The magnitude of the magnetic field in the coil is 21.65 T.
The given parameters;
number of turns, N = 500 turnsarea of the coil, A = [tex]6\times 10^{-4} \ m^2[/tex]change in time, t = 15 sThe induced emf in the coil is determined by applying Faradays law;
[tex]emf =N \frac{d\phi }{dt} \\\\emf = N ( \frac{\phi _2 - \phi_1}{t} )\\\\emf= N(\frac{BAsin\ 60 - BAsin\ 90}{t} )\\\\emf = NBA(\frac{sin60 - sn90}{t} )\\\\-0.058 = 500(6\times 10^{-4})\times B\times (\frac{0.866 - 1}{15} )\\\\-0.058 = -0.00268B\\\\B = \frac{0.058}{0.00268} \\\\B = 21.65 \ T[/tex]
Thus, the magnitude of the magnetic field in the coil is 21.65 T.
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2. Un niño hace girar con la mano una pelota de hule que se encuentra sujeta mediante un cordón de
0.75 m de longitud. Si la pelota da 0.7 vueltas a cada segundo, entonces,
a) ¿Cuál es el periodo de la pelota?
b) ¿Cuál es la velocidad lineal de la pelota?
Cuando el niño hace girar 0.7 vueltas por segundo una pelota de hule que se encuentra sujeta mediante un cordón de 0.75 m de longitud, tenemos que:
a) El periodo de la pelota es 1.43 segundos.
b) La velocidad lineal de la pelota es 3.3 m/s.
a) El periodo de la pelota está dado por:
[tex] T = \frac{2\pi}{\omega} [/tex]
En donde:
ω: es la velocidad angular
Dado que la pelota da 0.7 vueltas (revoluciones) cada segundo, la velocidad angular es:
[tex] \omega = \frac{0.7 \:rev}{s}*\frac{2\pi rad}{1 \:rev} = 4.40 rad/s [/tex]
Entonces, el periodo es:
[tex]T = \frac{2\pi}{\omega} = \frac{2\pi}{4.40 rad/s} = 1.43 s[/tex]
b) La velocidad lineal de la pelota se puede calcular usando la siguiente ecuación:
[tex] v = \omega r [/tex]
En donde:
r: es el radio de la circunferencia = longitud del cordón = 0.75 m
[tex]v = \omega r =4.40 rad/s*0.75 m = 3.3 m/s[/tex]
Por lo tanto, la velocidad lineal de la pelota es 3.3 m/s.
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HELP PLZZZZZZ AHHHHH
Answer: I think it's larger
Explanation: man im just trying to help you
negatively charged particles of radiation emitted from the decay of radioactive substances are known as
Answer: beta particles
Explanation:
that's the answer
one end of a light inextensible string is attached to a tool box of mass 2.5 kg which is lying on a horizontal table. The string passing over a smooth pulley and is tied at the other end to a bag of mass 1.4kg as shown in the diagram
a. If the toolbox on the point of sliding, find the value for μ, the coefficient of friction.
b. Supposing the coefficient of friction between the tool boxe and the table is 0.20, calculate the acceleration of the system and the tension in the string gravity as 10 m per second square
Answer:
the answer is A
Explanation:
I=24
Q=400C
t=102
Help please
[tex] \huge \bf༆ Answer ༄[/tex]
The given terms in the question are : -
I = Electric current = 2 AmperesQ = Charge = 400 CoulombsWe have been given the task to find out time (t)
The formula that can be used to find time is : -
[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]
Rearrange the formula,
[tex] \sf \: t = \dfrac { Q}{I }[/tex]
Solve for time (t)
[tex] \sf t = \dfrac{400}{2} [/tex][tex] \sf t = 200 \: \: sec[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
As the temperature of an air mass increases, its atmospheric pressure______. Group of answer choices
Answer:
its atmospheric pressure decreases
When the temperature of an air mass increases, its atmospheric pressure drops
ok done. Thank to me :>
An 8kg mass is placed on a 30 degrees frictionless inclines plane and is attached to a pulley to a hanging mass of 5kg
Calculate which direction will the system flow
B)what is the acceleration
C)the tension in the rope
Hi there!
We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.
(A)
The system will flow in the direction of the hanging block's movement downwards.
