A chemist mixes 100 milliliters of a solution that is 75% acid with 25 milliliters of a solution that is 35% acid.
Answer the questions below. Do not do any rounding.
(a) How many milliliters of acid are in the resulting mixture?
(b) What percentage of the resulting mixture is acid?

Answer:

the answer is the third one 3

Answer:

Hey there, first let's find the slope.

M=y2-y1/x2-x1.

M=7-3/2-1 which is 4/1.

So your slope is 4

So now we have y=4x+b.

Now we need our Y-intercept (B). which is -1

So your answer is Y=4x-1

Answer:

[tex] \sf k = 1 \\\\ \sf y = x [/tex]

Step-by-step explanation:

A graph between the amount of time that backpacker hikes to the distance travelled is given .

According to the Question ,

[tex]\sf \implies y \propto x \\\\\sf \implies y = kx [/tex]

[tex]\sf\implies 5 = k(5) \\\\\sf \implies k =\dfrac{5}{5}\\\\\sf \implies \boxed{\frak{\pink{ k = 1 }}}[/tex]

Again the constant of proportionality is the slope of the line.

[tex]\sf\implies y = mx + c \\\\\sf \implies y = 1(x) + 0 \\\\\sf \implies \boxed{\pink{\frak{ y = x }}}[/tex]

Answer:

x equals 375

Step-by-step explanation:

75+0.70x=0.90x

Answer:

m<b=107º

Step-by-step explanation:

180-41-32=107

D and B are congruent

Answer:

a)-30

b)-60

c)98

d)-54

Step-by-step explanation:

320/-4

-180/3

-14X-7

6X-9

Answer and explanation:

Temperature:

If it was -5°C, you know that it is very cold and below freezing point (0°C), but if it was 20°C you know the weather is quite warm.

0°C is freezing point and is used as a reference point to be able to tell if the temperature is warm or not.

Answer:

AA   as the angles are similar the sides are not similar so AA is the answer

Step-by-step explanation:

Answer:

continuous becasue the arrows point out meaning the go on forever

Step-by-step explanation:

Answer:

b = 2S/n - a.

Step-by-step explanation:

S=n/2(a + b)

a + b = S / n/2

a + b = 2S/n

b = 2S/n - a.

If the formula for determining the sum of the given arithmetic sequence is S = n/2(a + b), then 'b' can be expressed as b = [(2S/n) - a].

An arithmetic sequence is a sequence where the difference between any to consecutive terms are always equal.

Here, a and b are the first and the last terms respectively and n is the number of terms.

Therefore, the sum of the arithmetic sequence is:

S = n/2(a + b)

⇒ 2S/n = (a + b)

⇒ b = (2S/n) - a

Learn more about an arithmetic sequence here: https://brainly.com/question/25715593

#Tag #SPJ2

Answer:

-72

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]a^{-m}=\dfrac{1}{a^{m}}\\\\8^{-3}=\dfrac{1}{8^{3}}=\dfrac{1}{8*8*8}=\dfrac{1}{512}[/tex]

Answer:

x = 1, y = 1

x = -2, y = -8

x = 3, y = 7

Step-by-step explanation:

Answer:

180 out of 300

Step-by-step explanation:

Basically,

300÷120=2.5

Thereof,

72×2.5=180.

Hope this helps!

tag brainliest please...

Answer:

14/25=0.56

29/50=0.58

53/100=0.53

13/20=0.65

3/5=0.60

Answer:

2

Step-by-step explanation:

1) Subtract 44 from both sides of the equation

3x + 44 - 44 = 50 - 44

2) Simplify

a. Subtract the numbers

3x = 50 - 44

b. Subtract the numbers

3x = 6

3) Divide both sides of the equation by the same term

3x/3 = 6/3

4) Simplify

a. Cancel terms that are in both the numerator and denominator

x = 6/3

b. Divide the numbers

x = 2

Hello Carousel!

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex] \tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex]

First, let's take I as ⇨ [tex]\tt \:\int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x + 1}} \: dx \\ [/tex].

[tex]\tt \:I = \int \: \frac{ x + 2 }{( {x}^{2} + 3x + 3) \sqrt{x +1}} \: dx \\\tt \: I =\int \: \frac{ x + 2 }{( {x}^{2} + 2x + 1 + x + 2) \sqrt{x + 1}} \: dx \\ \tt \:I =\int \: \frac{ x + 2 }{( ({x + 1}^{2}) + x + 2) \sqrt{x + 1}}[/tex]

Let, x + 1 = m² => dx = 2mdm.

[tex]\tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: m} 2mdm \\ \tt \:I =\int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 \cdot \: \bcancel{ m}} 2 \bcancel{m}dm \\ \tt \: I = \: \int \: \frac{ {m}^{2} + 1}{ {m}^{4} + {m}^{2} + 1 } 2dm[/tex]

Now, divide the numerator & denominator by m²....we'll get it as...

[tex]\tt \:I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{ {m}^{2} + 1 + \frac{1}{ {m}^{2} } } \: dm \\\tt \: I =2\int \: \frac{ 1 + \frac{1}{ {m}^{2} } }{( {m}^{2} + \frac{1}{ {m}^{2} } - 2) + 3} \: dm \\\tt \: I =2\int \: \frac{ (1 + \frac{1}{ {m}^{2} }) \: dm }{ ({m} - \frac{1}{ m } ) ^{2} + 3} [/tex]

Now, let m - 1/m be t => (1 + 1/m²) dm = dt

[tex]\tt \:I =2\int \: \frac{ dt}{ {t}^{2} + 3 } \\ \tt \:I = 2\int \: \frac{ dt}{ {t}^{2} + ( \sqrt{3}) ^{2} }[/tex]

We know, [tex]\tt \:\int \: \frac{dx}{ {x}^{2} + a ^{2} } = \frac{1}{a} tan ^{ - 1} (\frac{x}{a} ) + c[/tex]...therefore...

