Physics High School

A cart is rolling along at a steady 6.6 m/s when it meets a slope. The cart accelerates at 2.0 m/s^2 as it rolls down the hill. How far from the top of the hill will the cart move in 5.5 s

Answers

Answer 1

Answer: 2 x 5.5= 11 m

Explanation: distance is equal to speed multiplied by time

Related Questions

Susie Small finds she weighs 300 N.
Calculate her mass.

Answers

Answer:

30Kg

Explanation:

Weight = mass x gravitational field strength

300 = mass x 10

mass = 30kg

gravitational field strength is 9.8 on earth but normally we take it to be 10 for easy reference and calculations

The mass will be "30 kg". A further solution is provided below.

According to the question,

Weight,

300 N

We know that,

Gravitational field strength,

The mass will be:

→ [tex]Weight = Mass\times Gravitational \ field \ strength[/tex]

or,

→ [tex]Mass = \frac{Weight}{Gravitational \ field \ strength}[/tex]

By putting the values, we get

→ [tex]= \frac{300}{10}[/tex]

→ [tex]= 30 \ kg[/tex]

Thus the above solution is right.

Learn more about mass here:

https://brainly.com/question/20353971

A marble block has dimensions of 0.4m x 0.4m x 2m. Knowing that the density of marble is 2,400 kg / m3, calculate the mass of the block and answer:

Um bloco de mármore tem dimensões 0,4m x 0,4m x 2m. Sabendo que a densidade do mármore é 2 400 kg/m3, calcule a massa do bloco e responda:

Answers

So to find the mass we must use the formula D=M/V but because we don’t have the mass, we must use the formula M=DxV

So to find volume, just multiple the length (0.4m) width (0.4m) and height (2m) and you will get 0.32m as the volume. Now multiple this volume with your given density of 2,400 kg/m and you will get 768 kg as the mass of the marble block.

Final answer: 768 kilograms (kg) as mass of the marble block.

A student drops a pebble from the edge of a vertical cliff. The pebble hits the ground 4 s after it was dropped. What is the velocity of the pebble just before it hits the ground?
A. 20 m/s
B. 40 m/s
C. 60 m/s
D. 80 m/s

Answers

Answer:

B. 40 m/s

Explanation:

v=vo+at

a= 10m/s squared

t=4s

vo=0

v=?

v=4(10)

v=40m/s

-Have a great day!

The velocity of the object just before it hits the ground is 40 m/s

The given parameters;

time of the pebble, t = 4 s

To find;

the velocity of the object just before it hits the ground;

The following kinematic equation will be used;

[tex]v = v_0 + gt[/tex]

where;

g is the acceleration due to gravity = 10 m/s²;

[tex]v = 0 + 10 \times 4\\\\v= 40 \ m/s[/tex]

Thus, the velocity of the object just before it hits the ground is 40 m/s

Learn more here: https://brainly.com/question/17956487

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