Answer:
The correct solution is:
(a) [tex]1.375\times 10^{-2} \ J[/tex]
(b) [tex]4.43\times 10^{-3} \ C[/tex]
(c) [tex]1.42\times 10^{-3} \ F[/tex]
(d) [tex]178.57 \ \Omega[/tex]
Explanation:
The given values are:
Effective duration of the flash,
ζ = 0.25 s
Average power,
[tex]P_{avg}=55 \ mW[/tex]
[tex]=55\times 10^{-3} \ W[/tex]
Average voltage,
[tex]V_{avg}=3.1 \ V[/tex]
Now,
(a)
⇒ [tex]E=P_{avg}\times \zeta[/tex]
On substituting the values, we get
⇒ [tex]=55\times 10^{-3}\times 0.25[/tex]
⇒ [tex]=1.375\times 10^{-2} \ J[/tex]
(b)
⇒ [tex]E=Q\times V_{avg}[/tex]
then,
⇒ [tex]Q=\frac{E}{V_{avg}}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{1.375\times 10^{-2}}{3.1}[/tex]
⇒ [tex]=4.43\times 10^{-3} \ C[/tex]
(c)
⇒ [tex]C=\frac{Q}{V}[/tex]
⇒ [tex]=\frac{4.43\times 10^{-3}}{3.1}[/tex]
⇒ [tex]=1.42\times 10^{-3} \ F[/tex]
(d)
As we know,
⇒ [tex]R=\frac{1}{4C}[/tex]
⇒ [tex]=\frac{1}{4\times 1.42\times 10^{-3}}[/tex]
⇒ [tex]=\frac{1000}{5.6}[/tex]
⇒ [tex]=178.57 \ \Omega[/tex]
Calculate the average maximum height for all three trials when the mass of the bottle is 0.125 kg, 0.250 kg,
0.375 kg, and 0.500 kg.
Record your calculations in Table A of your Student Guide.
When the mass of the bottle is 0.125 kg, the average maximum height of the beanbag is
m.
When the mass of the bottle is 0.250 kg, the average maximum height of the beanbag is
m.
When the mass of the bottle is 0.375 kg, the average maximum height of the beanbag is
m.
When the mass of the bottle is 0.500 kg, the average maximum height of the beanbag is
m.
Answer:
10
Explanation:
i dont know this is right answer
0.35
0.91
1.26
1.57
Explanation:
I did it on ed2020 and got it correct
HELP ITS DUE IN 4 MINUTES
Answer:
the nephew
Explanation:
because we need to First find the trails that is on top of all the others in order to find who was the last to leave, since the person that was last to leave would most likely step on another person's trail that has been theirs before them.
by looking at this picture I noticed that the butler's footprint was the latest one but the dogs footprint steps over it therefore making it the last to leave, and the person who owns a dog is her nephew so therefore the nephew is the one that stole the butterfly trophy.
A concept is the general idea of objects, events, animals, or people based on common features, traits, or characteristics.
Please select the best answer from the choices provided
ОТ
OF
Answer:
True.
Explanation:
Science can be defined as a branch of intellectual and practical study which systematically observe a body of fact in relation to the structure and behavior of non-living and living organisms (animals, plants and humans) in the natural world through experiments.
A concept is the general idea of objects, events, animals, or people based on common features, traits, or characteristics. It is typically considered to be an abstract idea or general notion that is formed by the mental combination of all the characteristics pertaining to the idea.
Generally, concepts are used in the problem-solving process as it serves as a benchmark or yardstick for the solutions. Some examples of concepts in physics are conservation of energy and momentum, electromagnetic waves, heat, motion and forces, electricity and magnetism, gravity, etc.
Answer:
TRUE
Explanation:
edge
What is the difference between the isotopes Hydrogen-2 and Hydrogen-3?
Answer:
They each have one single proton (Z = 1), but differ in the number of their neutrons. Hydrogen has no neutron, deuterium has one, and tritium has two neutrons. The isotopes of hydrogen have, respectively, mass numbers of one, two, and three.
