Answer:
Explanation:
Speed is total distance traveled over time taken to do so.
If AB is measured in kilometers, time (t) for the whole trip is
t = AB/60 + AB/40
t = 2AB/120 + 3AB/120
t = 5AB/120 hrs
Average speed is distance over time
s = 2AB / (5AB/120)
s = 2(120)/5
s = 48 km/hr
s = 48(1000 m/km / 3600 s/hr) = 13.333333.... 13 m/s
Velocity is displacement over time.
As displacement is zero, velocity is zero
v = 0 km/hr = 0 m/s
Pretty harsh reporting answers just because they are wrong.
(a / xy=2x+a)does anyone can solve this??
Answer:??
Answer:
Explanation:
a / xy = 2x + a
a = 2x²y + axy
a(1 - xy) = 2x²y
a = 2x²y / (1 - xy)
a / xy = 2x + a
a = 2x²y + axy
a = y(2x² + ax)
y = a / (2x² + ax)
a / xy = 2x + a
a = 2x²y + axy
a / xy = 2x + a
0 = 2yx² + ayx - a
x = (-ay ±√((ay)² - 4(2y)(-a))) / (2(2y))
x = (-ay ±√(a²y² + 8ay)) / 4y
Magma usually stays below the Earth's
under great pressure.
o mantle
Inner core
outer core
Crust
Answer:
In the inner vote part of the earth
at room tmeperature none of the metals are
What metal is not at room temperature?
Mercury is a metallic chemical element that is an only metal that is not a solid at room temperature.
The vertical and horizontal components of the velocity of a golf ball after being struck by a club are 4.0 m s1 and 5.0 m s respectively. Determine the magnitude and direction of the velocity of the golf ball. A 6.30 m s-1 B 6.35 m s-1 C 6.40 m s-1 D 6.45 m 5-1
The magnitude and direction of the velocity of the golf ball is 6.4 m/s at 38.7⁰.
The given parameters:
Vertical component of the velocity, [tex]v_y = 4 \ m/s[/tex]Horizontal component of the velocity, [tex]v_x = 5 \ m/s[/tex]The magnitude of the resultant velocity of the golf ball is calculated as follows;
[tex]v= \sqrt{v_y^2 + v_x^2} \\\\v = \sqrt{4^2 + 5^2} \\\\v = 6.4 \ m/s[/tex]
The direction of the golf ball's velocity is calculated as follows;
[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{4}{5} )\\\\\theta = 38.7 \ ^0[/tex]
Thus, the magnitude and direction of the velocity of the golf ball is 6.4 m/s at 38.7⁰.
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You are in Paris, 50. m up on an Eiffel Tower support leg observation deck. If you throw a euro downward at a velocity of -1.0 m/s, how long would it take the coin to hit the ground?
Here’s my work to your question. I used kinematic equations to solve. :)
which of the following are ways in which energy can be transferred to or from a substance?
a.) heat and internal energy
b.) work and internal energy
c.) heat and work
d.) heat and kinetic energy
Answer:
a
Explanation:
the answer is a because it is feasible
______ uses radioactive materials to create contrast in the body and help form images of the structure and function of organs.
Answer:
Nuclear medicine or PET scanning (Positron Emission Tomography)
Explanation:
Not super sure what your question is looking for but I think it can be either. PET is a technology used in the nuclear medicine field, and nuclear medicine is a broad field of using the technology the question described.
What is an ellipse?
a plane that slices between orbits
an oval-shaped orbit
a circular orbit
the center of gravity between orbiting objects
Answer:
i think it's C thx correct me if wrong
One potato plant makes 7.5
potatoes. There are 10.000
people on a ship and 3
potatoes per person. How
many potato plants are
needed per person.
If all conditions are ideal, you may harvest about five to 10 potatoes per plant for your gardening efforts. Yields are based on both the care your give your plants during the growing season and the variety of potatoes you choose to grow.
answer
7.5×10.000=75÷3=25
A 0.75 kg model car is moving west at a speed of 9.0 m/s when it collides head-on with a 2.00 kg model truck that is traveling east at a speed of 10.0 m/s. After the collision, the 0.75 kg model car is now moving east at 11 m/s. What is the speed and direction of the model truck after the collision?
Answer:
2.5 m/s east
Explanation:
Let east be the positive direction for velocity.