(B)
Summation of forces of block on incline:
∑F = -M₁gsinФ + T
Summation of forces of hanging block:
∑F = M₂g - T
Sum both summations:
∑F = -M₁gsinФ + T + M₂g - T
∑F = M₂g -M₁gsinФ
According to Newton's Second Law:
∑F = ma
Thus:
(M₁ + M₂)a = M₂g -M₁gsinФ
[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]
Plug in the values:
[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]
(C)
Calculate the rope's tension using one of the above equations:
∑F₂ = M₂g - T
Rearrange for T:
T = M₂g - m₂a
Plug in values:
T = 5(9.8) - 5(0.754) = 45.23 N
What is the potential energy of a 50kg car on top of a 600m hill?
Answer:
294,000 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 50 × 9.8 × 600 = 294,000
We have the final answer as
294,000 JHope this helps you
More potential energy can be stored by moving against the magnetic force closer to a magnet?
Answer:
if your saying can it? then yes or if you are asking what type of magnetic force then its fr its actual self magnetic force
Explanation:
1 point
What is the potential energy of a bird flying, if the bird has 1000 J of total
energy and 450 J of kinetic energy? (only put the number, no units or
commas)
Answer:
the bird has 550J of potential energy
Explanation:
PEtotal=PE+KE
1000J=PE+450J
subtracting the kinetic energy from the total we get:
1000J-450J=PE
550J=PE
How can speed be defined
A) acceleration
B) change in velocity/time
C) distance / time
D) displacement/time
Answer:
Speed can be defined in (C) distance / time.
I hope this helped at all.
please help me please help
Answer:
Answer → Distance is 5 × 10⁴ km
Explanation:
Gravitational formular
[tex]{ \tt{F = \frac{GMm}{ {r}^{2} } }} \\ [/tex]
F is the gravitational forceG is the universal gravitational constantr is the separation distanceM & m are the massesFor the first case;
[tex]{ \tt{F _{1} = \frac{GMm}{2.5 \times {10}^{4} } }} \\ [/tex]
For the second case;
[tex]{ \tt{F _{2} = \frac{GMm}{r _{2}} }} \\ [/tex]
but F2 = ½F1
Therefore, F1 = 2F2
Hence:
[tex]{ \tt{ \frac{GMm}{2.5 \times {10}^{4} } =2 \times \frac{GMm}{r _{2} } }} \\ \\ { \tt{ \frac{1}{2.5 \times {10}^{4} } = \frac{2}{r _{2} } }} \\ \\ { \tt{r _{2} = 2 \times 2.5 \times {10}^{4} }} \\ \\ { \underline{ \tt{ \: \: r _{2} = 5 \times {10}^{4} \: km \: \: }}}[/tex]
Answer: Distance is 5 × 10⁴ km
Explanation:
As the distance between two objects changes, how does the gravitational force between them change?
Answer:
Explanation:
The gravitational force = G * m1 * m2 / r^2
That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.
cecily is inflating her bicyble tyre with the pump below. when she pushes the plunger down, it is moving against a force appliefd by the air inside the cynlinder. this means that the plunger is doing ___
Answer:
"work against the force of the air in the tire"
The air in the tire provides a force opposing the force of the air provided by the plunger.
a helicopter cruises at a constant velocity when the total thrust of the engines is 5,000 N. How much air resistance acts on the jet ??
Hi there!
[tex]\large\boxed{F_{A} = -5000N}}[/tex]
For an object to be moving at constant velocity:
∑F = 0 (The sum of the forces acting on the object MUST be 0 N)
We can do a summation of forces for this helicopter in the HORIZONTAL direction:
∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0
Thus, if we substitute in the given value for Ft:
Ft = -Fa
5000N = -Fa
Fa = -5000N
A crankshaft of an engine increases its spin from 1,000 rpm to 1,500 rpm in 0.5 s. What is its angular acceleration? (1 rev=2π rad)
600 rad/s2
100 rad/s2
500 rad/s2
60 rad/s2
the answer is 100 rad/s2
Two cars A and B are moving along a straight road in the OPPOSITE direction with velocities of 25 km/h and 40 km/h, respectively. Find the velocity of car B relative to car
Answer:
65km/h
Explanation:
Here,
Relative velocity of car moving in different directions with different velocities =Va + Vb
=25+40
=65 km/h
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Find the number of moles in a 28.0g sample of NH3.