[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{t}{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 1}[/tex]

Now, substitute the value of 't' in eq. 1..we'll get..

[tex]\tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{m - \frac{1}{m} }{ \sqrt{3} } ) + c \: \rightarrow \boxed{ \tt \: eq. \: 2}[/tex]

Now, substitute the value of 'm' in eq. 2...we'll get...

[tex] \tt \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{ \sqrt{x + 1} - \frac{1}{ \sqrt{x - 1} } }{ \sqrt{3} } ) + c \\ \tt \:I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x + 1 - 1}{ \sqrt{3} \sqrt{x - 1} } ) + c \\ \boxed{\boxed{ \bf \: I = \frac{2}{ \sqrt{3} } {tan}^{ - 1} ( \frac{x }{ \sqrt{3 (x - 1} )} ) + c }}[/tex]

__________________

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Hope it'll help you!

ℓu¢αzz ッ

Answer:

8.3

Step-by-step explanation:

Answer:

3x - 2 = 4

x = 2

Step-by-step explanation:

3x - 2 = 4 ---> plus 2 on both sides

3x = 6 --> divide by 3 on both sides

x = 2

the answer is -6.

the negative 7 turns the answer negative.

Answer:

Step-by-step explanation:

Take 2 points:

Find the slope:

Find the y- intercept:

The line is:

The sum of the measure of angle of a triangle = 180° .

Given two angles = 92° and 72°

92° + 72° = 164°

180° - 164° = 16° (Ans)

Answer:

the answer is  16!

Answer:

[tex]A = 48.815[/tex]

Step-by-step explanation:

[tex] \frac{a}{ \sin(A) } = \frac{b}{ \sin(B) } [/tex]

[tex] \frac{12.5}{ \sin(A) } = \frac{15.4}{ \sin(68) } [/tex]

[tex]12.5 \sin(68) = 15.4 \sin(A) [/tex]

[tex] \frac{12.5 \sin(68) }{15.4} = \frac{15.4 \sin(A) }{15.4} [/tex]

[tex] \sin(A) = \frac{12.5 \sin(68) }{15.4} [/tex]

[tex] A=\sin ^{ - 1} ( \frac{12.5 \sin(68) }{15.4} ) [/tex]

[tex]A = 48.815[/tex]

A) multiply the price of the game by 5%

42.99 x 0.05 = 2.1495 rounds to 2.15

Amount of tax = $2.15

B) add the amount of tax to the price of the game:

42.99 + 2.15 = 45.14

Total cost = $45.14

Answer:

8.) Rational

10.) Irrational

Step-by-step explanation:

8.) This is rational because although it is a decimal, it is terminating, meaning it has an end.

10.) This is irrational because it is a repeating decimal with seemingly no pattern.

Answer:

x = 14

Step-by-step explanation:

10x-30+5x = 180

Combine like terms

* 15x-30 = 180

Add 30 from both sides

* 15x 30+-30 = 180+30

Divide 15 both sides

* 15x/15x = 210/15x

x = 14

Hope this helps :)

Answer:

2.4 cm

Step-by-step explanation:

1.2/3 = 0.96/x

x = (3 *0.96) / 1.2

x = 2.4 cm

Answer:

Thus, width is 6 and length is 25.

Step-by-step explanation:

Let us assume the width is x, then, the length is (4x+1).

Therefore, 2x + 2(4x+1) = 62

Or, 2x + 8x + 2 =62

Or, 10x = 60

Or, x = 6

Answer:

27 units.

Step-by-step explanation:

The perimeter is equal to 2 x length + 2 x width.

If the width is 4 then:

62 = 2 x length + 2 x 4

62 = 2 x length + 8

Then, we can subtract 8 from both sides.

54 = 2 x length

Next, divide both sides by 2

27 = length

so,

The length is 27 units.

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

and

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

So, By using Long Division Method, we have

[tex]\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\: {x}^{2} - 3x + 2\:\:}}}\\ {\underline{\sf{x + 1}}}& {\sf{\: {x}^{3}  -  {2x}^{2} - x + 2 \:\:}} \\{\sf{}}& \underline{\sf{- {x}^{3} - {x}^{2} \: \: \:  \:  \:  \:  \:  \:  \:  \: \:\:}} \\ {{\sf{}}}& {\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - 3{x}^{2} - x +2  \:  \:  \:  \:   \:  \:  \:  \:\:}} \\{\sf{}}& \underline{\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  3{x}^{2} + 3x  \:  \:  \:  \:  \:  \: \:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 2x + 2 \:\:}} \\{\sf{}}& \underline{\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: - 2x - 2\:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 0\:\:}}  \end{array}\end{gathered}\end{gathered}\end{gathered}[/tex]

So,

[tex]\bf\implies \:Remainder = 0[/tex]

Verification

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

[tex] \purple{\rm :\longmapsto\:Remainder = 0}[/tex]

[tex] \purple{\rm :\longmapsto\:Quotient = {x}^{2} - 3x + 2}[/tex]

Now, Consider

[tex]\rm :\longmapsto\:Divisor \times Quotient + Remainder[/tex]

[tex]\rm \:  =  \: (x + 1)( {x}^{2} - 3x + 2) + 0[/tex]

[tex]\rm \:  =  \: {x}^{3} - {3x}^{2} + 2x + {x}^{2} - 3x + 2[/tex]

[tex]\rm \:  =  \: {x}^{3} - {2x}^{2} - x + 2[/tex]

[tex]\rm \:  =  \: Dividend[/tex]

Hence, Verified

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