A candy company claims that 31% of the candies are orange. We randomly sample 100 candies. We wish to know the probability our sample is 29% orange candies or less. Round answers to 4 decimal places and answer numerically (0.31, not 31%)

Find the probability our sample is 29% orange candies or less P(x<0.29)

Answers

Answer 1

Using the normal distribution and the central limit theorem, it is found that:

P(x < 0.29) = 0.2981.

Normal Probability Distribution

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex], as long as [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex].

In this problem:

31% of the candies are orange, hence p = 0.31.We randomly sample 100 candies, hence n = 100.

Then, the mean and the standard error are given by:

[tex]\mu = p = 0.31[/tex]

[tex]s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.31(0.69)}{100}} = 0.04625[/tex]

The probability our sample is 29% orange candies or less is the p-value of Z when X = 0.29, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.29 - 0.31}{0.04625}[/tex]

[tex]Z = -0.43[/tex]

[tex]Z = -0.43[/tex] has a p-value of 0.2981.

Hence:
P(x < 0.29) = 0.2981.

To learn more about the normal distribution and the central limit theorem, you can take a look at https://brainly.com/question/24663213


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Answers

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Step-by-step explanation:

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Answers

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Answers

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Answers

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Here we have two parallel lines lines( UB and DK).

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Answers

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Answers

Answer: 36

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Answer:

36

Step-by-step explanation:

Hi there!

We want to find the least common multiple (LCM) of 12 and 18

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Answers

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Answers

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Answers

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Answers

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Answers

Answer:

d = 50

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Answers

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sine 60

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Answers

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Answers

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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