A compound is made up of 168.2 g Cd, 35.96 g C, 4.53 g H, and 47.91 g O. What is the empirical formula of this compound

Answers

Answer 1

Considering the definition of empirical formula,  the empirical formula is Cd₁C₂H₃O₂= CdC₂H₃O₂.

Definition of empirical formula

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

Empirical formula of the compound

You know that a compound is made up of 168.2 g Cd, 35.96 g C, 4.53 g H, and 47.91 g O.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

Cd: [tex]\frac{168.2 g}{112.4 \frac{g}{mole} } =[/tex] 1.496 moles

C: [tex]\frac{35.96 g}{12 \frac{g}{mole} } =[/tex] 2.997 moles

H: [tex]\frac{4.53 g}{1 \frac{g}{mole} } =[/tex] 4.53 moles

O: [tex]\frac{47.91 g}{16 \frac{g}{mole} } =[/tex] 2.994 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Cd: [tex]\frac{1.496 moles}{1.496 moles } =[/tex] 1

C: [tex]\frac{2.997 moles}{1.496 moles } =[/tex] 2

H: [tex]\frac{4.53 moles}{1.496 moles } =[/tex] 3.02≅ 3

O: [tex]\frac{2.994 moles}{1.496 moles } =[/tex] 2

Therefore the Cd: C: H: O mole ratio is 1: 2: 3: 2.

Finally, the empirical formula is Cd₁C₂H₃O₂= CdC₂H₃O₂.

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The difference between the amount of heat actually released upon the hydrogenation of benzene and that calculated for the hydrogenation of an imaginary cyclohexatriene is called the _________ of benzene.

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From what we know, we can confirm that the difference measured by the experiment in the heat released when compared to the hydrogenation of an imaginary cyclohexatriene is called the stabilization energy of benzene.

What is stabilization energy?

This is a term used to describe the difference in measured energy of a chemical structure compared to the theoretical energy amounts expected to be measured. In this experiment, the heat that was released did not match the calculated energy expected, which is a prime example of stabilization energy at work.

Therefore, we can confirm that the difference measured by the experiment is called the stabilization energy of benzene.

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The engine displacement in cubic nanometer (nm³) is 8.785×10²⁴ nm³

Data obtained from the question Displacement in in³ = 536 in³Displacement in nm³ =? Conversion scale

1 in³ = 1.639×10²² nm³

With the above convesion scale we can obtain the displacement in nm³

How to determine the displacement in nm³

1 in³ = 1.639×10²² nm³

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536 in³ = 536 × 1.639×10²²

536 in³ = 8.785×10²⁴ nm³

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Part B
The image models what happened after each cup was placed over an effervescent tablet. Note the changes in the water level and the air space in both glasses. The tablets are shown to help see how the experiment was setup, but the model represents the air bubbles after the tablets fully dissolved. Write down your observations in the space provided.

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Answer:

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Calculate the number of atoms/molecules present in
(a) 1 mole of sulphur.
(b) 2 moles of oxygen gas.

Answers

Answer:

1 mole contains 6.02 ×10^23 atoms

1 mole of Sulphur will contain 6.02 ×10^23 atoms

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What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol

Answers

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x 0.5 mol EDTA  x  374 g EDTA  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

The amount in grams of EDTA needed to make 315.1 mL of a 0.05 M is equal to 5.89 g.

Molar concentration

In a 0.05M solution, there are 0.05 moles of the substance per 1 liter, that is, in 315.1 ml we have:

                                        [tex]\frac{0.05 mol}{xmol}= \frac{1000ml}{315.1ml}[/tex]

                                           [tex]x = 0.016 mol[/tex]

Thus, 0.016 mol EDTA of  is needed to prepare the solution.

Mass calculation

To calculate the mass in an amount of moles, we use the molar mass, so that:

                                          [tex]m = MM \times mol[/tex]

                                         [tex]m = 374 \times 0.016[/tex]

                                             [tex]m = 5.89 g[/tex]

So, the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M is equal to 5.89 g.

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Explanation:

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Answer:

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Answers

Answer:

C.) Sodium Chloride

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Percent composition

The percent composition of a component of a compound is found by dividing the mass of the component by the mass of the compound.

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Answers

The statements that are applicable to Hess's Law include:

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What is Hess's Law?

Hess's Law is also referred to as Hess's law of constant heat summation and it was named after a Swiss-born Russian chemist called Germain Hess.

Hess's Law states that the energy change experienced in an overall chemical reaction is equal to the sum of the energy changes in each chemical reactions that it contains.

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Answer:

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is 5509.12

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