A compound having an approximate molar mass of 165 - 170 g has the following...
A compound having an approximate molar mass of 165 - 170 g has the following percentage composition by mass: carbon, 42.87%; hydrogen, 3.598%; oxygen,
28.55%; nitrogen, 25.00%. Determine the empirical and molecular formulas of
the compound.

Answers

Answer 1

Answer:

Find ratio of atoms for empirical formula, divide mass by atomic mass

C=42.87/12 = 3.57

H= 3.598/1 = 3.598

O= 28.55/16 = 1.784

N= 25.00/14 =1.1785

to see ratio, divide by smallest no

Gives C2H2ON for empirical formula

Empirical mass = 24 +2 +16 + 14 = 56

165 to 170 /56 = 3

so molecular formula = empirical formula x 3= C6H6O3N3

Answer 2

1. The empirical formula of the compound is C₂H₂ON

2. The molecular formula of the compound is C₆H₆O₃N₃

1. Determination of the empirical formula.

From the question given above, the following data were obtained:

Carbon (C) = 42.87%

Hydrogen (H) = 3.598%

Oxygen (O) = 28.55%

Nitrogen (N) = 25.00%

Empirical formula =?

C = 42.87%

H = 3.598%

O = 28.55%

N = 25.00%

Divide by their molar mass

C = 42.87 / 12 = 3.5725

H = 3.598 / 1 = 3.598

O = 28.55 / 16 = 1.7844

N = 25.00 / 14 = 1.7857

Divide by the smallest

C = 3.5725 / 1.7844 = 2

H = 3.598 / 1.7844 = 2

O = 1.7844 / 1.7844 = 1

N = 1.7857 / 1.7844 = 1

Therefore, the empirical formula of the compound is C₂H₂ON

2. Determination of the molecular formula.

Molar mass of compound = (165 + 170)/2

Molar mass of compound = 335/2

Molar mass of compound = 167.5 g/mol

Empirical formula = C₂H₂ON

Molecular formula =?

Molecular formula = Empirical formula × n = molar mass of compound

[C₂H₂ON]n = 167.5

[(12×2) + (2×1) + 16 + 14]n = 167.5

[24 + 2 + 16 + 14]n = 167.5

56n = 167.5

Divide both side by 56

n = 167.5 / 56

n = 3

Molecular formula = [C₂H₂ON]n

Molecular formula = [C₂H₂ON]₃

Molecular formula = C₆H₆O₃N₃

Therefore, the Molecular formula of the compound is C₆H₆O₃N₃

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Related Questions

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Answers

Answer:

0.14 kg

Explanation:

The mass of the ball can be found by using the formula

[tex]m = \frac{2k}{ {v}^{2} } \\ [/tex]

v is the velocity

k is the kinetic energy

From the question we have

[tex]m = \frac{2(3.10)}{ {6.70}^{2} } = \frac{6.20}{44.89} \\ = 0.138115...[/tex]

We have the final answer as

0.14 kg

Hope this helps you

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Answers

Explanation:

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Eggshells have a similar chemical composition to our tooth enamel, making them react similarly with other chemicals. This can help us understand what stains tooth enamel. When we brush an eggshell with fluoridated toothpaste, it strengthens the shell and protects it from acid, just like it does for our tooth enamel.

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Answers

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HOPE IT HELPS...

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Answers

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Answers

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Answers

Answer:

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Explanation:

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where n is the number of moles

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L is the Avogadro's constant which is

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From the question we have

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Answers

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Answer:

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Answer:

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Answers

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brainly.com/question/26366780

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Answers

Answer:

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Answers

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Answers

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Answers

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Answers

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Answers

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Answers

Answer:

[tex]\huge\mathtt{{\colorbox{silver}{ANSWER~~~↴}}}[/tex]

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Answers

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Answers

Answer:

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hope it helps you

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Mass = 2500 g
Initial temperature = 25 o C Final temperature = 25.13 oC
Equations
q = m C p Δ T C p = q / (mΔT)

1. How much heat energy (q) did the water gain?

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3. Compare the heat capacity you calculated with the one below, which one matches?
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Answers

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Further explanation  

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Q in = Q out  

Heat can be calculated using the formula:  

Q = mc∆T  

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1. Heat of water gained

[tex]\tt Q=2500\times 4.18\times (25.13-25)=1358.5~J[/tex]

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