Explanation:
A 4.0 kg circular disk slides in the x- direction on a frictionless horizontal surface with a speed of 5.0 m/s as shown in the adjacent Figure. It collides with an identical disk that is at rest before the collision. The collision is elastic. Disk 1 goes off at an 60 5.0 m/s angle of 60 with respect to the x-direction. Disk 2 g 30 goes off at an angle of 30 with respect to the x-direction. What best describes the speeds of the disks after the collision?
Solution :
Let [tex]$m_1=m_2=4$[/tex] kg
[tex]$u_1 = 5$[/tex] m/s
Let [tex]$v_1$[/tex] and [tex]$v_2$[/tex] are the speeds of the disk [tex]$m_1$[/tex] and [tex]$m_2$[/tex] after the collision.
So applying conservation of momentum in the y-direction,
[tex]$0=m_1 .v_1_y -m_2 .v_2_y $[/tex]
[tex]$v_1_y = v_2_y$[/tex]
[tex]$v_1 . \sin 60=v_2. \sin 30$[/tex]
[tex]$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$[/tex]
[tex]$v_2=1.732 \times v_1$[/tex]
Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.
Now applying conservation of momentum in the x-direction,
[tex]$m_1.u_1=m_1.v_1_x+m_2.v_2_x$[/tex]
[tex]$u_1=v_1_x+v_2_x$[/tex]
[tex]$5=v_1. \cos 60 + v_2 . \cos 30$[/tex]
[tex]$5=v_1. \cos 60 + 1.732 \times v_1 \cos 30$[/tex]
[tex]$v_1 = 2.50$[/tex] m/s
So, [tex]$v_2 = 1.732 \times 2.5$[/tex]
= 4.33 m/s
Therefore, speed of the disk 2 after collision is 4.33 m/s
When light passes through
an
object, it's called
A. transparent
B. absorption
C. refraction
D. reflection
Which of the following would fill in the table where "A" is?
Symbol
Element Name
Atomic Number Mass Number
#nº
#p
#e
Net Charge
Si
Silicon
A (#13)
27
B (#14 14 C (#15)
0
D (#16)
Potassium
18
39
19
18 E (#17)
A. 3
B. 13
C. 14
D. 28
Answer:
.lyrjhg.
Explanation:
qqlqfgtjnfh
While being thrown, a net force of 132 N acts on a baseball (mass = 140g) for a period of 4.5 x 10^-2 sec. what is the magnitude of the change in momentum of the ball?
Answer:
5.94 N·s
Explanation:
F = 132 N
t = 0.045 s
Impulse = Ft = (132 N)(0.045 s) = 5.94 N·s
What flows in electricity?
A. Electrons
B. Protons
C. Neutrons
Answer:
A.
Explanation:
Electrons
An airplane in level flight is acted on by four basic forces. Drag is air resistance, lift is the upward force provided by the wings, thrust is the force provided
by the airplane's engines, and weight is the downward force of gravity acting on the airplane.
Lift
Thrust
Drag
Weight
In level flight at constant speed, which pair of forces must be equal?
HELP ITS DUE IN 4 MINUTES
Answer:
The nephew
Explanation:
The nephew has a seeing eye dog which means the nephews tracks are the dogs tracks, and the dog tracks are not covered by anything which means the dog was last and stole the butterfly.
Hope this helps!
Which of the following best
describes amplitude?
A. Amplitude is how fast a wave travels.
B. Amplitude is how far a wave moves from its resting
position
C. Amplitude is the resting position of a wave.
Answer:
its b
Explanation:
Amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.
how solar system believed to have been formed?
Explanation:
Our solar system formed about 4.5 billion years ago from a dense cloud of interstellar gas and dust. The cloud collapsed, possibly due to the shockwave of a nearby exploding star, called a supernova. When this dust cloud collapsed, it formed a solar nebula—a spinning, swirling disk of material.
the equation P^xV^yT^z= constant is Boyle law for what is the values of x,y,z
Answer:
x = 1, y = 1 and z = 0
Explanation:
Given equation;
[tex]P^x V^y T^z = constant[/tex]
Boyle's law states that at constant temperature, the volume of a fixed mass of gas is inversely proportional to its pressure.