PLS URGENTLY
Answer:
Molar mass of NH3=14+3=17g
[tex]mole = \frac{given \: mass}{molar \: mass} \\ mole = \frac{28}{17} \\ mole = 1.65[/tex]
BRAINLIST
If a statue is made out of wood, which of these words correctly describes the statue?
OA.
wooded
ОВ.
woody
OC.
non-wood
OD.
wooden
Answer:
Od- Wooden
Explanation:
It would not make sense if it was non-wood because that make it no a wood base product, OC is not right because its not a a plant that produces wood as its structural tissue and thus has a hard stem. An OA justT o take or get a supply of wood. so its Od
A rock climber’s shoe loosens a rock, and her climbing buddy at the bottom of the cliff notices that the rock takes 3.20 s to fall to the ground. How high up the cliff is the rock climber?
Answer:
50.176 [m].
Explanation:
1) the required height can be calculated using the formula:
h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;
2) if V₀=0, t=3.2, g=9.8, then
h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].
on average, astronauts grow ________ percent in space.
Answer:
3
Explanation:
Astronauts in space can grow up to 3 percent taller during the time spent living in microgravity, NASA scientists say. That means that a 6-foot-tall (1.8 meters) person could gain as many as 2 inches (5 centimeters) while in orbit.
A small ball is attached to one end of a spring that has an unstrained length of 0.201 m. The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of 3.41 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0176 m.
Required:
By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?
The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
The given parameters;
unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/sThe radius of the circular path when spring is stretched is calculated as;
R = l₁ + x
R = 0.201 + 0.0176
R = 0.2186 m
The spring constant is calculated as follows;
[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]
The extension of the spring when the ball is allowed to hang straight down, motionless;
[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]
Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.
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a soccer ball is kicked at an angle of 35° and it lands on even ground.
A) What angle will produce the same range?
B) Which angle of the two will produce the highest ball?
C) Which angle of the two will produce the ball that is in the air the longest?
D) What angle in this situation would produce the furthest range?
Hi there!
A)
The angle that will produce the same range is the compliment of 35°.
Thus, kicking the ball at 55° will result in the same range.
We can prove this by using the derived range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
An angle of 35° yields:
[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]
An angle of 55° yields:
[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]
Both are the same, thus indicating that 55° produces the same range.
B)
The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.
sin(55) > sin(35)
C)
The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.
We can prove this using:
vf = vi + at
0 = vy - 9.8t
vy/9.8 = t
Greater vy (vertical component of velocity) ⇒ greater time taken.
D)
The angle that would result in the furthest range is 45°.
We can prove this using calculus. Recall the above range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
We can take the derivative and use the first-derivative test to find its critical point:
[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]
Evaluate:
[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]
A. The angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.
For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.
In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.
The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.
Therefore, the angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
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Which object has the most thermal energy?
A. A 6 kg rock at 10°C
B. A 10 kg rock at 10°C
C. A6 kg rock at 15°C
D. A 10 kg rock at 15°C
Answer:
D is the answer
Explanation:
D is the most highest one so
the answer is D
Answer:
10 kg rock at 15 degrees celcius
a force that is at rest or moves in at a constant speed and in a constant direction is called a what force
The question is fishing for "balanced force".
But the description in the question is terrible.
name the substance that combines with water in photosynthesis
Answer:
carbon dioxide
Explanation:
its common sense
When there is a temperature inversion, you would expect to experience Group of answer choices clouds with extensive vertical development above an inversion aloft. good visibility in the lower levels of the atmosphere and poor visibility above an inversion aloft. an increase in temperature as altitude increases.
Temperature inversion leads to an increase in temperature as altitude increases.
The term temperature inversion refers to a situation in which a layer of warm air lies over a layer of cool air. This is also referred to as thermal inversion. This occurs when the air below to loose heat rapidly.
One of the effects of temperature inversion is reduction in visibility. So, thermal inversion leads to an increase in temperature as altitude increases.
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ignore this i put the wrong grade sorry
Answer:
Oh its fine i am not in college but its still fine
Explanation:
Describe the forces that make a bicycle move.
Answer:
this is an example of Newton's Second Law, acceleration happens when a force acts on a mass.
the force that makes the bicycle move is your foot pushing against the pedal
A swimming pool has dimension of 30m×10m×3m. When it is filled with water , what is the thrust on the bottom and sides
Answer:
3,900m³
Explanation: