A chemist adds 470.0 mL of a 8.8 times 10^-5 mM silver(II) oxide (AgO) solution to a reaction flask. Calculate the mass in micrograms of silver(II) oxide chemist has added to the flask. Round your answer to 2 significant digits.

Answers

Answer 1

Answer:

5.1 μg

Explanation:

Step 1: Given data

Volume of solution (V): 470.0 mL (0.4700 L)

Concentration of the solution (C): 8.8 × 10⁻⁵ mM (8.8 × 10⁻⁸ M)

Step 2: Calculate the moles (n) of AgO added

We will use the following expression.

n = C × V

n = 8.8 × 10⁻⁸ mol/L × 0.4700 L

n = 4.1 × 10⁻⁸ mol

Step 3: Calculate the mass (m) corresponding to 4.1 × 10⁻⁸ moles of AgO

The molar mass of AgO is 123.87 g/mol.

4.1 × 10⁻⁸ mol × 123.87 g/mol = 5.1 × 10⁻⁶ g

Step 4: Convert "m" to micrograms

We will use the conversion factor 1 g = 10⁶ μg.

5.1 × 10⁻⁶ g × 10⁶ μg/1 g = 5.1 μg


Related Questions

Identify the two ways that rocks are broken down into smaller pieces?
A
abrasion and erosion
B
deposition and erosion
C
physical weathering and deposition
D
physical weathering and chemical weathering


answer pleaseeeeeeeee i only have one minute

Answers

Answer:

A or C

Explanation:

Answer: It is D.

Explanation: Edge 2021

Which characteristic of a star will determine how it ends

Answers

in like a few years the star will explode

When you apply 1000 joules of energy to 50 grams of water its temperature changes to 30 degrees . What was the initial temperature in celsius?

Answers

Answer:

25.2°C

Explanation:

Given parameters:

Energy applied to the water  = 1000J

Mass of water  = 50g

Final temperature  = 30°C

Unknown:

Initial temperature  = ?

Solution:

To solve this problem, we use the expression below:

            H  = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

     1000  = 50 x 4.184 x (30  -  initial temperature )

     1000  = 209.2(30 - initial temperature)

      4.78  = 30 - initial temperature

      4.78  - 30  = - initial temperature

         Initial temperature  = 25.2°C

How many ATOMS of OXYGEN are there in the following compound

Answers

6 Atoms!
Mg = 1 atom.
O = 4 atoms.
A = 1 atom.

Calculate the temperature change when 2.00 L at 293 K is compressed to 1.00 L.

Answers

Answer:

[tex]\Delta T=-146.5K[/tex]

Explanation:

Hello!

In this case, given the Charles' law which allows us to understand the volume-temperature behavior as shown below:

[tex]\frac{T_1}{V_1}=\frac{T_2}{V_2}[/tex]

Thus, given that we need to calculate the final temperature after the compression, we obtain:

[tex]T_2=\frac{V_2T_1}{V_1}=\frac{1.00L*293K}{2.00L}\\\\T_2=146.5K[/tex]

Thus, the temperature change would be:

[tex]\Delta T=T_2-T_1=146.5K-293K\\\\\Delta T=-146.5K[/tex]

Best regards!


Which type of species distribution pattern might require collaboration between different countries for effective preservation?

Answers

Answer:

migratory distribution

Explanation: The pattern of migratory distribution of species may require collaboration between different countries for effective preservation. This is because species migration can make them enter different territories, which will need to provide an effective level of preservation for species survival

which of the following is a strong acid?
A, HCI (hydrochloric acid)
B, HF (hydrofluoric acid)
C, NaOH (sodium hydroxide)
D, NH3 (ammonia)

Answers

HCI is the strongest out of those.

The pressure exerted by the atmosphere at sea level is 14.7 Libs per square inch how many pounds of force are pressing on a rectangle with an area of 76.3cm^2

Answers

Pounds of force pressing on a rectangle : F = 173.86 lbs

Further explanation

Given

P at sea level = 14.7 lbs/in²

Area of rectangle : A = 76.3 cm²

Required

Pounds of force

Solution

P = F/A

F= P.A

Conversion :

1 cm² = 0.155 in²

76.3 cm² = 11.827 in²

Input the value :

F = 14.7 lbs/in² x 11.827 in²

F = 173.86 lbs

What did organizing information on the periodic table reveal?
A. Subatomic particles
B. New forms of energy
C. Molecular structures
D. Periodic patterns and trends

Answers

Answer:

The groupings of elements in the periodic table reveal various trends, present in groups such as the alkali metals and noble gases, or the lanthanides and actinides. The periodic table can be used to find information on elements or predict the properties of as-of-yet undiscovered elements.

Explanation:

Answer: D

Just took the quiz

Which best describes why NH4+ can form an ionic bond with Cl–?
Its outermost shell gains one or more electrons from Cl–.
Its positive charge is attracted to the negative charge of Cl–.
It has a negative charge that is spread over the entire ion.
It has a nitrogen atom that is strongly attracted to Cl–.

Answers

Answer:

Its positive charge is attracted to the negative charge of Cl–.

Explanation:

The best description of why NH₄⁺ forms an ionic bond with Cl⁻ is that its positive charge is attracted to the negative charge of Cl⁻.

An ionic bond forms as a result of transfer of electrons. As a result the seemingly metal ion is attracted to the negative non-metal ion.

The electrostatic force of attraction between these ions is the ionic or electrovalent bond.

So, the attraction between these opposite charges will form the ionic bond.

Answer:

B: Its positive charge is attracted to the negative charge of Cl–

Explanation:

right on edge2021

. Predict the possible products for the following reaction and include
molecular, complete ionic, and net ionic equations.

NA2SO4 (aq) +γ (BrO3)2 (aq) --->

Answers

Answer:

Introduction

As a diligent student of chemistry, you will likely encounter tons of reactions that occur in aqueous solution (perhaps you are already drowning in them!). When ions are involved in a reaction, the equation for the reaction can be written with various levels of detail. Depending on which part of the reaction you are interested in, you might write a molecular, complete ionic, or net ionic equation.

Definitions of molecular, complete ionic, and net ionic equations

A molecular equation is sometimes simply called a balanced equation. In a molecular equation, any ionic compounds or acids are represented as neutral compounds using their chemical formulas. The state of each substance is indicated in parentheses after the formula. [Huh?]

Let's consider the reaction that occurs between \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text. When aqueous solutions of \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text are mixed, solid \text{AgCl}AgClstart text, A, g, C, l, end text and aqueous \text{NaNO}_3NaNO

3

start text, N, a, N, O, end text, start subscript, 3, end subscript are formed. Using this information, we can write a balanced molecular equation for the reaction:

\text{AgNO}_3(aq) + \text{NaCl}(aq) \rightarrow \text{AgCl}(s) + \text{NaNO}_3(aq)AgNO

3

(aq)+NaCl(aq)→AgCl(s)+NaNO

3

(aq)start text, A, g, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis, plus, start text, N, a, C, l, end text, left parenthesis, a, q, right parenthesis, right arrow, start text, A, g, C, l, end text, left parenthesis, s, right parenthesis, plus, start text, N, a, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis

[What kind of reaction is this?]

If we could zoom in on the contents of the reaction beaker, though, we wouldn't find actual molecules of \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, or \text{NaNO}_3NaNO

3

start text, N, a, N, O, end text, start subscript, 3, end subscript. Since \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, and \text{NaNO}_3NaNO

3

start text, N, a, N, O, end text, start subscript, 3, end subscript are soluble ionic compounds, they dissociate into their constituent ions in water. For example, \text{NaCl}NaClstart text, N, a, C, l, end text dissociates into one ion of \text{Na}^+Na

+

start text, N, a, end text, start superscript, plus, end superscript for every ion of \text{Cl}^-Cl

start text, C, l, end text, start superscript, minus, end superscript; these ions are stabilized by ion-dipole interactions with the surrounding water molecules. [I don't get it!]

Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.

Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.

Sodium chloride dissociates into sodium and chloride ions in water, and these ions become solvated by the highly polar water molecules. Image credit: "Salts: Figure 1" by OpenStax Anatomy and Physiology, CC-BY-NC-SA 4.0.

From the molecular formula, we can rewrite the soluble ionic compounds as dissociated ions to get the complete ionic equation:

\text{Ag}^+(aq) + \blueD{{\text{NO}_3}^-(aq)} + \maroonD{\text{Na}^+(aq)} + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) + \maroonD{\text{Na}^+(aq)} + \blueD{{\text{NO}_3}^- (aq)}Ag

+

(aq)+NO

3

 

(aq)+Na

+

(aq)+Cl

(aq)→AgCl(s)+Na

+

(aq)+NO

3

 

 

(aq)

+

Na

+

(aq)

+Cl

(aq)→AgCl(s)+

Na

+

(aq)

+

NO

3

 

(aq)

100POINTS! ANSWER ALL 3 PARTS (look at the picture)

Answers

Answer:

Part 1-B

Part 2-D

Part 3-A

Answer:

1.B

2.D

3.A

Explanation:

.......................

Simplify (4f+13g)(2w)

Answers

Answer:

8fw+26gw

i think this is it

Your answer would be 8fw + 46gw !!

Please mark BRAINLEST

A solid substance formed from a solution is a(n)

a. reactant
b. equation
C. compound
d. precipitate

Answers

Question:

A solid substance formed from a solution is a(n).

Answer:

D. Precipitate

#CARRYONLEARNING #STUDYWELL
Question:

A solid substance formed from a solution is a(n)

Choosing:

a. reactant

b. equation

C. compound

d. precipitate

Answer:

D. Precipitate

#READINGHELPSWITHLEARNING #CARRYONLEARNING #STUDYWELL

A mixture is made by combining 1.29 lb of salt and 5.35 lb of water.
What is the percentage of salt (by mass) in this mixture?

Answers

Answer:

19.47%

Explanation:

[tex]\frac{1.29}{1.29+5.35}[/tex]

Please recheck, for this answer may not be correct

Which of these features was most likely formed by a divergent boundary?
A.Himalayan Mountains
B. San Andreas Fault
C.Mt. St. Helens
D.Great Rift Valley

Answers

Answer:

I think the answer is Himalayan Mountain

Explanation:

I'm not sure but I think so

Answer:

Today, the term is most often used to refer to the valley of the East African Rift, the divergent plate boundary which extends from the Afar Triple Junction southward across eastern Africa, and is in the process of splitting the African Plate into two new separate plates.

Explanation:

So it is D

what type of reaction is AsCl+H2S --> As2S3+HCl

Answers

Answer:

Double replacement:

Explanation:

Chemical equation:

2AsCl  +  3H₂S     →       As₂S₃ + 6HCl

The given reaction is double displacement reaction. In this reaction arsenic trichloride and hydrogen sulfide react and produced arsenic sulfide and hydrogen chloride. In double displacement reaction both anion an cation of reactants are exchanged with each other.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

General equation:

AB + CD → AD +CB

Elemental phosphorus reacts with chlorine gas according to the equation
P4(s)+6Cl2(g)→4PCl3(l)
A reaction mixture initially contains 45.57 g P4 and 130.2 g Cl2.

Once the reaction has reached completion, what mass (in g) of the excess reactant is left?
(Express the mass in grams to three significant figures.)

Answers

Mass (in g) of the excess reactant (P₄) left = 7.626 g

Further explanation

Given

Reaction

P4(s)+6Cl2(g)→4PCl3(l)

45.57 g P4 and 130.2 g Cl2

Required

mass (in g) of the excess reactant left

Solution

mol P₄ (MW=124 g/mol) :

45.57 : 124 = 0.3675

mol Cl₂(MW=71 g/mol) :

130.2 : 71 = 1.834

mol : coefficient of reactant : P₄ : Cl₂ :

= 0.3675/1 : 1.834/6

= 0.3675 : 0.306

Cl₂ as limiting reactant(smaller ratio)

Reacted mol of P₄ (as an excess reactant):

=1/6 x 1.834

= 0.306

Unreacted mol of P₄ :

= 0.3675 - 0.306

= 0.0615

Mass of P₄(left) :

= 0.0615 x 124

= 7.626 g

How many electrons must nitrogen gain to become like it’s closest noble gas, Neon?

Answers

Answer:

3

Explanation:

275L/sec to mL/hour with work

Answers

275 L/sec x (1000 ml/1L)x (1 hour)/60 sec = final answer

What are important things we can figure out by looking at a food web?

Answers

Answer:

We can find out what animals eat..and how long a food chain could get..?

Explanation:

Energy transfer between organisms

What is the empirical formula of C9H18

Answers

Answer:

CH2

Explanation:

there is a common factor for 9;18 which is 9 so u divide both numbers by it 9/9 and 18/9 giving 1:2 so 1 C to every 2 H so CH2

The empirical formula of C9H18 will be CH2.

What is the empirical formula?

The empirical formula of a compound shows the ratio of atoms present in a compound. The molecular formula of the compound shows the total number of atoms present in a compound.

Here, C9H18 if we divide the number of total atoms by 9, C9/ 9, and H18/ 9. the ratio will be in the form of 1: 2. therefore, the empirical formula will be CH2.

C9H18 is the molecular formula of the compound, while CH2 is the empirical formula of the compound. The molecular formula of butane is C4H16, then its empirical formula is CH4.  The molecular formula of compound is P4H10 then its empirical formula is P2H5.

Therefore, The empirical formula of C9H18 will be CH2.

To learn more about empirical formulas refer to the link:

https://brainly.com/question/14044066

#SPJ2

What is creating our Earth's Magnetic field?
1) Our Earth's iron liquid outer core rotating around the solid inner core
2) Our Earth having a stationary inner core
3) Our Earth having rocky center
4) All of the above

Answers

Answer:

1) Our Earth's iron liquid outer core rotating around the solid inner core

Explanation:

The earth's magnetic field or the geomagnetic field is produced as a result of the earth's iron liquid outer core rotating around the solid inner core.

This produces the earth's magnetic field.

The earth's core is made up of solid and liquid region. Only the densest elements are found within this region. So, the core is made up of metals which are mainly iron and nickel. The outer core is liquid or molten iron and the inner core is solid. The molten iron and nickel in the outer core moves around the inner core and generates the currents which induces a magnetic field round the earth.

Zack and Frankie were planning a game of flashlight tag on both Friday and Saturday night.

Answers

Answer:

oKaY?!

Explanation:

Which chemical used to make explosives is a fertilizer-based explosive, but requires nitric acid as a component to be an explosive compound, and has a wide range of uses, including as a noncorrosive de-icing material for sidewalks?
a. Aluminum nitrate
b. Triacetone triperoxide (TATP)
c. Hexamethylene triperoxide diamine (HMTD)
d. Urea nitrate

Answers

Answer:

d. Urea nitrate

Explanation:

Urea nitrate is a fertilizer-based explosive that is produced in one step by reaction of urea with nitric acid. The is an exothermic reaction, therefore, necessary steps and precautions must be taken to ensure safety during the process. The equation of the reaction is given below:

(NH₂)₂CO (aq) + HNO₃ (aq) → (NH₂)₂COHNO₃ (s)

It is as easily-made explosive and can also be used as a catalyst in Diels-Alder reactions of aromatic amines.

In the presence of water, urea nitrate readily decomposes to its original components, urea and nitric acid.