Mathematically the law is written as;
[tex]PV = constant[/tex]
From the given equation, the values of x, y and z that will match this law is calculated as follows;
[tex]P^1 V^1 T^0 = constant\\\\P^1 = P\\\\V^1 = V\\\\T^0 = 1\\\\P \times V \times 1 = PV = constant\\\\Thus, x = 1, \ y = 1 \ \ and \ z = 0[/tex]
how can you Make different objects using blocks
A marshmallow is fired from ground level with an initial speed of 41.5 m/s at an
angle of 33.5° above the horizontal. (a) Determine the maximum height reached
by the marshmallow. (b) Determine the horizontal range that the marshmallow
travels during its flight.
Which statement explains how a chemical reaction depends on collisions
between molecules?
A. The reactants must collide in a certain way for the reaction to
occur.
B. The reaction will occur if the reactants collide in anyway.
C. The reaction will occur if the product collide in anyway.
D. The product must collide in a certain way for the reaction to occur
Answer: A. The reactants must collide in a certain way for the reaction to occur.
Explanation: I did the quiz :)
Answer:
A) The reactants must collide in a certain way for the reaction to
occur.
Explanation:
A.P.E.X
If you stand at a certain position and count the number of crests that pass by you over a certain amount of time, what are you most likely measuring? Period Speed Wavelength Frequency
Answer:
Wavelength
Explanation:
A vibration can cause a disturbance to travel through a medium, transporting energy without transporting matter. This is what a wave is.
elophase II is the final and the fourth stage in meiosis II when the chromosomes reach the opposite poles of the
Answer: The correct answer is formation of four haploid nuclei.
The event occurring during telophase II includes formation of four haploid daughter cells. Telophase II is the final and the fourth stage in meiosis II when the chromosomes reach the opposite poles of the nuclear spindle. During this stage both the daughter cells get divided forming four haploid cells. The development of the nuclear envelope around each set of the chromosome and cytokinesis also takes place during telophase II.
Explanation:
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The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 75-kg (165-lb) person of height 1.83 m (6 ft) has a body surface area of approximately 2.0 m2. (a) What is the net amount of heat this person could radiate per second into a room at 18°C (about 65°F) if his skin’s surface temperature is 30°C? (At such temperatures, nearly all the heat is infrared radiation, for which the body’s emissivity is 1.0, regardless of the amount of pigment.) (b) Normally, 80% of the energy produced by metabolism goes into heat, while the rest goes into things like pumping blood and repairing cells. Also normally, a person at rest can get rid of this excess heat just through radiation. Use your answer to part (a) to find this person’s basal metabolic rate.
Answer:
(a) Q = 142.67 W
(b) Basal Metabolic Rate = 178.33 W
Explanation:
(a)
We can find the heat radiated by the person by using Stefan-Boltzman's law:
[tex]Q = \sigma A (T^4 - T_{s}^4)\\[/tex]
where,
Q = heat radiated per second = ?
σ = Stefan-Boltzman Constant = 5.6703 x 10⁻⁸ W/m².k⁴
A = Surface Area = 2 m²
T = Temperature of Skin = 30° C + 273 = 303 k
Ts = Temperature of room = 18° C +273 = 291 k
Therefore,
[tex]Q = (5.6703\ x\ 10^{-8}\ W/m^2.k^4)(2\ m^2)[(303\ k)^4-(291\ k)^4][/tex]
Q = 142.67 W
(b)
Since the heat calculated in part (a) is 80 percent of basal metabolic rate. Therefore,
[tex]Q = (0.8)(Basal\ Metabolic\ Rate)\\Basal\ Metabolic\ Rate = \frac{Q}{0.8}\\\\Basal\ Metabolic\ Rate = \frac{142.67\ W}{0.8}[/tex]
Basal Metabolic Rate = 178.33 W
(a) The excess heat just through radiation Q = 142.67 W
(b) Basal Metabolic Rate = 178.33 W
What is metabolic rate?Basal metabolic rate is the number of calories your body needs to accomplish its most basic (basal) life-sustaining functions.
(a) We can find the heat radiated by the person by using Stefan-Boltzman's law:
[tex]Q=\sigma A(T^4-T_s^4)[/tex]
where,
Q = heat radiated per second = ?
σ = Stefan-Boltzman Constant = 5.6703 x 10⁻⁸ W/m².k⁴
A = Surface Area = 2 m²
T = Temperature of Skin = 30° C + 273 = 303 k
Ts = Temperature of room = 18° C +273 = 291 k
Therefore,
[tex]Q=(5.6703\times 10^{-8}\times (2)\times[(303)-(291)][/tex]
Q = 142.67 W
(b) Since the heat calculated in part (a) is 80 percent of basal metabolic rate. Therefore,
[tex]\rm Q=0.8\times (Basal\ Metabolic\ Rate)[/tex]
[tex]\rm Basal\ metabolic \ Rate = \dfrac{Q}{0.8}[/tex]
[tex]\rm Basal\ Metabolic\ Rate = \dfrac{142.67}{0.8} =178.330W[/tex]
Basal Metabolic Rate = 178.33 W
Hence the excess heat just through radiation Q = 142.67 and Basal Metabolic Rate = 178.33 W
To know more about Basal metabolic rate Follow
https://brainly.com/question/14095049
What happens during
convection?
A. Heat is transferred from warmer
objects to cooler objects by direct contact.
B. Heat is transferred from warmer
objects to cooler objects by moving fluids.
C. Heat is transferred from warmer
objects to cooler objects through empty
space.
Answer:
B
Explanation:
A force of 880 newtons stretches a spring 4 meters. A mass of 55 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 8 m/s. Find the equation of motion. x(t)
Answer:
x(t) = -8sin2t
Explanation:
See the attachment for solution
From my solving, we can deduce that w² = 4, and thus, w = 2
Therefore, the general solution is
x(t) = c1 cos2t + c2 sin2t
Considering the final variable, we can conclude that
x(0) = 0
x'(0) = -8 m/s
The final solution, thus
x(t) = -8sin2t
PLEASE HELP ASAPPPPP
Answer:
link
Explanation:
ww.comhwhelp
Why does the principal of lateral continuity work?
Answer:
Explanation:
Gdvxhvdygshxvgxgvvvvgehcbjdhvshchbeukshcvgdferfacsxzdwlf!?ñpdjabdjcbdjshfhfgdsfadqewstgdvdhsvchsxh
The principle of lateral continuity works, because they are continuous. Rocks that are alike but were separated by an erosional feature, can be originally continuous.
1. Describe the components of the reflex arc
Which letter represents the
Pacific Plate?
Answer:
C
Explanation:
You measure the pressure of the four tires of your car each to be 35.0 pounds per square inch (psi). You then roll your car forward so that each tire is upon a sheet of paper. You outline the surface area of contact between each tire and the paper, which you later measure to be 32.0 square inches. What is the weight of your car
Answer:
Weight of car = 36034.88 lb.ft/s²
Explanation:
We are told the pressure of the four tires of your car is; P = 35.0 psi
Also, the surface area of contact is; A = 32 in²
Thus;
Weight of tires = Pressure × Area
W_tires = 35 × 32
Weight_tires = 1120lb.
To get the weight of the car, we will multiply the tire weight by acceleration due to gravity.
It's value in ft/s² is g = 32.174 ft/s²
Thus;
Weight of car = 1120 × 32.174
Weight of car = 36034.88 lb.ft/s²
5. Widely spaced isobars indicate
high winds
winds oriented north to south
light winds
variable winds
Answer:
Light Winds
Explanation:
our battery has died and your friends push your vehicle so you can kick-start the engine. You and the vehicle have a combined mass of 1600 kg. If your friends do 6000 J of work and one-third of that is dissipated by friction, how fast is your vehicle traveling?