The change in momentum of the 0.75 kg model car is ...
m1·v2 -m1·v1 = (0.75 kg)(11 m/s) -(0.75 kg)(-9 m/s)
= (0.75 kg)(20 m/s) = 15 kg·m/s
The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.
m2·v2 -m2·v1 = (2 kg)(v2 m/s) -(2 kg)(10 m/s) = 2(v2 -10) kg·m/s
The required relation is ...
15 kg·m/s = -2(v2 -10) kg·m/s
-7.5 = v2 -10 . . . . divide by -2
2.5 = v2 . . . . . . . add 10
The velocity of the model truck after the collision is 2.5 m/s east.
Would you please help me with this? I can't figure it out, please! I need to know what the E means!
Answer:
Without the full content of your question, I will have to GUESS at the context and assume
E = Energy
released when glucose is broken down.
all pressure topics in physics
Describe a vibration that is not periodic. NO LINKS PLEASE
Answer:
1)The position change of almost any manually operated room light switch.
2) Sunlight striking a point on the ground on a partly cloudy and windy day
Explanation:
2 examples of non fossil fuels ?
Answer:
-> Hydropower
-> Solar power
Explanation:
-> Hydropower
[] The power of water! It is the use of falling or fast-running water to produce electricity for power. Impoundments or da*ms are mainly used in this type of power source.
-> Solar power
[] The power of the sun! It is the use of sunlight, or solar energy, to produce electricity for power. You have probably heard of solar panels, and this is the main way to collect it.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
Wind energy and solar power
Explanation:
they do not use fossil fuels
True or False If the mass of the object increases, then the potential energy of the object decreases.
In Newton's cannonball experiment, if the velocity is equal the orbital velocity the Cannon ball
will
O stay in orbit
O fall to the earth
O escape the earth
O none of the above
In Newton's cannonball experiment, if the velocity is equal to the orbital velocity then the cannonball will stay in Orbit.
Newtons cannonball experiment stated that the distance that a cannonball will travel, before being drawn into the Earth by the forces of gravity, is dependent on the initial velocity.
Therefore, if the cannonball is launched at a velocity that matches the orbital velocity, then it will not be able to be drawn in by gravity due to the Earth moving away from the cannonball at the same speed at which the cannonball itself is falling.
This means that the cannonball will continue to fall without reaching the Earth, therefore staying in orbit, much like that of the moon or planets around the sun.
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Explain how the linear rate spring operates?
Please respect! Can you answer this for me?
Answer:
ıf u find the answer can u comment me to notification thank u
Explanation:
For northern hemisphere observers, which celestial object would be above the horizon for the greatest
amount of time: one that is on the celestial equator, one that is 30° above the celestial equator, one that is
70° above the celestial equator, or one that is 40" below the celestial equator? Which one would be above
the horizon the greatest amount of time for southern hemisphere observers? Explain your answer.
Answer:
Explanation:
For a person at about 20° North latitude, an object 70° above the celestial equator would never set. It's arc path would touch the horizon be never sink below it. Observers north of 20° see it all night. Observers south of 20° an object 70° above the celestial equator would spend the greatest amount of time above the horizon.
For southern hemisphere observers, the object 40" below the celestial equator will spend the most time above the horizon. Nearly 12 hours per day. Did you mean 40°? 40 seconds is very close to the equator itself. However, the result is the same.
For northern hemisphere observers, the celestial object that is 70° above the celestial equator would be above the horizon for the greatest amount of time.
What is the equator?The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.
For northern hemisphere observers, the celestial object that is 70° above the celestial equator would be above the horizon for the greatest amount of time.
One that is 40" below the celestial equator would be above the horizon for the greatest amount of time for southern hemisphere observers.
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AP Physical problem the wording is really throwing me off and im totally lost on how to do this. I would love some help please and thank you!
Explanation:
a) Here is the free-body diagram. Note that I included the components of the weight mg (shown in dotted arrows) for use in the other parts of the problem.
b) The component of the weight parallel to the plane (shown in the diagram as a dotted arrow along the x-axis) is [tex]mg\sin15[/tex] and it is equal to
[tex]mg\sin15 = (25\:\text{kg})(9.8\:\text{m/s}^2)\sin15 = 63.4\:\text{N}[/tex]
c) Applying Newton's 2nd law to the y-axis, we can write
[tex]y:\;\;\;N - mg\cos15 = 0 \Rightarrow N = mg\cos15[/tex]
[tex]N = (25\:\text{kg})(9.8\:\text{m/s}^2)\cos15 = 236.7\:\text{N}[/tex]
d) The component of the weight mg into the plane is the same as the normal force, hence it's also 236.7 N.
