tex]\Delta S = \left[\frac{ (0.010\,kg)\cdot \left(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)}{44.010\,\frac{kg}{kmol} } \right]\cdot \ln \left(\frac{11.5\,L}{6.15\,L}\right)[/tex]

[tex]\Delta S = 1.183\times 10^{-3}\,\frac{kJ}{K}[/tex]

The change in entropy of the carbon dioxide is [tex]1.183\times 10^{-3}[/tex] kilojoules per Kelvin.

Answer:

3)Some gas molecules move further apart and some move closer together.

Explanation:

because When more gas particles enter a container, there is less space for the particles to spread out, and they become compressed. The particles exert more force on the interior volume of the container. This force is called pressure. There are several units used to express pressure.

Answer:

The answer is "Option e"

Explanation:

The ionic bond arousal system of the outer shells (VSEPR) allows us to determine which one of the feasible solutions are found in the majority of instances. It's also supposed to occupy the space with electrical pairs and also to reduce electrical couple repulsive forces to a minimum, its cheapest electricity framework. This theory can be used for predicting a form of electron pairs with a different mass of a particle's core electrons.

Answer:

In the given case, to get a blue flame, one should open the air inlet further. To increase the size of the flame one should open the gas regulator further. When one opens the air inlet, more amount of oxygen goes within, and thus, one can get a more intense form of blue flame.

When one opens the gas regulator more concentration of gas goes and the larger the size of flame one gets.

To regulate a bunsen burner follow this procedure

To get a blue flame, you should rotate the wheel  of the burner anticlockwise further to reduce the level of oxygen flow.

To increase the size of the flame, you should rotate the wheel clockwise further

The bunsen burner is an apparatus in the laboratory used to carry out experiment when heating of substance is required, hence it is used to add heat to substances, it has a wheel used to regulate the flow of air which is required for combustion, it has a hose which is used to tap gas to the burner

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Answer:

c. SP2

Explanation:

The image in the diagram below shows the structure of  NO₃⁻

Nitrogen is the central atom with the electronic configuration of 1s² 2s² 2p³.

So in its outermost shell, it has 3 electrons and the hybridization is sp²

However,

According to Hund's rule:

The ground state of Nitrogen is;    

1s²    2s²   2p³

↑↓     ↑      ↑  ↑  ↑

At the excited state when it is attached to 3 different oxygen ions, we have:

                1s²     2s²        2p⁵

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑↓   ↑      

                1s²     2s²        2p⁵

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑↓   ↑

                1s²     2s²        2p⁴

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑   ↑

Thus, the 3 sp² orbital lies in a plane and form 3 N - O σ- bond and one π- bond.

Answer:

Both sulphur and oxygen have two unshared pairs of electrons

Explanation:

The compound sulphur monoxide has the formula S=O. It is quite analogous to the diatomic molecules of the group 16 elements.

We must remember that each group element has six electrons in their outermost shell. Two of these are lone pairs leaving only two electrons available for bond formation.

These two electrons are used to form the sigma and pi bonds in S=O, leaving two lone pairs on each of sulphur and oxygen atoms.

Answer:

[tex]atoms \ H= 9.767x10^{24}atoms[/tex]

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

[tex]atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms[/tex]

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

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Answer:

The reaction is 2F_2 (g) + 2H_2 O (g) rightarrow 4HF (g) + O_2 (g) 2 moles of fluorine gas (F_2) reacts with 2 moles of water vapors (H_2 O) to produce 4 moles of hy

Answer:

Call 911 then or run away

Explanation:

Answer:

NaCl may be i guess so....

The coefficient for Br and OH has been 3 and 6 respectively. Thus option C is correct.

If the reaction takes place in a basic medium, the reaction can be given as:

[tex]\rm Br_2\;+\;OH^-\;\rightarrow\;BrO_3^-\;+\;Br\;+H_2O[/tex]

The coefficient has been placed in the chemical reaction to balance the number of atoms on the product and the reactant side.

The number of atoms of Br on the product side has been 2, and the reactant side has been 2.

The oxygen atoms have been 1 on the reactant side, and 3 on the product side.

It has been balanced as:

[tex]\rm 3\;Br_2\;+\;6\;OH^-\;\rightarrow\;BrO_3^-\;+\;5\;Br^-\;+\;3\;H_2O[/tex]

The coefficient for Br and OH has been 3 and 6 respectively. Thus option C is correct.

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