Answer:2.23 m/s
Explanation:
Given
Mass of person and vehicle is [tex]m=1600\ kg[/tex]
Total work done is [tex]W_t=6000\ J[/tex]
Friction consumes one-third of the energy
The remaining two-third is consumed to increase the kinetic energy
[tex]\Rightarrow \dfrac{2}{3}\times 6000=\dfrac{1}{2}\times 1600\times v^2\\\\\Rightarrow 4000\times 2=1600\times v^2\\\\\Rightarrow v=\sqrt{5}\ \approx 2.23\ m/s[/tex]
Consider two insulating balls with evenly distributed equal and opposite charges on their surfaces, held with a certain distance between the centers of the balls. Construct a problem in which you calculate the electric field (magnitude and direction) due to the balls at various points along a line running through the centers of the balls and extending to infinity on either side. Choose interesting points and comment on the meaning of the field at those points. For example, at what points might the field be just that due to one ball and where does the field become negligibly small? Among the
things to be considered are the magnitudes of the charges and the distance between the centers of the balls. Your instructor may wish for you to consider the electric field off axis or for a more complex array of charges, such as those in a water molecule.
Answer:
interest point:
1) Point on the left side
2) Point within the radius r₁ of the first sphere
3) Point between the two spheres
4) point within the radius r₂ of the second sphere
5) Right side point
Explanation:
In this case, the total electric field is the vector sum of the electric fields of each sphere, to simplify the calculation on the line that joins the two spheres
We will call the sphere on the left 1 and it has a positive charge Q with radius r1, the sphere on the right is called 2 with charge -Q with radius r2. The total field is
E_ {total} = E₁ + E₂
E_{ total} = [tex]k \frac{Q}{x_1^2} + k \frac{Q}{x_2^2}[/tex]
the bold indicate vectors, where x₁ and x₂ are the distances from the center of each sphere. If the distance that separates the two spheres is d
x₂ = x₁ -d
E total = [tex]k \frac{Q}{x_1^2} - k \frac{Q}{(x_1 - d)^2}[/tex]
Let's analyze the field for various points of interest.
1) Point on the left side
in this case
E_ {total} = [tex]k Q \ ( \frac{1}{x_1^2} - \frac{1}{(x_1 +d)2} )[/tex]
E_ {total} = [tex]k \frac{Q}{x_1^2}[/tex] [tex]( 1 - \frac{1}{(1 + \frac{d}{x_1} )^2 } )[/tex]
We have several interesting possibilities:
* We can see that as the point is further away the field is more similar to the field created by two point charges
* there is a point where the field is zero
E_ {total} = 0
x₁² = (x₁ + d)²
2) Point within the radius r₁ of the first sphere.
In this case, according to Gauus' law, the charge is on the surface of the sphere at the point, there is no charge inside so this sphere has no electric field on its inner point
E_ {total} = [tex]-k \frac{Q}{x_2^2} = -k \frac{Q}{((d-x_1)^2}[/tex]
this expression holds for the points located at
-r₁ <x₁ <r₁
3) Point between the two spheres
E_ {total} = [tex]k \frac{Q}{x_1^2} + k \frac{Q}{(d+x_1)^2}[/tex]
This champ is always different from zero
4) point within the radius r₂ of the second sphere, as there is no charge inside, only the first sphere contributes
E_ {total} = [tex]+ k \frac{Q}{(d-x_1)^2}[/tex]+ k Q / (d-x1) 2
point range
-r₂ <x₂ <r₂
5) Right side point
E_ {total} = [tex]k \frac{Q}{(x_2-d)^2} - k \frac{Q}{x_2^2}[/tex]
E_ {total} = [tex]- k \frac{Q}{x_2^2} ( 1- \frac{1}{(1- \frac{d}{x_2})^2 } )[/tex]- k Q / x22 (1- 1 / (x1 + d) 2)
we have two possibilities
* as the distance increases the field looks more like the field created by two point charges
* there is a point where the field is zero