e) To solve for the coefficient of friction, we apply Newton's 2nd law to the x-axis:
[tex]x:\;\;\;mg\sin15 - F_f = 0[/tex]
[tex]\Rightarrow F_f = mg\sin15\;\;(2)[/tex]
where [tex]F_f[/tex] is the frictional force defined as [tex]F_f = \mu N[/tex] so we can use Eqn(1) on Eqn (2) to write
[tex]\mu (mg\cos15) = mg\sin15[/tex]
Solving for [tex]\mu,[/tex] we get
[tex]\mu = \dfrac{\sin15}{\cos15} = \tan15 = 0.27[/tex]
Draw the graphs for exothermic and endothermic reactions Label: axes, reactants, products, Energy of reaction, heat energy change
Answer:
axes, reactants, products, Energy of reaction, heat energy
Explanation:
axes, reactants, products, Energy of reaction, heat energyaxes, reactants, products, Energy of reaction,grreactantsaphs heat energy
someone plz help
An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Answer:
Explanation:
v² = u² + 2as
a = (v² - u²) / 2s
a = (93² - 0²) / (2(49))
a = 88.255102...
a = 88 m/s²
Which of these is a push or a pull? Acceleration Force Mass Inertia
Answer:
the answer is force . force is applied as a push or pull
Best way to demonstrate that waves transfer energy
Answer:
Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.
Explanation:
A person sitting in a chair with wheels stands up, causing the chair to roll backward across the floor. The momentum of the chair
a. was zero while stationary and increased when the person stood.
b. was greatest while the person sat in the chair.
c. remained the same.
d. was zero when the person got out of the chair and increased while the person sat.
Answer:
a. was zero while stationary and increased when the person stood.
Explanation:
momentum is mass times velocity.
initial velocity was zero
final velocity was NOT zero.
How much power does it take to lift 30.0 N 10.0 m high in 10.00 s?
Answer:
60w
Explanation:
The power required is 30 Watt.
Let us recall that power is defined as the rate of doing work. Hence, we can write as follows;
Power = Work done/ time taken
Now;
work done = Force × distance
Force = 30.0 N
Distance = 10.0 m
work done = 30.0 N × 10.0 m = 300 J
The power expended = 300 J/10.00 s = 30 Watt
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Name the energy possessed by hot air
Answer:
geothermal energy
Explanation:
the energy is obtained from the heat within the surface of earth
Answer:
heat energy
Explanation:
What is the height of a building (in meters) if it takes a rock 8.2 seconds to drop from it's roof?
Answer:
d = 329.81m
Explanation:
V_f = V_0+a*t
V_f = Velocity final
V_0 = Velocity initial
a = acceleration
t = time
V_f = (0m/s)+(9.81m/s²)*(8.2s)
V_f = 80.442m/s
d = ((V_f-V_0)/2)*t
d = distance
d = ((80.442m/s-0m/s)/2)*(8.2s)
d = 329.81m
Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2.
The two cars stick together after the collision.
Car 2 was traveling at v2i = 30.0 m/s before the collision.
What is the kinetic, in [J], of the system after the collision if m1 = 2500 kg and m2 = 1000 kg?
Answer:
Explanation:
Conservation of momentum
2500(0) + 1000(30) = (2500 + 1000)v
v = 8.57 m/s
KE = ½(2500 + 1000)8.57² = 128,571.428... = 128 KJ
The kinetic energy of the system after the collision would be 128.5 KJ.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2. The two cars stick together after the collision. Car 2 was traveling at v2i = 30.0 m/s before the collision.
By using the conservation of the momentum,
2500(0) + 1000(30) = (2500 + 1000)v
v = 8.57 m/s
The final velocity of the system comes out to be 8.57 m/s.
The kinetic energy of the system after the collision,
KE =1/2×(2500 + 1000)×8.57² = 128,571.4
= 128.5 KJ
Thus, the kinetic energy of the system after the collision would be 128.5 KJ.
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A 3.2 kg solid disk with a radius of 0.45 m has a tangential force of 420.4 N applied to it. What is the moment of inertia applied to the disk
Answer:
Explanation:
Your question makes no sense.
moment of inertia is a property of the disk and its geometry.
The moment of inertia of a uniform solid disk around an axis through its geometric center and perpendicular to its flat ends is
I = ½mR² = ½(3.2)0.45² = 0.324 kg•m²
the applied torque about the same axis would be
τ = FR = 420.4(0.45) = 189.18 N•m
and the angular acceleration about the same axis would be
α = τ/I = 189.18/0.324 = 583.9 rad/s²