On its own, urea  is commonly used as a deicer for sidewalks as it is a noncorrosive de-icing material. However, it is a more costly method of deicing,  compared to other methods and it is best used where water runs off into vegetation than into a water-body or a storm drain because of its high-oxygen demand which could result in its reducing the oxygen level of the water body. It It is readily found in nature (in our urine) and is also  synthesized artificially.  It has a very high nitrogen content, and is most often used as a nitrogen‐based fertilizer.

Write a balanced equation for the double-replacement precipitation reaction described, using the smallest possible integer coefficients.

A precipitate forms when aqueous solutions of lead(II) nitrate and magnesium sulfate are combined.

Do not include states such as (s) or (aq). It is not necessary for you to indicate which of the products is the precipitate.

_____ + _____ ----> _____ + _____

2). Write a balanced equation for the double-replacement precipitation reaction described, using the smallest possible integer coefficients.

A precipitate forms when aqueous solutions of manganese(II) nitrate and potassium hydroxide are combined.

Do not include states such as (s) or (aq). It is not necessary for you to indicate which of the products is the precipitate.

_____ + _____ -----> _____ + _____

3). Write a balanced equation for the single-replacement oxidation-reduction reaction described, using the smallest possible integer coefficients.
The reaction that takes place when zinc metal combines with aqueous hydrobromic acid.

______ + ______ -----> _____ + _____

4). Write a balanced equation for the single-replacement oxidation-reduction reaction described, using the smallest possible integer coefficients.
The reaction that takes place when copper metal combines with aqueous silver nitrate .

_____ + _____ ---> _____ + _____

Answers

Answer:

1)Pb(NO3)(aq) + MgSO4(aq)------> Mg(NO3)2(aq) + PbSO4(s)

2)Mn(NO3)2(aq) + 2KOH(aq) ----->Mn(OH)2(s) + 2KNO3(aq)

3)Zn(s) + 2H^2+(aq)----->Zn^2+(aq) + H2(g)

4) Cu(s) + 2Ag^+(aq) ---->Cu^2+(aq) + 2Ag(s)

Explanation:

A double replacement reaction is one in which ions exchange partners.

We can see that the ions in the reactants exchanged their partners in the products. Solid lead II sulphate was precipitated.

Reaction 2 is a single replacement reaction. Solid manganese hydroxide is formed.

Reactions 3 and 4 are redox processes as shown in the respective equations.

What can you do differently for
the last half of the year in science? Whether it is
improving study skills, turning work in on time

Answers

Answer:

I would say, what helps me is really paying attention in class and asking questions, also making sure you study for upcoming test's and quizzes and completely assingments on time

Explanation:

What is the speed of an electromagnetic wave with a frequency of 8 Hz and a wavelength of 5.78 nm? (1 nm = 10-9 m)

Answers

Explanation:

Speed = Frequency * Wavelength

= 8Hz * 5.78nm

= (8 * 5.78 * 10^-9)m/s

= (4.624 * 10^-8)m/s or 46.24nm/s.

PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP!!!

DUE IN 5 MINUTES

TRUE OR FALSE? CHEMISTRY PLEASE ONLY ANSWER IF YOU’RE 100% SURE!!

Answers

Answer:

true mark me brainlist

Explanation:

3. The endpoint of a titration involving the reaction of MnO4- to Mn2+ can be detected
by the ... *

A) useofa pH probe.
B) use of redor blue litmus.
C)pink colour of the Mn+2.
D)addition of an indicator like methyl orange.

Answers

The solution of manganese ion, Mn2+ is colorless. This way, the reaction involves a colour change from pink to transparent.

There is no option with this information.

So, the best answer is (A)

Answer:

C)pink colour of the Mn+2.

Explanation:

First of all, a titration involving the change from MnO4- to Mn2+ is a redox reaction.

This redox reaction does not need an indicator because the MnO4- has a deep violet colour while Mn2+ has a light pink colour.

Hence, the change from MnO4- to Mn2+ is signaled by the appearance of the light pink colour of Mn2+ at end point.

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