A competitive diver dives from a 33-foot high diving board. The height of the diver in feet after 't' seconds is given by u(t) = −16t^2 + 4t + 33. At the moment the diver begins her dive, another diver begins climbing the diving board ladder at a rate of 2 feet per second. At what height above the pool deck do the two divers pass each other? Please answer it quickly, it's for my homework.

Answers

Answer 1

Answer:

[tex]t = 0.375s[/tex]

Step-by-step explanation:

Given

[tex]h(t) = -16t^2 + 4t + 33[/tex] --- driver 1

[tex]Rate = 2ft/s[/tex] -- driver 2

[tex]height = 33ft[/tex]

Required

The time they passed each other

First, we determine the function of driver 2.

We have that:

[tex]Rate = 2ft/s[/tex] and [tex]height = 33ft[/tex]

So, the function is:

[tex]h_2(t) = Height - Rate * t[/tex]

[tex]h_2(t) = 33 - 2t[/tex]

The time they drive pass each other is calculated as:

[tex]h(t) = h_2(t)[/tex]

[tex]-16t^2 + 4t + 33= 33 - 2t[/tex]

Collect like terms

[tex]-16t^2 + 4t + 2t= 33 - 33[/tex]

[tex]-16t^2 + 6t= 0[/tex]

Divide through by 2t

[tex]-8t + 3= 0[/tex]

Solve for -8t

[tex]-8t = -3[/tex]

Solve for t

[tex]t = \frac{-3}{-8}[/tex]

[tex]t = 0.375s[/tex]


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[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{21(2x - 6) = 30(x + 1)}[/tex]

[tex]\large\textsf{21(2x) + 21(-6) = 30(x) + 30(1)}[/tex]

[tex]\large\textsf{21(2x) = 42x}[/tex]

[tex]\large\textsf{21(-6) = -126}[/tex]

[tex]\large\textsf{30(x) = 30x}[/tex]

[tex]\large\textsf{30(1) = 30}[/tex]

[tex]\large\textsf{42x - 126 = 30x + 30}[/tex]

[tex]\large\text{Put ALL your LIKE TERMS TOGETHER}[/tex]

[tex]\large\text{NEW EQUATION: \textsf {42x - 30x = 126 + 30}}[/tex]

[tex]\large\textsf{42x - 30x = 12x}[/tex]

[tex]\large\textsf{126 + 30 = 156}[/tex]

[tex]\large\text{NEW EQUATION: \textsf{12x = 156}}[/tex]

[tex]\large\text{DIVIDE 12 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{12x}{12}=\dfrac{156}{12}}[/tex]

[tex]\large\text{CANCEL out: } \mathsf{\dfrac{12}{12}}\large\text{ because that gives you 1}[/tex]

[tex]\large\text{KEEP: }\mathsf{\dfrac{156}{12}}\large\text{ because that helps you solve for your the given equation} \\\\\large\text{and your YZ result}[/tex]

[tex]\mathsf{\dfrac{156}{12}=\bf 13}[/tex]

[tex]\large\text{NEW and FINAL EQUATION: \textsf{30 + 1 + 13}}[/tex]

[tex]\large\textsf{30 + 1 + 13}[/tex]

[tex]\large\textsf{30 + 1 = \bf 31}[/tex]

[tex]\large\textsf{= 31 + 13}[/tex]

[tex]\large\textsf{= \bf 44}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf YZ = 44 }}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]


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